subject:"\"\\\[PHP\\\] regular expression\""

Re: [PHP] Regular Expression

2011-11-07 Thread Richard Quadling

On 5 November 2011 05:39, Negin Nickparsa  wrote:

> your welcome my Friend,I used it myself.
>
> On 11/4/11, drive view  wrote:
> > Thanks alot Negin for the prompt reply.  This is most useful.
> >
> > Regards
> >
> > Best Toni
> >
> > On Sat, Nov 5, 2011 at 6:30 AM, Negin Nickparsa 
> wrote:
> >
> >> http://weblogtoolscollection.com/regex/regex.php
> >>
> >> On 11/4/11, drive view  wrote:
> >> > Hi
> >> >
> >> > I'm new to PHP.  I'm currently trying understand how to apply the
> >> patterns
> >> > for the preg* commands and I am having difficulty finding a good
> source
> >> > explaining in detail how to build a filter.  I would appreciate if
> >> someone
> >> > can direct me to such a website.
> >> >
> >> > Thanks
> >> >
> >> > Toni
> >> >
> >>
> >
>
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>
>
I use  http://www.regular-expressions.info

The site's author also has a book which I would recommend :
http://www.regular-expressions.info/cookbook.html




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Re: [PHP] Regular Expression

2011-11-04 Thread Negin Nickparsa

your welcome my Friend,I used it myself.

On 11/4/11, drive view  wrote:
> Thanks alot Negin for the prompt reply.  This is most useful.
>
> Regards
>
> Best Toni
>
> On Sat, Nov 5, 2011 at 6:30 AM, Negin Nickparsa  wrote:
>
>> http://weblogtoolscollection.com/regex/regex.php
>>
>> On 11/4/11, drive view  wrote:
>> > Hi
>> >
>> > I'm new to PHP.  I'm currently trying understand how to apply the
>> patterns
>> > for the preg* commands and I am having difficulty finding a good source
>> > explaining in detail how to build a filter.  I would appreciate if
>> someone
>> > can direct me to such a website.
>> >
>> > Thanks
>> >
>> > Toni
>> >
>>
>

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Re: [PHP] Regular Expression

2011-11-04 Thread drive view

Thanks alot Negin for the prompt reply.  This is most useful.

Regards

Best Toni

On Sat, Nov 5, 2011 at 6:30 AM, Negin Nickparsa  wrote:

> http://weblogtoolscollection.com/regex/regex.php
>
> On 11/4/11, drive view  wrote:
> > Hi
> >
> > I'm new to PHP.  I'm currently trying understand how to apply the
> patterns
> > for the preg* commands and I am having difficulty finding a good source
> > explaining in detail how to build a filter.  I would appreciate if
> someone
> > can direct me to such a website.
> >
> > Thanks
> >
> > Toni
> >
>

Re: [PHP] Regular Expression

2011-11-04 Thread Negin Nickparsa

http://weblogtoolscollection.com/regex/regex.php

On 11/4/11, drive view  wrote:
> Hi
>
> I'm new to PHP.  I'm currently trying understand how to apply the patterns
> for the preg* commands and I am having difficulty finding a good source
> explaining in detail how to build a filter.  I would appreciate if someone
> can direct me to such a website.
>
> Thanks
>
> Toni
>

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[PHP] Regular Expression

2011-11-04 Thread drive view

Hi

I'm new to PHP.  I'm currently trying understand how to apply the patterns
for the preg* commands and I am having difficulty finding a good source
explaining in detail how to build a filter.  I would appreciate if someone
can direct me to such a website.

Thanks

Toni

Re: [PHP] Regular Expression to get the whole Comma Separated String in Array Key

2010-06-30 Thread Richard Quadling

On 30 June 2010 15:12, Gaurav Kumar  wrote:
> Hi All,
>
> Need help in resolving the below problem-
>
>
> I would like to get the whole comma separated string into an array value-
>
> 1. $postText = "chapters 5, 6, 7, 8";
> OR
> 2. $postText = "chapters 5, 6;
> OR
> 3. $postText = "chapters 5, 6, 7";
>
> What i have done so far is-
> preg_match('/chapter[s]*[ ]*(\d+, \d+, \d+)/i', $postText, $matches);
>
> The above will exactly match the third value $postText = "chapters 5, 6, 7";
>
> By Above $matches will contain a value of : $matches[1] = '5, 6, 7';
>
> Now i need a SINGLE regular expression which can match first, second
> variable above or any number of comma separated string and IMPORTANTLY
> provide me that whole comma separated sting value (as above) in single array
> key element like below-
>
> $matches[1] = '5, 6, 7';
> OR
> $matches[1] = '5, 6';
> OR
> $matches[1] = '5, 6, 7, 8, 9';
>
>
> Also I have to use regular expression only as the flow of the code does not
> permit to use any other method to get comma separated string from the
> master/base string.
>
> Thanks,
>
> Gaurav Kumar
>

Try ...

preg_match('/chapters? ?((?:\d++(?:, )?)+)/im', $old_string, $a_Matches))


chapters? ?((?:\d++(?:, )?)+)

Match the characters âchapterâ literally Â«chapterÂ»
Match the character âsâ literally Â«s?Â»
   Between zero and one times, as many times as possible, giving back
as needed (greedy) Â«?Â»
Match the character â â literally Â« ?Â»
   Between zero and one times, as many times as possible, giving back
as needed (greedy) Â«?Â»
Match the regular expression below and capture its match into
backreference number 1 Â«((?:\d++(?:, )?)+)Â»
   Match the regular expression below Â«(?:\d++(?:, )?)+Â»
  Between one and unlimited times, as many times as possible,
giving back as needed (greedy) Â«+Â»
  Match a single digit 0..9 Â«\d++Â»
 Between one and unlimited times, as many times as possible,
without giving back (possessive) Â«++Â»
  Match the regular expression below Â«(?:, )?Â»
 Between zero and one times, as many times as possible, giving
back as needed (greedy) Â«?Â»
 Match the characters â, â literally Â«, Â»


Created with RegexBuddy
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[PHP] Regular Expression to get the whole Comma Separated String in Array Key

2010-06-30 Thread Gaurav Kumar

Hi All,

Need help in resolving the below problem-


I would like to get the whole comma separated string into an array value-

1. $postText = "chapters 5, 6, 7, 8";
OR
2. $postText = "chapters 5, 6;
OR
3. $postText = "chapters 5, 6, 7";

What i have done so far is-
preg_match('/chapter[s]*[ ]*(\d+, \d+, \d+)/i', $postText, $matches);

The above will exactly match the third value $postText = "chapters 5, 6, 7";

By Above $matches will contain a value of : $matches[1] = '5, 6, 7';

Now i need a SINGLE regular expression which can match first, second
variable above or any number of comma separated string and IMPORTANTLY
provide me that whole comma separated sting value (as above) in single array
key element like below-

$matches[1] = '5, 6, 7';
OR
$matches[1] = '5, 6';
OR
$matches[1] = '5, 6, 7, 8, 9';


Also I have to use regular expression only as the flow of the code does not
permit to use any other method to get comma separated string from the
master/base string.

Thanks,

Gaurav Kumar

Re: [PHP] regular expression

2010-06-07 Thread Ashley Sheridan

On Mon, 2010-06-07 at 22:54 +0300, Tanel Tammik wrote:

> "Peter Lind"  wrote in message 
> news:aanlktilqkz8dnc0zacfv70tctf2wqkgpzojccqtuw...@mail.gmail.com...
> > On 1 June 2010 17:33, Ashley Sheridan  wrote:
> >> On Tue, 2010-06-01 at 16:31 +0100, Richard Quadling wrote:
> >>
> >>> $re1 = '/^[a-z]++$/i';
> >>> $re2 = '/^[a-z ]++$/i';
> >>>
> >>>
> >>>
> >>> --
> >>> -
> >>> Richard Quadling
> >>> "Standing on the shoulders of some very clever giants!"
> >>> EE : http://www.experts-exchange.com/M_248814.html
> >>> EE4Free : http://www.experts-exchange.com/becomeAnExpert.jsp
> >>> Zend Certified Engineer : 
> >>> http://zend.com/zce.php?c=ZEND002498&r=213474731
> >>> ZOPA : http://uk.zopa.com/member/RQuadling
> >>>
> >>
> >>
> >> Why the double ++ in the expressions there? Surely one + would match the
> >> 1 or more characters that you need and the second one would just be
> >> surplus?
> >>
> >
> > Equally important: why have three people already done this persons
> > homework. 5 minutes googling would have answered this ...
> >
> >
> > -- 
> > 
> > WWW: http://plphp.dk / http://plind.dk
> > LinkedIn: http://www.linkedin.com/in/plind
> > BeWelcome/Couchsurfing: Fake51
> > Twitter: http://twitter.com/kafe15
> > 
> 
> i made an regular expression now by myself. i need to check if string starts 
> with 'get' and is followed only by letters a-z case insensitive. am i 
> correct?
> 
> '/^get[a-z]++$/i'
> 
> Br
> Tanel 
> 
> 
> 


Yep, that looks right. If you're in any doubt, there are lots of online
regex testers which you can run strings and patterns against. Just
Google for them.

Thanks,
Ash
http://www.ashleysheridan.co.uk

Re: [PHP] regular expression

2010-06-07 Thread Tanel Tammik


"Peter Lind"  wrote in message 
news:aanlktilqkz8dnc0zacfv70tctf2wqkgpzojccqtuw...@mail.gmail.com...
> On 1 June 2010 17:33, Ashley Sheridan  wrote:
>> On Tue, 2010-06-01 at 16:31 +0100, Richard Quadling wrote:
>>
>>> $re1 = '/^[a-z]++$/i';
>>> $re2 = '/^[a-z ]++$/i';
>>>
>>>
>>>
>>> --
>>> -
>>> Richard Quadling
>>> "Standing on the shoulders of some very clever giants!"
>>> EE : http://www.experts-exchange.com/M_248814.html
>>> EE4Free : http://www.experts-exchange.com/becomeAnExpert.jsp
>>> Zend Certified Engineer : 
>>> http://zend.com/zce.php?c=ZEND002498&r=213474731
>>> ZOPA : http://uk.zopa.com/member/RQuadling
>>>
>>
>>
>> Why the double ++ in the expressions there? Surely one + would match the
>> 1 or more characters that you need and the second one would just be
>> surplus?
>>
>
> Equally important: why have three people already done this persons
> homework. 5 minutes googling would have answered this ...
>
>
> -- 
> 
> WWW: http://plphp.dk / http://plind.dk
> LinkedIn: http://www.linkedin.com/in/plind
> BeWelcome/Couchsurfing: Fake51
> Twitter: http://twitter.com/kafe15
> 

i made an regular expression now by myself. i need to check if string starts 
with 'get' and is followed only by letters a-z case insensitive. am i 
correct?

'/^get[a-z]++$/i'

Br
Tanel 



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Re: [PHP] regular expression

2010-06-02 Thread Richard Quadling

On 2 June 2010 16:35, Jan G.B.  wrote:
> 2010/6/1 Peter Lind :
>> On 1 June 2010 17:33, Ashley Sheridan  wrote:
>>> On Tue, 2010-06-01 at 16:31 +0100, Richard Quadling wrote:
>>>
 $re1 = '/^[a-z]++$/i';
 $re2 = '/^[a-z ]++$/i';



 --
 -
 Richard Quadling
 "Standing on the shoulders of some very clever giants!"
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>>>
>>>
>>> Why the double ++ in the expressions there? Surely one + would match the
>>> 1 or more characters that you need and the second one would just be
>>> surplus?
>>>
>>
>> Equally important: why have three people already done this persons
>> homework. 5 minutes googling would have answered this ...
>>
>
> Even more important: No answer is correct, because f.e. "äüßćéâ" are
> also letters.
>
> Bye
>
> ;-)
>

So, would ...

/^[^\p{M}\p{Z}\p{N}\p{P}\p{S}\p{C}\d\s]++$/i

be ok?



-- 
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Re: [PHP] regular expression

2010-06-02 Thread Jan G.B.

2010/6/1 Peter Lind :
> On 1 June 2010 17:33, Ashley Sheridan  wrote:
>> On Tue, 2010-06-01 at 16:31 +0100, Richard Quadling wrote:
>>
>>> $re1 = '/^[a-z]++$/i';
>>> $re2 = '/^[a-z ]++$/i';
>>>
>>>
>>>
>>> --
>>> -
>>> Richard Quadling
>>> "Standing on the shoulders of some very clever giants!"
>>> EE : http://www.experts-exchange.com/M_248814.html
>>> EE4Free : http://www.experts-exchange.com/becomeAnExpert.jsp
>>> Zend Certified Engineer : http://zend.com/zce.php?c=ZEND002498&r=213474731
>>> ZOPA : http://uk.zopa.com/member/RQuadling
>>>
>>
>>
>> Why the double ++ in the expressions there? Surely one + would match the
>> 1 or more characters that you need and the second one would just be
>> surplus?
>>
>
> Equally important: why have three people already done this persons
> homework. 5 minutes googling would have answered this ...
>

Even more important: No answer is correct, because f.e. "äüßćéâ" are
also letters.

