#2607: find_minimum_on_interval() uses the wrong scipy function
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Reporter: AlexGhitza | Owner: was
Type: defect | Status: new
Priority: major | Milestone: sage-4.7.1
Component: calculus | Keywords: sd31
Work_issues: | Upstream: N/A
Reviewer: | Author:
Merged: | Dependencies:
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Comment(by kcrisman):
#5960 was a dup. Here are the examples from there.
{{{
sage: h(x) = -sin(x) - 2*sin(2*x)
sage: h.find_minimum_on_interval(0, 2*pi)
(-1.3271810224585345, 3.8298351449342838)
But there is another local minimum at h(0.8666760871050464) =
-2.73581510406
sage: find_minimum_on_interval(x*(x-1)*(x+1), -2, 2)
(-0.38490017945975047, 0.57735026913115706)
The minimum on this interval is the endpoint h(-2) = 6.
sage: find_minimum_on_interval((x-2)*(x-1)*x*(x+1) - x, -2, 2)
(-0.43749999999999994, -0.49999999973911674)
but
sage: find_minimum_on_interval((x-2)*(x-1)*x*(x+1) - x, 0, 2)
(-2.6642135623730949, 1.7071067879138031)
}}}
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Ticket URL: <http://trac.sagemath.org/sage_trac/ticket/2607#comment:8>
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