ok.. anyone know how to do this right off. Still working with variable interpreting and now I need to create a scalar based on it. ie;
$fname=danny; $$fname=test; Now I know the above will result in scalar $danny = test but I need to create something like such. $$fname . $lname=mallory; To create a scalar called $dannylname and set to mallory but I am getting concatenation errors on scalar assignment. Any Ideas? Danny -------------------------------------------------------------------------------- For unsubscription of this list send an email to [EMAIL PROTECTED] with email data containing unsubscribe emailadd sambar
