Nobody? :-(
emkayenne wrote:
>
> Hello, I'm pretty new to R and I am having a hrd time getting a grip. Just
> a question: can someone tell me how to have more than one graphics windown
> open at the same time? I want to look at some plote at the same time...,
> how is this done? If someone has a
hello ,every one ,
I draw a figure as shown in appendix A,
The tick characters in the Y-axis is arranged in the vertical
direction.Now I want to arranged the Y-axis tick in the horizontal
direction.
How could I do ,then?
Thank you .
--
TANG Jie
Email: totang...@gmail.com
Tel: 0086-2154896104
Hi,
I have 2 date vectors d1 and d2.
d1 <- structure(c(14526, 14495, 14464, 14433, 14402, 14371, 14340, 14309,
14278, 14247, 14216, 14185), class = "Date")
d2 <- structure(c(14526, 14509, 14488, 14466, 14453, 14441, 14396, 14388,
14343, 14333, 14310, 14281), class = "Date")
I would like to cre
On a similar note, I'm trying to plot continuous values on the y vs.
categorical (dates) on the x and I want to color by date, but I want the
colors to be random so points close to each other are easily
distinguishable. Any thoughts?
Thanks,
Jon
per freem-2 wrote:
>
> hi all,
>
> suppose I ha
Dear all,
I seem to have many problems as I run R on my ubuntu system.
want to set a mirror so that anytime I use the command "install.packages",
it does not ask me for which mirror to use but go direct.
This is because of the error I keep on getting below and I dont know how to
solve it.
Please
> library(rJava)
Error in library(rJava) : there is no package called 'rJava'
> install.packages("rJava")
Warning in install.packages("rJava") :
argument 'lib' is missing: using '/usr/local/lib/R/site-library'
--- Please select a CRAN mirror for use in this session ---
Loading Tcl/Tk interface ..
Hello, I'm pretty new to R and I am having a hrd time getting a grip. Just a
question: can someone tell me how to have more than one graphics windown
open at the same time? I want to look at some plote at the same time..., how
is this done? If someone has a suggestion for a (good) introductory gui
Hello All,
Is anyone aware of an R package for Bayesian Belief Networks (BBN) that
can handle latent (hidden) nodes? I am referring to process learning
the structure and the parameters of the model. Based on the
documentation, the "bnlearn" package does not provide for such
capability. In ad
Dear Matthieu or other friends,
I want to select two unknown thresholds with the following function:
grid<- selectSETAR(x1, m=1, thDelay=0, criterion=C("AIC","SSR"),
nthresh=2)
print(grid)
plot(grid)
where x1 is a price time series.
However, it always shows the following error.
Er
Hello
I am a new user of R software. I benefit from using vrtest-package. However,
the codes provided by the aforementioned package, for example, calculate the
test statistics for Lo and Mackinlay (1988) under the assumptions of
homoscedasticity and heteroscedasticity without computing the value
Hi,
Does anybody know a good package/function for performing nonlinear/kernel
canonical correlation analysis in R? I tried the kcca() function in
'kernlab' package, but it requires both datasets to contain equal number of
variables, which isn't the case with my datasets. I'm therefore looking for
*Hello,
I have had this serious problem while trying to install package rJava. It is
a requirement by the package JGR and it cannot be downloaded due to the
error indicated below.
I have googled and looked at the FAQ but no solution yet.
Please advise.
Kind regards,
Lazarus
> install.packages("r
I extracted the data for hours of a day and created some graphs here:
http://yihui.name/en/2009/10/5-revisions-committed-to-r/
Certainly our R core gods are so very hard-working and devoted that
some even commit revisions to R at 3am in the morning!
Regards,
Yihui
--
Yihui Xie
Phone: 515-294
On Fri, 9 Oct 2009, Duncan Murdoch wrote:
On 09/10/2009 5:05 PM, johannes rara wrote:
Hi,
file.info is producing data.frame with ctime variable. Help file says
that on Unix this is 'last status change' and on Windows 'creation
time'.
No, that is not what it says. It actually says
What
It appears several that of my scripts are beginning to reaching maturity, so I
am curious if it is possible to add an external GUI to run the scripts from
this simplified GUI interface.
