>array(
>'a' => 'one',
>'b' => 'one',
>'c' => 'zero',
>'d' => 'two'
>);
>
>through this and am having a hind time with then logic... Could you
>explain how the output would be array('c' => 'zero', 'd' => 'two')??
I was being pretty sloppy with the code (should've posted pseudocode to
begin with,
> -Original Message-
> From: Mike Migurski [mailto:[EMAIL PROTECTED]
> Sent: Thursday, October 30, 2003 1:37 PM
> To: Allowee
> Cc: [EMAIL PROTECTED]
> Subject: Re: [PHP] removing all duplicate values from an array
>
> >>I'm looking for a fu
On Thursday 30 October 2003 20:37, Mike Migurski wrote:
> >>I'm looking for a function that does almost the same as array_unique()
> >>
> >>But it must also delete the other duplicate entry.
> >
> >
> >
> >Untested pseudo-PHP follows -
> >
> > $encountered_elements = array();
> > foreach($o
>>I'm looking for a function that does almost the same as array_unique()
>>
>>But it must also delete the other duplicate entry.
>
>
>Untested pseudo-PHP follows -
>
> $encountered_elements = array();
> foreach($original_array as $key => $val)
> if(in_array($val, $encounte
Or... you could use array_count_values() and loop through the array it
produces to find out how many of each duplicate value exists in the
original array.
http://www.php.net/manual/en/function.array-count-values.php
Kevin
-Original Message-
From: Allowee [mailto:[EMAIL PROTECTED]
Sent:
>I'm looking for a function that does almost the same as array_unique()
>
>But it must also delete the other duplicate entry.
Untested pseudo-PHP follows -
$encountered_elements = array();
foreach($original_array as $key => $val)
if(in_array($val, $encountered_ele
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