Quoting Jon Detert <[email protected]>:
On Mon, Feb 21, 2011 at 4:15 PM, Mike Brady
<[email protected]> wrote:
Quoting Jon Detert <[email protected]>:
Hello,
I can't join a winxp box to my samba domain. I just have one samba
server, meant to act as a PDC for domain='CHI'.
Any ideas how to troubleshoot and/or remedy?
Thanks,
Jon
Context:
------------
samba v3.3.8 on CentOS v5.5, using ldapsam backend. Domainname ='CHI'.
smbldap-tools v0.9.6.
I 'populated' the ldap with 'smbldap-populate'.
I try to join the winxp box, authenticating to the domain as user
'jdetert', which is a member of the 'Administrators' group:
# smbldap-groupshow Administrators
dn: cn=Administrators,ou=Groups,dc=infinityhealthcare,dc=com
objectClass: top,posixGroup,sambaGroupMapping
gidNumber: 544
cn: Administrators
description: Netbios Domain Members can fully administer the
computer/sambaDomainName
sambaSID: S-1-5-32-544
sambaGroupType: 5
displayName: Administrators
memberUid: jdetert,root
What happens:
----------------------
a failure dialog window pops up on the winxp box with this message:
'The following error occurred attempting to join the domain "CHI":
The user name could not be found.'
-- snip --
I am working through a similar setup at the moment.
Looking at the smbldap-useradd source, status 9 is "user must not exist in
LDAP", so I assume from that that the workstation userid already exists?
Turns out you are correct. So, I deleted the 'user'="testfsclient$"
from the ou=Computers, and retried, but it failed with the same error,
and it re-created the user object.
Any ideas how/why joining the domain is not fully working?
Thanks,
Jon
Jon
The error is returned if there is a successful LDAP query for the
machine name "anywhere" in LDAP. Does the machine name exist
somewhere else other than ou=Computers?
You could also try running the full smbldap-useradd command as it is
logged from the command line and see if it gives any more information.
The smldap-user script does print out additional information that
Samba doesn't look like it captures in the logs.
Mike
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