On Wed, Oct 26, 2011 at 22:48, Robert Layton <[email protected]> wrote:
> You have it correct. I haven't done this level of algebra for a while, so
> I'll need to work it out.
> If I have it correctly, I should be able to do:
> log(a!) + log(b!) + log((N-a)!) + log((N-b)!) - log(N!) - log(n!) -
> log((a-n)!) - log((b-n)!) - log((N-a-b+n)!),
> then apply Stirling and simplify?

Exactly.


-- 
 - Alexandre

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