#10254: elimination_ideal returns an ideal of the original ring
---------------------------+------------------------------------------------
   Reporter:  mmezzarobba  |       Owner:  AlexGhitza
       Type:  defect       |      Status:  new       
   Priority:  major        |   Milestone:            
  Component:  algebra      |    Keywords:            
     Author:               |    Upstream:  N/A       
   Reviewer:               |      Merged:            
Work_issues:               |  
---------------------------+------------------------------------------------
 If ``J`` is an ideal of a Multivariate Polynomial Ring ``R``,
 ``J.elimination_ideal`` returns an ideal of ``R``, regardless of the
 variables being eliminated.  Is this intentional?

 For instance, in the doctest
 {{{
 sage: R.<x,y,t,s,z> = PolynomialRing(QQ,5)
 sage: I = R * [x-t,y-t^2,z-t^3,s-x+y^3]
 sage: I.elimination_ideal([t,s])
 Ideal (y^2 - x*z, x*y - z, x^2 - y) of Multivariate
 Polynomial Ring in x, y, t, s, z over Rational Field
 }}}
 the final result is an ideal of Q[x,y,t,s,z], while I would have expected
 an ideal of Q[x,y,z].

-- 
Ticket URL: <http://trac.sagemath.org/sage_trac/ticket/10254>
Sage <http://www.sagemath.org>
Sage: Creating a Viable Open Source Alternative to Magma, Maple, Mathematica, 
and MATLAB

-- 
You received this message because you are subscribed to the Google Groups 
"sage-trac" group.
To post to this group, send email to [email protected].
To unsubscribe from this group, send email to 
[email protected].
For more options, visit this group at 
http://groups.google.com/group/sage-trac?hl=en.

Reply via email to