Thanks Nick, your tip is valuable. Am Mittwoch, 22. Oktober 2014 15:33:14 UTC+2 schrieb Nick Stanchenko: > > Hi, > > It should be relatively straightforward if you know your way around macros > :) > Here’s one that serializes pairs (key, value): > https://github.com/macroid/macroid/blob/master/src/main/scala/macroid/Bundles.scala#L24 > From there, you just need to add the case class inspection bit. Example (a > bit convoluted): > https://github.com/jto/validation/blob/master/validation-core/src/main/scala/play/api/data/mapping/MappingMacros.scala#L41, > > see also line 89 for usage. > On a final note, I would make it typeclass-based rather than > inheritance-based: > > trait Bundleable[A] { > def toBundle(x: A): Bundle > def fromBundle(b: Bundle): Try[A] > } > > implicit def genBundleable[A]: Bundleable[A] = macro ??? > > def bundle[A: Bundleable](x: A) = > implicitly[Bundleable[A]].toBundle(x) > > This way you can define instances of Bundleable[A] both manually and > automatically. And your data model is not polluted with Android nonsense. > > Hope that helps, > Nick > > > On Wednesday, October 22, 2014 8:06:44 AM UTC+1, David Pérez wrote: >> >> Hi all, >> >> I've made recently this StackOverflow question: >> >> >> http://stackoverflow.com/questions/26501968/deserializing-objects-automatically-to-a-bundle >> >> Any answers and/or clues will be welcome. >> >> David >> >
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