Re: [asterisk-users] PHP can't insert - Can someone please help

2010-07-12 Thread Gerald A
Hi Bruce,

On Sat, Jul 10, 2010 at 2:17 PM, bruce bruce bruceb...@gmail.com wrote:


 I have my html/php file set so that the input field only takes 3 digit 3
 digit 4 digit (NPA, NXX, Block) so your purposal of: *'201,0); drop
 database YOUR_DATABASE'; *would fail due to big length and also I tested
 with inputing letters and my IF function caught it and exited.

 Further more, everything else (other than phone input fields) is drop down
 boxes with specific numbers or letters inserted in them. I should be 100%
 safe with those right?


Another moment of trepidation should be triggered when you use the words
input field as related to forms.

While most people will use an ordinary web browser and whatever fields you
provide, hackers aren't most people. Anyone wanting to break your site isn't
going to be nice and follow the nice rules and use the forms which might
have validation.

Even beginner not-nicers can put together a simple form with your POST as
their target and whatever field lengths and values as they want.

You have to treat all input as hostile, since it all can be. It's the only
way you can be safe.

Thanks,
Gerald
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Re: [asterisk-users] PHP can't insert - Can someone please help

2010-07-11 Thread Matthew J. Roth
Bruce, 

These two links may be helpful to you: 

  PHP: SQL Injection - Manual 
http://www.php.net/manual/en/security.database.sql-injection.php 

  PHP: mysql_real_escape_string - Manual 
http://www.php.net/manual/en/function.mysql-real-escape-string.php 

Regards, 

Matthew Roth 
InterMedia Marketing Solutions 
Software Engineer and Systems Developer 

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Re: [asterisk-users] PHP can't insert - Can someone please help

2010-07-10 Thread Zeeshan Zakaria
Its not wise to haste in posting for help without first spending sometime
thinking yourself. Your mysql syntax is not right, you can clearly see the
missing single quotes starting from 'ext-local. I would also suggest to use
a different syntax for this mysql statement, i.e. using SET instead of
VALUES, which makes the syntax much clearer, i.e. INSERT INTO `table` SET
`col1` =  'value1', `col2`= 'val2' and so on.

Zeeshan A Zakaria

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On 2010-07-10 12:13 AM, bruce bruce bruceb...@gmail.com wrote:

Hi Guys,

I am making another module for Voicemail. I have three fields in a POST form
that have to be connected together to make it a single 10 digit number but
there is something wrong in my syntax probably.


$npaa = ('$_POST[anpa]');
$nxxa = ('$_POST[anxx]');
$blocka = ('$_POST[ablock]');

*$grplist = $npaa.$nxxa.$blocka;*

$sql=INSERT INTO findmefollow(grpnum, strategy, grptime, grppre, grplist,
annmsg_id, postdest, dring, needsconf, remotealert_id, toolate_id, ringing,
pre_ring)
VALUES 
('$_POST[grpnum]','ringall','$_POST[grptime]','$_POST[grppre]',$grplist,'0','$_POST[postdest]','','','0','0','Ring','$_POST[pre_ring]');


It seems that $grplist is the problem. Can someone please point what is
wrong?

Error:
Error: You have an error in your SQL syntax; check the manual that
corresponds to your MySQL server version for the right syntax to use near
'('333')(''),'0','ext-local,vmb2000,1','','','0','0','Ring','0')' at
line 3

Thanks,
Bruce

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Re: [asterisk-users] PHP can't insert - Can someone please help

2010-07-10 Thread bruce bruce
Thank you for the amazing reply. First few lines of your e-mail was EXACTLY
getting me to where I made a mistake. I guess I didn't take the () and ' '
at their face value and was looking somewhere else for the problem.

For sanatizing you mean checking the numbers to make sure they are valid
numbers and not alphabet or other charecters? or, are you pointing the fact
that I am keeping mysql root password in plain .php file? I have done an
include of a php file which has mysql root password and that is insert as an
#incldue in the html file. So, if someone checks source for html can't see
mysql root password. Even though root is user on mysql is to accept only
from localhost.

I would really appreciate it if you can weigh in on it a bit.