Bye

;-)

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Re: [PHP] regular expression

2010-06-02 Thread Richard Quadling

On 2 June 2010 06:12, Peter  wrote:
> Hi  Tanel,
>
> 1. only letters
>
> $str = 'helloworld';
>
> if(preg_match("/^[a-zA-Z]*$/",$str))
> echo "only letters";
> else
> echo "failed";
>
> 2. only letters and spaces
>
> $str = 'hello world';
>
> if(preg_match("/^[a-zA-Z\s]*$/",$str))
> echo "only letters and spaces";
> else
> echo "failed";
>
>
> Regards
> Peter.M

Be careful with using *.

The issue of a zero length string is important.

* will allow a zero length string.

++ will force the regex to match something, so zero length strings are rejected.



/s will match space, formfeed, newline, carriage return, horizontal
tab, and vertical tab

So a string with newlines (for example a  with line breaks)
would match.





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Re: [PHP] regular expression

2010-06-01 Thread Peter


Hi  Tanel,

1. only letters

$str = 'helloworld';

if(preg_match("/^[a-zA-Z]*$/",$str))
echo "only letters";
else
echo "failed";

2. only letters and spaces

$str = 'hello world';

if(preg_match("/^[a-zA-Z\s]*$/",$str))
echo "only letters and spaces";
else
echo "failed";


Regards
Peter.M

Tanel Tammik wrote:

How to check with regular expression (preg) if string has:

1. only letters
2. only letters and spaces

Br
Tanel 




  


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Re: [PHP] regular expression

2010-06-01 Thread Ashley Sheridan

On Tue, 2010-06-01 at 17:32 +0100, Richard Quadling wrote:

> On 1 June 2010 16:38, Ashley Sheridan  wrote:
> > Ah, I ought to have guessed as it's you! ;)
> 
> What are you insinuating?
> 
> --
> -
> Richard Quadling
> "Standing on the shoulders of some very clever giants!"
> EE : http://www.experts-exchange.com/M_248814.html
> EE4Free : http://www.experts-exchange.com/becomeAnExpert.jsp
> Zend Certified Engineer : http://zend.com/zce.php?c=ZEND002498&r=213474731
> ZOPA : http://uk.zopa.com/member/RQuadling
> 


I've never known anyone to optimise code quite as much as you! That's
not a bad thing though.

Thanks,
Ash
http://www.ashleysheridan.co.uk

Re: [PHP] regular expression

2010-06-01 Thread Richard Quadling

On 1 June 2010 16:38, Ashley Sheridan  wrote:
> Ah, I ought to have guessed as it's you! ;)

What are you insinuating?

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Re: [PHP] regular expression

2010-06-01 Thread Ashley Sheridan

On Tue, 2010-06-01 at 16:35 +0100, Richard Quadling wrote:

> On 1 June 2010 16:33, Ashley Sheridan  wrote:
> >
> > On Tue, 2010-06-01 at 16:31 +0100, Richard Quadling wrote:
> >
> > $re1 = '/^[a-z]++$/i';
> > $re2 = '/^[a-z ]++$/i';
> >
> >
> >
> > --
> > -
> > Richard Quadling
> > "Standing on the shoulders of some very clever giants!"
> > EE : http://www.experts-exchange.com/M_248814.html
> > EE4Free : http://www.experts-exchange.com/becomeAnExpert.jsp
> > Zend Certified Engineer : http://zend.com/zce.php?c=ZEND002498&r=213474731
> > ZOPA : http://uk.zopa.com/member/RQuadling
> >
> >
> > Why the double ++ in the expressions there? Surely one + would match the 1 
> > or more characters that you need and the second one would just be surplus?
> >
> > Thanks,
> > Ash
> > http://www.ashleysheridan.co.uk
> >
> >
> 
> ++ doesn't give back. As there is no need to do any backtracking, this
> is supposed to be a slight optimization.
> 
> 
> 
> --
> -
> Richard Quadling
> "Standing on the shoulders of some very clever giants!"
> EE : http://www.experts-exchange.com/M_248814.html
> EE4Free : http://www.experts-exchange.com/becomeAnExpert.jsp
> Zend Certified Engineer : http://zend.com/zce.php?c=ZEND002498&r=213474731
> ZOPA : http://uk.zopa.com/member/RQuadling


Ah, I ought to have guessed as it's you! ;)

I didn't know about that in regex's, I've learnt something new today!

Thanks,
Ash
http://www.ashleysheridan.co.uk

Re: [PHP] regular expression

2010-06-01 Thread Peter Lind

On 1 June 2010 17:33, Ashley Sheridan  wrote:
> On Tue, 2010-06-01 at 16:31 +0100, Richard Quadling wrote:
>
>> $re1 = '/^[a-z]++$/i';
>> $re2 = '/^[a-z ]++$/i';
>>
>>
>>
>> --
>> -
>> Richard Quadling
>> "Standing on the shoulders of some very clever giants!"
>> EE : http://www.experts-exchange.com/M_248814.html
>> EE4Free : http://www.experts-exchange.com/becomeAnExpert.jsp
>> Zend Certified Engineer : http://zend.com/zce.php?c=ZEND002498&r=213474731
>> ZOPA : http://uk.zopa.com/member/RQuadling
>>
>
>
> Why the double ++ in the expressions there? Surely one + would match the
> 1 or more characters that you need and the second one would just be
> surplus?
>

Equally important: why have three people already done this persons
homework. 5 minutes googling would have answered this ...


-- 

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Re: [PHP] regular expression

2010-06-01 Thread Richard Quadling

On 1 June 2010 16:33, Ashley Sheridan  wrote:
>
> On Tue, 2010-06-01 at 16:31 +0100, Richard Quadling wrote:
>
> $re1 = '/^[a-z]++$/i';
> $re2 = '/^[a-z ]++$/i';
>
>
>
> --
> -
> Richard Quadling
> "Standing on the shoulders of some very clever giants!"
> EE : http://www.experts-exchange.com/M_248814.html
> EE4Free : http://www.experts-exchange.com/becomeAnExpert.jsp
> Zend Certified Engineer : http://zend.com/zce.php?c=ZEND002498&r=213474731
> ZOPA : http://uk.zopa.com/member/RQuadling
>
>
> Why the double ++ in the expressions there? Surely one + would match the 1 or 
> more characters that you need and the second one would just be surplus?
>
> Thanks,
> Ash
> http://www.ashleysheridan.co.uk
>
>

++ doesn't give back. As there is no need to do any backtracking, this
is supposed to be a slight optimization.



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Re: [PHP] regular expression

2010-06-01 Thread Richard Quadling

On 1 June 2010 16:31, Richard Quadling  wrote:
> $re1 = '/^[a-z]++$/i';



^[a-z]++$

Options: case insensitive; ^ and $ match at line breaks

Assert position at the beginning of a line (at beginning of the string
or after a line break character) «^»
Match a single character in the range between “a” and “z” «[a-z]++»
   Between one and unlimited times, as many times as possible, without
giving back (possessive) «++»
Assert position at the end of a line (at the end of the string or
before a line break character) «$»


> $re2 = '/^[a-z ]++$/i';



^[a-z ]++$

Options: case insensitive; ^ and $ match at line breaks

Assert position at the beginning of a line (at beginning of the string
or after a line break character) «^»
Match a single character present in the list below «[a-z ]++»
   Between one and unlimited times, as many times as possible, without
giving back (possessive) «++»
   A character in the range between “a” and “z” «a-z»
   The character “ ” « »
Assert position at the end of a line (at the end of the string or
before a line break character) «$»


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Re: [PHP] regular expression

2010-06-01 Thread Ashley Sheridan

On Tue, 2010-06-01 at 16:31 +0100, Richard Quadling wrote:

> $re1 = '/^[a-z]++$/i';
> $re2 = '/^[a-z ]++$/i';
> 
> 
> 
> -- 
> -
> Richard Quadling
> "Standing on the shoulders of some very clever giants!"
> EE : http://www.experts-exchange.com/M_248814.html
> EE4Free : http://www.experts-exchange.com/becomeAnExpert.jsp
> Zend Certified Engineer : http://zend.com/zce.php?c=ZEND002498&r=213474731
> ZOPA : http://uk.zopa.com/member/RQuadling
> 


Why the double ++ in the expressions there? Surely one + would match the
1 or more characters that you need and the second one would just be
surplus?

Thanks,
Ash
http://www.ashleysheridan.co.uk

Re: [PHP] regular expression

2010-06-01 Thread Richard Quadling

$re1 = '/^[a-z]++$/i';
$re2 = '/^[a-z ]++$/i';



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Re: [PHP] regular expression

2010-06-01 Thread Ashley Sheridan

On Tue, 2010-06-01 at 18:19 +0300, Tanel Tammik wrote:

> How to check with regular expression (preg) if string has:
> 
> 1. only letters
> 2. only letters and spaces
> 
> Br
> Tanel 
> 
> 
> 

Use preg_match() to find an expression within a string. You can use
something like this to grab check if a string contains only letters or
numbers:

if(preg_match('/^[a-zA-Z0-9]+$/'), $string)
{

}

Thanks,
Ash
http://www.ashleysheridan.co.uk

Re: [PHP] regular expression

2010-06-01 Thread Adam Richardson

On Tue, Jun 1, 2010 at 11:19 AM, Tanel Tammik  wrote:

> How to check with regular expression (preg) if string has:
>
> 1. only letters
> 2. only letters and spaces
>
> Br
> Tanel
>
>
>
> --
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> To unsubscribe, visit: http://www.php.net/unsub.php
>
>
$re1 = '/^[a-zA-Z]+$/';
$re2 = '/^[a-zA-Z ]+$/';

Adam

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[PHP] regular expression

2010-06-01 Thread Tanel Tammik

How to check with regular expression (preg) if string has:

1. only letters
2. only letters and spaces

Br
Tanel 



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Re: [PHP] Regular Expression Problem

2009-02-26 Thread Ashley Sheridan

On Thu, 2009-02-26 at 10:09 -0500, Alice Wei wrote:
> Hi, 
> 
>   I have two lines here as follows:
> 
> 1  -0.123701962557954E+03   0.460967618024691E+02
> -0.12354765900E+03   0.46259109000E+02
> 
> What I am trying to do here is to only have 
> 
> 1  -0.123701962557954E+03   0.460967618024691E+02 be the output so I 
> can do further processing with it, however, with the code I have in the 
> following, I have both lines in the output. Here is the code:
> 
> $file = "test.txt";
> $fp = fopen($file, "r");
> $lines = file($file);
> 
> foreach($lines as $line_num => $line)
> {
> if (preg_match("/([^0-9]+\s+)(\-?\d+\.?\d+(\+?E?\d+)?){2}/", $line))
> 
> echo $line;
> 
> }
>   
> Could anyone please tell me that even when I specify that the line has to 
> start with [^0-9]+\s with one occurrence, why I still get 
> -0.12354765900E+03   0.46259109000E+02?
> 
> Thanks a lot for your help.
> 
> Alice
> 
> 
> _
> Express yourself with gadgets on Windows Live Spaces
> http://discoverspaces.live.com?source=hmtag1&loc=us
what about a regex something like:

/^(\d{1,})\s+([\d\.E\+\-])+\s+([\d\.E\+\-])+$/

The brackets () allow you to then extract the specific portions of the
string as you wish, so the first match is the whole line, the second is
the 1 (or whatever other number), the third is the first floating-point
number, etc.

I'm assuming that the 1 here is some sort of line number possibly? The
bit inside the curly braces ({1,}) just says to match the digit 1 or
more times. You can limit it by adding a number after the comma, so
{1,3} for 1-3 digits.

Hope this helps?


Ash
www.ashleysheridan.co.uk


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RE: [PHP] Regular Expression Problem

2009-02-26 Thread Alice Wei


Hi, 
I have two lines here as follows:

1  -0.123701962557954E+03   0.460967618024691E+02
-0.12354765900E+03   0.46259109000E+02

What I am trying to do here is to only have 

1  -0.123701962557954E+03   0.460967618024691E+02 be the output so I 
can do further processing with it, however, with the code I have in the 
following, I have both lines in the output. Here is the code:

$file = "test.txt";
$fp = fopen($file, "r");
$lines = file($file);

foreach($lines as $line_num => $line)
{
if (preg_match("/([^0-9]+\s+)(\-?\d+\.?\d+(\+?E?\d+)?){2}/", $line))

echo $line;

}
  
Could anyone please tell me that even when I specify that the line has to start 
with [^0-9]+\s with one occurrence, why I still get -0.12354765900E+03  
 0.46259109000E+02?

Thanks a lot for your help.

Alice


_
Express yourself with gadgets on Windows Live Spaces
http://discoverspaces.live.com?source=hmtag1&loc=us
  

[^0-9] means not a digital

^[0-9] is the right way..


Thanks for your help. I cannot imagine that I have missed that. 

Alice

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Re: [PHP] Regular Expression Problem

2009-02-26 Thread 惠新宸





Alice Wei wrote:

  Hi, 

  I have two lines here as follows:

1  -0.123701962557954E+03   0.460967618024691E+02
-0.12354765900E+03   0.46259109000E+02

What I am trying to do here is to only have 

1  -0.123701962557954E+03   0.460967618024691E+02 be the output so I can do further processing with it, however, with the code I have in the following, I have both lines in the output. Here is the code:

$file = "test.txt";
$fp = fopen($file, "r");
$lines = file($file);

foreach($lines as $line_num => $line)
{
if (preg_match("/([^0-9]+\s+)(\-?\d+\.?\d+(\+?E?\d+)?){2}/", $line))

echo $line;

}
  
Could anyone please tell me that even when I specify that the line has to start with [^0-9]+\s with one occurrence, why I still get -0.12354765900E+03   0.46259109000E+02?

