On 3 September 2013 15:22, Glenn Fowler wrote:
>
> On Tue, 3 Sep 2013 04:35:56 +0200 Tina Harriott wrote:
>> The arithmetic function int() does not work in sh (AT&T Research) 93v-
>> 2013-08-27
>
>> I get this:
>> ksh -c 'print -- $(( log2( int(pow(2,69) )) ))'
>> 69
>
>> But it should print 'nan', as it does if I use explicitly an
>> intermediate integer variable:
>> ksh -c 'integer i; print -- $(( i=pow(2,69) , log2(i) ))'
>> nan
>
> in ksh93 the int() arith function is an alias for the shell floor()
> which calls the C library floorl() (or floor() if long double not available)
> C floor() has no "too big to fit in C integral value" error
>
> if int(f) is supposed to act like the C cast (int)f then the ksh int() needs
> to
> be its own function that implements the cast (ksh_int_type)f
int() like C++ int() may be more intuitive. I haven't found any
mapping table shell arithmetic function name->C function name so I
assumed it works like C/C++.
Coincidentally there is no float() function to turn an integer into
ksh's equivalent of a long double. The purpose would be to promote the
variables type to a long double (typeset -lE) so that integer x=1;
$((float(x)/3)) yields 0.3
Tina
--
Tina Harriott - Women in Mathematics
Contact: tina.harriott.m...@gmail.com
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