You can look a the string example:
https://scikit-learn.org/stable/modules/generated/sklearn.preprocessing.LabelEncoder.html
Sent from my phone - sorry to be brief and potential misspell. Can you give me an example? ---------------------------------------------------------------------------------------
Prof. Malik Yousef , Associate Professor Zefat Academic College , Department of Information System Home Page: Google Scholar Profile :
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you can use the LabelEncoder then. It will encode the classes for you.
The only string column is the label column(class labels, n.pre, and c.pre). if the scoring = 'accuracy' then it works fine.So I think I need somehow to set up the postive_lable.. that I don't know how to do that. ---------------------------------------------------------------------------------------
Prof. Malik Yousef , Associate Professor Zefat Academic College , Department of Information System Home Page: Google Scholar Profile :
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It looks like your data contains string. You need to make some preprocessing before to give it the linear model.
Hello When in using the scoring to be 'f1' then i get an error. Here is the code and the error
X=data y=target_column classifier = LinearSVC() rfecv = RFECV(estimator=classifier, step=0.1, cv=StratifiedKFold(5),scoring='f1')
The error is : ValueError: pos_label=1 is not a valid label: array([u' c.pre', u'n.pre'], dtype='<U5')
Please your help (I'm new to using scikit-leanr) ---------------------------------------------------------------------------------------
Prof. Malik Yousef , Associate Professor Zefat Academic College , Department of Information System Home Page: Google Scholar Profile :
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