[il-antlr-interest: 28869] [antlr-interest] Find X :-)

2010-05-18 Thread Sameh W. Zaky
Dear All,

I have in my grammar:

fragment UNIT_NAME :;

ID : ('a'..'z'|'_')*
{
if ( myLookUpMethod( *X* ) ) $type=UNIT_NAME;
}
;
===

Instead of *X*, I wanna refer to the text that is in red.. For example, the
token w_aw_s  is ID. I want to take the text of this token w_aw_s and
look it up in a certain array and if it is in this array then I set its type
to UNIT_NAME.

P.S.: I tried to replace *X* with *$text* but I receive the error:

[16:15:56] symbol  : method myLookUpMethod(java.lang.String)
[16:15:56] location: class SimpleTestLexer
[16:15:56] if(myLookUpMethod(getText())) _type=UNIT_NAME;
[16:15:56]^
[16:15:56] 1 error

Find X :-)

Many Thanks !
-- 
Sameh W. Zaky

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[il-antlr-interest: 28870] Re: [antlr-interest] Find X :-)

2010-05-18 Thread Sameh W. Zaky
OK, Sorry for that!

Just after I have sent this message I realized that the problem is that
ANTLR cannot find my method myLookUpMethod..
I have defined it in @members{} part of the grammar file.. But ANTLR still
cannot find it.. Any idea?

On Tue, May 18, 2010 at 4:35 PM, Sameh W. Zaky sameh...@gmail.com wrote:

 Dear All,

 I have in my grammar:

 fragment UNIT_NAME :;

 ID : ('a'..'z'|'_')*
  {
 if ( myLookUpMethod( *X* ) ) $type=UNIT_NAME;
  }
 ;
 ===

 Instead of *X*, I wanna refer to the text that is in red.. For example,
 the token w_aw_s  is ID. I want to take the text of this token w_aw_s
 and look it up in a certain array and if it is in this array then I set its
 type to UNIT_NAME.

 P.S.: I tried to replace *X* with *$text* but I receive the error:

 [16:15:56] symbol  : method myLookUpMethod(java.lang.String)
 [16:15:56] location: class SimpleTestLexer
 [16:15:56] if(myLookUpMethod(getText())) _type=UNIT_NAME;
 [16:15:56]^
 [16:15:56] 1 error

 Find X :-)

 Many Thanks !
 --
 Sameh W. Zaky




-- 
Sameh W. Zaky

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[il-antlr-interest: 28871] Re: [antlr-interest] Find X :-)

2010-05-18 Thread John B. Brodie
On Tue, 2010-05-18 at 17:10 +0200, Sameh W. Zaky wrote:
 OK, Sorry for that!
 
 Just after I have sent this message I realized that the problem is that
 ANTLR cannot find my method myLookUpMethod..
 I have defined it in @members{} part of the grammar file.. But ANTLR still
 cannot find it.. Any idea?

since it is in the lexer, the method needs to be defined in a
@lexer::members{} section

@members{} defaults to the parser when placed in a combined grammar.

 
 On Tue, May 18, 2010 at 4:35 PM, Sameh W. Zaky sameh...@gmail.com wrote:
 
  Dear All,
 
  I have in my grammar:
 
  fragment UNIT_NAME :;
 
  ID : ('a'..'z'|'_')*
   {
  if ( myLookUpMethod( *X* ) ) $type=UNIT_NAME;
   }
  ;
  ===
 
  Instead of *X*, I wanna refer to the text that is in red.. For example,
  the token w_aw_s  is ID. I want to take the text of this token w_aw_s
  and look it up in a certain array and if it is in this array then I set its
  type to UNIT_NAME.
 
  P.S.: I tried to replace *X* with *$text* but I receive the error:
 
  [16:15:56] symbol  : method myLookUpMethod(java.lang.String)
  [16:15:56] location: class SimpleTestLexer
  [16:15:56] if(myLookUpMethod(getText())) _type=UNIT_NAME;
  [16:15:56]^
  [16:15:56] 1 error
 
  Find X :-)
 
  Many Thanks !
  --
  Sameh W. Zaky
 
 
 
 




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[il-antlr-interest: 28872] Re: [antlr-interest] ANTLR Two Simple Questions :-)

2010-05-18 Thread Jim Idle
Well, err the method inArray() is an imaginary method that you will write. It 
just needs to take a string and see if that string is currently something that 
should be a UNIT_NAME. If it is real simple then you could just use a standard 
List object of your choice.

