(resent because of mail issues on my end)
On Mon, 22 Oct 2018, Thomas Schwinge wrote:
I had a quick look at the difference, and a[j][i] remains in this form
throughout optimization. If I write instead *((*(a+j))+i) = 0; I get
j_10 = tmp_17 / 1025;
i_11 = tmp_17 % 1025;
_1 = (long unsi
On Mon, Oct 22, 2018 at 6:35 PM Thomas Schwinge wrote:
>
> Hi!
>
> Thanks for all your comments already! I continued looked into this for a
> bit (but then got interrupted by a higher-priority task). Regarding this
> one specifically:
>
> On Fri, 12 Oct 2018 21:14:11 +0200, Marc Glisse wrote:
>
Hi!
Thanks for all your comments already! I continued looked into this for a
bit (but then got interrupted by a higher-priority task). Regarding this
one specifically:
On Fri, 12 Oct 2018 21:14:11 +0200, Marc Glisse wrote:
> On Fri, 12 Oct 2018, Thomas Schwinge wrote:
>
> > Hmm, and without a