Re: [xwiki-users] xwql join query
It doesn't have to be an xwql query. It could be sql, hql, anything that would work ;) -- View this message in context: http://xwiki.475771.n2.nabble.com/xwql-join-query-tp5762763p5763606.html Sent from the XWiki- Users mailing list archive at Nabble.com. ___ users mailing list users@xwiki.org http://lists.xwiki.org/mailman/listinfo/users
Re: [xwiki-users] xwql join query
I tried the query and it doesn't work. It seems that "member of" causes the query to fail to execute. Unfortunately I cannot use "Database tree" as the data type for "Supplier" property of Fruit. -- View this message in context: http://xwiki.475771.n2.nabble.com/xwql-join-query-tp5762763p5763517.html Sent from the XWiki- Users mailing list archive at Nabble.com. ___ users mailing list users@xwiki.org http://lists.xwiki.org/mailman/listinfo/users
Re: [xwiki-users] xwql join query
On 11/22/2010 04:27 PM, afrey wrote: > > I tried the following query but I didn't get anything :( > #set($fruits = $services.query.xwql("from doc.object(Fruit.FruitClass) as > fru, doc.object(Supplier.SupplierClass) as sup where > fru.Supplier.Name=sup.Name and sup.City='Melbourne'").execute()) On http://platform.xwiki.org/xwiki/bin/view/DevGuide/QueryGuide#HQueryLanguageExamples there is a query described as "Search blogs per category". Blog category is a database tree but "member of" might work with database lists also. Can you try: #set($fruits = $services.query.xwql("from doc.object(Fruit.FruitClass) as fru, doc.object(Supplier.SupplierClass) as sup where sup member of fru.Supplier and sup.City='Melbourne'").execute()) Hope this helps, Marius ___ users mailing list users@xwiki.org http://lists.xwiki.org/mailman/listinfo/users
Re: [xwiki-users] xwql join query
Yes, sorry I forgot to mention. Supplier property is a Database List (it allows to select one Supplier from all of the Supplier objects created). Therefore I cannot have it set as string. It needs to be a selection from Supplier objects. Please check the previous post to see the join query that I tried. Alina. -- View this message in context: http://xwiki.475771.n2.nabble.com/xwql-join-query-tp5762763p5763031.html Sent from the XWiki- Users mailing list archive at Nabble.com. ___ users mailing list users@xwiki.org http://lists.xwiki.org/mailman/listinfo/users
Re: [xwiki-users] xwql join query
Hi Alina, On 11/22/2010 04:12 PM, afrey wrote: > > Hi all, > > I'm struggling creating a xwql query that joins two tables. > > Let's say I have two classes: Fruit and Supplier. > Fruit has the following properties: Name, Supplier. What's the type of the "Supplier" property? Is it a database list? Have you tried using a string property instead (e.g. supplier name) and a join condition like fruit.Supplier = supplier.Name ? Hope this helps, Marius > Supplier has the following properties: Name, City. > > I need the query that returns: > All Fruit that has Supplier with City='Melbourne'. > > I can get all the Fruit objects: > #set($fruits = $services.query.xwql("from doc.object(Fruit.FruitClass) as > fru").execute()) > > And separately I can get all the Supplier objects that have city='Melbourne' > #set($suppliers = $services.query.xwql("where > doc.object(Supplier.SupplierClass).City='Melbourne'").execute()) > > But I can't combine them. Please advise. > > Alina. ___ users mailing list users@xwiki.org http://lists.xwiki.org/mailman/listinfo/users
Re: [xwiki-users] xwql join query
I tried the following query but I didn't get anything :( #set($fruits = $services.query.xwql("from doc.object(Fruit.FruitClass) as fru, doc.object(Supplier.SupplierClass) as sup where fru.Supplier.Name=sup.Name and sup.City='Melbourne'").execute()) -- View this message in context: http://xwiki.475771.n2.nabble.com/xwql-join-query-tp5762763p5762809.html Sent from the XWiki- Users mailing list archive at Nabble.com. ___ users mailing list users@xwiki.org http://lists.xwiki.org/mailman/listinfo/users