#11309: Sage sees -x +y > 0, -y + x >= 0, and x -y > 0 as equivalent
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Reporter: tnv | Owner: burcin
Type: defect | Status: positive_review
Priority: major | Milestone: sage-4.7.1
Component: symbolics | Keywords: inequality equality
relational sd31 __richcmp__
Work_issues: | Upstream: N/A
Reviewer: Karl-Dieter Crisman | Author: Keshav Kini, Burcin
Erocal
Merged: | Dependencies:
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Comment(by tnv):
It now can tell that -x +y >0 is different than -y + x >= 0 but it says
that -x+y >0 is not the same as y > x ---
or may be this is another problem ?
{{{
sage: ( -x+y >0 ) == (y > x )
False
sage: (-x + y < 0) == (-x < -y)
False
sage: (x + y == 0) == (x == -y)
False
sage: (x - y == 0) == (x == y)
False
sage: (- x + y == 0) == (0 == -x + y)
False
sage: (x < y) == (y > x)
False
sage: (x == y) == (-x == -y)
False
sage: (x + y < 1 ) == (x + y -1 < 0)
False
}}}
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Ticket URL: <http://trac.sagemath.org/sage_trac/ticket/11309#comment:20>
Sage <http://www.sagemath.org>
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