#8656: face_lattice does not seem to work for unbounded polyhedra
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   Reporter:  novoselt  |       Owner:  mhampton  
       Type:  defect    |      Status:  new       
   Priority:  major     |   Milestone:  sage-4.4.2
  Component:  geometry  |    Keywords:            
     Author:            |    Upstream:  N/A       
   Reviewer:            |      Merged:            
Work_issues:            |  
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Comment(by vbraun):

 The non-compactness is not the issue, the 1-d interval in a 2-d ambient
 space fails as well:

 {{{
 sage: for lset in
 Polyhedron(vertices=[(1,0),(0,1)]).face_lattice().level_sets(): print lset
 ....:
 [(None, (0, 1, 2))]
 [((1,), (0, 2)), ((0,), (0, 1))]
 [((0, 1), (0,))]
 [((0, 1), None)]
 }}}

 On the other hand, I would argue that the novoselt's Quadrant example is
 correct: The rays stand for points at infinite distance and are properly
 counted as points. A triangle would have 8 faces. The edge at infinity is
 not counted as a face of the quadrant (=double infinite triangle), hence
 the quadrant does have 7 faces.

 The fundamental flaw of the face_lattice() function is that
 1) its description does not explain in detail what is computed
 2) The result should be returned by means of the H/Vrepresentation
 objects, and not by their indices.

-- 
Ticket URL: <http://trac.sagemath.org/sage_trac/ticket/8656#comment:1>
Sage <http://www.sagemath.org>
Sage: Creating a Viable Open Source Alternative to Magma, Maple, Mathematica, 
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