#11498: Improve LaTeXing of strings
-----------------------------+----------------------------------------------
Reporter: novoselt | Owner: jason, mpatel, was
Type: enhancement | Status: needs_review
Priority: major | Milestone: sage-4.7.1
Component: notebook | Keywords: sd31
Work_issues: | Upstream: N/A
Reviewer: John Palmieri | Author: Andrey Novoseltsev
Merged: | Dependencies:
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Comment(by jhpalmieri):
I happened to take a look at the ticket, so I saw the new patch; mine is
based on that one.
The documentation for regular expressions in Python is
[http://docs.python.org/library/re.html here]. In the code
{{{
if s.find('\\verb') != -1:
import re
s = re.sub("\\\\verb(.)(.*?)\\1", "\\2", s)
s = s.replace("\\phantom{x}", " ")
}}}
the second and third lines are the ones involving regular expressions.
Line 3 is a search-and-replace command: it searches the argument s for a
pattern {{{\verb}}} followed by a single character (that's the {{{.}}}),
and putting that character in parentheses allows you to refer to it later
as {{{\1}}}. Then there are any number of characters (that's the
{{{.*?}}}, also enclosed in parentheses, so you can refer to it later as
{{{\2}}}), followed by whatever the first character was (that's the
{{{\\1}}}). It replaces all of this with the string in the second set of
parentheses, {{{\2}}}.
There is one subtlety in this: the standard way to refer to any string of
characters is {{{.*}}}, but the problem here is that in a string like
{{{
\verb|a|, \verb|b|
}}}
if we used {{{.*}}}, then the string \2 would match "a|, \verb|b" --
everything between the first "|" and the last "|": by default, regular
expression matches use the longest match possible. Using {{{.*?}}}
instead of {{{.*}}} tells it to match the shortest string possible
instead, so it does two replacements: first \2 matches "a", and then it
matches "b", turning this into
{{{
a, b
}}}
--
Ticket URL: <http://trac.sagemath.org/sage_trac/ticket/11498#comment:8>
Sage <http://www.sagemath.org>
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