The answer to this may be obvious, but I was wondering in the rms
package and the survfit(), how you can plot the censored time points
as ticks.
Take for example,
library(survival)
library(rms)
foo <- data.frame(Time=c(1,2,3,4,5,6,10), Status=c(1,1,0,0,1,1,1))
answer <- survfit(Surv(foo$Time, fo
Thank you very much for your suggestion...that works perfectly.
Thanks,
Andrew
On Mon, Apr 4, 2011 at 5:46 PM, Prof Brian Ripley wrote:
> On Mon, 4 Apr 2011, Andrew Yee wrote:
>
>> This has to do with using pipe() and grep and read.csv()
>>
>> I have a .csv file that
This has to do with using pipe() and grep and read.csv()
I have a .csv file that I grep using pipe() and read.csv() as follows:
read.csv(pipe('grep foo bar.csv'))
However, is there a way to have this command run when for example,
there is no "foo" text in the bar.csv file? I get an error messag
I'm mortified to report that the location I set in TMPDIR was not a
valid directory in the system I was using (I copied it from another
system), so this is a mea culpa on my part!
Andrew
On Mon, Oct 18, 2010 at 7:46 AM, Prof Brian Ripley
wrote:
>
> On Sun, 17 Oct 2010, Andrew Yee wr
I noticed that if I specify the location of TMPDIR in .bashrc as follows on
a Linux 64 bit system:
export TMPDIR=/store/home/ayee/.tmp
I get the following error message when installing R
make[3]: Entering directory `/home/ayee/R-patched/src/library/base'
building package 'base'
make[4]: Entering
Dallazuanna wrote:
> Try this:
>
> format(dt, '%Y-%m-%d'), if you want Date class:
>
> as.Date(format(dt, '%Y-%m-%d'))
>
>
>
>
> On Mon, Sep 13, 2010 at 2:24 PM, Andrew Yee wrote:
>
>> Thanks David, now I wonder how you can have as.Da
Thanks David, now I wonder how you can have as.Date() render the date using
local time rather than UTC.
Andrew
On Mon, Sep 13, 2010 at 12:08 PM, David Winsemius wrote:
>
> On Sep 13, 2010, at 11:56 AM, Andrew Yee wrote:
>
> I'm trying to understand why as.Date() is converti
I'm trying to understand why as.Date() is converting a the modified date of
a file from August 22 to August 23.
> foo <- file.info(file.to.process)
> str(foo)
'data.frame': 1 obs. of 10 variables:
$ size : num 5.37e+09
$ isdir : logi FALSE
$ mode :Class 'octmode' int 436
$ mtime : POSIX
Thanks for the tip!
Andrew
On Fri, Apr 9, 2010 at 8:04 PM, Gabor Grothendieck
wrote:
> Try this:
>
> suppressWarnings(as.numeric("A"))
>
> On Fri, Apr 9, 2010 at 7:22 PM, Andrew Yee wrote:
> > I'm interested in testing whether or not a character str
I'm interested in testing whether or not a character string is numeric or
not as follows:
is.na(as.numeric('3')) # returns F
is.na(as.numeric('A')) # I'd like this to return T without issuing a warning
about NAs introduced by coercion.
I guess you could suppress the warning with options(warn=-1),
I have a file that I'm planning on manipulating with sqldf(). The header
for this file is malformed, and I was wondering if there's a way to specify
the values of the header ahead of time. I can see there are T/F options for
header in sqldf(... list(header=T, ...), but was wondering if there's a
eley
> spec...@stat.berkeley.edu
>
>
>
>
> On Fri, 5 Mar 2010, Andrew Yee wrote:
>
>> I'm trying to find a way for converting multiple lines of text into a
>> table. I'm not sure if there's a way where you ca
I'm trying to find a way for converting multiple lines of text into a
table. I'm not sure if there's a way where you can use read.delim()
to read in multiple lines of text and create the following data frame
with something akin to rehape()?. Apologies if there is an obvious
way to do this.
A: 1
Uwe, you're right, it turns out that cairo hadn't been previously installed
on the system.
Andrew
2010/2/19 Uwe Ligges
>
>
> On 19.02.2010 17:44, Andrew Yee wrote:
>
>> I was wondering if someone could help with the antialias option in tiff().
>> I&#x
I was wondering if someone could help with the antialias option in tiff().
I'm running R 2.9.2 on a Linux machine.
I'm working on creating a tiff file and have tried different antialias
parameters, e.g. default, none, gray, and subpixel, but don't seem to be
seeing a difference in the output. Or
Hi, I was wondering how you can create a pdf where the output is vertically
justified with for example a one inch margin on top using pdf().
