Re: [css-d] Four that could be two

[Mike Dougherty]

I think the active state is used if you keyboard navigate the links without 
activating them.  The 
link that will be followed by pressing the space/enter key can be "active" 
without sharing the 
"hover" status.  True, many people navigate solely with the mouse.  As a 
general rule, I would 
suggest being extra explicit about your selectors and rules rather than relying 
on default 
behaviors.

On Fri, 26 May 2006 15:20:32 -0700
  "skye estes" <[EMAIL PROTECTED]> wrote:
> On 5/26/06, Scott Haneda <[EMAIL PROTECTED]> wrote:
> no problem. also note that if your hover and active states are the same,
> only specifying rules for the hover state will be enough, as you have to be
> hovering over a link in order for it to be active.
> 
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Re: [css-d] Four that could be two

[skye estes]

On 5/26/06, Scott Haneda <[EMAIL PROTECTED]> wrote:
>
> > should do it. note that you need to specify the class (.secondLinks)
> before
> > the state (:hover).
>
> Thanks, just what I needed


no problem. also note that if your hover and active states are the same,
only specifying rules for the hover state will be enough, as you have to be
hovering over a link in order for it to be active.

if, however, you want to do something different with the link, such as
change it's color when you click on it, a seperate rule for the active state
would be in order.


·skye·
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Re: [css-d] Four that could be two

[Scott Haneda]

> should do it. note that you need to specify the class (.secondLinks) before
> the state (:hover).

Thanks, just what I needed
-- 
-
Scott HanedaTel: 415.898.2602
 Novato, CA U.S.A.


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Re: [css-d] Four that could be two

[skye estes]

On 5/26/06, Scott Haneda <[EMAIL PROTECTED]> wrote:
>
> I see four total things here, but two are the same and the other two are
> the
> same, is there some way to merge these so there are only two blocks?
>
> a:visited.secondLinks {
> color: #FFF;
> text-decoration: none;
> }
>
> a:link.secondLinks {
> color: #FFF;
> text-decoration: none;
> }

becoming this code:
a.secondLinks, a.secondLinks:visited {
 color: #FFF;
text-decoration: none;
}

a:active.secondLinks {
> color: #FFF;
> text-decoration: underline;
> }
>
> a:hover.secondLinks {
> color: #FFF;
> text-decoration: underline;
> }

becoming this code:
a.secondLinks:hover,  a.secondLinks:active  {
color: #FFF;
text-decoration: underline;
}

should do it. note that you need to specify the class (.secondLinks) before
the state (:hover).

·skye·
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[css-d] Four that could be two

[Scott Haneda]

I see four total things here, but two are the same and the other two are the
same, is there some way to merge these so there are only two blocks?

a:visited.secondLinks {
color: #FFF;
text-decoration: none;
}

a:link.secondLinks {
color: #FFF;
text-decoration: none;
}

a:active.secondLinks {
color: #FFF;
text-decoration: underline;
}

a:hover.secondLinks {
color: #FFF;
text-decoration: underline;
}
-- 
-
Scott HanedaTel: 415.898.2602
 Novato, CA U.S.A.


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