Thanks a lot for your help.

Alice


_
Express yourself with gadgets on Windows Live Spaces
http://discoverspaces.live.com?source=hmtag1&loc=us
  

[^0-9] means not a digital
^[0-9] is the right way..

-- 
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惠
新宸 xinchen.hui |  SYS |  (+8610)82602112-7974 | :laruence

[PHP] Regular Expression Problem

2009-02-26 Thread Alice Wei


Hi, 

  I have two lines here as follows:

1  -0.123701962557954E+03   0.460967618024691E+02
-0.12354765900E+03   0.46259109000E+02

What I am trying to do here is to only have 

1  -0.123701962557954E+03   0.460967618024691E+02 be the output so I 
can do further processing with it, however, with the code I have in the 
following, I have both lines in the output. Here is the code:

$file = "test.txt";
$fp = fopen($file, "r");
$lines = file($file);

foreach($lines as $line_num => $line)
{
if (preg_match("/([^0-9]+\s+)(\-?\d+\.?\d+(\+?E?\d+)?){2}/", $line))

echo $line;

}
  
Could anyone please tell me that even when I specify that the line has to start 
with [^0-9]+\s with one occurrence, why I still get -0.12354765900E+03  
 0.46259109000E+02?

Thanks a lot for your help.

Alice


_
Express yourself with gadgets on Windows Live Spaces
http://discoverspaces.live.com?source=hmtag1&loc=us

Re: [PHP] Regular Expression Backreference in subpattern.

2008-09-27 Thread Shiplu

On 9/27/08, Richard Lynch <[EMAIL PROTECTED]> wrote:
> Not sure what you think the (?P is doing, but it looks very suspicious to 
> me...
>
>  I'm no PCRE expert though...
>
>  Try this:
>
>  '|\\s*charge\\s*\\s*\\s*([0-9]*)\\s*|'
>
>  \\s allows for whitespace
>
>  If you only want ones that HAVE to have numbers, and no blanks, change * 
> after the 0-9] bit into +
>

It doesnt need \\s or \s. Because I have given the string. \s* is okay though.
Well, ?P is 100% okay with PCRE. it gives name subpattern matches
(details: http://www.php.net/manual/en/regexp.reference.php);


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RE: [PHP] Regular Expression Backreference in subpattern.

2008-09-27 Thread Richard Lynch

Not sure what you think the (?P is doing, but it looks very suspicious to me...

I'm no PCRE expert though...

Try this:

'|\\s*charge\\s*\\s*\\s*([0-9]*)\\s*|'

\\s allows for whitespace

If you only want ones that HAVE to have numbers, and no blanks, change * after 
the 0-9] bit into +


From: Shiplu [EMAIL PROTECTED]
Sent: Saturday, September 27, 2008 10:24 AM
To: PHP General
Subject: [PHP] Regular Expression Backreference in subpattern.

The string is "charge100".
I want and array( "charge"=>100).
I am using this regular expression,
'/([^<]+)<\/td>(?P<\1>\d+)<\/td>/'.


But its not working..

I get this error.,
PHP Warning:  preg_match(): Compilation failed: syntax error after (?P
at offset 25 in E:\src\php\WebEngine\- on line 4

any idea?

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[PHP] Regular Expression Backreference in subpattern.

2008-09-27 Thread Shiplu

The string is "charge100".
I want and array( "charge"=>100).
I am using this regular expression,
'/([^<]+)<\/td>(?P<\1>\d+)<\/td>/'.


But its not working..

I get this error.,
PHP Warning:  preg_match(): Compilation failed: syntax error after (?P
at offset 25 in E:\src\php\WebEngine\- on line 4

any idea?

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Re: [PHP] Regular Expression differences between 4.4 and 5.2

2008-09-12 Thread Jochem Maas


Ewen Cumming schreef:

Actually bummer - testing on wrong version.

The U modifier is causing problems too - only matching the first character
instead of the whole string.


hmm, missed that, that might require adding ?U to relevant sub-assertion ...

I'm wondering if your regexp is not 'wrong' (big word in this case),
try this variation:

$pattern = '#<\\!T_([^> ]+)([^>]*)>(?:(.*)?<\\!T_end\\1>)?#si';

gives me the same output as your expected results, albeit that there
are less 'root' keys in the matches array ... so you may need to
change some code with regard to fishing out values from $matches





2008/9/12 Ewen Cumming <[EMAIL PROTECTED]>


Hi Jochem,

Replacing the 's' modifier with 'm' fixed it this instance but broke other
parts on the site (the same result as removing 's').

But the other regex ( $pattern = "/ ]+)([^>]*)>(.*?)|
]+)([^>]*)>/Ui";) is working perfectly.

I will continue to test and see if it throws up any other problems. Many
thanks for such a quick and great response.

I will file a bug report however I may need to submit the full test string
as cutting it down any further seems to 'fix' the discrepency.

Thanks again,
Ewen



2008/9/12 Jochem Maas <[EMAIL PROTECTED]>

Jochem Maas schreef:

Ewen Cumming schreef:


Hi everybody,



 ...



BUT I may have work around for you, try this regexp (replaces s modifer
with m modifier):

$pattern = "/ ]+)([^>]*)>(.*?)|
]+)([^>]*)>/mi";



the following pattern also seems to do what you want:

$pattern = "/ ]+)([^>]*)>(.*?)|
]+)([^>]*)>/Ui";


Im interested to know if either of these two solve your immediate issue.








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Re: [PHP] Regular Expression differences between 4.4 and 5.2

2008-09-12 Thread Ewen Cumming

Actually bummer - testing on wrong version.

The U modifier is causing problems too - only matching the first character
instead of the whole string.



2008/9/12 Ewen Cumming <[EMAIL PROTECTED]>

> Hi Jochem,
>
> Replacing the 's' modifier with 'm' fixed it this instance but broke other
> parts on the site (the same result as removing 's').
>
> But the other regex ( $pattern = "/ 
> ]+)([^>]*)>(.*?)|
> ]+)([^>]*)>/Ui";) is working perfectly.
>
> I will continue to test and see if it throws up any other problems. Many
> thanks for such a quick and great response.
>
> I will file a bug report however I may need to submit the full test string
> as cutting it down any further seems to 'fix' the discrepency.
>
> Thanks again,
> Ewen
>
>
>
> 2008/9/12 Jochem Maas <[EMAIL PROTECTED]>
>
> Jochem Maas schreef:
>>
>>> Ewen Cumming schreef:
>>>
 Hi everybody,


>>>  ...
>>
>>
>>> BUT I may have work around for you, try this regexp (replaces s modifer
>>> with m modifier):
>>>
>>> $pattern = "/ ]+)([^>]*)>(.*?)|
>>> ]+)([^>]*)>/mi";
>>>
>>>
>> the following pattern also seems to do what you want:
>>
>> $pattern = "/ ]+)([^>]*)>(.*?)|
>> ]+)([^>]*)>/Ui";
>>
>>
>> Im interested to know if either of these two solve your immediate issue.
>>
>
>

Re: [PHP] Regular Expression differences between 4.4 and 5.2

2008-09-12 Thread Ewen Cumming

Hi Jochem,

Replacing the 's' modifier with 'm' fixed it this instance but broke other
parts on the site (the same result as removing 's').

But the other regex ( $pattern = "/
]+)([^>]*)>(.*?)|
]+)([^>]*)>/Ui";) is working perfectly.

I will continue to test and see if it throws up any other problems. Many
thanks for such a quick and great response.

I will file a bug report however I may need to submit the full test string
as cutting it down any further seems to 'fix' the discrepency.

Thanks again,
Ewen



2008/9/12 Jochem Maas <[EMAIL PROTECTED]>

> Jochem Maas schreef:
>
>> Ewen Cumming schreef:
>>
>>> Hi everybody,
>>>
>>>
>>  ...
>
>
>> BUT I may have work around for you, try this regexp (replaces s modifer
>> with m modifier):
>>
>> $pattern = "/ ]+)([^>]*)>(.*?)|
>> ]+)([^>]*)>/mi";
>>
>>
> the following pattern also seems to do what you want:
>
> $pattern = "/ ]+)([^>]*)>(.*?)| ]+)([^>]*)>/Ui";
>
>
> Im interested to know if either of these two solve your immediate issue.
>

Re: [PHP] Regular Expression differences between 4.4 and 5.2

2008-09-12 Thread Jochem Maas


Jochem Maas schreef:

Ewen Cumming schreef:

Hi everybody,




...



BUT I may have work around for you, try this regexp (replaces s modifer 
with m modifier):


$pattern = "/ ]+)([^>]*)>(.*?)| ]+)([^>]*)>/mi";



the following pattern also seems to do what you want:

$pattern = "/ ]+)([^>]*)>(.*?)| ]+)([^>]*)>/Ui";


Im interested to know if either of these two solve your immediate issue.

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Re: [PHP] Regular Expression differences between 4.4 and 5.2

2008-09-12 Thread Jochem Maas


Ewen Cumming schreef:

Hi everybody,



...



 ]+)([^>]*)>(.*?)| ]+)([^>]*)>/si";
preg_match_all( $pattern, $string, $matches );

echo phpversion();
var_dump($matches);
?>

Input.inc contains the string that is giving the different results - its
probably to long to include so you can find it at
http://www.workingweb.nl/example/input.inc.

The results of this being run can be seen at:
PHP4 (desired result) - http://www.workingweb.nl/example/php4results
PHP5 - http://www.workingweb.nl/example/php5results

If the pattern modifier 's' is removed the regex behaves consistently again
(but this breaks other pages on our website so can't be used as a
workaround). Besides I don't see why that should make any difference.



it seem you have found a regression, submit a bug with a short repro script
(cut down the test HTML and include it in the script).
I tested with php 5.2.6, it shows the same behaviour as 5.2.0.


BUT I may have work around for you, try this regexp (replaces s modifer with m 
modifier):

$pattern = "/ ]+)([^>]*)>(.*?)| ]+)([^>]*)>/mi";


my test script was:

http://www.workingweb.nl/example/input.inc' );


// $pattern = '#(?: ]+)([^>]*)>(.*?)| 
]+)([^>]*)>)#mi';
$pattern = "/ ]+)([^>]*)>(.*?)| ]+)([^>]*)>/mi";

preg_match_all( $pattern, $string, $matches );

echo phpversion();
var_dump($matches);




Here is the version information from the PHP CLI versions I've been testing
with:
[EMAIL PROTECTED]:~$ php4 -v
PHP 4.4.4-8+etch6 (cli) (built: May 16 2008 15:59:34)
Copyright (c) 1997-2006 The PHP Group
Zend Engine v1.3.0, Copyright (c) 1998-2004 Zend Technologies
[EMAIL PROTECTED]:~$ php5 -v
PHP 5.2.0-8+etch11 (cli) (built: May 10 2008 10:46:24)
Copyright (c) 1997-2006 The PHP Group
Zend Engine v2.2.0, Copyright (c) 1998-2006 Zend Technologies

Any help on this would be very appreciated.

Thanks,
Ewen




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[PHP] Regular Expression differences between 4.4 and 5.2

2008-09-12 Thread Ewen Cumming

Hi everybody,

I'm trying to migrate our PHP code base to PHP5. For the most part the
transition hs been smooth however I'm really stuck on a regular expression
which gives different results in 4.4 and 5.2.

I've looked through migration guides but as far as I can see nothing should
have changed in Regex handling between the versions.

I've created the following script below to test the match:

 ]+)([^>]*)>(.*?)| ]+)([^>]*)>/si";
preg_match_all( $pattern, $string, $matches );

echo phpversion();
var_dump($matches);
?>

Input.inc contains the string that is giving the different results - its
probably to long to include so you can find it at
http://www.workingweb.nl/example/input.inc.

The results of this being run can be seen at:
PHP4 (desired result) - http://www.workingweb.nl/example/php4results
PHP5 - http://www.workingweb.nl/example/php5results

If the pattern modifier 's' is removed the regex behaves consistently again
(but this breaks other pages on our website so can't be used as a
workaround). Besides I don't see why that should make any difference.

Here is the version information from the PHP CLI versions I've been testing
with:
[EMAIL PROTECTED]:~$ php4 -v
PHP 4.4.4-8+etch6 (cli) (built: May 16 2008 15:59:34)
Copyright (c) 1997-2006 The PHP Group
Zend Engine v1.3.0, Copyright (c) 1998-2004 Zend Technologies
[EMAIL PROTECTED]:~$ php5 -v
PHP 5.2.0-8+etch11 (cli) (built: May 10 2008 10:46:24)
Copyright (c) 1997-2006 The PHP Group
Zend Engine v2.2.0, Copyright (c) 1998-2006 Zend Technologies

Any help on this would be very appreciated.

Thanks,
Ewen

Re: [PHP] Regular Expression by Exception

2008-08-04 Thread Micah Gersten

I don't know how to use the POSIX classes, but if you use preg_replace:
preg_replace("/[^$params]/", '', $string);

I think this will work.

Thank you,
Micah Gersten
onShore Networks
Internal Developer
http://www.onshore.com



Alberto García Gómez wrote:
> Fellows:
>
> If I use ereg_replace($params, $string) I can replace the char that
> match with $params in the $string.
>
> BUT, how I can replace ALL chars EXCEPT the chars in $params.
>
> Something like !$params, I think
>
>

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[PHP] Regular Expression by Exception

2008-08-04 Thread Alberto García Gómez


Fellows:

If I use ereg_replace($params, $string) I can replace the char that match 
with $params in the $string.