For example in
pdf(file='test.pdf', paper='letter', pagecentre=F)
### code for plot ###
dev.off()
is there an option where it generate output that starts f
//yihui.name
> Department of Statistics, Iowa State University
> 3211 Snedecor Hall, Ames, IA
>
>
>
> On Fri, Oct 23, 2009 at 1:02 PM, Duncan Murdoch
> wrote:
> > On 10/23/2009 1:28 PM, Andrew Yee wrote:
> >>
> >> This is kind of a dumb question: I know
This is kind of a dumb question: I know you can use isdebugged() to find
out if a specific function is flagged for debugging, but is there a way to
list all the functions that are flagged for debugging?
Thanks,
Andrew
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_
Thanks, as you suggested,
do.call(rbind, lapply(foo, unlist))
does the trick.
On Sat, Oct 3, 2009 at 8:30 PM, David Winsemius wrote:
>
> On Oct 3, 2009, at 7:51 PM, Andrew Yee wrote:
>
> Take the following code:
>> foo <- list()
>>
>> foo[[1]] <- list(a=1,
unlist()
Andrew
On Sat, Oct 3, 2009 at 8:01 PM, Gabor Grothendieck
wrote:
> Try this:
>
> matrix(list(1, 11, 111, 2, 22, 222), nc = 2, dimnames = list(NULL, c("a",
> "b")))
>
> or
>
> out <- list(1, 11, 111, 2, 22, 222)
> dim(out) <- c(3, 2)
>
Take the following code:
foo <- list()
foo[[1]] <- list(a=1, b=2)
foo[[2]] <- list(a=11, b=22)
foo[[3]] <- list(a=111, b=222)
result <- do.call(rbind, foo)
result[,'a']
In this case, result[,'a'] shows a list. Is there a more elegant way such
that result is a "regular" matrix of vectors? I imag
;, 'John')
> PCH <- c('+','O','$')
>
> # Plotting
> plot(x, pch = PCH)
> legend('topright', pch = PCH, Text, ncol = 3)
>
> should be close to what you want. Note that the text() / points()
> combination could be avoide
1*x[2], expression(beta) )
> text(2.95,1.01*x[3], expression(gamma) )
>
> should get you close.
>
> See ?text, ?expression and ?legend for more information.
>
> HTH,
>
> Jorge
>
>
> On Thu, Jul 9, 2009 at 10:53 AM, Andrew Yee wrote:
>
>> Hi, is there
Hi, is there a way to treat a data symbol, e.g. one with pch = 16, as a
character?
Specifically, I'm interested in creating a line of text as follows using the
text() function
O alpha O beta O gamma
where the "O" is pch 16 and filled with a specific color.
Not sure if this is possible or not.
T
; On Fri, 26 Jun 2009, David Scott wrote:
>
> Andrew Yee wrote:
>>
>>> A naive question: what happened to the xlsReadWrite package?
>>> http://cran.r-project.org/web/packages/xlsReadWrite/
>>>
>>> It says that it was removed from the CRAN repository.
A naive question: what happened to the xlsReadWrite package?
http://cran.r-project.org/web/packages/xlsReadWrite/
It says that it was removed from the CRAN repository. Are there any plans
for it be available again?
Thanks,
Andrew
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__
Thanks, that works great.
Andrew
On Fri, May 22, 2009 at 5:42 PM, William Dunlap wrote:
> > -Original Message-
> > From: r-help-boun...@r-project.org
> > [mailto:r-help-boun...@r-project.org] On Behalf Of Andrew Yee
> > Sent: Friday, May 22, 2009 2:16 PM
> >
Take for example the following stripchart that's created:
b <- 1:5
a <- 11:15
e <- 21:25
f <- -11:-15
foo <- rbind(b,a,e,f)
stripchart(foo ~ rownames(foo))
In this case, I would like the bottom part of the plot to be the f vector,
followed by the e vector, etc.
However, R reorders the matrix a
Hi, I was wondering if someone in the mailing list has any insight into this
segfault error that I consistently find when running a script containing
heatmap() in R 2.8.1 and 2.8.0 on a Linux 64-bit machine.
Some points:
1. This occurs when running heatmap().
2. Interestingly, if I source() the s
I'm not sure where to begin with this, but I was wondering if someone could
refer me to an R package that would test to see if a distribution fits a
bimodal distribution better than a unimodal distribution.