 

Please replay to the list and not my personal email - thanks J

 

Jim

 

From: Sameh W. Zaky [mailto:sameh...@gmail.com] 
Sent: Tuesday, May 18, 2010 7:21 AM
To: Jim Idle
Subject: Re: [antlr-interest] ANTLR Two Simple Questions :-)

 

Dear Jim,

 

thanks for your reply.

 

Concerning point (1):

 

I did as you said:

 

fragment UNIT_NAME   :;

 

ID  :   ('a'..'z'|'_')*

  {

  if(inArray($text)) $type=UNIT_NAME;

  }

  ;

 

But when I click 'run' to run a test I get the error:

D:\My Documents\Downloads\Simple Test Grammar\output\SimpleTestLexer.java:604: 
cannot find symbol

[16:15:56] symbol  : method inArray(java.lang.String)

[16:15:56] location: class SimpleTestLexer

[16:15:56]  if(inArray(getText())) _type=UNIT_NAME; 

 

Any idea, how I can overcome this?

 

Thanks again for your time :-)

 

On Mon, May 17, 2010 at 6:54 PM, Jim Idle j...@temporal-wave.com wrote:



 -Original Message-
 From: antlr-interest-boun...@antlr.org [mailto:antlr-interest-
 boun...@antlr.org] On Behalf Of Sameh W. Zaky
 Sent: Monday, May 17, 2010 7:33 AM
 To: antlr-interest@antlr.org
 Subject: [antlr-interest] ANTLR Two Simple Questions :-)

 Dear All,

 I am a Masters student, I use Java, and I am trying to make my parser
 with
 the help of ANTLR. I need this for my Masters project.
 I am using ANTLRWorks 1.3.1
 I had 2 questions concerning it:

 1) How can I have a dynamic token name (or dynamic lexer)?
 *Example: (the symbol SERVICE, will have different token values,
 depending

 on certain list (array) whose contents change over time)*

Match the possible sequences generally, then change the token type if the 
strings match your dynamic list:

fragment SERVICE : ;
ID : ('a'..'z')+
   {
  If (myLookupMethod($text)) { $type = SERVICE; }
   }
 ;

So the token ID will be returned if the matched text is not in your list and 
the token SERVICE will be returned if it is.



 2) Given a certain grammar, how can I (or: is it possible to) get the
 list
 of all possible next tokens?

Read: http://www.antlr.org/wiki/display/ANTLR3/Custom+Syntax+Error+Recovery

Do I get a masters too? ;-)

Jim




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-- 
Sameh W. Zaky




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[il-antlr-interest: 28877] Re: [antlr-interest] Custom lexer and parser constructors

2010-05-18 Thread Bart Kiers
On Tue, May 18, 2010 at 6:04 PM, Cameron Ross cr...@kojeware.com wrote:

 Hi,

 Is there a way to define custom constructors for ANTLR lexers and parsers?


Sure, you can create custom methods, c-tors and attributes in:

@parser::members {
  // here
}

or

@lexer::members {
  // here
}

Regards,

Bart Kiers.

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[il-antlr-interest: 28878] Re: [antlr-interest] Custom lexer and parser constructors

2010-05-18 Thread Jim Idle
OK - just add the reporter to the paresr members and create a 
setErrorReporter() method.

 

Jim

 

From: Cameron Ross [mailto:cr...@kojeware.com] 
Sent: Tuesday, May 18, 2010 9:19 AM
To: Jim Idle
Cc: antlr-interest@antlr.org
Subject: Re: [antlr-interest] Custom lexer and parser constructors

 

Hi Jim,

 

My previous positing went unanswered so I thought I'd rephrase it to be more 
generic: http://www.antlr.org/pipermail/antlr-interest/2010-May/038661.html.  
Thanks for the lead on the superClass option... I'll look into it.

