#11155: abs(pi+I) = pi+I
--------------------------+-------------------------------------------------
Reporter: benreynwar | Owner: burcin
Type: defect | Status: new
Priority: critical | Milestone: sage-5.0
Component: symbolics | Keywords:
Work_issues: | Upstream: N/A
Reviewer: | Author:
Merged: | Dependencies:
--------------------------+-------------------------------------------------
Changes (by was):
* cc: burcin (added)
* priority: major => critical
* milestone: => sage-5.0
Old description:
> abs(pi+I) returns pi+I
>
> one would have expected:
> sqrt(pi^2+1)
New description:
abs(pi+I) returns pi+I
one would have expected:
{{{
sqrt(pi^2+1)
}}}
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Comment:
I can confirm this further. It's mathematically seriously incorrect... so
now moving from major to critical, and cc'ing burcin.
Note:
{{{
sage: z = pi + i
sage: abs(z)
pi + I
sage: sqrt((z*z.conjugate()).expand())
sqrt(pi^2 + 1)
}}}
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Ticket URL: <http://trac.sagemath.org/sage_trac/ticket/11155#comment:2>
Sage <http://www.sagemath.org>
Sage: Creating a Viable Open Source Alternative to Magma, Maple, Mathematica,
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