BUT, how I can replace ALL chars EXCEPT the chars in $params.

Something like !$params, I think 




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Re: [PHP] Regular Expression help need

2008-07-27 Thread James Dempster

On Fri, Jul 25, 2008 at 1:08 PM, Shelley <[EMAIL PROTECTED]> wrote:

> Hi Richard,
>
> Not exactly actually.
>
> What I mean is:
> Before: hi Richard>, & good morning<
> After:   hi Richard>, & good morning<
>
> I hope it's clear now.
>
> On Fri, Jul 25, 2008 at 7:53 PM, Richard Heyes <[EMAIL PROTECTED]>
> wrote:
>
> > > How can I make a string with & (NOT &, >, < or "), <, >
> > xml
> > > compatible?
> > > What is the expression to use?
> >
> > Not entirely sure what you're after (try posting some before and after
> > snippets), but by the sounds of it you don't need a regular expression
> > - strtr() will work for you. Or str_replace().
> >
> > --
> > Richard Heyes
> > http://www.phpguru.org
> >
>
>
>
> --
> Regards,
> Shelley
>


Is it possible for you to use a mixture of html_entity_decode, htmlentities
e.g.

, & good morning<');
echo 'hi Richard'.htmlentities($content).'';

/James

Re: [PHP] Regular Expression help need

2008-07-27 Thread Richard Heyes

> Before: hi Richard>, & good morning<
> After:   hi Richard>, & good morning<

By the sounds of it negative look ahead assertions may be of some
help. Or look behind assertions.

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Re: [PHP] Regular Expression help need

2008-07-26 Thread Micah Gersten

Are you talking about looking at blogs in a mobile phone browser or
actually downloading the blog into another format?

 
Thank you,
Micah Gersten
onShore Networks
Internal Developer
http://www.onshore.com



Shelley wrote:
> Ok, let me tell you what i want to achieve.
> I want to transfer users' blog onto mobile phone, so I should convert
> characters such as >, <, & (but not &, or >, or <, etc) into
> xml compatible ones, >, < &.
>
> Maybe there is some problem in my expression?
>
> Waiting for your response...
>
> On Sat, Jul 26, 2008 at 3:30 AM, Micah Gersten <[EMAIL PROTECTED]
> > wrote:
>
> Are you trying to make it xml compatible or XHTML compatible?  '&' is
> not valid HTML or XHTML as it has special meaning. If you want it to
> adhere to the standard and display correctly, you must use '&'
>
> Thank you,
> Micah Gersten
> onShore Networks
> Internal Developer
> http://www.onshore.com
>
>
>
> Shelley wrote:
> > Hi Richard,
> >
> > Not exactly actually.
> >
> > What I mean is:
> > Before: hi Richard>, & good morning<
> > After:   hi Richard>, & good
> morning<
> >
> > I hope it's clear now.
> >
> > On Fri, Jul 25, 2008 at 7:53 PM, Richard Heyes
> <[EMAIL PROTECTED] >
> > wrote:
> >
> >
> >>> How can I make a string with & (NOT &, >, < or
> "), <, >
> >>>
> >> xml
> >>
> >>> compatible?
> >>> What is the expression to use?
> >>>
> >> Not entirely sure what you're after (try posting some before
> and after
> >> snippets), but by the sounds of it you don't need a regular
> expression
> >> - strtr() will work for you. Or str_replace().
> >>
> >> --
> >> Richard Heyes
> >> http://www.phpguru.org
> >>
> >>
> >
> >
> >
> >
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
>
>
>
> -- 
> With best regards,
> Shelley Shyan
> http://phparch.cn

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Re: [PHP] Regular Expression help need

2008-07-25 Thread Shelley

Ok, let me tell you what i want to achieve.
I want to transfer users' blog onto mobile phone, so I should convert
characters such as >, <, & (but not &, or >, or <, etc) into xml
compatible ones, >, < &.

Maybe there is some problem in my expression?

Waiting for your response...

On Sat, Jul 26, 2008 at 3:30 AM, Micah Gersten <[EMAIL PROTECTED]> wrote:

> Are you trying to make it xml compatible or XHTML compatible?  '&' is
> not valid HTML or XHTML as it has special meaning. If you want it to
> adhere to the standard and display correctly, you must use '&'
>
> Thank you,
> Micah Gersten
> onShore Networks
> Internal Developer
> http://www.onshore.com
>
>
>
> Shelley wrote:
> > Hi Richard,
> >
> > Not exactly actually.
> >
> > What I mean is:
> > Before: hi Richard>, & good morning<
> > After:   hi Richard>, & good morning<
> >
> > I hope it's clear now.
> >
> > On Fri, Jul 25, 2008 at 7:53 PM, Richard Heyes <[EMAIL PROTECTED]>
> > wrote:
> >
> >
> >>> How can I make a string with & (NOT &, >, < or "), <, >
> >>>
> >> xml
> >>
> >>> compatible?
> >>> What is the expression to use?
> >>>
> >> Not entirely sure what you're after (try posting some before and after
> >> snippets), but by the sounds of it you don't need a regular expression
> >> - strtr() will work for you. Or str_replace().
> >>
> >> --
> >> Richard Heyes
> >> http://www.phpguru.org
> >>
> >>
> >
> >
> >
> >
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
>


-- 
With best regards,
Shelley Shyan
http://phparch.cn

Re: [PHP] Regular Expression help need

2008-07-25 Thread Micah Gersten

Are you trying to make it xml compatible or XHTML compatible?  '&' is
not valid HTML or XHTML as it has special meaning. If you want it to
adhere to the standard and display correctly, you must use '&'

Thank you,
Micah Gersten
onShore Networks
Internal Developer
http://www.onshore.com



Shelley wrote:
> Hi Richard,
>
> Not exactly actually.
>
> What I mean is:
> Before: hi Richard>, & good morning<
> After:   hi Richard>, & good morning<
>
> I hope it's clear now.
>
> On Fri, Jul 25, 2008 at 7:53 PM, Richard Heyes <[EMAIL PROTECTED]>
> wrote:
>
>   
>>> How can I make a string with & (NOT &, >, < or "), <, >
>>>   
>> xml
>> 
>>> compatible?
>>> What is the expression to use?
>>>   
>> Not entirely sure what you're after (try posting some before and after
>> snippets), but by the sounds of it you don't need a regular expression
>> - strtr() will work for you. Or str_replace().
>>
>> --
>> Richard Heyes
>> http://www.phpguru.org
>>
>> 
>
>
>
>   

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Re: [PHP] Regular Expression help need

2008-07-25 Thread Shelley

Hi Richard,

Not exactly actually.

What I mean is:
Before: hi Richard>, & good morning<
After:   hi Richard>, & good morning<

I hope it's clear now.

On Fri, Jul 25, 2008 at 7:53 PM, Richard Heyes <[EMAIL PROTECTED]>
wrote:

> > How can I make a string with & (NOT &, >, < or "), <, >
> xml
> > compatible?
> > What is the expression to use?
>
> Not entirely sure what you're after (try posting some before and after
> snippets), but by the sounds of it you don't need a regular expression
> - strtr() will work for you. Or str_replace().
>
> --
> Richard Heyes
> http://www.phpguru.org
>



-- 
Regards,
Shelley

Re: [PHP] Regular Expression help need

2008-07-25 Thread Richard Heyes

> How can I make a string with & (NOT &, >, < or "), <, > xml
> compatible?
> What is the expression to use?

Not entirely sure what you're after (try posting some before and after
snippets), but by the sounds of it you don't need a regular expression
- strtr() will work for you. Or str_replace().

-- 
Richard Heyes
http://www.phpguru.org

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[PHP] Regular Expression help need

2008-07-25 Thread Shelley

Hi all,

How can I make a string with & (NOT &, >, < or "), <, > xml
compatible?
What is the expression to use?

Thank you very much.

-- 
Regards,
Shelley

Re: [PHP] regular expression to find body text in mobile

2008-06-12 Thread Yui Hiroaki

The server recieve email from mobile phone.
I would like to retrieve the text of body of mobile phone, which recieve
email from mobile phone email.

Of cource, server run php and is able to use regular expression.
But the email, which is recieved by mobile phone, retrieve text body
on server.

Regards,
Yui

2008/6/12 Nitsan Bin-Nun <[EMAIL PROTECTED]>:
> I'm confused.
> PHP runs on the server, so it shouldn't be a problem at all to run regex
> search/reaplce/match/whatever on mobile phone internet, maybe you are
> talking on JS regex?
>
> Nitsan
>
>
> On 11/06/2008, Yui Hiroaki <[EMAIL PROTECTED]> wrote:
>>
>> Doese any know how to find text in mobile using Regular Expression?
>> I am using php.
>>
>> Regards,
>> Yui
>>
>> --
>> PHP General Mailing List (http://www.php.net/)
>> To unsubscribe, visit: http://www.php.net/unsub.php
>>
>
>

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Re: [PHP] regular expression to find body text in mobile

2008-06-11 Thread Nitsan Bin-Nun

I'm confused.
PHP runs on the server, so it shouldn't be a problem at all to run regex
search/reaplce/match/whatever on mobile phone internet, maybe you are
talking on JS regex?

Nitsan

On 11/06/2008, Yui Hiroaki <[EMAIL PROTECTED]> wrote:
>
> Doese any know how to find text in mobile using Regular Expression?
> I am using php.
>
> Regards,
> Yui
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
>

Re: [PHP] regular expression to find body text in mobile

2008-06-11 Thread Bastien Koert

On Wed, Jun 11, 2008 at 9:43 AM, Yui Hiroaki <[EMAIL PROTECTED]> wrote:

> Ooops!
> It it mobile mobile phone!
>
> Regards,
> Yui
>
> 2008/6/11 Richard Heyes <[EMAIL PROTECTED]>:
> >> Doese any know how to find text in mobile using Regular Expression?
> >> I am using php.
> >
> > Mobile what?
> >
> > --
> > Richard Heyes
>

You want to search for text that is on a screen on a mobile device? PHP runs
on the server, so it won't be able to manage that.

Can you be more clear about the goal? Help us understand what you want to
do.
-- 

Bastien

Cat, the other other white meat

Re: [PHP] regular expression to find body text in mobile

2008-06-11 Thread Yui Hiroaki

Ooops!
It it mobile mobile phone!

Regards,
Yui

2008/6/11 Richard Heyes <[EMAIL PROTECTED]>:
>> Doese any know how to find text in mobile using Regular Expression?
>> I am using php.
>
> Mobile what?
>
> --
> Richard Heyes
>
>Employ me:
> http://www.phpguru.org/cv
>
> ++
> | Access SSH with a Windows mapped drive |
> |http://www.phpguru.org/sftpdrive|
> ++
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
>

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Re: [PHP] regular expression to find body text in mobile

2008-06-11 Thread Richard Heyes


Doese any know how to find text in mobile using Regular Expression?
I am using php.


Mobile what?

--
Richard Heyes

Employ me:
http://www.phpguru.org/cv

++
| Access SSH with a Windows mapped drive |
|http://www.phpguru.org/sftpdrive|
++

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[PHP] regular expression to find body text in mobile

2008-06-11 Thread Yui Hiroaki

Doese any know how to find text in mobile using Regular Expression?
I am using php.

Regards,
Yui

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Re: [PHP] regular expression question

2007-09-01 Thread Richard Heyes

But how? The +[a-z]{2,} seems to allow at least two a-z clusters, but it 
doesn't include a period. /ml


Almost correct. The plus belongs to whatever comes before it, not after. 
So what you're referring to as matching two or more characters but not 
the period, is this:


[a-z]{2,}

And this will match one or more  "subdomains":

([-a-z0-9]+\.)+

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Re: [PHP] regular expression question

2007-08-31 Thread Per Jessen

Matthew Lasar wrote:

> At 11:32 AM 8/31/2007, Per Jessen wrote:
>>Matthew Lasar wrote:
>>
>> > But I don't understand why the second half of the regular
>> > expression works. I'm talking about this part:
>> >
>> > @([-a-z0-9]+\.)+[a-z]{2,}/";
>> >
>> > why is it able to detect repeated sections of the email address
>> > after "@" that are separated by periods? like "@email.alaska.com" .
>> > It looks to me like it's only looking for one example of that
>> > pattern. Does the "()" allow an unlimited number of patterns to
>> > pass?
>>
>>No, but the following '+' does.
> 
> But how? The +[a-z]{2,} seems to allow at least
> two a-z clusters, but it doesn't include a period. /ml
> 

That plus applies to the grouping () before it:

([-a-z0-9]+\.)+   one or more sequences of -a-z0-9 followed by a period



/Per Jessen, Zürich

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Re: [PHP] regular expression question

2007-08-31 Thread Matthew Lasar


At 11:32 AM 8/31/2007, Per Jessen wrote:

Matthew Lasar wrote:

> But I don't understand why the second half of the regular expression
> works. I'm talking about this part:
>
> @([-a-z0-9]+\.)+[a-z]{2,}/";
>
> why is it able to detect repeated sections of the email address after
> "@" that are separated by periods? like "@email.alaska.com" . It
> looks to me like it's only looking for one example of that pattern.
> Does the "()" allow an unlimited number of patterns to pass?

No, but the following '+' does.