 

Cameron.

 

On Tue, May 18, 2010 at 12:15 PM, Jim Idle j...@temporal-wave.com wrote:

Using a superClass=xyz option will probably get you where you want to be, but 
you might be better phrasing your question in terms of what you want to achieve 
rather than whether you can change the constructors.

However, it is just as easy to add members to the class and supply setter 
methods.

Jim


 -Original Message-
 From: antlr-interest-boun...@antlr.org [mailto:antlr-interest-
 boun...@antlr.org] On Behalf Of Cameron Ross
 Sent: Tuesday, May 18, 2010 9:04 AM
 To: antlr-interest@antlr.org
 Subject: [antlr-interest] Custom lexer and parser constructors

 Hi,

 Is there a way to define custom constructors for ANTLR lexers and
 parsers?


 Thanks,
 Cameon.


 List: http://www.antlr.org/mailman/listinfo/antlr-interest
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[il-antlr-interest: 28881] Re: [antlr-interest] ANTLR Two Simple Questions :-)

2010-05-18 Thread Sameh W. Zaky
That was helpful, thanks :-)

On Tue, May 18, 2010 at 5:31 PM, Jim Idle j...@temporal-wave.com wrote:

 Well, err the method inArray() is an imaginary method that you will write.
 It just needs to take a string and see if that string is currently something
 that should be a UNIT_NAME. If it is real simple then you could just use a
 standard List object of your choice.



 Please replay to the list and not my personal email - thanks J



 Jim



 From: Sameh W. Zaky [mailto:sameh...@gmail.com]
 Sent: Tuesday, May 18, 2010 7:21 AM
 To: Jim Idle
 Subject: Re: [antlr-interest] ANTLR Two Simple Questions :-)



 Dear Jim,



 thanks for your reply.



 Concerning point (1):



 I did as you said:



 fragment UNIT_NAME   :;



 ID  :   ('a'..'z'|'_')*

  {

  if(inArray($text)) $type=UNIT_NAME;

  }

  ;



 But when I click 'run' to run a test I get the error:

 D:\My Documents\Downloads\Simple Test
 Grammar\output\SimpleTestLexer.java:604: cannot find symbol

 [16:15:56] symbol  : method inArray(java.lang.String)

 [16:15:56] location: class SimpleTestLexer

 [16:15:56]  if(inArray(getText()))
 _type=UNIT_NAME;



 Any idea, how I can overcome this?



 Thanks again for your time :-)



 On Mon, May 17, 2010 at 6:54 PM, Jim Idle j...@temporal-wave.com wrote:



  -Original Message-
  From: antlr-interest-boun...@antlr.org [mailto:antlr-interest-
  boun...@antlr.org] On Behalf Of Sameh W. Zaky
  Sent: Monday, May 17, 2010 7:33 AM
  To: antlr-interest@antlr.org
  Subject: [antlr-interest] ANTLR Two Simple Questions :-)
 
  Dear All,
 
  I am a Masters student, I use Java, and I am trying to make my parser
  with
  the help of ANTLR. I need this for my Masters project.
  I am using ANTLRWorks 1.3.1
  I had 2 questions concerning it:
 
  1) How can I have a dynamic token name (or dynamic lexer)?
  *Example: (the symbol SERVICE, will have different token values,
  depending

  on certain list (array) whose contents change over time)*

 Match the possible sequences generally, then change the token type if the
 strings match your dynamic list:

 fragment SERVICE : ;
 ID : ('a'..'z')+
   {
  If (myLookupMethod($text)) { $type = SERVICE; }
   }
  ;

 So the token ID will be returned if the matched text is not in your list
 and the token SERVICE will be returned if it is.



  2) Given a certain grammar, how can I (or: is it possible to) get the
  list
  of all possible next tokens?

