[HTM Forum] [HTM Theory] Questions on displacement cells activation
[quote="nick, post:1, topic:5439"] Can there be displacement cells representing 2,3,n steps? [/quote] The example you referred to is a bit contrived because it is so small. In a real space, there might be millions of distinct places you might represent, each one of which could have a displacement applied. But yes, you could have a displacement that represented a jump from any location in space to any other. The steps don't really matter. Now think about this in a high-dimensional space and :exploding_head: I don't quite understand your 2nd two questions, but does my answer help explain anything? --- [Visit Topic](https://discourse.numenta.org/t/questions-on-displacement-cells-activation/5439/4) or reply to this email to respond. You are receiving this because you enabled mailing list mode. To unsubscribe from these emails, [click here](https://discourse.numenta.org/email/unsubscribe/321b79ec54da53cf9fde7980f456165471b522baa62f6fed859ee886935b058a).
[HTM Forum] [HTM Theory] Questions on displacement cells activation
Nick, I think I follow you up until the animations. I don't understand how either animation relates to the topic of displacement cells. --- [Visit Topic](https://discourse.numenta.org/t/questions-on-displacement-cells-activation/5439/2) or reply to this email to respond. You are receiving this because you enabled mailing list mode. To unsubscribe from these emails, [click here](https://discourse.numenta.org/email/unsubscribe/b62bd5c74e4f763fc551dc3b5f8f21541a94d01f0ae3e0cb94c1afefc9db24f6).
[HTM Forum] [HTM Theory/Neuroscience] Questions on displacement cells activation
> For example, if cell G(1,1) is active for a location on an object, a movement > one step to the right will cause G(2,1) to become active. Since the cells > tile space, an additional movement one step to the right will cause G(0,1) to > become active.  The supplementary material covers single step movements. In the Grid cell module in the **Figure A** when the cell G(1,1) is active a single step movement can be 1 step to the "left", "right", "up", "down", "left-up", "left-down", "right-up", "right-down" (diagonally) or "none" (same place but 1 step through time). All these count for 9 relative displacements of 1 step. That's why there are 9 Displacement cells representing them in the Displacement module.  **Figure B** shows that independent of which cell performs the 1 step to the right movement D(1,0) will represent the displacement. The formula in the supplementary material for calculating which displacement cell will become active is: G(x1,y1) --> G(x2,y2): D((x2-x1) mod 3, (y2-y1) mod 3) Testing with 1 step to the right: G(0,1) --> G(1,1): D(1 mod 3, 0 mod 3) = D(1,0) G(1,1) --> G(2,1): D(1 mod 3, 0 mod 3) = D(1,0) G(2,1) --> G(0,1): D(-2 mod 3, 0 mod 3) = D(1,0) Testing with 2 steps to the right: G(0,1) --> G(2,1): D(2 mod 3, 0 mod 3) = D(2,0) But D(2,0) is representing 1 step to the left. >From G(0,1) 1 step to the left or 2 steps to the right will both land on >G(2,1) but the displacement is different. Questions: 1. Can there be displacement cells representing 2,3,n steps? 2. Is this problem solved more elegantly by combining grid+displacement cells made to work on a different scale? 4. Is it done by extending the capabilities of displacement cells by changing the anatomy to different types of cells like conjunctive cells? --- [Visit Topic](https://discourse.numenta.org/t/questions-on-displacement-cells-activation/5439/1) or reply to this email to respond. You are receiving this because you enabled mailing list mode. To unsubscribe from these emails, [click here](https://discourse.numenta.org/email/unsubscribe/8b39aba87bc8e8a5ab43027024f608ec20ff3c47902c64dcfdcce0cb3d404b71).
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