#10930: specializations for symmetric functions
-----------------------------+----------------------------------------------
Reporter: mantepse | Owner: mantepse
Type: enhancement | Status: new
Priority: minor | Milestone: sage-4.7
Component: combinatorics | Keywords: principal specialization,
exponential specialization, symmetric functions
Author: Martin Rubey | Upstream: N/A
Reviewer: | Merged:
Work_issues: |
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Comment(by mantepse):
Hi Jason!
Many thanks for your quick comments.
1) Using trace I find
{{{
sage: S = SymmetricFunctions(QQ); s=S.s(); f = s[2,1]
sage: trace("f.principal_specialization()")
> <string>(1)<module>()
ipdb> s
--Call--
> /home/martin/SAGE/local/lib/python2.6/site-
packages/sage/combinat/sf/sfa.py(1653)principal_specialization()
1652
-> 1653 def principal_specialization(self, n=infinity, q=var('q')):
1654 r"""
ipdb> s
> /home/martin/SAGE/local/lib/python2.6/site-
packages/sage/combinat/sf/sfa.py(1681)principal_specialization()
1680 """
-> 1681 from sage.combinat.sf.sf import SymmetricFunctions
1682 p = SymmetricFunctions(self.parent().base_ring()).p()
ipdb>
}}}
but I was hoping that the principal specialisation from schur.py would be
called.
2) Well, currently the actual value of 1 is not used at all (I test q==1
and call principal_specialization without passing q). So my question
really is: some day somebody might implement something where the q is
actually used. Is it better then if the default is None and the doc says,
None should always mean one?
Thanks again!
--
Ticket URL: <http://trac.sagemath.org/sage_trac/ticket/10930#comment:5>
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