I did a variety of experiments and this is what I found.
The compiler puts automatic variables in registers if possible.
c is probably 4(ix).
I think in your example, d is assigned to the a register.
You might try this and see how it goes.
Douglas
char foo(unsigned char c)
{
char e;
e = c;
e += 5;
return e;
}
generates this...
;sample.c:1: char foo(unsigned char c)
; ---------------------------------
; Function foo
; ---------------------------------
_foo_start::
_foo:
push ix
ld ix,#0
add ix,sp
;sample.c:4: e = c;
;sample.c:5: e += 5;
ld a, 4 (ix)
add a,#0x05
ld l,a
;sample.c:6: return e;
pop ix
ret
_foo_end::
.area _CODE
.area _CABS
On Jun 25, 2011, at 12:49 PM, Egan Ford wrote:
> I have a function:
>
> void foo(unsigned char c)
> {
> char d;
> __asm
> ld a,(_c)
> ...
>
> How do I get the address for c and d? _c works if global, but not local.
>
> Thanks.
>
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