#12993: Bug in determining whether a poset is graded
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   Reporter:  saliola        |             Owner:  sage-combinat  
       Type:  defect         |            Status:  new            
   Priority:  major          |         Milestone:  sage-5.1       
  Component:  combinatorics  |          Keywords:  poset, combinat
Work issues:                 |   Report Upstream:  N/A            
  Reviewers:                 |           Authors:                 
  Merged in:                 |      Dependencies:                 
   Stopgaps:                 |  
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 This should return True:
 {{{
 sage: P = Poset(([1,2,3,4],[[1,4],[2,3],[3,4]]), facade = True)
 sage: P.is_graded()
 False
 }}}

 Anne's suggestion from this [https://groups.google.com/d/topic/sage-
 combinat-devel/XsMrxKdvl1A/discussion thread] on sage-combinat-devel:

     For a finite poset perhaps the easiest would be to

     - start with a random element in the poset, assign rank 0
     - look at all covers and cocovers and assign the rank according to the
 recurrence rank(x) = rank(y) + 1 if x covers y.
     - repeat with the new elements
     - if at any point an element is reached again and is assigned a
 different value from before, the poset is not graded; otherwise continue
 with new elements

-- 
Ticket URL: <http://trac.sagemath.org/sage_trac/ticket/12993>
Sage <http://www.sagemath.org>
Sage: Creating a Viable Open Source Alternative to Magma, Maple, Mathematica, 
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