You were right,
Other pointer point to usbram memory:
 inPtr =(byte *) &controlTransferBuffer;

were controlTransferBuffer is:
#pragma udata usbram5 controlTransferBuffer
volatile byte controlTransferBuffer[E0SZ];

changing code to:
 inPtr =(__data byte *) &controlTransferBuffer;

fixed my problems. For me this is an unusual sdcc behavior, I often
use pointers to char arrays, like:
char buf[32], *p;

 p=&buf

and "p" points correctly to buf, which is located in ram. So why it
won't work with usbram ?


regards,



2011/11/9 Kustaa Nyholm <kustaa.nyh...@planmeca.com>:
> On 11/9/11 11:54, "M L" <maricol...@gmail.com> wrote:
>>outPtr = &deviceDescriptor;
>>so I changed it to
>>outPtr = (byte *)&deviceDescriptor;
>
> >From the top of my head and not looking at the code,
> pointers in SDCC/PIC come in three types depending weather
> they refer to RAM, ROM or are generic.
>
> Your cast above may be generating a generic pointer
> where as most likely the original code intended a data
> (__data byte*)  or code pointer (__code byte*)
> depending where 'deviceDescriptor' is.
>
> The USB hardware in the pic only handless transfer
> to/from RAM (data), but most likely the actual device
> descriptor is in ROM (code). So examine the code
> to see what 'deviceDescriptor' is in your code
> and cast as appropriate.
>
> I may be totally wrong of course.
>
> br Kusti
>
>
>
>
>
>
>
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