 Read:
 http://www.antlr.org/wiki/display/ANTLR3/Custom+Syntax+Error+Recovery

 Do I get a masters too? ;-)

 Jim




 List: http://www.antlr.org/mailman/listinfo/antlr-interest
 Unsubscribe:
 http://www.antlr.org/mailman/options/antlr-interest/your-email-address




 --
 Sameh W. Zaky




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 http://www.antlr.org/mailman/options/antlr-interest/your-email-address




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[il-antlr-interest: 28882] [antlr-interest] enums in v4 ANTLR Java code generation considered useless

2010-05-18 Thread Terence Parr
 A lot of you have wondered why I'd don't use enum types for token types in the 
generated Java-based parsers:

enum TokenType { ID(3), INT(4) };

I gave it my best shot but once again I found that enums just don't seem to 
work for me. For example, without inheritance how can I define the match method?

void match(TokenType t) {}

Unfortunately this is in the superclass not the generated class so TokenType is 
not yet defined. Without inheritance, I have to use match(int). That means that 
there's no point in using the enum.

But, you say, I should be using generics on the parser to pass in the token 
type enum type. Fair enough, And I'll try once I tried to generic'ize the v3 
runtime for v4. We've had some discussion of this on the dev list.

Ter

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[il-antlr-interest: 28885] Re: [antlr-interest] enums in v4 ANTLR Java code generation considered useless

2010-05-18 Thread Scott Stanchfield
There are several advantages to enums:
* there is a discrete set of values that can be used (no accidental
42's passed in when 42 isn't a token type)
* the enum value can carry extra information
* the enum values can override methods differently

OH - one of the things that's clouding this is that you really don't
need the numeric type identifers anymore. You can just have

  public enum TokenType {
IDENT, INT ...;
  }

then in your match method:

  void match(TokenType type) {
if (LA(1).getType() == type) {
...
}
  }

And you can use the types in a switch statement:

  switch(type) {
case INT:
case IDENT:
...
  }

No more magic numbers! Woohoo!

-- Scott


Scott Stanchfield
http://javadude.com



On Tue, May 18, 2010 at 4:52 PM, Terence Parr pa...@cs.usfca.edu wrote:
 hi Edgar :)

 Don't i have to pass objects around then instead of ints with extra method 
 calls etc...?

 void match(TokenType t) {
  int ttype = t.getType();
 }

 no autoboxing etc...

 match(GeneratedTokenType.ID);

 Also i need Parser.GeneratedTokenType.ID in outside code.  pretty ugly.

 I guess i don't see enum advantages for token types and they cause confusion. 
 enum GeneratedTokenType implements TokenType vs int, in other words.

 Ter

 On May 18, 2010, at 1:47 PM, Edgar Espina wrote:

 Hi,

 TokenType can be an interface. Then your generated tokens can implemented
 this interface.

 enum GeneratedTokenType implements TokenType {
 ID(3);
 }

 Thanks,
 edgar

 On Tue, May 18, 2010 at 5:42 PM, Terence Parr pa...@cs.usfca.edu wrote:

 A lot of you have wondered why I'd don't use enum types for token types in
 the generated Java-based parsers:

 enum TokenType { ID(3), INT(4) };

 I gave it my best shot but once again I found that enums just don't seem to
 work for me. For example, without inheritance how can I define the match
 method?

 void match(TokenType t) {}

 Unfortunately this is in the superclass not the generated class so
 TokenType is not yet defined. Without inheritance, I have to use match(int).
 That means that there's no point in using the enum.

 But, you say, I should be using generics on the parser to pass in the token
 type enum type. Fair enough, And I'll try once I tried to generic'ize the v3
 runtime for v4. We've had some discussion of this on the dev list.

 Ter

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 edgar

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[il-antlr-interest: 28886] Re: [antlr-interest] enums in v4 ANTLR Java code generation considered useless

2010-05-18 Thread Scott Stanchfield
A little clarification...

Start with (as Edgar said)

  public interface TokenType { }
  public enum CommonTypes implements TokenType {
  EOF;  // others?
  }

  public class Token {
private TokenType type;
public TokenType getType() {return type;}
...
  }

  public class Parser ... {
  void match(TokenType type) {
if (LA(1).getType() == type) {
  ...
}
  }
  ...
  }


then for the specific parser, generate

  public enum FooParserTokenType implements TokenType {
IDENT, INT, ...;
  }


What might be nice would be to have a description available for the
type, something like

  public interface TokenType {
String getDescription();
  }

  public enum FooParserTokenType implements TokenType {
IDENT(identifier (lower camel case word of doom)),
INT(integer (digits, no decimal points), ...;
private String description;
private FooParserTokenType(String description) {
  this.description = description;
}
public String getDescription() {
  return description;
}
  }

this could be fed by something like

  IDENT
options {description=identifier (lower camel case word of doom)} : ...

and could be used to really help error messages by using
token.getType().getDescription().