Thanks,
Bruce

On Sat, Jul 10, 2010 at 7:42 AM, Gerald A geraldabli...@gmail.com wrote:

 Hi Bruce,

 First, your problem isn't PHP, it seems to be SQL and I'm guessing MySQL at
 that.

 Next, you seem to be accepting user input and not sanatizing it. DANGER
 WILL ROBINSON!!!
 This is bad, because it leaves you open to something known as a SQL
 injection attack.

 Now, as to syntax:

 On Sat, Jul 10, 2010 at 12:07 AM, bruce bruce bruceb...@gmail.com wrote:


 I am making another module for Voicemail. I have three fields in a POST
 form that have to be connected together to make it a single 10 digit number
 but there is something wrong in my syntax probably.


 $npaa = ('$_POST[anpa]');
 $nxxa = ('$_POST[anxx]');
 $blocka = ('$_POST[ablock]');

 *$grplist = $npaa.$nxxa.$blocka;*


 Ok, so suppose arpa=111, anxx=222 and ablock=.
 grplist would then be ('111')('333')('').

  $sql=INSERT INTO findmefollow(grpnum, strategy, grptime, grppre,
 grplist, annmsg_id, postdest, dring, needsconf, remotealert_id, toolate_id,
 ringing, pre_ring)
 VALUES 
 ('$_POST[grpnum]','ringall','$_POST[grptime]','$_POST[grppre]',$grplist,'0','$_POST[postdest]','','','0','0','Ring','$_POST[pre_ring]');


 It seems that $grplist is the problem. Can someone please point what is
 wrong?

 Error:
 Error: You have an error in your SQL syntax; check the manual that
 corresponds to your MySQL server version for the right syntax to use near
 '('333')(''),'0','ext-local,vmb2000,1','','','0','0','Ring','0')' at
 line 3


 Look closesly, grasshopper. See it? (Does the hint above help?) Hmmm, ok.

 Let's write the line as SQL:
 INSERT INTO findmefollow(grpnum, strategy, grptime, grppre, grplist,
 annmsg_id, postdest, dring, needsconf, remotealert_id, toolate_id, ringing,
 pre_ring)
 VALUES 
 ('0','ringall','0','0',('111')('333')(''),'0','0','','','0','0','Ring','0');

 Clear now? You are trying to insert the raw value --
 ('111')('333')('') -- into your database. This can't make any sense
 except as string, And this isn't one.

 I think what you might have meant is to quote the _whole thing_ as a
 string, and not the individual pieces. Then:
 $grplist = '(.$npaa.$nxxa.$blocka.)';
 and
 $blocka = ($_POST[ablock]);  # and for all of them above

 This would make the value '(111)(333)()', which should work fine.

 Now, if you really meant to add in the quotes, you'll have to quote the
 quotes, which can be hard to do in good times.

 Hope this helps,
 Gerald.

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Re: [asterisk-users] PHP can't insert - Can someone please help

2010-07-10 Thread bruce bruce
Further to my last post, I added this to santize. I also created a new mysql
user with access to only findmefollow portion of the asterisk table for
limited access and assigned only two simultaneous connections with only 10
changes queries per hour (as I know that no more queries will be put through
probably)

if ($npaa=200  $nxxa=200  $npaa!=900  $npaa!=911)

Should that suffice against SQL injections? The if condition changes the
string to number so it removes the chance of people adding
other characters and it also sticks to format NPAN or 2XX2.

Thanks

On Sat, Jul 10, 2010 at 10:21 AM, bruce bruce bruceb...@gmail.com wrote:

 Thank you for the amazing reply. First few lines of your e-mail was EXACTLY
 getting me to where I made a mistake. I guess I didn't take the () and ' '
 at their face value and was looking somewhere else for the problem.

 For sanatizing you mean checking the numbers to make sure they are valid
 numbers and not alphabet or other charecters? or, are you pointing the fact
 that I am keeping mysql root password in plain .php file? I have done an
 include of a php file which has mysql root password and that is insert as an
 #incldue in the html file. So, if someone checks source for html can't see
 mysql root password. Even though root is user on mysql is to accept only
 from localhost.

 I would really appreciate it if you can weigh in on it a bit.

