#12313: Fix yet another memory leak caused by caching of coercion data
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Reporter: SimonKing | Owner:
Type: defect | Status:
needs_review
Priority: major | Milestone: sage-5.3
Component: memleak | Resolution:
Keywords: coercion weak dictionary | Work issues:
Report Upstream: N/A | Reviewers: Simon King,
Jean-Pierre Flori, John Perry
Authors: Simon King, Jean-Pierre Flori | Merged in:
Dependencies: #11521, #11599, #12969, #12215 | Stopgaps:
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Comment (by SimonKing):
For completeness: `IdKeyDict` is also faster than a Python dict, but of
course that should mainly be true because we are comparing by identity,
not equality.
{{{
sage: from sage.structure.idkey_dict import IdKeyDict
sage: I1 = IdKeyDict(1,53)
sage: I3 = IdKeyDict(3,53)
sage: D1 = {}
sage: D3 = {}
sage: L = []
sage: for p in prime_range(10000):
....: L.append(GF(p)['x','y'])
....:
sage: for i,K in enumerate(L):
....: I1[K] = i
....: I3[K,K,True] = i
....: D1[K] = i
....: D3[K,K,True] = i
....:
sage: K = GF(97)['x','y']
sage: K2 = GF(next_prime(p))['x','y']
sage: K in I1
True
sage: K in D1
True
sage: K2 in I1
False
sage: K2 in D1
False
sage: (K,K,True) in D3
True
sage: (K,K,True) in I3
True
sage: %timeit K in D1
625 loops, best of 3: 720 ns per loop
sage: %timeit K in I1
625 loops, best of 3: 560 ns per loop
sage: %timeit K2 in D1
625 loops, best of 3: 763 ns per loop
sage: %timeit K2 in I1
625 loops, best of 3: 400 ns per loop
sage: %timeit (K,K,True) in D3
625 loops, best of 3: 1.53 µs per loop
sage: %timeit (K,K,True) in I3
625 loops, best of 3: 1.3 µs per loop
sage: %timeit (K2,K,True) in D3
625 loops, best of 3: 1.45 µs per loop
sage: %timeit (K2,K,True) in I3
625 loops, best of 3: 555 ns per loop
sage: %timeit D1[K]
625 loops, best of 3: 647 ns per loop
sage: %timeit I1[K]
625 loops, best of 3: 502 ns per loop
sage: %timeit D3[K,K,True]
625 loops, best of 3: 1.48 µs per loop
sage: %timeit I3[K,K,True]
625 loops, best of 3: 1.23 µs per loop
}}}
--
Ticket URL: <http://trac.sagemath.org/sage_trac/ticket/12313#comment:171>
Sage <http://www.sagemath.org>
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