Fair enough.
# New Ticket Created by mt1957
# Please include the string: [perl #131242]
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With Rakudo version 2017.04.3-66-g7648793 built on MoarVM version
2017.04-44-gf0db882
implemen
On Tue, 02 May 2017 03:30:44 -0700, mt1...@gmail.com wrote:
> With Rakudo version 2017.04.3-66-g7648793 built on MoarVM version
> 2017.04-44-gf0db882
> implementing Perl 6.c. on a system (uname -a) Linux h03-fedora
> 4.10.11-100.fc24.x86_64 #1 SMP Tue Apr 18 17:25:04 UTC 2017 x86_64
> x86_64 x86
On Tue, 02 May 2017 03:30:44 -0700, mt1...@gmail.com wrote:
> With Rakudo version 2017.04.3-66-g7648793 built on MoarVM version
> 2017.04-44-gf0db882
> implementing Perl 6.c. on a system (uname -a) Linux h03-fedora
> 4.10.11-100.fc24.x86_64 #1 SMP Tue Apr 18 17:25:04 UTC 2017 x86_64
> x86_64 x86
Thanks very much
Marcel
Thanks very much
Marcel
Using the caller() in Perl 5 one can figure out if the file was loaded
as a module or executed as a script.
In Python one could check if __name__ is equal to "__main__".
Is there some way in Perl 6 to tell if a file was executed directly or
loaded into memory as a module?
regards
Gabor
# New Ticket Created by Zoffix Znet
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Both of these forms produce the error below
my %stuff = ;
say 'foo bar meows' ~~
On Tue, May 02, 2017 at 05:02:40PM +0200, Gabor Szabo wrote:
: Using the caller() in Perl 5 one can figure out if the file was loaded
: as a module or executed as a script.
:
: In Python one could check if __name__ is equal to "__main__".
:
: Is there some way in Perl 6 to tell if a file was exec
On Tue, 2 May 2017 17:02:40 +0200
Gabor Szabo wrote:
> Is there some way in Perl 6 to tell if a file was executed directly or
> loaded into memory as a module?
One way that seems to work: define a ``sub MAIN``; it will be invoked
when you execute the file as a program, but won't be touched if you
# New Ticket Created by Zoffix Znet
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https://irclog.perlgeek.de/perl6-dev/2017-05-02#i_14519628
* TimToady notes that .pe
# New Ticket Created by Aleks-Daniel Jakimenko-Aleksejev
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Code:
say "abc" ~~ /)> . <(/
Result (2015.12 … 2017.03):
#
Result
Hi All,
Why does this work
$ perl6 -e 'my $x="abcdef"; if $x.contains( "abc" ) { say "yes" } else {
say "no" };'
yes
And this does not?
$ perl6 -e 'my $x="abcdef"; if $x.contains( 'abc' ) { say "yes" } else {
say "no" };'
===SORRY!=== Error while compiling -e
Undeclared routine:
abc u
Careful :-)
You're actually closing the single quote youstarted with perl6 -e. In
other words, this is your Shell's doing.
You can execute this as a script with single quote around string literals
with no issues
Streetcars
On May 3, 2017 10:27, "ToddAndMargo" wrote:
> Hi All,
>
> Why does th
On 05/02/2017 10:02 PM, Shrivats wrote:
Careful :-)
You're actually closing the single quote youstarted with perl6 -e. In
other words, this is your Shell's doing.
You can execute this as a script with single quote around string
literals with no issues
Streetcars
Mumble. And I did know that
On 05/02/2017 10:02 PM, Shrivats wrote:
Careful :-)
You're actually closing the single quote youstarted with perl6 -e. In
other words, this is your Shell's doing.
You can execute this as a script with single quote around string
literals with no issues
Streetcars
Mumble. I did know that.
T
On 05/01/2017 08:29 AM, Steve Mynott wrote:
A useful and usable production distribution of Perl 6
I posted the following RFE:
Would you please compile RPM's up for 2017.04:
https://github.com/nxadm/rakudo-pkg/issues/11
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