 Thanks,
 Bruce


 On Sat, Jul 10, 2010 at 7:42 AM, Gerald A geraldabli...@gmail.com wrote:

 Hi Bruce,

 First, your problem isn't PHP, it seems to be SQL and I'm guessing MySQL
 at that.

 Next, you seem to be accepting user input and not sanatizing it. DANGER
 WILL ROBINSON!!!
 This is bad, because it leaves you open to something known as a SQL
 injection attack.

 Now, as to syntax:

 On Sat, Jul 10, 2010 at 12:07 AM, bruce bruce bruceb...@gmail.comwrote:


 I am making another module for Voicemail. I have three fields in a POST
 form that have to be connected together to make it a single 10 digit number
 but there is something wrong in my syntax probably.


 $npaa = ('$_POST[anpa]');
 $nxxa = ('$_POST[anxx]');
 $blocka = ('$_POST[ablock]');

 *$grplist = $npaa.$nxxa.$blocka;*


 Ok, so suppose arpa=111, anxx=222 and ablock=.
 grplist would then be ('111')('333')('').

  $sql=INSERT INTO findmefollow(grpnum, strategy, grptime, grppre,
 grplist, annmsg_id, postdest, dring, needsconf, remotealert_id, toolate_id,
 ringing, pre_ring)
 VALUES 
 ('$_POST[grpnum]','ringall','$_POST[grptime]','$_POST[grppre]',$grplist,'0','$_POST[postdest]','','','0','0','Ring','$_POST[pre_ring]');


 It seems that $grplist is the problem. Can someone please point what is
 wrong?

 Error:
 Error: You have an error in your SQL syntax; check the manual that
 corresponds to your MySQL server version for the right syntax to use near
 '('333')(''),'0','ext-local,vmb2000,1','','','0','0','Ring','0')' at
 line 3


 Look closesly, grasshopper. See it? (Does the hint above help?) Hmmm, ok.

 Let's write the line as SQL:
 INSERT INTO findmefollow(grpnum, strategy, grptime, grppre, grplist,
 annmsg_id, postdest, dring, needsconf, remotealert_id, toolate_id, ringing,
 pre_ring)
 VALUES 
 ('0','ringall','0','0',('111')('333')(''),'0','0','','','0','0','Ring','0');

 Clear now? You are trying to insert the raw value --
 ('111')('333')('') -- into your database. This can't make any sense
 except as string, And this isn't one.

 I think what you might have meant is to quote the _whole thing_ as a
 string, and not the individual pieces. Then:
 $grplist = '(.$npaa.$nxxa.$blocka.)';
 and
 $blocka = ($_POST[ablock]);  # and for all of them above

 This would make the value '(111)(333)()', which should work fine.

 Now, if you really meant to add in the quotes, you'll have to quote the
 quotes, which can be hard to do in good times.

 Hope this helps,
 Gerald.



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Re: [asterisk-users] PHP can't insert - Can someone please help

2010-07-10 Thread Gerald A
Hi Bruce,

On Sat, Jul 10, 2010 at 11:12 AM, bruce bruce bruceb...@gmail.com wrote:

 Further to my last post, I added this to santize. I also created a new
 mysql user with access to only findmefollow portion of the asterisk table
 for limited access and assigned only two simultaneous connections with only
 10 changes queries per hour (as I know that no more queries will be put
 through probably)

 if ($npaa=200  $nxxa=200  $npaa!=900  $npaa!=911)

 Should that suffice against SQL injections? The if condition changes the
 string to number so it removes the chance of people adding
 other characters and it also sticks to format NPAN or 2XX2.


There are two things -- the first is, who call this script? If it's
something you control 100%, you can mitigate the risk a bit. I don't really
like this tact, because if the script gets repurposed, you end up with
something that could be very dangerous.

The second thing is simple -- most people think small here, but you have to
think big and know a bit about how PHP works. PHP strings are pretty amazing
things, and one of the pesky things is that you can put all kinds of things
in it. Now, if that string variable is created as a result of a form input,
then that string can be anything. For a moment, think about if it $npaa =
'201,0); drop database YOUR_DATABASE'; Now, that is pretty nasty, and it
would muck up further SQL injections, but now you get the idea. You should
always check to make sure the data you are getting is what you are
expecting, and exclude what you aren't.

