> disp_digits="0123"; IIRC, this works if disp_digits is a pointer to char. And "0123" as an expression is a pointer to five chars.
You could only use it with an initialized array as such: char disp_digits[] = "0123"; Cheers, Bodo ------------------------------------------------------------------------------ vRanger cuts backup time in half-while increasing security. With the market-leading solution for virtual backup and recovery, you get blazing-fast, flexible, and affordable data protection. Download your free trial now. http://p.sf.net/sfu/quest-d2dcopy1 _______________________________________________ Sdcc-user mailing list Sdcc-user@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/sdcc-user
