Jason,
I'm getting everything back from the php script just fine but I can not get
it into the select at all... I posted a new thread just a bit ago...
what I find is that if I use an onclick event to call my addOption function
with static data it works fine but if I call my function with static data
using the onSuccess of Ajax.updater the only thing that happens is the
select gets zero'd!
Phil
On Tue, Jun 7, 2011 at 4:13 PM, Jason jwestbr...@gmail.com wrote:
Also make sure you exit; after the print json_ecode() so there is not
additional output that will corrupt your JSON string
Jason
On Jun 6, 6:15 am, Eric lefauv...@gmail.com wrote:
Hello,
This is a little out of topic, but here are few hints:
The easiest way to do that is to build a PHP array, and to use
JSON_Encode to convert it into a JSON encoded string;
You also need to change the content-type of your response to let
prototype know it is actually JSON.
Simple example:
?php
$myCities = Array(Paris,Madrid,New-York,London);
header('Content-Type: application/json');
print json_encode($myCities);
?
Eric
On Jun 4, 11:15 am, Johan Arensman johanm...@gmail.com wrote:
You can use basic Json, but this is basic javascript, not specific for
prototype
{
cars: [
{
make: 'some make name',
models: [
{ name: 'model 1' },
{ name: 'model 2' }
]
},
{
make: 'some other make name',
models: [
{ name: 'model 3' },
{ name: 'model 4' }
]
},
]
}
Something like this?
Greets,
Johan
On Fri, Jun 3, 2011 at 9:31 PM, Phil Petree phil.pet...@gmail.com
wrote:
Hey All!
I'm biting the bullet and trying to break away from XML and go to
json.
I using Ajax.Updater to call cities.php which looks up the available
cities
for a given zip code (yes there can be more than one city - my zip
has 4
possibilities!) and return those in a select
How do these need to be returned/formatted in php?
Can anyone point me to one of the car/make/model examples? I can't
find
one for prototype...
Thanks,
Pete
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