But how? The +[a-z]{2,} seems to allow at least 
two a-z clusters, but it doesn't include a period. /ml




/Per Jessen, ZÃ¼rich

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- Release Date: 8/30/2007 6:05 PM


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Re: [PHP] regular expression question

2007-08-31 Thread Per Jessen

Matthew Lasar wrote:

> But I don't understand why the second half of the regular expression
> works. I'm talking about this part:
> 
> @([-a-z0-9]+\.)+[a-z]{2,}/";
> 
> why is it able to detect repeated sections of the email address after
> "@" that are separated by periods? like "@email.alaska.com" . It
> looks to me like it's only looking for one example of that pattern.
> Does the "()" allow an unlimited number of patterns to pass?

No, but the following '+' does. 


/Per Jessen, Zürich

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[PHP] regular expression question

2007-08-31 Thread Matthew Lasar


Hello:

I've adapted this regular expression script from a book, but I'm not 
clear why it works.


$email = "[EMAIL PROTECTED]";
$pattern = "/[EMAIL PROTECTED]@([-a-z0-9]+\.)+[a-z]{2,}/";
___

if ( preg_match($pattern,$email) )
{
print "yes! " . $email . " matches!";
}
else { print "no match"; }
___

When I run this script, I get the "yes! [EMAIL PROTECTED] 
matches!" statement.


But I don't understand why the second half of the regular expression 
works. I'm talking about this part:


@([-a-z0-9]+\.)+[a-z]{2,}/";

why is it able to detect repeated sections of the email address after 
"@" that are separated by periods? like "@email.alaska.com" . It 
looks to me like it's only looking for one example of that pattern. 
Does the "()" allow an unlimited number of patterns to pass?


thanks for any and all guidance

Matthew

Matthew Lasar  ||  llfcc.net  


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RE: [PHP] Regular expression - URL validator

2007-08-29 Thread Richard Lynch

Yes, make sure you have http:// on the front.

http://$link";;
?>

On Tue, August 28, 2007 3:22 pm, Wagner Garcia Campagner wrote:
> Thanks Jim,
>
> Your sugestion worked perfect for me!!
>
> I have another question:
>
> After i validate this URL i want to put a link with this URL in my
> page.
>
> The problem is that if the URL is like (www.aol.com), when i create
> the
> link, this URL is appended with the URL of my site. The result is a
> link
> pointing to: http:///www.aol.com
>
> But if the URL is like (http://aol.com), then the link is created
> correct.
>
> Is there a way to avoid the first situation... so the link is created
> correct?
>
> Thanks again,
> Wagner.
>
>
>
> -Original Message-
> From: Jim Lucas [mailto:[EMAIL PROTECTED]
> Sent: segunda-feira, 27 de agosto de 2007 17:36
> To: PHP General; [EMAIL PROTECTED]
> Subject: Re: [PHP] Regular expression - URL validator
>
>
> Wagner Garcia Campagner wrote:
>  > Hello,
>  >
>  > I found this regular expression on a web site.
>  > It is basicaly an URL validator.
>  >
>  > I'm trying to implement this in my web site, but i receive errors.
>  >
>  > I think this is a PERL REGEX so what should i do to make it work in
> php?
>  >
>  >
>  > $valid =
>  >
> (preg_match('^H|h)(T|t)|(F|f))(T|t)(P|p)((S|s)?))\://)?(www.|[a-zA-Z0-9]
>  >
> .)[a-zA-Z0-9\-\.]+\.[a-zA-Z]{2,6}(\:[0-9]{1,5})*(/($|[a-zA-Z0-9\.\,\;\?\'\\\
>  > +&%\$#\=~_\-]+))*$', $_POST['website']));
>
> This should be preg_match('/.../i', $_POST['website'])
>
> your regex should look something like this.
>
> ^((ftp|(http(s)?))://)?(\.?([a-z0-9-]+))+\.[a-z]{2,6}(:[0-9]{1,5})?(/[a-zA-Z
> 0-9.,;\?|\'+&%\$#=~_-]+)*$
>
> So, put it all together and it should look like this.
>
> 
> $url = "...PUT YOUR TEST URL HERE...";
>
> if (
> preg_match('!^((ftp|(http(s)?))://)?(\.?([a-z0-9-]+))+\.[a-z]{2,6}(:[0-9]{1,
> 5})?(/[a-zA-Z0-9.,;\?|\'+&%\$#=~_-]+)*$!i',
> $url) ) {
>   echo "Matched";
> } else {
>   echo "Did not match";
> }
>
>
>
>
>  >
>  > if ($valido == 0) {
>  > something here;
>  > }
>  > else {
>  > something else here;
>  > }
>  >
>  >
>  > Thanks a lot in advance,
>  > Wagner.
>  >
>
>
>
> --
> Jim Lucas
>
> "Some men are born to greatness, some achieve greatness,
> and some have greatness thrust upon them."
>
> Twelfth Night, Act II, Scene V
>  by William Shakespeare
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
>


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Re: [PHP] Regular expression - URL validator

2007-08-29 Thread Jim Lucas


Wagner Garcia Campagner wrote:

Thanks again Jim,

That's what i really need.

I'm testing this function...

If i put a URL like www.example.com, then it works fine and turns it to
http://www.example.com

But if i put a URL like http://www.example.com, then it also put another
header so it turns to http://http://www.example.com

I also tried with the strstr function, but receive the same response.

Thanks in advance,
Wagner.


Give this a shot

ftp://www.google.com";);
echo "\n";
echo fixurl("http://www.google.com";);
echo "\n";
echo fixurl("https://www.google.com";);
?>

--
Jim Lucas

   "Some men are born to greatness, some achieve greatness,
   and some have greatness thrust upon them."

Twelfth Night, Act II, Scene V
by William Shakespeare

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RE: [PHP] Regular expression - URL validator

2007-08-29 Thread Wagner Garcia Campagner

Thanks again Jim,

That's what i really need.

I'm testing this function...

If i put a URL like www.example.com, then it works fine and turns it to
http://www.example.com

But if i put a URL like http://www.example.com, then it also put another
header so it turns to http://http://www.example.com

I also tried with the strstr function, but receive the same response.

Thanks in advance,
Wagner.



-Original Message-
From: Jim Lucas [mailto:[EMAIL PROTECTED]
Sent: terça-feira, 28 de agosto de 2007 18:35
To: [EMAIL PROTECTED]
Cc: PHP General
Subject: Re: [PHP] Regular expression - URL validator


Wagner Garcia Campagner wrote:
> Thanks Jim,
>
> Your sugestion worked perfect for me!!
>
> I have another question:
>
> After i validate this URL i want to put a link with this URL in my page.
>
> The problem is that if the URL is like (www.aol.com), when i create the
> link, this URL is appended with the URL of my site. The result is a link
> pointing to: http:///www.aol.com
>
> But if the URL is like (http://aol.com), then the link is created correct.
>
> Is there a way to avoid the first situation... so the link is created
> correct?
>
> Thanks again,
> Wagner.
>
You could always do a string comparison for http(s)? in the url

if ( strpos($url, array('https://', 'http://')) === false ) {
$url = 'http://'.$url;
}

--
Jim Lucas

"Some men are born to greatness, some achieve greatness,
and some have greatness thrust upon them."

Twelfth Night, Act II, Scene V
 by William Shakespeare

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Re: [PHP] Regular expression - URL validator

2007-08-28 Thread Jim Lucas


Wagner Garcia Campagner wrote:

Thanks Jim,

Your sugestion worked perfect for me!!

I have another question:

After i validate this URL i want to put a link with this URL in my page.

The problem is that if the URL is like (www.aol.com), when i create the
link, this URL is appended with the URL of my site. The result is a link
pointing to: http:///www.aol.com

But if the URL is like (http://aol.com), then the link is created correct.

Is there a way to avoid the first situation... so the link is created
correct?

Thanks again,
Wagner.


You could always do a string comparison for http(s)? in the url

if ( strpos($url, array('https://', 'http://')) === false ) {
$url = 'http://'.$url;
}

--
Jim Lucas

   "Some men are born to greatness, some achieve greatness,
   and some have greatness thrust upon them."

Twelfth Night, Act II, Scene V
by William Shakespeare

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Re: [PHP] Regular expression - URL validator

2007-08-28 Thread shiplu

On 8/28/07, Wagner Garcia Campagner <[EMAIL PROTECTED]> wrote:
>
> Thanks Jim,
>
> Your sugestion worked perfect for me!!
>
> I have another question:
>
> After i validate this URL i want to put a link with this URL in my page.
>
> The problem is that if the URL is like (www.aol.com), when i create the
> link, this URL is appended with the URL of my site. The result is a link
> pointing to: http:///www.aol.com
>
> But if the URL is like (http://aol.com), then the link is created correct.
>
> Is there a way to avoid the first situation... so the link is created
> correct?
>
> Thanks again,
> Wagner.
>
>
>
> -Original Message-
> From: Jim Lucas [mailto:[EMAIL PROTECTED]
> Sent: segunda-feira, 27 de agosto de 2007 17:36
> To: PHP General; [EMAIL PROTECTED]
> Subject: Re: [PHP] Regular expression - URL validator
>
>
> Wagner Garcia Campagner wrote:
> > Hello,
> >
> > I found this regular expression on a web site.
> > It is basicaly an URL validator.
> >
> > I'm trying to implement this in my web site, but i receive errors.
> >
> > I think this is a PERL REGEX so what should i do to make it work in php?
> >
> >
> > $valid =
> >
>
> (preg_match('^H|h)(T|t)|(F|f))(T|t)(P|p)((S|s)?))\://)?(www.|[a-zA-Z0-9]
> >
>
> .)[a-zA-Z0-9\-\.]+\.[a-zA-Z]{2,6}(\:[0-9]{1,5})*(/($|[a-zA-Z0-9\.\,\;\?\'\\\
> > +&%\$#\=~_\-]+))*$', $_POST['website']));
>
> This should be preg_match('/.../i', $_POST['website'])
>
> your regex should look something like this.
>
>
> ^((ftp|(http(s)?))://)?(\.?([a-z0-9-]+))+\.[a-z]{2,6}(:[0-9]{1,5})?(/[a-zA-Z
> 0-9.,;\?|\'+&%\$#=~_-]+)*$
>
> So, put it all together and it should look like this.
>
> 
> $url = "...PUT YOUR TEST URL HERE...";
>
> if (
>
> preg_match('!^((ftp|(http(s)?))://)?(\.?([a-z0-9-]+))+\.[a-z]{2,6}(:[0-9]{1,
> 5})?(/[a-zA-Z0-9.,;\?|\'+&%\$#=~_-]+)*$!i',
> $url) ) {
> echo "Matched";
> } else {
> echo "Did not match";
> }
>
>
>
>
> >
> > if ($valido == 0) {
> > something here;
> > }
> > else {
> > something else here;
> > }
> >
> >
> > Thanks a lot in advance,
> > Wagner.
> >
>
>
>
> --
> Jim Lucas
>
> "Some men are born to greatness, some achieve greatness,
> and some have greatness thrust upon them."
>
> Twelfth Night, Act II, Scene V
>  by William Shakespeare
>
> --
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> To unsubscribe, visit: http://www.php.net/unsub.php
>
>
you must use http://www.aol.com not www.aol.com. coz the later is not a
valid url. The protocol is not specified there. and if you use
www.aol.comis your href of a tags, the browser will automatically add
your current web
address as prefix as if its a relative url.
if your site is http://www.example.com/folder/site.html
and if you use href="/www.aol.com" it will show http://www.example.com/
www.aol.com
if you use href="www.aol.com" it will show
http://www.example.com/folder/<http://www.aol.com/>
www.aol.com
you have to use href="http://www.aol.com"; the absolute one.

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RE: [PHP] Regular expression - URL validator

2007-08-28 Thread Wagner Garcia Campagner

Thanks Jim,

Your sugestion worked perfect for me!!

I have another question:

After i validate this URL i want to put a link with this URL in my page.

The problem is that if the URL is like (www.aol.com), when i create the
link, this URL is appended with the URL of my site. The result is a link
pointing to: http:///www.aol.com

But if the URL is like (http://aol.com), then the link is created correct.

Is there a way to avoid the first situation... so the link is created
correct?

Thanks again,
Wagner.

-Original Message-
From: Jim Lucas [mailto:[EMAIL PROTECTED]
Sent: segunda-feira, 27 de agosto de 2007 17:36
To: PHP General; [EMAIL PROTECTED]
Subject: Re: [PHP] Regular expression - URL validator

Wagner Garcia Campagner wrote:
 > Hello,
 >
 > I found this regular expression on a web site.
 > It is basicaly an URL validator.
 >
 > I'm trying to implement this in my web site, but i receive errors.
 >
 > I think this is a PERL REGEX so what should i do to make it work in php?
 >
 >
 > $valid =
 >
(preg_match('^H|h)(T|t)|(F|f))(T|t)(P|p)((S|s)?))\://)?(www.|[a-zA-Z0-9]
 >
.)[a-zA-Z0-9\-\.]+\.[a-zA-Z]{2,6}(\:[0-9]{1,5})*(/($|[a-zA-Z0-9\.\,\;\?\'\\\
 > +&%\$#\=~_\-]+))*$', $_POST['website']));

This should be preg_match('/.../i', $_POST['website'])

your regex should look something like this.

^((ftp|(http(s)?))://)?(\.?([a-z0-9-]+))+\.[a-z]{2,6}(:[0-9]{1,5})?(/[a-zA-Z
0-9.,;\?|\'+&%\$#=~_-]+)*$

So, put it all together and it should look like this.