The scripts are fairly rudimentary so the GUI only needs a few radial buttons
and a could of numeric fields
No, actually it does better to not suppress all output, because it tells you
where the trouble comes from by just showing the NA for the slope. The
intercept the regression gives you is the mean of y in this case. As for the
slope, Ted's graphic is illustrative as to why no slope can be estimated.
On 10/09/2009 11:36 PM, sahil seth wrote:
Hello R users,
I am writing a summary() for a custom class, and am to display the integers
right justified,
Say where x is the vector with integers, I am using the following:
cat("\t",format(x),"\t"...other columns)
this way I am trying to pass the forma
library(lattice)
barchart(Titanic, scales = list(x = "free"),
auto.key = list(title = "Survived"))
Or if you prefer vertical:
barchart(Titanic, scales = list(x = "free"),
auto.key = list(title = "Survived"), horizontal=FALSE)
There are adjustments available to the space betwe
-- Forwarded message --
From: Khanh Nguyen
Date: Fri, Oct 9, 2009 at 10:10 PM
Subject: Re: [R] Creating a Clustered-Stacked Column Chart
To: zhijie zhang
May be you can try to look into ggplot2
http://had.co.nz/ggplot2/position_fill.html
-k
On Fri, Oct 9, 2009 at 9:57 PM, zh
Thanks a lot. Maybe someone else has the method to solve that.
2009/10/9 John Kane
> I don't think I've seen an R version, probably because the technique is not
> very good for displaying data.
>
> Have a look at http://chartsgraphs.wordpress.com/tag/r-and-excel/ for an
> alternative method of
tim.colors() in library fields
On Fri, Oct 9, 2009 at 2:51 PM, Tim Clark wrote:
> Dear List,
>
> Is there a color palette avaliable similar to what is used in satellite ocean
> color imagery? I.e. a gradient with blue on one end and red on the other,
> with yellow in the middle? I have tried
Just so we complete (partially) the web-record...
Some further hunting determined that the &apos was an apostrophe -
obvious only in retrospect! Removal of this character has resolved the
Entity errors, but not the xmlParseStartTag: invalid element name errors.
I had assumed that the two
On Oct 9, 2009, at 6:36 PM, Sharon Beckett wrote:
I'm just learning R (I don't know any other programming languages),
and I have a question. I am trying to figure out how to ask for user
input (say, a set of 3 numbers) then put those numbers into an
array.
I've looked around, but I have
Dear R Helpers,
I have a pretty large dataframe (150,000 variables, 10,000 entries for
each) and have to run a regression on each of the variables. Recorded are
the pvals.
I wrote a function and use sapply. The function looks something like this:
calcpval<-function(x){
modela <- lm(appl
I'm just learning R (I don't know any other programming languages),
and I have a question. I am trying to figure out how to ask for user
input (say, a set of 3 numbers) then put those numbers into an array.
I've looked around, but I haven't been able to find any answers that I
understa
On 09/10/2009 5:05 PM, johannes rara wrote:
Hi,
file.info is producing data.frame with ctime variable. Help file says
that on Unix this is 'last status change' and on Windows 'creation
time'. Is there a way to get 'last status change' on Windows using
some R function?
What does "last status ch
Hi Carol,
It isn't at all clear exactly what you are trying to do, but you might want to
read the help for either points() and lines() [to put more than one data pair
on a single plot], or for par, specifically mfrow and mfcol, or for layout [to
put more than one plot on a single device window].
Fair point.
Thanks.
-Original Message-
From: David Winsemius [mailto:dwinsem...@comcast.net]
Sent: Friday, October 09, 2009 5:02 PM
To: Brecknock, Peter
Cc: Daniel Malter; r-help@r-project.org
Subject: Re: [R] lm output
On Oct 9, 2009, at 5:45 PM, Brecknock, Peter wrote:
> Daniel
>
>
On Oct 9, 2009, at 5:45 PM, Brecknock, Peter wrote:
Daniel
Thanks very much for the reply.
