Am 02.04.2018 um 14:35 schrieb Maarten Brock:
>
> In the generated code I see that the lower 16 bits are loaded into x, not
> the upper. And the most significant byte is loaded into a by using #<sym,
> but that seems to fail. If you instead use #(sym>>16) it seems alright to
> me.
>
> Maarten
void f(void)
{
void (*p)(void) = &f;
(*p)();
}
compiles to:
ld a, #<_f
ldw x, #_f
; test.c: 4: (*p)();
push #(00103$)
push #(00103$ >> 8)
push #(00103$ >> 16)
push a
ld a, xl
push a
ld a, xh
push a
retf
00103$:
; test.c: 5: }
retf
The lower 16 bits are loaded into x (but it should be the upper 16
bits). The lower 8 bits get loaded into a correctly.
I guess I'll implement some workaround that makes the register allocator
not want to use x for the upper 16 bits in such an assignment (but I
don't like having code geneation need workarounds for assembler issues).
Philipp
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