 > if ($valido == 0) {
 > something here;
 > }
 > else {
 > something else here;
 > }
 >
 >
 > Thanks a lot in advance,
 > Wagner.
 >

--
Jim Lucas

"Some men are born to greatness, some achieve greatness,
and some have greatness thrust upon them."

Twelfth Night, Act II, Scene V
 by William Shakespeare

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Re: [PHP] Regular expression - URL validator

2007-08-27 Thread Jim Lucas


Wagner Garcia Campagner wrote:
> Hello,
>
> I found this regular expression on a web site.
> It is basicaly an URL validator.
>
> I'm trying to implement this in my web site, but i receive errors.
>
> I think this is a PERL REGEX so what should i do to make it work in php?
>
>
> $valid =
> (preg_match('^H|h)(T|t)|(F|f))(T|t)(P|p)((S|s)?))\://)?(www.|[a-zA-Z0-9]
> .)[a-zA-Z0-9\-\.]+\.[a-zA-Z]{2,6}(\:[0-9]{1,5})*(/($|[a-zA-Z0-9\.\,\;\?\'\\\
> +&%\$#\=~_\-]+))*$', $_POST['website']));

This should be preg_match('/.../i', $_POST['website'])

your regex should look something like this.

^((ftp|(http(s)?))://)?(\.?([a-z0-9-]+))+\.[a-z]{2,6}(:[0-9]{1,5})?(/[a-zA-Z0-9.,;\?|\'+&%\$#=~_-]+)*$

So, put it all together and it should look like this.

if ( 
preg_match('!^((ftp|(http(s)?))://)?(\.?([a-z0-9-]+))+\.[a-z]{2,6}(:[0-9]{1,5})?(/[a-zA-Z0-9.,;\?|\'+&%\$#=~_-]+)*$!i', 
$url) ) {

echo "Matched";
} else {
echo "Did not match";
}




>
> if ($valido == 0) {
> something here;
> }
> else {
> something else here;
> }
>
>
> Thanks a lot in advance,
> Wagner.
>



--
Jim Lucas

   "Some men are born to greatness, some achieve greatness,
   and some have greatness thrust upon them."

Twelfth Night, Act II, Scene V
by William Shakespeare

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[PHP] Regular expression - URL validator

2007-08-27 Thread Wagner Garcia Campagner

Hello,

I found this regular expression on a web site.
It is basicaly an URL validator.

I'm trying to implement this in my web site, but i receive errors.

I think this is a PERL REGEX so what should i do to make it work in php?


$valid =
(preg_match('^H|h)(T|t)|(F|f))(T|t)(P|p)((S|s)?))\://)?(www.|[a-zA-Z0-9]
.)[a-zA-Z0-9\-\.]+\.[a-zA-Z]{2,6}(\:[0-9]{1,5})*(/($|[a-zA-Z0-9\.\,\;\?\'\\\
+&%\$#\=~_\-]+))*$', $_POST['website']));

if ($valido == 0) {
something here;
}
else {
something else here;
}


Thanks a lot in advance,
Wagner.

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RE: [PHP] Regular Expression just one step away from what I need....

2007-08-17 Thread Jay Blanchard

[snip]
I am no regex expert but wouldn't
preg_match_all( "/'([^']+)'/Ui", $theString, $matches);

Be more flexible?
[/snip]

Thanks all, I completely forgot about greedy/ungreedy. That is what you
get for being rusty!

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Re: [PHP] Regular Expression just one step away from what I need....

2007-08-17 Thread Geoff Nicol

I am no regex expert but wouldn't
preg_match_all( "/'([^']+)'/Ui", $theString, $matches);

Be more flexible?

On 8/17/07, Thijs Lensselink <[EMAIL PROTECTED]> wrote:
>
>
> If it's only real words this will do:
>
> $theString = "'foo''bar''glorp'";
> preg_match_all( "/'([a-z]+)'/Ui", $theString, $matches);
>
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>
>

Re: [PHP] Regular Expression just one step away from what I need....

2007-08-17 Thread Robert Cummings

On Fri, 2007-08-17 at 12:00 -0500, Jay Blanchard wrote:
> Given the string 'foo''bar''glorp' (all quotes are single quotes)I had
> hoped to find a regular expression using preg_match that would return an
> array containing just those words without having to go through
> additional gyrations, like exploding a string to get an array. I have
> only had limited luck
> 
> $theString = "'foo''bar''glorp'";
> preg_match( "/\'(.*)\'/", $theString, $matches);
> print_r($matches);

You want to add the ungreedy modifier...

preg_match( "/\'(.*)\'/U", $theString, $matches);

Cheers,
Rob.
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Re: [PHP] Regular Expression just one step away from what I need....

2007-08-17 Thread Thijs Lensselink

Jay Blanchard wrote:

> Given the string 'foo''bar''glorp' (all quotes are single quotes)I had
> hoped to find a regular expression using preg_match that would return an
> array containing just those words without having to go through
> additional gyrations, like exploding a string to get an array. I have
> only had limited luck
>
> $theString = "'foo''bar''glorp'";
> preg_match( "/\'(.*)\'/", $theString, $matches);
> print_r($matches);
>
> Array
> (
> [0] => 'foo''bar''glorp'
> [1] => foo''bar''glorp
> )
>
> Of course $matches[0] has the entire string and $matches[1] contains the
> returned string minus the leading and trailing single quote. I can
> explode $matches[1] to get what I want, but it is an extra step and I am
> sure that I have done this before but cannot locate the code in
> question. I would like the results to be
>
> Array
> (
> [0] => 'foo''bar''glorp'
> [1] => foo
> [2] => bar
> [3] => glorp
> )
>
> That way I can use the $matches array without having to create another
> array to hold the values. I feel as if I am really close on the regex to
> do this, but cannot seem to find (after much head scratching and teeth
> gnashing) the proper solution.
>
> Much thanks!
>
>   
If it's only real words this will do:

$theString = "'foo''bar''glorp'";
preg_match_all( "/'([a-z]+)'/Ui", $theString, $matches);

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[PHP] Regular Expression just one step away from what I need....

2007-08-17 Thread Jay Blanchard

Given the string 'foo''bar''glorp' (all quotes are single quotes)I had
hoped to find a regular expression using preg_match that would return an
array containing just those words without having to go through
additional gyrations, like exploding a string to get an array. I have
only had limited luck

$theString = "'foo''bar''glorp'";
preg_match( "/\'(.*)\'/", $theString, $matches);
print_r($matches);

Array
(
[0] => 'foo''bar''glorp'
[1] => foo''bar''glorp
)

Of course $matches[0] has the entire string and $matches[1] contains the
returned string minus the leading and trailing single quote. I can
explode $matches[1] to get what I want, but it is an extra step and I am
sure that I have done this before but cannot locate the code in
question. I would like the results to be

Array
(
[0] => 'foo''bar''glorp'
[1] => foo
[2] => bar
[3] => glorp
)

That way I can use the $matches array without having to create another
array to hold the values. I feel as if I am really close on the regex to
do this, but cannot seem to find (after much head scratching and teeth
gnashing) the proper solution.

Much thanks!

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Re: [PHP] regular expression and forbidden words

2007-07-18 Thread Ben Schmidt


Nicolas Quirin wrote:

Hi,

i'm french, i'm using regular expressions in php in order to rewrite 
hyperlink tags in a specific way before apache output is beeing sent to 
client.


Purpose is to replace href attribute of any A html tag by a javascript 
function calling an ajax loader.


Currently I have wrote that:

 $pattern = '/href="(http:\/\/dev.netdoor.fr|(\.))\/index.php\?page=(.*?)">(.*?)<\\/a>/i'; 

 $replacement = 'OnClick="javascript:yui_fastLoader(\'./systeme/chargeur.php?page=$4\');">$5'; 


 $html_mark = preg_replace($pattern, $replacement, $html_mark);

it works, but it's too permissive, it replaces too much links (some 
links with some get parameters must stay unchanged)


I don't really understand my pattern...it's a little strange for me...lol

I wouldn't like to rewrite links that contains any of the following 
words in get parameters (query string):


 noLoader
 noLeftCol
 skipallbutpage
 skipservice

i would like to rewrite only link that begin with 
'http://dev.netdoor.fr' or '.'


examples:

href="http://dev.netdoor.fr/index.php?page=./comptes/index.php&noLoader&noLeftCol&idx=6&bdx=423&skipservice";>test 



=>must be not rewritted!

href="./index.php?page=./comptes/mediatheque/index.php&filter=mov;flv;mpeg&idx=7">name 



=>must be rewritted like this :

OnClick="javascript:yui_fastLoader(\'./systeme/chargeur.php?page=./comptes/mediatheque/index.php&filter=mov;flv;mpeg&idx=7\');">name 




Please help me...:0)

best regards

nicolas


It's complicated. I'd resort to using a callback. Even if it's possible
with just patterns, it wouldn't be very readable! Something like this:

if (!function_exists('make_replacement')) {
 function make_replacement($m) {
  $n=$m[2];
  if (preg_match('~^(http://dev.netdoor.fr|\.)/index\.php\?(.*?)$~',
$n,$mm)) {
   if (!preg_match('~noLoader|noLeftCol|skipallbutpage|skipservice~',
 $mm[2])) {
$n='javascript:void(0);" '.
  'OnClick="javascript:yui_fastLoader(\'./systeme/chargeur.php?'.
  $mm[2].'\')';
   }
  }
  return $m[1].'href="'.$n.'"'.$m[3];
 }
}
$pat='~()~i';
$html_mark=preg_replace_callback($pat,'make_replacement',$html_mark);

Ben.

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Re: [PHP] regular expression and forbidden words

2007-07-18 Thread Ben Schmidt


Nicolas Quirin wrote:

Hi,

i'm french, i'm using regular expressions in php in order to rewrite 
hyperlink tags in a specific way before apache output is beeing sent to 
client.


Purpose is to replace href attribute of any A html tag by a javascript 
function calling an ajax loader.


Currently I have wrote that:

 $pattern = '/href="(http:\/\/dev.netdoor.fr|(\.))\/index.php\?page=(.*?)">(.*?)<\\/a>/i'; 

 $replacement = 'OnClick="javascript:yui_fastLoader(\'./systeme/chargeur.php?page=$4\');">$5'; 


 $html_mark = preg_replace($pattern, $replacement, $html_mark);

it works, but it's too permissive, it replaces too much links (some 
links with some get parameters must stay unchanged)


I don't really understand my pattern...it's a little strange for me...lol

I wouldn't like to rewrite links that contains any of the following 
words in get parameters (query string):


 noLoader
 noLeftCol
 skipallbutpage
 skipservice

i would like to rewrite only link that begin with 
'http://dev.netdoor.fr' or '.'


examples:

href="http://dev.netdoor.fr/index.php?page=./comptes/index.php&noLoader&noLeftCol&idx=6&bdx=423&skipservice";>test 



=>must be not rewritted!

href="./index.php?page=./comptes/mediatheque/index.php&filter=mov;flv;mpeg&idx=7">name 



=>must be rewritted like this :

OnClick="javascript:yui_fastLoader(\'./systeme/chargeur.php?page=./comptes/mediatheque/index.php&filter=mov;flv;mpeg&idx=7\');">name 




Please help me...:0)

best regards

nicolas


It's complicated. I'd resort to using a callback. Even if it's possible 
with just patterns, it wouldn't be very readable! Something like this:


if (!function_exists('make_replacement')) {
   function make_replacement($m) {
  $n=$m[2];
  if 
(preg_match('~^(http://dev.netdoor.fr|\.)/index\.php\?(.*?)$~',$n,$mm)) {

 echo "MATCHED\n";
 if 
(!preg_match('~noLoader|noLeftCol|skipallbutpage|skipservice~',$mm[2])) {

echo "NOT MATCHED\n";
$n='javascript:void(0);" '.

'OnClick="javascript:yui_fastLoader(\'./systeme/chargeur.php?'.
  $mm[2].'\')';
 }
  }
  return $m[1].'href="'.$n.'"'.$m[3];
   }
}
$pat='~()~i';
$html_mark=preg_replace_callback($pat,'make_replacement',$html_mark);

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[PHP] regular expression and forbidden words

2007-07-18 Thread Nicolas Quirin


Hi,

i'm french, i'm using regular expressions in php in order to rewrite 
hyperlink tags in a specific way before apache output is beeing sent to 
client.


Purpose is to replace href attribute of any A html tag by a javascript 
function calling an ajax loader.


Currently I have wrote that:

 $pattern = '/href="(http:\/\/dev.netdoor.fr|(\.))\/index.php\?page=(.*?)">(.*?)<\\/a>/i';
 $replacement = 'OnClick="javascript:yui_fastLoader(\'./systeme/chargeur.php?page=$4\');">$5';

 $html_mark = preg_replace($pattern, $replacement, $html_mark);

it works, but it's too permissive, it replaces too much links (some links 
with some get parameters must stay unchanged)


I don't really understand my pattern...it's a little strange for me...lol

I wouldn't like to rewrite links that contains any of the following words in 
get parameters (query string):


 noLoader
 noLeftCol
 skipallbutpage
 skipservice

i would like to rewrite only link that begin with 'http://dev.netdoor.fr' or 
'.'


examples:

href="http://dev.netdoor.fr/index.php?page=./comptes/index.php&noLoader&noLeftCol&idx=6&bdx=423&skipservice";>test


=>must be not rewritted!

href="./index.php?page=./comptes/mediatheque/index.php&filter=mov;flv;mpeg&idx=7">name


=>must be rewritted like this :

OnClick="javascript:yui_fastLoader(\'./systeme/chargeur.php?page=./comptes/mediatheque/index.php&filter=mov;flv;mpeg&idx=7\');">name



Please help me...:0)

best regards

nicolas

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[PHP] regular expression and forbidden words

2007-07-17 Thread Nicolas Quirin

Hi,

i'm french, i'm using regular expressions in php in order to rewrite hyperlink 
tags in a specific way before apache output is beeing sent to client.

