Re: [Amforth] Forward declaration for recursive word
Thanks Matthis, It is working now. Do you know if the construction “ TO and VALUE “ is available for amForth? Cheers Jan > Op 5 dec. 2018, om 19:28 heeft Matthias Trute het volgende > geschreven: > > Am Mittwoch, den 05.12.2018, 13:50 +0100 schrieb Jan Kromhout via > Amforth-devel: >> Hello >> >> >> I wont to use the forward declaration “forward:” to solve my >> recursive word roll. >> >> Is this use of forward: correct? > > the forward declaration is for cases in which > one word calls another one before the other > one is defined. Something like > > : foo bar ; > : bar foo ; > > > >> >> forward: roll >> >> : roll >> dup 0< \ 0<= >> if >>drop >> else >>swap >r 1- roll r> swap >> then >> ; > > Replace the roll inside your definition with > recurse and it should work (if the > code is correct, I did not check it) > >> >> When I look into the definition of forward: I find the word “iplace”. > > Oops. I'll update the docs. > >> What is this iplace? > > > \ copy a counted flash string to ram > : iplace ( f-addr r-addr -- ) >> r icount $ff and ( -- f-addr' len ) > dup r@ c! r> ( -- f-addr' len r-addr) > 1+ rot rot > 2/ 1+ bounds ?do >i @i over ! >cell+ > loop > drop > ; > > Matthias > > > > ___ > Amforth-devel mailing list for http://amforth.sf.net/ > Amforth-devel@lists.sourceforge.net > https://lists.sourceforge.net/lists/listinfo/amforth-devel ___ Amforth-devel mailing list for http://amforth.sf.net/ Amforth-devel@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/amforth-devel
Re: [Amforth] Forward declaration for recursive word
Am Mittwoch, den 05.12.2018, 13:50 +0100 schrieb Jan Kromhout via Amforth-devel: > Hello > > > I wont to use the forward declaration “forward:” to solve my > recursive word roll. > > Is this use of forward: correct? the forward declaration is for cases in which one word calls another one before the other one is defined. Something like : foo bar ; : bar foo ; > > forward: roll > > : roll > dup 0< \ 0<= > if > drop > else > swap >r 1- roll r> swap > then > ; Replace the roll inside your definition with recurse and it should work (if the code is correct, I did not check it) > > When I look into the definition of forward: I find the word “iplace”. Oops. I'll update the docs. > What is this iplace? \ copy a counted flash string to ram : iplace ( f-addr r-addr -- ) >r icount $ff and ( -- f-addr' len ) dup r@ c! r> ( -- f-addr' len r-addr) 1+ rot rot 2/ 1+ bounds ?do i @i over ! cell+ loop drop ; Matthias ___ Amforth-devel mailing list for http://amforth.sf.net/ Amforth-devel@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/amforth-devel
[Amforth] Forward declaration for recursive word
Hello I wont to use the forward declaration “forward:” to solve my recursive word roll. Is this use of forward: correct? forward: roll : roll dup 0< \ 0<= if drop else swap >r 1- roll r> swap then ; When I look into the definition of forward: I find the word “iplace”. When I look for this word in the dictionary I can’t find it. Do I a search with grep -nr ‘iplace’ amforth-6.7 grep is find only dup 1- swap @i here iplace here count ( copy to temporary ram) What is this iplace? Cheers, Jan Kromhout ___ Amforth-devel mailing list for http://amforth.sf.net/ Amforth-devel@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/amforth-devel
