On Fri, Dec 30, 2011 at 11:28:39AM +0100, Andreas Mueller wrote:
> It might be that I haven't really understood the meaning of ROC
> curves, but I thought it worked like @ogrisel said.
> Whatever the correct method to produce a ROC curve
> from a linear classifier, I'm pretty sure that using the decision
> function is very common in the ML literature.

I agree that the only thing that an ROC curve requires as an input is
some arbitrary number, ideally that controls the ratio of false postives
vs false negatives. In my experiment, the decision function is indeed a
good candidate for that, and thus my remark isn't fully justified. In
addition, with a linear-SVM the decision function is really well-behaved
in feature space.

Thus I should remove my remark that it is a hack.

Gael

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