If the data fails the underlying assumptions of regression wouldn't
it make sense to suppress all the output and not just the slope
coefficient?
Incidently, if I run this simple example in Excel i
?lines
?points
Something like :
x <- 1:10
y1 <- rnorm(10, 4, 3)
y2 <- rnorm(5,5,2)
ymax <- max(c(y1,y2))
ymin <- min(c(y1,y2))
plot(x, y1, col='red',ylim = c(ymin,ymax))
lines(y2, col='green')
--- On Fri, 10/9/09, carol white wrote:
> From: carol white
> Subject: [R] plot the same types
On 09-Oct-09 21:45:04, Brecknock, Peter wrote:
> Daniel
> Thanks very much for the reply.
>
> If the data fails the underlying assumptions of regression wouldn't it
> make sense to suppress all the output and not just the slope
> coefficient?
>
> Incidently, if I run this simple example in Excel
Daniel
Thanks very much for the reply.
If the data fails the underlying assumptions of regression wouldn't it make
sense to suppress all the output and not just the slope coefficient?
Incidently, if I run this simple example in Excel it returns the slope as 0.
Intuitively, this makes sense to
On 09-Oct-09 21:12:18, Brecknock, Peter wrote:
> Hi All
> I am running a linear regression using the lm object.
>
> In the event that my independent variable is the same across all
> observations the regression slope is returned as an NA.
>
> For example, if I have the following
>
> y=c(10,12,1
That comes out as an NA because X'X is not invertible because it is not full
rank (one row/column is a linear combination of the other(s)). And that
means there is no unique solution to the system.
y=c(10,12,17)
x=c(5,5,5)
X=cbind(1,x)
X
t(X)%*%X
solve(t(X)%*%X)
Therefore, nope, there is now way
Hi All
I am running a linear regression using the lm object.
In the event that my independent variable is the same across all
observations the regression slope is returned as an NA.
For example, if I have the following
y=c(10,12,17)
x=c(5,5,5)
lm = lm(y~x)
produces the following
Coefficient
Hi,
How to plot the same types of graphics on the same R graphic device? Suppose
that we want to plot a vector y against x (using plot for instance). How is it
possible to plot y against x for different values of these two vectors on the
same device so that the plots could be compared?
Cheers,
Hi,
file.info is producing data.frame with ctime variable. Help file says
that on Unix this is 'last status change' and on Windows 'creation
time'. Is there a way to get 'last status change' on Windows using
some R function?
Thanks,
Johannes
__
R-help@
> Date: Fri, 09 Oct 2009 18:18:05 +0200
> From: Tomas Lanczos
> Sender: r-help-boun...@r-project.org
> Precedence: list
>
> Hello,
>
> I need to put 2 or more different time series to one plot for comparison
> each other. The problem is that the time series are irregular, moreover
> the time le
Hi
You may find that you need to use the compilation tools. I gave up on
using R from Mandriva repositories as the R base is usually out of
date and the selection of packages available depends on the interests
of those who produced them. If I knew how rpm spec files worked I
might do something abo
Chicagoland R Users:
We are pleased to announce a Fall meetup for Chicagoland R users. This
is open to anyone with an interest in R: practioners, researchers,
casual users and other interested parties.
WHEN: October 29, 2009 @5:30
WHERE: Jak's Tap www.jakstap.com
A short series of so-called ligh
I am attempting to graph 12 months of temperatures, delineate the months with a
vline and place the names of the months at the top of the graph.
So far I have gotten everything to work except the names, despite getting a
similar graph to work yesterday the day before yesterday with Baptise A's h
Thanks! The colorRampPalette() did just what I need.
Tim
Tim Clark
Department of Zoology
University of Hawaii
--- On Fri, 10/9/09, Barry Rowlingson wrote:
> From: Barry Rowlingson
> Subject: Re: [R] Satellite ocean color palette?