This is where Java enums get really cool -- carrying extra data.

I've gotta upload an enumeration talk I gave at work (which described
other cool things you can do, like the GoF state pattern and something
kinda close to function pointers in java)

Hope this helps!
-- Scott


Scott Stanchfield
http://javadude.com



On Tue, May 18, 2010 at 5:58 PM, Scott Stanchfield sc...@javadude.com wrote:
 There are several advantages to enums:
 * there is a discrete set of values that can be used (no accidental
 42's passed in when 42 isn't a token type)
 * the enum value can carry extra information
 * the enum values can override methods differently

 OH - one of the things that's clouding this is that you really don't
 need the numeric type identifers anymore. You can just have

  public enum TokenType {
    IDENT, INT ...;
  }

 then in your match method:

  void match(TokenType type) {
    if (LA(1).getType() == type) {
        ...
    }
  }

 And you can use the types in a switch statement:

  switch(type) {
    case INT:
    case IDENT:
    ...
  }

 No more magic numbers! Woohoo!

 -- Scott

 
 Scott Stanchfield
 http://javadude.com



 On Tue, May 18, 2010 at 4:52 PM, Terence Parr pa...@cs.usfca.edu wrote:
 hi Edgar :)

 Don't i have to pass objects around then instead of ints with extra method 
 calls etc...?

 void match(TokenType t) {
  int ttype = t.getType();
 }

 no autoboxing etc...

 match(GeneratedTokenType.ID);

 Also i need Parser.GeneratedTokenType.ID in outside code.  pretty ugly.

 I guess i don't see enum advantages for token types and they cause 
 confusion. enum GeneratedTokenType implements TokenType vs int, in other 
 words.

 Ter

 On May 18, 2010, at 1:47 PM, Edgar Espina wrote:

 Hi,

 TokenType can be an interface. Then your generated tokens can implemented
 this interface.

 enum GeneratedTokenType implements TokenType {
 ID(3);
 }

 Thanks,
 edgar

 On Tue, May 18, 2010 at 5:42 PM, Terence Parr pa...@cs.usfca.edu wrote:

 A lot of you have wondered why I'd don't use enum types for token types in
 the generated Java-based parsers:

 enum TokenType { ID(3), INT(4) };

 I gave it my best shot but once again I found that enums just don't seem to
 work for me. For example, without inheritance how can I define the match
 method?

 void match(TokenType t) {}

 Unfortunately this is in the superclass not the generated class so
 TokenType is not yet defined. Without inheritance, I have to use 
 match(int).
 That means that there's no point in using the enum.

 But, you say, I should be using generics on the parser to pass in the token
 type enum type. Fair enough, And I'll try once I tried to generic'ize the 
 v3
 runtime for v4. We've had some discussion of this on the dev list.

 Ter

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 --
 edgar

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[il-antlr-interest: 28887] [antlr-interest] help please

2010-05-18 Thread Ernesto Castillo
hello everybody my name is Ernesto and i am calling for help on antlr 
programming, i am a newby in this and  i am in my second semester  master , 
after 12 years ago that finish my degree in computer science but because the 
circumstance never work  in the computer  field, but planning to get into, so 
this semester i am taking compiler, and my first  programming assignment was 
really bad because i am not clear how put together the java with the antlr. i 
know how Java work because my first semester i took Java and i used it with 
eclipse . Now i thing i have properly installed the antlr 3.2 nevertheless  i 
do not know if i have to install antlrwork because the IDE , i was trying to do 
the main java with eclipse to invoke antlr but never work . so i feel lost in 
the sea and i have the antlr book but look like is the old version. my computer 
is Mac . i would appreciate the help thanks  



  


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