I think the below would suffice to interpolate precision (if I've
understood correctly). I'm not sure if there's a vectorised way to do it
given the existing implementation.
if interpolate:
for i in range(1, len(precision)):
precision[i] = precision[i-1:i+1].max()
Equivalently:
if interpolate:
best = precision[0]
for i in range(1, len(precision)):
best = precision[i] = max(best, precision[i])
- Joel
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