Le 20/06/2011 21:21, Romain Beauxis a écrit : > Le 20 juin 2011 11:22, Mix Dance<[email protected]> a écrit : >> Hi! > Hi! > >> If the name of my podcast is "podcast 32.mp3", i must use this example? > > If you want to extract the number, you only need to use string.extract: > ret = string.extract(pattern="podcast\s([0-9]+).mp3", filename) > number = ret["1"] > > Romain > >> def url.split(uri) = >> >> ret = string.extract(pattern="#podcast ({0-9}+).mp3$#,uri) >> >> args = ret["2"] >> >> if args != "" then >> >> l = string.split(separator="&",args) >> >> def f(x) = >> >> ret = string.split(separator="=",x) >> >> (url.decode(list.nth(ret,0)), >> >> url.decode(list.nth(ret,1))) >> >> end >> >> l = list.map(f,l) >> >> (ret["1"],l) >> >> else >> >> (uri,[]) >> >> end >> >> end >> >> But how recover the name of the file in play progress? >> Thanks >> >> Antoine >> Hi
I have try tour example but i have an error: At line 54, char 59: unbound symbol filename The line 54 is: ret = string.extract(pattern="podcast ([0-9]+).mp3", filename) I think the variable doesn't exist but i don't know what is the good variable Thanks Antoine ------------------------------------------------------------------------------ EditLive Enterprise is the world's most technically advanced content authoring tool. Experience the power of Track Changes, Inline Image Editing and ensure content is compliant with Accessibility Checking. http://p.sf.net/sfu/ephox-dev2dev _______________________________________________ Savonet-users mailing list [email protected] https://lists.sourceforge.net/lists/listinfo/savonet-users