> To: "Tim Clark"
> Cc: r-help@r-project.org
> Date: Frida
Dear list,
I would like to start some R workshops at King's College London, and
to do so, I would like to use the "Use R!" logo at
http://www.agrocampus-ouest.fr/math/useR-2009//useR%21%202008_fichiers/useR-middle.png
Since it seems to be difficult to get a shell account at KCL, I also went
ahead
On Fri, 2009-10-09 at 11:51 -0700, Tim Clark wrote:
> Dear List,
>
> Is there a color palette avaliable similar to what is used in satellite ocean
> color imagery? I.e. a gradient with blue on one end and red on the other,
> with yellow in the middle? I have tried topo.colors(n) but that comes
On Fri, Oct 9, 2009 at 7:51 PM, Tim Clark wrote:
> Dear List,
>
> Is there a color palette avaliable similar to what is used in satellite ocean
> color imagery? I.e. a gradient with blue on one end and red on the other,
> with yellow in the middle? I have tried topo.colors(n) but that comes ou
See ?colorRampPallete
On Fri, Oct 9, 2009 at 3:51 PM, Tim Clark wrote:
> Dear List,
>
> Is there a color palette avaliable similar to what is used in satellite ocean
> color imagery? I.e. a gradient with blue on one end and red on the other,
> with yellow in the middle? I have tried topo.col
Dear List,
Is there a color palette avaliable similar to what is used in satellite ocean
color imagery? I.e. a gradient with blue on one end and red on the other, with
yellow in the middle? I have tried topo.colors(n) but that comes out more
yellow on the end. I am looking for something simi
Uwe Ligges wrote:
Uwe Ligges wrote:
Kim Vanselow wrote:
Dear R-Users and Developers,
I want to calculate something like k-means clustering, but with
ordinal data (Braun-Blanquet) to combine this classification
technique with a NMDS-Ordination.
I found an algorithm especially developed f
Thanks to Dirk for pointing it out in my blog : "thomas" and "tlumley"
are the same person. Also "martyn" and "plummer", and "paul" and
"murrell" ... updated number of commits per author below
> sort( table( simple$author ), decreasing=T )
ripleymaechler hornik pd mu
On Oct 9, 2009, at 6:42 AM, Zhen Lin wrote:
I tried this:
(c is the column vector with indices of those rows I want to replace)
table[c,]<-replace(table[c,],c,newRows)
but it does not work and the error is:
new columns would leave holes after existing columns
replace() is supposed to work
Content-Type: text/plain; charset="iso-8859-1"
Content-Transfer-Encoding: quoted-printable
MIME-Version: 1.0
Thanks Mark=2C the reg.line trick seemed to work really well.
David - hopefully the hex-text will have gone now - if not=2C please accept=
my apologies as=2C this is=2C as far as I kn
plot.zoo and xyplot.zoo in the zoo package can both do that:
library(zoo)
z <- zoo(c(21, 34, 33, 41, 39, 38, 37, 28, 33, 40),
as.Date(c("1992-01-10", "1992-01-17", "1992-01-24", "1992-01-31",
"1992-02-07", "1992-02-14", "1992-02-21", "1992-02-28", "1992-03-06",
"1992-03-13")))
#
On Oct 9, 2009, at 12:41 PM, Ashta wrote:
Hi all,
Thank you for your help. Now I am able to select every 5th row of
the data
from the main data set (x)
using
sub1<- x[seq(1, nrow(x), by=5), ]
So sub1 contains one fith of the data set X. I want also create
another
data set that will c
You are emitting weird hex-stuff from your mail client. And from what
I can tell that is not a reproducible example even if hex-ation
problem gets fixed. There is a worked example in segments.
On Oct 9, 2009, at 10:45 AM, Steve Murray wrote:
Content-Type: text/plain; charset="iso-8859-1"
sub3 <- x[-seq(1, nrow(x), by=5), ]
Notice the '-' in front of the seq() command. This will select
everything but what is in the sequence.
From: Ashta [mailto:sewa...@gmail.com]
Sent: Friday, October 09, 2009 12:42 PM
To: Nutter, Benjamin
Cc: r-help@r-proje
It probably means that your data is not in the right format. PLEASE do
read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
If you show the data, it might help. It sounds like something is
empty, but it is hard to te
Thanks David,
for answering this question.
