Re: [agi] Re: Shhh!

2010-08-03 Thread Jim Bromer
I meant transfinite.  Thank you for correcting me on that.  However,
your suggestion to post when I actually solve the problem is one of the most
absurd comments I have ever seen in these groups given the absolute
necessity of posting about AI-related ideas that have yet to be solved, and
especially given your own history of posting about unverifiable conjectures
as if they were absolute truths.

I thought that it would be impossible to use a single computer program to
iterate every irrational number even if given infinite resources because the
irrationals are considered to be transfinite.  However, I found a way to do
it.  What really surprised me was that I also found an abbreviated method to
do it.  (And there may also be a super-abbreviated method that would look
humorously absurd.)  However, there are four issues.  One is that the
algorithm obviously will not make much progress, two is that the algorithm
can only output an infinity of finite representations, three the algorithm
has no known use and four is that the algorithm has one error.  It cannot
recognize that all binary numbers that have a fractional part .111(followed
by infinite ones) is equal to 1, or .999 (followed by infinite 9s) in for
decimal numbers is equal to 1.

However, the theoretical problem, while not directly related to AGI, is
interesting enough to make it worthwhile.  And I believe that there is a
chance that I might be able to use it to solve an important problem, but
that is purely speculative.
Jim Bromer
On Mon, Aug 2, 2010 at 4:12 PM, Matt Mahoney matmaho...@yahoo.com wrote:

   Jim, you are thinking out loud. There is no such thing as
 trans-infinite. How about posting when you actually solve the problem.


 -- Matt Mahoney, matmaho...@yahoo.com


  --
 *From:* Jim Bromer jimbro...@gmail.com
 *To:* agi agi@v2.listbox.com
 *Sent:* Mon, August 2, 2010 9:06:53 AM
 *Subject:* [agi] Re: Shhh!

 I think I can write an abbreviated version, but there would only be a few
 people in the world who would both believe me and understand why it would
 work.

 On Mon, Aug 2, 2010 at 8:53 AM, Jim Bromer jimbro...@gmail.com wrote:

 I can write an algorithm that is capable of describing ('reaching') every
 possible irrational number - given infinite resources.  The infinite is not
 a number-like object, it is an active form of incrementation or
 concatenation.  So I can write an algorithm that can write *every* finite
 state of *every* possible number.  However, it would take another
 algorithm to 'prove' it.  Given an irrational number, this other algorithm
 could find the infinite incrementation for every digit of the given number.
 Each possible number (including the incrementation of those numbers that
 cannot be represented in truncated form) is embedded within a single
 infinite infinite incrementation of digits that is produced by the
 algorithm, so the second algorithm would have to calculate where you would
 find each digit of the given irrational number by increment.  But the thing
 is, both functions would be computable and provable.  (I haven't actually
 figured the second algorithm out yet, but it is not a difficult problem.)

 This means that the Trans-Infinite Is Computable.  But don't tell anyone
 about this, it's a secret.



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[agi] Re: Shhh!

2010-08-02 Thread Jim Bromer
I think I can write an abbreviated version, but there would only be a few
people in the world who would both believe me and understand why it would
work.

On Mon, Aug 2, 2010 at 8:53 AM, Jim Bromer jimbro...@gmail.com wrote:

 I can write an algorithm that is capable of describing ('reaching') every
 possible irrational number - given infinite resources.  The infinite is not
 a number-like object, it is an active form of incrementation or
 concatenation.  So I can write an algorithm that can write *every* finite
 state of *every* possible number.  However, it would take another
 algorithm to 'prove' it.  Given an irrational number, this other algorithm
 could find the infinite incrementation for every digit of the given number.
 Each possible number (including the incrementation of those numbers that
 cannot be represented in truncated form) is embedded within a single
 infinite infinite incrementation of digits that is produced by the
 algorithm, so the second algorithm would have to calculate where you would
 find each digit of the given irrational number by increment.  But the thing
 is, both functions would be computable and provable.  (I haven't actually
 figured the second algorithm out yet, but it is not a difficult problem.)

 This means that the Trans-Infinite Is Computable.  But don't tell anyone
 about this, it's a secret.





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Re: [agi] Re: Shhh!

2010-08-02 Thread Matt Mahoney
Jim, you are thinking out loud. There is no such thing as trans-infinite. How 
about posting when you actually solve the problem.

 -- Matt Mahoney, matmaho...@yahoo.com





From: Jim Bromer jimbro...@gmail.com
To: agi agi@v2.listbox.com
Sent: Mon, August 2, 2010 9:06:53 AM
Subject: [agi] Re: Shhh!


I think I can write an abbreviated version, but there would only be a few 
people 
in the world who would both believe me and understand why it would work.


On Mon, Aug 2, 2010 at 8:53 AM, Jim Bromer jimbro...@gmail.com wrote:

I can write an algorithm that is capable of describing ('reaching') every 
possible irrational number - given infinite resources.  The infinite is not a 
number-like object, it is an active form of incrementation or concatenation.  
So 
I can write an algorithm that can write every finite state of every possible 
number.  However, it would take another algorithm to 'prove' it.  Given an 
irrational number, this other algorithm could find the infinite incrementation 
for every digit of the given number.  Each possible number (including 
the incrementation of those numbers that cannot be represented in truncated 
form) is embedded within a single infinite infinite incrementation of digits 
that is produced by the algorithm, so the second algorithm would have to 
calculate where you would find each digit of the given irrational number by 
increment.  But the thing is, both functions would be computable and provable.  
(I haven't actually figured the second algorithm out yet, but it is not 
a difficult problem.)
 
This means that the Trans-Infinite Is Computable.  But don't tell anyone about 
this, it's a secret.
 

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