On Fri, Dec 11, 2015 at 06:22:22PM -0700, Mike Brown wrote:
> In the meantime, I would still be excited to know if there is a way to get
> access to the filename or the full path from the playlist, so I don't have to
> resort to annotations.
Figured it out.
If you run 'liquidsoap -r untaggedfile.mp3' you will see the undocumented
metadata added by liquidsoap. This includes initial_uri and filename.
I don't know where these come from, but it seems that when the playlist is a
list of file paths, initial_uri and filename values are the same, i.e.
"filename" includes the whole path.
You can do some string manipulation to parse this path in an attempt to get
discrete artist & title values, or you can whittle it down to just the base
filename to set as title, omitting the artist. Here's the general idea:
def set_song(m) =
a = m["artist"]
t = m["title"]
if a == "" and t == "" then
# get the everything after the last slash or backslash in the filename
t = list.nth(list.rev(string.split(separator='(/|\\)',m["filename"])),0)
# remove the extension
t = list.nth(string.split(separator='\.',t),0)
# before first space-dash-space is artist, after is title
parts = string.split(separator=" - ",t)
if list.length(parts) > 1 then
a = list.nth(parts,0)
t = string.concat(separator=" - ",list.tl(parts))
[("artist","#{a}"),("title","#{t}")]
else
[("artist","#{a}"),("title","#{t}")]
end
else
[("artist","#{a}"),("title","#{t}")]
end
end
s = map_metadata(strip=true,set_song,s)
While researching this, I discovered that if you want string.split() to have a
lone backslash as the separator regex, separator='\\' will not parse.
Strangely, separator='\\.' does work, but of course it picks up the next
character after the backslash. I tried between one and four backslashes and
combos with \029, all to no avail. Finally I hit on a workaround:
separator='(\\)'. Bizarre!
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