> On Oct 8, 2009, at 4:33 AM, msig...@yahoo.com wrote:
>
>> Dear all
>> when I try to install "distr", the following error appears, I am using
>> R in windows. can u suggest me?
>>
>
> I'm not a Windows user, but the obvious questions would be "How?".
Hi all,
Thank you for your help. Now I am able to select every 5th row of the data
from the main data set (x)
using
sub1<- x[seq(1, nrow(x), by=5), ]
So sub1 contains one fith of the data set X. I want also create another
data set that will contain the remaining data set from X (ie., four f
Google is your friend! (search on "Tukey median line fit"); e.g.
http://www.amstat.org/publications/jse/v14n2/morrell.html
Bert Gunter
Genentech Noclinical Statistics
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of shanmukha patel
Hi,
I have a strange behavior of plot function when trying to plot a
discriminant analysis obtained by fda.
I'd attached the data for reproduction. I made the same analysis (linear
discriminant analysis) but using lda and fda (default args, using
"polyreg"). The resulting coefficients and trace pro
It plots on my system just fine. You might want to check what
directory (getwd()) that you are plotting in.
On Fri, Oct 9, 2009 at 12:17 PM, Anne Buunk wrote:
>
> Hi. With your help, I've fixed the errors in my for loops.
>
> But now, the for loop isn't working correctly. There should be a plot,
On Fri, Oct 9, 2009 at 4:54 PM, Anne Buunk wrote:
> text(0.5,0.5, text = paste(letters[i], "+",
> numbers[j],"=", letters [i+j+k])
Missing ) on the end there. You have one ( for text( and one for
paste( but only one ")".
Use an editor that matches parentheses, and read
Hello,
I need to put 2 or more different time series to one plot for comparison
each other. The problem is that the time series are irregular, moreover
the time lenghts and periods are not the same. Is there a way to manage
it in R?
Many thanks for any hint and advice in advance
Tomas
_
Hi. With your help, I've fixed the errors in my for loops.
But now, the for loop isn't working correctly. There should be a plot,
but there's no plot when I run the for loop..
This is the code:
letters = c("A","B","C","D","E","F","G","H","I","J")
numbers = 1:3
for(i in 1:6){
The following code isn't working and we can't figure out why..
letters = c("A","B","C","D","E","F","G","H","I","J")
numbers = 1:3
for(i in 1:6){ #6 letters
for (j in 1:3) { #3 numbers
for (k in -1:1) {
A parenthesis is missing. You can figure that out easily watching the first
error.
text(0.5,0.5, text = paste(letters[i], "+", numbers[j],"=", letters [i+j+k]))
Xavier
- Mail Original -
De: "Antje##"
À: r-help@r-project.org
Envoyé: Vendredi 9 Octobre 2009 17h36:34 GMT +01:00 Amsterdam
try using 'sprintf'
On Fri, Oct 9, 2009 at 8:36 AM, sahil seth wrote:
> Hello R users,
> I am writing a summary() for a custom class, and am to display the integers
> right justified,
> Say where x is the vector with integers, I am using the following:
> cat("\t",format(x),"\t"...other columns)
>
1) No need to post multiple times to the list
2) use the is.na function to test if a value is missing, not == or !=
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
> On Behalf Of premmad
> Sent: Friday, October 09, 2009 5:05 AM
> To: r-help@
Because you missed your closing parens in the "text" function call. The closing
parens is closing the "paste" function, you need one more. I don't know what
you're trying to do here, but I am guessing there's a faster way?
> -Original Message-
> From: r-help-boun...@r-project.org [mai
What you want is:
book$r<-ifelse(is.na(book$r), 10,book$x+20)
On Fri, Oct 9, 2009 at 5:46 AM, premmad wrote:
>
> I have one column
> x
> 97
> 94
> 91
> 90
> NA
> NA
> NA
> NA
> I tried
> book$r<-ifelse(book$x!=NA,book$x+20,10)
> I expect to get the result as follows
> 107
> 104
> 91
> 90
> 10
>
Hello R users,
I am writing a summary() for a custom class, and am to display the integers
right justified,
Say where x is the vector with integers, I am using the following:
cat("\t",format(x),"\t"...other columns)
this way I am trying to pass the format(x), to the cat function to display
it,
but
Dear colleagues,
I'm trying (and failing) to write the script required to generate a
chart that would help me assess the forecasting accuracy of a logistic
regression model by plotting the cumulative proportion of observed
events occurring in cases across the range of possible predicted
probabilit
I tried this:
(c is the column vector with indices of those rows I want to replace)
table[c,]<-replace(table[c,],c,newRows)
but it does not work and the error is:
new columns would leave holes after existing columns
Can anyone help please?