Purpose is to replace href attribute of any A html tag by a javascript function 
calling an ajax loader.

Currently I have wrote that:

  $pattern = '/(.*?)<\\/a>/i';
  $replacement = '$5';
  $html_mark = preg_replace($pattern, $replacement, $html_mark);

it works, but it's too permissive, it replaces too much links (some links with 
some get parameters must stay unchanged)

I don't really understand my pattern...it's a little strange for me...lol

I wouldn't like to rewrite links that contains any of the following words in 
get parameters (query string):

  noLoader
  noLeftCol
  skipallbutpage
  skipservice

i would like to rewrite only link that begin with 'http://dev.netdoor.fr' or '.'

examples:

http://dev.netdoor.fr/index.php?page=./comptes/index.php&noLoader&noLeftCol&idx=6&bdx=423&skipservice";>test
 

=>must be not rewritted!

name

=>must be rewritted like this :

name


Please help me...:0)

best regards

nicolas

Re: [PHP] regular expression and forbidden words

2007-07-17 Thread Arpad Ray


Nicolas Quirin wrote:

Hi,

i'm french, i'm using regular expressions in php in order to rewrite hyperlink 
tags in a specific way before apache output is beeing sent to client.

Purpose is to replace href attribute of any A html tag by a javascript function 
calling an ajax loader.

Currently I have wrote that:

  $pattern = '/(.*?)<\\/a>/i';
  $replacement = '$5';
  $html_mark = preg_replace($pattern, $replacement, $html_mark);

it works, but it's too permissive, it replaces too much links (some links with 
some get parameters must stay unchanged)

I don't really understand my pattern...it's a little strange for me...lol

I wouldn't like to rewrite links that contains any of the following words in 
get parameters (query string):

  noLoader
  noLeftCol
  skipallbutpage
  skipservice

i would like to rewrite only link that begin with 'http://dev.netdoor.fr' or '.'

examples:

http://dev.netdoor.fr/index.php?page=./comptes/index.php&noLoader&noLeftCol&idx=6&bdx=423&skipservice";>test 


=>must be not rewritted!

name

=>must be rewritted like this :

name


Please help me...:0)

best regards

nicolas



The key here is (?!) - the negative assertion, it should look something 
like this:


$p = '#href="(?:\.|http://dev.netdoor.fr)/index\.php\?page=(?![^"]*(?:noLoader|noLeftCol|skipallbutpage|skipservice))([^"]*)">(.*?)#is';
$r = 'OnClick="javascript:yui_fastLoader(\'./systeme/chargeur.php?page=$1\');">$2';


Arpad

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[PHP] regular expression and forbidden words

2007-07-17 Thread Nicolas Quirin

Hi,

i'm french, i'm using regular expressions in php in order to rewrite hyperlink 
tags in a specific way before apache output is beeing sent to client.

Purpose is to replace href attribute of any A html tag by a javascript function 
calling an ajax loader.

Currently I have wrote that:

  $pattern = '/(.*?)<\\/a>/i';
  $replacement = '$5';
  $html_mark = preg_replace($pattern, $replacement, $html_mark);

it works, but it's too permissive, it replaces too much links (some links with 
some get parameters must stay unchanged)

I don't really understand my pattern...it's a little strange for me...lol

I wouldn't like to rewrite links that contains any of the following words in 
get parameters (query string):

  noLoader
  noLeftCol
  skipallbutpage
  skipservice

i would like to rewrite only link that begin with 'http://dev.netdoor.fr' or '.'

examples:

http://dev.netdoor.fr/index.php?page=./comptes/index.php&noLoader&noLeftCol&idx=6&bdx=423&skipservice";>test
 

=>must be not rewritted!

name

=>must be rewritted like this :

name


Please help me...:0)

best regards

nicolas

Re: [PHP] Regular Expression

2007-02-05 Thread Frank Arensmeier


5 feb 2007 kl. 22.12 skrev H.T:


Do you know good regular expression editor or something simialar?

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Regex online: www.regextester.com
//frank

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Re: [PHP] Regular Expression

2007-02-05 Thread Richard Lynch

On Mon, February 5, 2007 3:12 pm, H.T wrote:
> Do you know good regular expression editor or something simialar?

"The Regex Coach"

Helps you figure things out piece by piece with fancy color
highlighting of what matches what, and a tree graph and everything.

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Fw: [PHP] Regular Expression

2007-02-05 Thread Satyam

- Original Message - 
From: "H.T" <[EMAIL PROTECTED]>

To: 
Sent: Monday, February 05, 2007 10:12 PM
Subject: [PHP] Regular Expression

Do you know good regular expression editor or something simialar?

This goes into the 'something similar' category:

From the documentation:

The Regex Coach together with this documentation can be downloaded from 
http://weitz.de/files/regex-coach.exe (Windows installer) or 
http://weitz.de/files/regex-coach.tgz (Linux tar archive).

It's great to try and test the expressions

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[PHP] Regular Expression

2007-02-05 Thread H.T

Do you know good regular expression editor or something simialar?

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Re: [PHP] Regular Expression Problem

2007-01-24 Thread Jochem Maas

Roman Neuhauser wrote:
> # [EMAIL PROTECTED] / 2007-01-24 23:55:27 +0100:
>> Roman Neuhauser wrote:
>>> Are you doing this to learn regular expressions or are you actually
>>> trying to do work? Because you're going the wrong way.
>>> It's XML, why do you treat it as text?
>> not everyone shares that sentiment. in terms of lowest common denominator
>> XML is also a string. then there is the question of whether it's actually
>> marked as XML, whether there is valid DTD and whether the XML itself 
>> validates
>> against the DTD - if any of the answers is 'no' then your looking at tag 
>> soup.
> 
> as long as it's wellformed he can use it for what it is: a serialized
> composite structure, like the result of serialize($aTreeOfObjects).
> You can use preg_match() to extract a subset of the tree, but why bother
> if you have unserialize($aTreeOfObjects)->getElementById("foo")?

nothing to do with this argument but:

this reminds of a thread on internals where someone was trying to determine
if a serialized data was *safe* to run ... the data was coming from a cookie (I 
think),
unserializing the data without first checking it didn't contain something
evil was a bad idea - the proposed solution was a fairly simple regex
that checked for 'object' notation in the serialized string. :-)


>  

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Re: [PHP] Regular Expression Problem

2007-01-24 Thread Jochem Maas

Richard Luckhurst wrote:
> Hi Jochem,
> 
> JM> 
> JM> you be needing an ungreedy modifier on yer regex.
> JM> 
> 
> JM> see here:
> JM> http://php.net/manual/en/reference.pcre.pattern.modifiers.php
> 
> Thanks very much. That solved my problem and I my now getting exactly what I
> want. I had seen the reference to greedy and ungreedy but had not understood 
> the
> concept.

for a better understanding I recommend the film WallStreet - that
should get you up to speed on the concept of greed ;-)

> 
> Regards
> 
> Richard
> 
> 

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Re: [PHP] Regular Expression Problem

2007-01-24 Thread Richard Lynch

You want to add a 'U' after you closing # so that matches are
"Ungreedy" -- I.e., they do NOT grab as much text as the can to
fulfill the pattern (greedy) but they grab as LITTLE text as they can
to fulfill the pattern (ungreedy)

On Wed, January 24, 2007 4:27 pm, Richard Luckhurst wrote:
> Hi List
>
> I must be dumb as I have been battling my way through regular
> expression
> examples for a while and I can not work out why the following does not
> work
> properly. I am the first to admit that regular expressions confuse me
> greatly.
>
> The string is a piece of XML as follows and I have put that string
> into a
> variable called $xml_string
>
>
> 
>   addChdPrice="0.0" addInfPrice="0.0">
>  
> class="V">
> class="V">
>  
>  
>   addChdPrice="0.0" addInfPrice="0.0">
>  
> class="V">
> class="V">
>  
>  
> 
>
>
> What I am trying to do is extract the first 
> chunk.
>
> I am using the following, based on the example at
> http://php.net/manual/en/function.preg-match.php example 3
>
> preg_match('##', $xml_string,$matches);
> $tempstr = $matches[0];
>
> What I actually get in $tempstr is everything from the first  through to
> the last (second) 
>
> I would have expected preg_match to have matched from the first
>  to the first .
>
> I suspect I do not have the regular expression correct. I would great
> appreciate
> any help on sorting out the regular expression so that it only returns
> the first
> chunk of the string.
>
>
>
> Regards,
> Richard Luckhurst
>
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>
>


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Re: [PHP] Regular Expression Problem

2007-01-24 Thread Paul Novitski


At 1/24/2007 02:27 PM, Richard Luckhurst wrote:

What I am trying to do is extract the first  chunk.

...

preg_match('##', $xml_string,$matches);
$tempstr = $matches[0];

What I actually get in $tempstr is everything from the first through to

the last (second) 

I would have expected preg_match to have matched from the first 

to the first .



At 1/24/2007 02:55 PM, Jochem Maas wrote:


you be needing an ungreedy modifier on yer regex.


see here:
http://php.net/manual/en/reference.pcre.pattern.modifiers.php



You can also ask regexp to return the text up to but not including 
the next '<':


#http://juniperwebcraft.com 


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Re[2]: [PHP] Regular Expression Problem

2007-01-24 Thread Richard Luckhurst

Hi Jochem,

JM> 
JM> you be needing an ungreedy modifier on yer regex.
JM> 

JM> see here:
JM> http://php.net/manual/en/reference.pcre.pattern.modifiers.php

RL Thanks very much. That solved my problem and I my now getting exactly what I
RL want. I had seen the reference to greedy and ungreedy but had not understood 
the
RL concept.

RL Regards

RL Richard

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Re: [PHP] Regular Expression Problem

2007-01-24 Thread Roman Neuhauser

# [EMAIL PROTECTED] / 2007-01-25 09:27:59 +1100:
> 
>   addInfPrice="0.0">
>  
>
>
>  
>  
>   addInfPrice="0.0">
>  
>
>
>  
>  
> 
> 
> 
> What I am trying to do is extract the first  chunk.
 
> preg_match('##', $xml_string,$matches);
> $tempstr = $matches[0];
> 
> What I actually get in $tempstr is everything from the first  to
> the last (second) 
 
Strange, you should have gotten nothing:

s (PCRE_DOTALL)

If this modifier is set, a dot metacharacter in the pattern matches
all characters, including newlines. Without it, newlines are
excluded.

> I would have expected preg_match to have matched from the first  through
> to the first .

As Jochem wrote, you also need U (PCRE_UNGREEDY).

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Re: [PHP] Regular Expression Problem

2007-01-24 Thread Roman Neuhauser

# [EMAIL PROTECTED] / 2007-01-24 23:55:27 +0100:
> Roman Neuhauser wrote:
> > Are you doing this to learn regular expressions or are you actually
> > trying to do work? Because you're going the wrong way.
> > It's XML, why do you treat it as text?
> 
> not everyone shares that sentiment. in terms of lowest common denominator
> XML is also a string. then there is the question of whether it's actually
> marked as XML, whether there is valid DTD and whether the XML itself validates
> against the DTD - if any of the answers is 'no' then your looking at tag soup.

as long as it's wellformed he can use it for what it is: a serialized
composite structure, like the result of serialize($aTreeOfObjects).
You can use preg_match() to extract a subset of the tree, but why bother
if you have unserialize($aTreeOfObjects)->getElementById("foo")?
 
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Re: [PHP] Regular Expression Problem

2007-01-24 Thread Jochem Maas

Roman Neuhauser wrote:
> # [EMAIL PROTECTED] / 2007-01-25 09:27:59 +1100:
>> I must be dumb as I have been battling my way through regular expression
>> examples for a while and I can not work out why the following does not work
>> properly. I am the first to admit that regular expressions confuse me 
>> greatly.
>>
>> The string is a piece of XML as follows and I have put that string into a
>> variable called $xml_string
>>
>>
>> 
>>  > addInfPrice="0.0">
>>  
>>
>>
>>  
>>  
>>  > addInfPrice="0.0">
>>  
>>
>>
>>  
>>  
>> 
>>
>>
>> What I am trying to do is extract the first  chunk.


you be needing an ungreedy modifier on yer regex.


see here:
http://php.net/manual/en/reference.pcre.pattern.modifiers.php

> Are you doing this to learn regular expressions or are you actually
> trying to do work? Because you're going the wrong way.
> It's XML, why do you treat it as text?

not everyone shares that sentiment. in terms of lowest common denominator
XML is also a string. then there is the question of whether it's actually
marked as XML, whether there is valid DTD and whether the XML itself validates
against the DTD - if any of the answers is 'no' then your looking at tag soup.

there is a lot more tagsoup in this world than there is proper xml.

that said it can't hurt to throw simpleXML at the problem :-)

> 

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Re[2]: [PHP] Regular Expression Problem

2007-01-24 Thread Richard Luckhurst

Hi Roman,

RN> Are you doing this to learn regular expressions or are you actually
RN> trying to do work? Because you're going the wrong way.
RN> It's XML, why do you treat it as text?

