Hi,
Here is how I can print the first line of your page. I hope the code
is self-explanatory...
# GET the file
f = snd(http.get("http://feeds.wnyc.org/radiolab";))
# Split in lines
l = string.split(separator="\n",f)
# Print the first line
print(list.hd(l))
Cheers,
Samuel
On Sun, Aug 23, 2015 at 8:34 PM, Eduardo Martinez
<[email protected]> wrote:
> Hello,
>
> Can anybody on the list answer this question?
> Is there a simple way to convert a playlist source to a list in order to use
> list.hd to retrieve only the first item within a RSS playlist?
>
> Of course I can simply do this outside of ls, but I'm trying to stay within
> liquidsoap.
>
>
> On Fri, Aug 21, 2015, 4:42 PM Eduardo Martinez <[email protected]>
> wrote:
>>
>> How can I retrieve only the first item from a RSS playlist source?
>>
>> I'm trying something like:
>>
>> single(list.hd(playlist("http://feeds.wnyc.org/radiolab";)))
>>
>> But list.hd is expecting an actual list not a source.
>>
>> At line 8, char 35-151:
>> this value has type
>> source(_)
>> but it should be a subtype of
>> [_]
>>
>> Is there a way to convert a playlist to a list object so I can then use
>> list.hd?
>> Or is there another mechanism to retrieve only the first item from a
>> playlist source?
>>
>> Thanks in advance.
>>
>
> ------------------------------------------------------------------------------
>
> _______________________________________________
> Savonet-users mailing list
> [email protected]
> https://lists.sourceforge.net/lists/listinfo/savonet-users
>
------------------------------------------------------------------------------
_______________________________________________
Savonet-users mailing list
[email protected]
https://lists.sourceforge.net/lists/listinfo/savonet-users