Thanks
--
View this message in context:
http://www.n
I have one column
x
97
94
91
90
NA
NA
NA
NA
I tried
book$r<-ifelse(book$x!=NA,book$x+20,10)
I expect to get the result as follows
107
104
91
90
10
10
10
10
But what i was getting is empty column of variable r.How to solve this
--
View this message in context:
http://www.nabble.com/Handlin
The following code isn't working and we can't figure out why..
letters = c("A","B","C","D","E","F","G","H","I","J")
numbers = 1:3
for(i in 1:6){ #6 letters
for (j in 1:3) { #3 numbers
for (k in -1:1) { #a
Hi all,
I'm from Brazil.
I fit a Tobit model to FLUID MILK CONSUMPTION (DEPENDENT VARIABLE)
data using survreg (attached).
I am confused about the output interpretation and I would like yours
explanations.
Thanks,
Marcio Roberto Silva __
Hi Rob.
Without the file content_1.xml or any information
from the R call stack (e.g. options(error = recover)
and then run the command and dynamically explore the
state of affairs when the error occurs), there is
no way for us to know what the problem might be.
Somehow, the XML parser appears t
In further offline discussion with the poster it was explained that
the purpose of this is to display the icon object and not to return an
instantiatedProtoMethod which was what the code was attempting to do.
That is in proto, g$icon is not the icon object. It is the icon method
instantiated with t
Content-Type: text/plain; charset="iso-8859-1"
Content-Transfer-Encoding: quoted-printable
MIME-Version: 1.0
Thanks for flagging up the 'segments' command. However=2C I'm having troubl=
e getting it to work - this is probably due to me misunderstanding the docu=
mentation for this command.
Th
I don't think I've seen an R version, probably because the technique is not
very good for displaying data.
Have a look at http://chartsgraphs.wordpress.com/tag/r-and-excel/ for an
alternative method of displaying the data using lattice.
--- On Fri, 10/9/09, zhijie zhang wrote:
> From: zhiji
Hi Steve,
>> However, I am finding that ... the trendline ... continues to run beyond
>> this data segment
>> and continues until it intersects the vertical axes at each side of the
>> plot.
Your "best" option is probably Prof. Fox's reg.line function in package car.
##
library(car)
?reg.line
Dear Madan,
Please see the qq.plot() function in the car package.
I hope this helps,
John
> -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On
> Behalf Of Madan Sigdel
> Sent: October-09-09 8:54 AM
> To: r-help@r-project.org
> Subject: [R]
If you want curve with substitute(...), you can try something about like this:
f <- eval(parse(text = paste("substitute(", formula(yfit)[3], ",
as.list(coef(yfit)))", sep = "")))
curve(f, ...)
2009/10/9 Henrique Dallazuanna :
> Try with predict:
>
> plot(x, y)
> lines(0:10, predict(yfit, list(x =
Hello,
Today, Brian Ripley commited the revision 5 of R's svn repository.