Thanks,
Andrew
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>> >
>> > a <- data.frame(var.1 = 1:5)
>> > b <- data.frame(var.1 = 11:15)
>> > test.list <- list(a=a, b=b)
>> > res=do.call(rbind,test.list)
>> > res$var.2=substr(rownames(res),1,1)
>> > rownames(res)=NULL
>> > res
In the following code, I'd like to be able to create a new variable
containing the value of the names of the list.
a <- data.frame(var.1 = 1:5)
b <- data.frame(var.1 = 11:15)
test.list <- list(a=a, b=b)
# in this case, names(test.list) is "a" and "b"
# and I'd like to use lapply() so that
# I
; Andrew
>
> levels(factor(foo, levels=c('b','a')))
>
> should work. You can make foo an ordered factor too, but that is not
> necessary.
>
> HTH ...
>
> Peter Alspach
>
>
>> -Original Message-----
>> From: [EMAIL PROTECTED]
>
Apologies for the naieveness of this question, but I'm having trouble
figuring out to have factor() maintain original ordering.
For example,
foo <- c("b","b","a","a")
levels(factor(foo, ordered=T)) #I'd like this to return as "b" "a"
#not "a" "b"
I thoug
Thanks for tracking this down.
Andrew
On Mon, Jun 16, 2008 at 4:49 PM, Peter Dalgaard <[EMAIL PROTECTED]>
wrote:
> Andrew Yee wrote:
>
>> I've been trying to figure out a parameter that will let you separately
>> adjust the parameters for the axis line from the tick
I've been trying to figure out a parameter that will let you separately
adjust the parameters for the axis line from the tick mark.
In the following example, I would like to suppress the axis line, but keep
the tick marks.
Thanks,
Andrew
foo <- data.frame(x=1:3, y=4:6)
plot(foo$x, foo$y, type="
ot;Second inner y axis label",side=4)
> mtext("First outer x axis label",side=1,outer=TRUE)
> mtext("First outer y axis label",side=2,outer=TRUE)
> mtext("Second outer x axis label",side=3,outer=TRUE)
> mtext("Second outer y axis label",side
Here's a naive question about axis()
How do you control the location of the labels with the axis() command?
In the following example:
foo <- data.frame(plot.x=seq(1:3), plot.y=seq(4:6))
plot(foo$plot.x, foo$plot.y, type='n', axes=FALSE)
points(foo$plot.x, foo$plot.y)
axis(1, at=foo$plot.x, label
Great, thanks, that was helpful.
Andrew
On Thu, Apr 24, 2008 at 2:15 PM, Achim Zeileis <[EMAIL PROTECTED]>
wrote:
> On Thu, 24 Apr 2008, Andrew Yee wrote:
>
> > I've found RColorBrewer useful for its qualitative palettes, but wished
> that
> > it could generate m
I've found RColorBrewer useful for its qualitative palettes, but wished that
it could generate more than 12 qualitative palettes (e.g. with Set3). Any
suggestions for alternative color palette generators that can handle e.g. 18
distinctive colors? (I'm aware of using rainbow(), but this doesn't
g
Thanks!
On 4/18/08, Katharine Mullen <[EMAIL PROTECTED]> wrote:
> do.call(rbind, list.foo)
>
> On Fri, 18 Apr 2008, Andrew Yee wrote:
>
> > Is there an efficient way to use rbind() with the five dataframes
> described
> > in the following example:
> >
&
Is there an efficient way to use rbind() with the five dataframes described
in the following example:
a <- c(1:5)
list.foo <- lapply(a, function(x) data.frame(beta=a*rnorm(10),
deta=a*rnorm(10)))
big.data.frame <- rbind(list.foo[[1]], list.foo[[2]], list.foo[[3]],
list.foo[[4]], list.foo[[5]]) #is
t; seeing is a viewer artifact of doing so -- the antialiasing isn't working
> for you.
>
>
>
> On Thu, 3 Apr 2008, Andrew Yee wrote:
>
> >
> >
> >
> > Here's a question: I noticed that when I tried to create this simple
> > graph of rectang
Here's a question: I noticed that when I tried to create this simple
graph of rectangles and text, R appears to generate text that is
rasterized (this is seen both on the monitor and when the output is
directed to a pdf file). Any thoughts?
value.seq <- c("<4",as.character(seq(from=4,to=10)),">1
Hi, I've been using R in Windows but am now starting to use it more often in
the UNIX environment. In Windows, I'm used to the text provided by the user
appearing in red, and the output from R appearing in blue. Is there a way
to achieve this in UNIX?
Thanks,
Andrew
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