I am well aware it is XML and I could use an XML parser or simpleXML. I am
trying to learn regular expressions as I have a fair bit of work coming up that
will require the use pattern matching within strings. It just so happens that
some of the data looks like XML, hence the reason I am using a piece of XML for
this learning process.


Regards

Richard

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Re: [PHP] Regular Expression Problem

2007-01-24 Thread Roman Neuhauser

# [EMAIL PROTECTED] / 2007-01-25 09:27:59 +1100:
> I must be dumb as I have been battling my way through regular expression
> examples for a while and I can not work out why the following does not work
> properly. I am the first to admit that regular expressions confuse me greatly.
> 
> The string is a piece of XML as follows and I have put that string into a
> variable called $xml_string
> 
> 
> 
>   addInfPrice="0.0">
>  
>
>
>  
>  
>   addInfPrice="0.0">
>  
>
>
>  
>  
> 
> 
> 
> What I am trying to do is extract the first  chunk.
 
Are you doing this to learn regular expressions or are you actually
trying to do work? Because you're going the wrong way.
It's XML, why do you treat it as text?

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[PHP] Regular Expression Problem

2007-01-24 Thread Richard Luckhurst

Hi List

I must be dumb as I have been battling my way through regular expression
examples for a while and I can not work out why the following does not work
properly. I am the first to admit that regular expressions confuse me greatly.

The string is a piece of XML as follows and I have put that string into a
variable called $xml_string



 
 
   
   
 
 
 
 
   
   
 
 



What I am trying to do is extract the first  chunk.

I am using the following, based on the example at
http://php.net/manual/en/function.preg-match.php example 3

preg_match('##', $xml_string,$matches);
$tempstr = $matches[0];

What I actually get in $tempstr is everything from the first 

I would have expected preg_match to have matched from the first .

I suspect I do not have the regular expression correct. I would great appreciate
any help on sorting out the regular expression so that it only returns the first
chunk of the string.



Regards,
Richard Luckhurst

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Re: [PHP] regular expression help!

2007-01-18 Thread Roman Neuhauser

(Haven't received William's email yet => scavenging Jochem's reply.)

# [EMAIL PROTECTED] / 2007-01-18 18:01:19 +0100:
> William Stokes wrote:
> > "Roman Neuhauser" <[EMAIL PROTECTED]> kirjoitti 
> >> This passes with 5.2:
> >>
> >> class ImgSrcTest extends Tence_TestCase
> >> {
> >>private $src, $str, $xml;
> >>function setUp()
> >>{
> >>$this->src = 'fubar.jpg';
> >>$this->str = sprintf(
> >>'',
> >>$this->src
> >>);
> >>$this->xml = new SimpleXmlElement($this->str);
> >>}
> >>function testReturnsAttributeAsSimpleXMLElements()
> >>{
> >>return $this->assertEquals(
> >>'SimpleXMLElement', 
> >>get_class($this->xml['src'])
> >>);
> >>}
> >>function testCastToStringYieldsTheAttributeValue()
> >>{
> >>return $this->assertEquals($this->src, strval($this->xml['src']));
> >>}
> >> }
> > 
> > Could you specify the functionality of your script a bit please. (How it 
> > works)

It's a unit test showing how you can use SimpleXML to do what you want.
It's written for Testilence out of sheer laziness, but any unit testing
tool would do (after cosmetic changes to the code).

The "test case" contains two pretty obvious tests, just read the
function names, their bodies should be pretty obvious. On thing that
might be a little non-obvious is the strval(): that was the only way I
found to get the string out of the very uncommunicative
SimpleXMLElement.

> > I forgot to mention that this part:
> > 
> > ',
> > 
> > is not always the same. The image properties can vary.

That's one of the reasons I didn't go the regexp route.
Don't treat XML as text, it's not.

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Re: [PHP] regular expression help!

2007-01-18 Thread Jochem Maas

William Stokes wrote:
> Hello Roman,
> 
> Could you specify the functionality of your script a bit please. (How it 
> works)

it's a hint as to how you might use simpleXML to extract the values of a src
attribute from the definition of an img tag.

> 
> I forgot to mention that this part:
> 
> ',
> 
> is not always the same. The image properties can vary.
> 
> Thanks
> -Will
> 
> 
> 
> 
> "Roman Neuhauser" <[EMAIL PROTECTED]> kirjoitti 
> viestissä:[EMAIL PROTECTED]
>> # [EMAIL PROTECTED] / 2007-01-18 12:34:36 +0200:
>>> I need to strip all characters from the following text string exept the
>>> image path...
>>>
>>> ">> src=\"../../images/new/thumps/4123141112007590373240.jpg\" />"...and then
>>> store the path to DB. Image path lengh can vary so I guess that I need to
>>> extract all characters after scr=\"until next\"or 
>>> somethig
>>> similar.
>> This passes with 5.2:
>>
>> class ImgSrcTest extends Tence_TestCase
>> {
>>private $src, $str, $xml;
>>function setUp()
>>{
>>$this->src = 'fubar.jpg';
>>$this->str = sprintf(
>>'',
>>$this->src
>>);
>>$this->xml = new SimpleXmlElement($this->str);
>>}
>>function testReturnsAttributeAsSimpleXMLElements()
>>{
>>return $this->assertEquals('SimpleXMLElement', 
>> get_class($this->xml['src']));
>>}
>>function testCastToStringYieldsTheAttributeValue()
>>{
>>return $this->assertEquals($this->src, strval($this->xml['src']));
>>}
>> }
>>
>> -- 
>> How many Vietnam vets does it take to screw in a light bulb?
>> You don't know, man.  You don't KNOW.
>> Cause you weren't THERE. http://bash.org/?255991 
> 

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Re: [PHP] regular expression help!

2007-01-18 Thread William Stokes

Hello Roman,

Could you specify the functionality of your script a bit please. (How it 
works)

I forgot to mention that this part:

',

is not always the same. The image properties can vary.

Thanks
-Will




"Roman Neuhauser" <[EMAIL PROTECTED]> kirjoitti 
viestissä:[EMAIL PROTECTED]
># [EMAIL PROTECTED] / 2007-01-18 12:34:36 +0200:
>> I need to strip all characters from the following text string exept the
>> image path...
>>
>> "> src=\"../../images/new/thumps/4123141112007590373240.jpg\" />"...and then
>> store the path to DB. Image path lengh can vary so I guess that I need to
>> extract all characters after scr=\"until next\"or 
>> somethig
>> similar.
>
> This passes with 5.2:
>
> class ImgSrcTest extends Tence_TestCase
> {
>private $src, $str, $xml;
>function setUp()
>{
>$this->src = 'fubar.jpg';
>$this->str = sprintf(
>'',
>$this->src
>);
>$this->xml = new SimpleXmlElement($this->str);
>}
>function testReturnsAttributeAsSimpleXMLElements()
>{
>return $this->assertEquals('SimpleXMLElement', 
> get_class($this->xml['src']));
>}
>function testCastToStringYieldsTheAttributeValue()
>{
>return $this->assertEquals($this->src, strval($this->xml['src']));
>}
> }
>
> -- 
> How many Vietnam vets does it take to screw in a light bulb?
> You don't know, man.  You don't KNOW.
> Cause you weren't THERE. http://bash.org/?255991 

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Re: [PHP] regular expression help!

2007-01-18 Thread Roman Neuhauser

# [EMAIL PROTECTED] / 2007-01-18 12:34:36 +0200:
> I need to strip all characters from the following text string exept the 
> image path...
> 
> " src=\"../../images/new/thumps/4123141112007590373240.jpg\" />"...and then 
> store the path to DB. Image path lengh can vary so I guess that I need to 
> extract all characters after scr=\"until next\"or somethig 
> similar.

This passes with 5.2:

class ImgSrcTest extends Tence_TestCase
{
private $src, $str, $xml;
function setUp()
{
$this->src = 'fubar.jpg';
$this->str = sprintf(
'',
$this->src
);
$this->xml = new SimpleXmlElement($this->str);
}
function testReturnsAttributeAsSimpleXMLElements()
{
return $this->assertEquals('SimpleXMLElement', 
get_class($this->xml['src']));
}
function testCastToStringYieldsTheAttributeValue()
{
return $this->assertEquals($this->src, strval($this->xml['src']));
}
}

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[PHP] regular expression help!

2007-01-18 Thread William Stokes

Hello,

Can someone here give me a glue how to do the following. I guess I need to 
use regular expressions here. I have absolutely zero experience with regular 
expressions. (if there's another way to do this I don't mind. I jus need to 
get this done somehow :)

I need to strip all characters from the following text string exept the 
image path...

""...and then 
store the path to DB. Image path lengh can vary so I guess that I need to 
extract all characters after scr=\"until next\"or somethig 
similar.

Thanks for your advise!
-Will

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Re: [PHP] Regular Expression help

2007-01-04 Thread Jochem Maas

Arpad Ray wrote:
> Note that $ allows a trailing newline, but \z doesn't.

I had to test that before believing you:

php -r 
'var_dump(preg_match("#^[a-z]+\$#","abc"),preg_match("#^[a-z]+\$#","abc\n"),preg_match("#^[a-z]+\z#","abc\n"));'

you are right, that could consitute a nice big gotcha in some situations,
although I have the habit of running trim on everything bit of data that
has to be validated/santized (prior to any more specific checks/cleansing)
so I have been protecting my self unwittingly:

php -r 'var_dump("abc\n", trim("abc\n"));'

none the less I think I'll be using \z more often now that I have
been properly introduced to it (including answering any regexp questions
around here!)

thanks Arpad :-)


> 
> Arpad
> 
> Stut wrote:
>> Chris Boget wrote:
>>> >> echo 'Is String: [' . ( is_string( 'a1b2c3' ) && preg_match(
>>> '/[A-Za-z]+/', 'a1b2c3' )) . ']';
>>> echo 'Is Numeric: [' . ( is_numeric( 'a1b2c3' ) && preg_match(
>>> '/[0-9]+/', 'a1b2c3' )) . ']';
>>> echo 'Is String: [' . ( is_string( 'abcdef' ) && preg_match(
>>> '/[A-Za-z]+/', 'abcdef' )) . ']';
>>> echo 'Is Numeric: [' . ( is_numeric( '123456' ) && preg_match(
>>> '/[0-9]+/', '123456' )) . ']';
>>> ?>
>>>
>>> Why is the first "Is String" check returning true/showing 1? 
>>> preg_match should fail because 'a1b2c3' contains numbers and, as
>>> such, doesn't match the pattern...
>>
>> It does match the pattern. The expression says "1 or more A-Za-z in
>> sequence". If you want to check against the whole string you need to
>> add the start and end markers...
>>
>> preg_match( '/^[A-Za-z]+$/', 'a1b2c3' ))
>>
>> Look at the manual page for preg_match and read up on the third
>> parameter. Use it to see what is matching the expression.
>>
>> -Stut
>>
> 

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Re: [PHP] Regular Expression help

2007-01-04 Thread Arpad Ray


Note that $ allows a trailing newline, but \z doesn't.

Arpad

Stut wrote:

Chris Boget wrote:

echo 'Is String: [' . ( is_string( 'a1b2c3' ) && preg_match( 
'/[A-Za-z]+/', 'a1b2c3' )) . ']';
echo 'Is Numeric: [' . ( is_numeric( 'a1b2c3' ) && preg_match( 
'/[0-9]+/', 'a1b2c3' )) . ']';
echo 'Is String: [' . ( is_string( 'abcdef' ) && preg_match( 
'/[A-Za-z]+/', 'abcdef' )) . ']';
echo 'Is Numeric: [' . ( is_numeric( '123456' ) && preg_match( 
'/[0-9]+/', '123456' )) . ']';

?>

Why is the first "Is String" check returning true/showing 1?  
preg_match should fail because 'a1b2c3' contains numbers and, as 
such, doesn't match the pattern...


It does match the pattern. The expression says "1 or more A-Za-z in 
sequence". If you want to check against the whole string you need to 
add the start and end markers...


preg_match( '/^[A-Za-z]+$/', 'a1b2c3' ))

Look at the manual page for preg_match and read up on the third 
parameter. Use it to see what is matching the expression.


-Stut



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Re: [PHP] Regular Expression help

2007-01-04 Thread Stut


Chris Boget wrote:

echo 'Is String: [' . ( is_string( 'a1b2c3' ) && preg_match( 
'/[A-Za-z]+/', 'a1b2c3' )) . ']';
echo 'Is Numeric: [' . ( is_numeric( 'a1b2c3' ) && preg_match( 
'/[0-9]+/', 'a1b2c3' )) . ']';
echo 'Is String: [' . ( is_string( 'abcdef' ) && preg_match( 
'/[A-Za-z]+/', 'abcdef' )) . ']';
echo 'Is Numeric: [' . ( is_numeric( '123456' ) && preg_match( 
'/[0-9]+/', '123456' )) . ']';

?>

Why is the first "Is String" check returning true/showing 1?  
preg_match should fail because 'a1b2c3' contains numbers and, as such, 
doesn't match the pattern...


It does match the pattern. The expression says "1 or more A-Za-z in 
sequence". If you want to check against the whole string you need to add 
the start and end markers...


preg_match( '/^[A-Za-z]+$/', 'a1b2c3' ))

Look at the manual page for preg_match and read up on the third 
parameter. Use it to see what is matching the expression.


-Stut

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