I took this as an opportunity to do some data analysis of the log and
posted some code and graphics on my blog:
http://romainfrancois.blog.free.fr/index.php?post/2009/10/09/celebrating-R-commit-5
The plots of t
Try with predict:
plot(x, y)
lines(0:10, predict(yfit, list(x = 0:10)))
2009/10/9 Primoz PETERLIN :
> Dear all,
>
> Here I come with another stupid question. Suppose I want to use nls()
> to fit a series of data (here modelled by generated points), then plot
> the points and the fitting curve. I
On Oct 9, 2009, at 5:50 AM, Steve Murray wrote:
Dear all,
I am using abline(lm ...) to insert a linear trendline through a
portion of my data (e.g. dataset[,36:45]). However, I am finding
that whilst the trendline is correctly displayed and representative
of the data portion I've chosen
Hi,
I am using "line" function to plot the line. And I would like to understand
"Tukeyline" algorithm. Since, the line function is calling the Tukeyline
algorithm(which is compiled code) using foreign function interface, I am not
able to look into the source code of this algorithm. Can somebody
Try this:
x <- array(1:1000, rep(10, 3))
vList <- list(i = 4:6, j = 4:6, ... = 4:6)
do.call('[', c(list(x), vList))
On Fri, Oct 9, 2009 at 7:18 AM, Mark McDowall
wrote:
> I want to select a subset of an array, but I want to make a function so that
> it can handle any number of dimensions.
>
> Th
-begin included message ---
With "rpart" we can get several terminals and draw it in the TREE plot.
Now I am trying to draw a plot like this: x-axis is each terminal's
value, and y-axis is those observe values. Does anyone has idea what
gramma should I use? Thanks in advance.
-
Dear list
I want to plot the QQ plot with some distributions like geometrical , lognormal
and truncated normal with confidence bands. does this options available.
Iam new to R. If you have any scripts and examples please kindly suggest me.
thank you
madan
[[alternative H
Dear All,
In R, is there a way (or a function) I can quickly check whether all the NA
values in one new created numerical variable happened are because of
or something else in the original dataset? And how can we easily group these
NAs separately based on different reason (e.g. some NA are
A couple of ways:
List.glm <- list()
for(i in 1:n) list.glm[[i]] <-glm(,,,)
OR
List.glm <- lapply(1:n, function(x) glm(,,,))
On Fri, Oct 9, 2009 at 7:54 AM, P.Branco wrote:
>
> Hello,
>
> I am trying to run a for-loop in which I want to add glm output objects
> sequentially into a list. I d
Hello,
I am trying to run a for-loop in which I want to add glm output objects
sequentially into a list. I do not know how to give names to each object in
a list. I tried this :
List.glm <- list()
for(i in 1:n)
list.glm <- list(list.glm, glm(,,,))
but it is obviously unsuited…
Best rega
Dear list,
I am trying to set up a propensity-weighted regression using the
survey package. Most of my population is sampled with a sampling
probability of one (that is, I have the full population). However, for
a subset of the data I have only a 50% sample of the full population.
In previous work
Hello joris, when i type the command:
> ?installed.packages
seems it works fine and shows me the man page of install.packages()
Then i followed ur instructions by first removing DAAG
> remove.packages("DAAG")
Warning in remove.packages("DAAG") :
argument 'lib' is missing: using
/home/simon/R/i48
Hello David, seems there's sth wrong with my R.
I used to start R with Emacs+ESS, so i didn't find the error message till
today i ran R in an terminal :
si...@simon-t400:~$ R
R version 2.9.2 (2009-08-24)
Copyright (C) 2009 The R Foundation for Statistical Computing
ISBN 3-900051-07-0
R is free s
I want to select a subset of an array, but I want to make a function so that
it can handle any number of dimensions.
This is probably best described with an example
> x <- 1:100
> dim(x) <- c(10,10)
> x
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10]
[1,]1 11 21 31 41 51
Dear all,
I am using abline(lm ...) to insert a linear trendline through a portion of my
data (e.g. dataset[,36:45]). However, I am finding that whilst the trendline is
correctly displayed and representative of the data portion I've chosen, the
line continues to run beyond this data segment an
Hi all,
In R, is there some functions or ways to create a Clustered-Stacked
Column Chart as the example in the following page
http://peltiertech.com/Excel/ChartsHowTo/ClusterStack.html?
I have browsed the R Graph Gallery (http://addictedtor.free.fr/graphiques/)
and searched the R site, and di
Hi,
If you work on Windows you can reduce the priority of the Rgui.exe
process. You can do this in the task manager, right click > Priority.
cheers,
Paul
venkata kirankumar wrote:
Hi all,
I have a problem with CPU usage while running the Rgui.exe
problem is
while I am running scripts on R
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