Re: Format Code Repeat Counts?
MRAB wrote:
Scott David Daniels wrote:
MRAB wrote:
The shortest I can come up with is:
"[" + "][".join(letters) + "]"
Maybe a golf shot:
"][".join(letters).join("[]")
Even shorter:
"["+"][".join(letters)+"]"
:-)
I was going by PEP8 rules. ;-)
--Scott David Daniels
Scott David dani...@acm.org
--
http://mail.python.org/mailman/listinfo/python-list
Re: Format Code Repeat Counts?
Scott David Daniels wrote:
MRAB wrote:
The shortest I can come up with is:
"[" + "][".join(letters) + "]"
Maybe a golf shot:
"][".join(letters).join("[]")
Even shorter:
"["+"][".join(letters)+"]"
:-)
--
http://mail.python.org/mailman/listinfo/python-list
Re: Format Code Repeat Counts?
Thanks all! That was most helpful and informative. Best, Josiah -- http://mail.python.org/mailman/listinfo/python-list
Re: Format Code Repeat Counts?
MRAB wrote:
The shortest I can come up with is:
"[" + "][".join(letters) + "]"
Maybe a golf shot:
"][".join(letters).join("[]")
--Scott David Daniels
scott.dani...@acm.org
--
http://mail.python.org/mailman/listinfo/python-list
Re: Format Code Repeat Counts?
En Wed, 12 Aug 2009 19:23:32 -0300, Chris Rebert
escribió:
On Wed, Aug 12, 2009 at 4:34 PM, jschwab wrote:
As a more concrete example, say I have several sets of letters in a
list of strings
letters = ["aeiou", "hnopty", "egs", "amsp"]
and I wanted to build a regular expression string out of them like
re_str <==> "[aeiou][hnopty][egs][amsp]"
Right now, the best I've got that doesn't require an explicit string
like "[{1}][{2}][{3}][{4}]" is
re_str = "".join(map(lambda x: "[{0}]".format(x), letters))
Is there a better way?
Slightly better, by using a generator expression instead of map() and
lambda:
re_str = "".join("[{0}]".format(x) for x in letters)
Though obviously MRAB's is shorter (and a good show of lateral thinking).
Another way, using {} auto-numbering (requires Python 3.1 or the future
2.7)
p3> letters = ["aeiou", "hnopty", "egs", "amsp"]
p3> ("[{}]"*len(letters)).format(*letters)
'[aeiou][hnopty][egs][amsp]'
--
Gabriel Genellina
--
http://mail.python.org/mailman/listinfo/python-list
Re: Format Code Repeat Counts?
On 8/12/2009 1:34 PM jschwab said...
Are repeat counts supported Python's str.format() in some fashion?
In Fortran my format strings can have repeat counts.
write(*, fmt="3F8.3") [1, 2, 3]
1.000 2.000 3.000
I don't think printf-style format codes, which is what'd I'd
previously used in Python, allow for repeat counts.
As a more concrete example, say I have several sets of letters in a
list of strings
letters = ["aeiou", "hnopty", "egs", "amsp"]
and I wanted to build a regular expression string out of them like
re_str <==> "[aeiou][hnopty][egs][amsp]"
Right now, the best I've got that doesn't require an explicit string
like "[{1}][{2}][{3}][{4}]" is
re_str = "".join(map(lambda x: "[{0}]".format(x), letters))
Is there a better way?
I don't know. I often end up at something like:
"[%s]"*len(letters) % tuple(letters)
Emile
--
http://mail.python.org/mailman/listinfo/python-list
Re: Format Code Repeat Counts?
Chris Rebert wrote:
On Wed, Aug 12, 2009 at 4:34 PM, jschwab wrote:
As a more concrete example, say I have several sets of letters in a
list of strings
letters = ["aeiou", "hnopty", "egs", "amsp"]
and I wanted to build a regular expression string out of them like
re_str <==> "[aeiou][hnopty][egs][amsp]"
Right now, the best I've got that doesn't require an explicit string
like "[{1}][{2}][{3}][{4}]" is
re_str = "".join(map(lambda x: "[{0}]".format(x), letters))
Is there a better way?
Slightly better, by using a generator expression instead of map() and lambda:
re_str = "".join("[{0}]".format(x) for x in letters)
Though obviously MRAB's is shorter (and a good show of lateral thinking).
Python 3.1 supports auto-numbered placeholders "[{}]", so:
re_str = ("[{}]" * len(letters)).format(*letters)
--
http://mail.python.org/mailman/listinfo/python-list
Re: Format Code Repeat Counts?
On Wed, Aug 12, 2009 at 4:34 PM, jschwab wrote:
> As a more concrete example, say I have several sets of letters in a
> list of strings
> letters = ["aeiou", "hnopty", "egs", "amsp"]
> and I wanted to build a regular expression string out of them like
> re_str <==> "[aeiou][hnopty][egs][amsp]"
> Right now, the best I've got that doesn't require an explicit string
> like "[{1}][{2}][{3}][{4}]" is
> re_str = "".join(map(lambda x: "[{0}]".format(x), letters))
>
> Is there a better way?
Slightly better, by using a generator expression instead of map() and lambda:
re_str = "".join("[{0}]".format(x) for x in letters)
Though obviously MRAB's is shorter (and a good show of lateral thinking).
Cheers,
Chris
--
http://blog.rebertia.com
--
http://mail.python.org/mailman/listinfo/python-list
Re: Format Code Repeat Counts?
jschwab wrote:
Are repeat counts supported Python's str.format() in some fashion?
In Fortran my format strings can have repeat counts.
write(*, fmt="3F8.3") [1, 2, 3]
1.000 2.000 3.000
I don't think printf-style format codes, which is what'd I'd
previously used in Python, allow for repeat counts.
As a more concrete example, say I have several sets of letters in a
list of strings
letters = ["aeiou", "hnopty", "egs", "amsp"]
and I wanted to build a regular expression string out of them like
re_str <==> "[aeiou][hnopty][egs][amsp]"
Right now, the best I've got that doesn't require an explicit string
like "[{1}][{2}][{3}][{4}]" is
re_str = "".join(map(lambda x: "[{0}]".format(x), letters))
Is there a better way?
The shortest I can come up with is:
"[" + "][".join(letters) + "]"
--
http://mail.python.org/mailman/listinfo/python-list
