Arthur A. Gleckler scripsit: > The eqv? procedure returns #t if... obj1 and obj2 are procedures whose > location tags are equal. > > The eqv? procedure returns #f if... obj1 and obj2 are procedures > that would behave differently (return different value(s) or have > different side effects) for some arguments. > > The above definition of eqv? allows implementations latitude in > their treatment of procedures and literals: implementations are free > either to detect or to fail to detect that two procedures or two > literals are equivalent to each other, and can decide whether or not > to merge representations of equivalent objects by using the same > pointer or bit pattern to represent both.
+1 > Eq? and eqv? are guaranteed to have the same behavior on symbols, > booleans, the empty list, pairs, procedures, and non-empty strings > and vectors. +1, with the addition of records after pairs and bytevectors after vectors. -- John Cowan [email protected] http://www.ccil.org/~cowan Does anybody want any flotsam? / I've gotsam. Does anybody want any jetsam? / I can getsam. --Ogden Nash, No Doctors Today, Thank You _______________________________________________ Scheme-reports mailing list [email protected] http://lists.scheme-reports.org/cgi-bin/mailman/listinfo/scheme-reports