So, are your tests sufficient? I can't remember off the top of my head if
the string - integer only considers the first number, or it considers the
whole string. (PHP usually errs on the side of ease of use, so I think my
snippet above would still pass your test). If your expecting only numbers,
I'd write a function that ensures that only numbers are parts of the input.
(And not just for the 3 above variables).
Really, you should never see $_POST(var) (or any PHP CGI variable) that
derives directly from user input.

It takes a few minutes extra, but it'll save hours of sorting later if you
get hit by a SQL injection.

Hope this helps,
Gerald
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Re: [asterisk-users] PHP can't insert - Can someone please help

2010-07-10 Thread bruce bruce
Thanks again. Apparently all POST variables come through as strings. The
function you pointed out is I think already built in php as

is_numeric() http://www.php.net/manual/en/function.is-numeric.php.

http://php.net/manual/en/function.is-int.php
http://www.php.net/manual/en/function.is-numeric.php

http://www.php.net/manual/en/function.is-numeric.phpIf that runs TRUE and
if I keep my =200 and !=911 or !900 I should be safe from SQL injections.
And along with dial-out routes rules, I think I can make this stronger.

I have my html/php file set so that the input field only takes 3 digit 3
digit 4 digit (NPA, NXX, Block) so your purposal of: *'201,0); drop database
YOUR_DATABASE'; *would fail due to big length and also I tested with
inputing letters and my IF function caught it and exited.

Further more, everything else (other than phone input fields) is drop down
boxes with specific numbers or letters inserted in them. I should be 100%
safe with those right?

By using form POST there should be no other loop holes left opened right?
It's not like php $_GET so people can't try typing to the browser in this
format:

http://www.w3schools.com/welcome.php?fname=Peterage=37

Thanks a lot,
Bruce

On Sat, Jul 10, 2010 at 1:41 PM, Gerald A geraldabli...@gmail.com wrote:

 Hi Bruce,

 On Sat, Jul 10, 2010 at 11:12 AM, bruce bruce bruceb...@gmail.com wrote:

 Further to my last post, I added this to santize. I also created a new
 mysql user with access to only findmefollow portion of the asterisk table
 for limited access and assigned only two simultaneous connections with only
 10 changes queries per hour (as I know that no more queries will be put
 through probably)

 if ($npaa=200  $nxxa=200  $npaa!=900  $npaa!=911)

 Should that suffice against SQL injections? The if condition changes the
 string to number so it removes the chance of people adding
 other characters and it also sticks to format NPAN or 2XX2.


 There are two things -- the first is, who call this script? If it's
 something you control 100%, you can mitigate the risk a bit. I don't really
 like this tact, because if the script gets repurposed, you end up with
 something that could be very dangerous.

 The second thing is simple -- most people think small here, but you have to
 think big and know a bit about how PHP works. PHP strings are pretty amazing
 things, and one of the pesky things is that you can put all kinds of things
 in it. Now, if that string variable is created as a result of a form input,
 then that string can be anything. For a moment, think about if it $npaa =
 '201,0); drop database YOUR_DATABASE'; Now, that is pretty nasty, and it
 would muck up further SQL injections, but now you get the idea. You should
 always check to make sure the data you are getting is what you are
 expecting, and exclude what you aren't.

 So, are your tests sufficient? I can't remember off the top of my head if
 the string - integer only considers the first number, or it considers the
 whole string. (PHP usually errs on the side of ease of use, so I think my
 snippet above would still pass your test). If your expecting only numbers,
 I'd write a function that ensures that only numbers are parts of the input.
 (And not just for the 3 above variables).
 Really, you should never see $_POST(var) (or any PHP CGI variable) that
 derives directly from user input.

 It takes a few minutes extra, but it'll save hours of sorting later if you
 get hit by a SQL injection.

 Hope this helps,
 Gerald

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Re: [asterisk-users] PHP can't insert - Can someone please help

2010-07-10 Thread bruce bruce
Here is the steel strong sanitizer:

$npaa = $_POST[anpa];
$nxxa = $_POST[anxx];
$blocka = $_POST[ablock];

# Sanitize
$blocka_san = strspn($blocka, 0123456789);

*if ($blocka_san==4  is_numeric($npaa)  is_numeric($nxxa) 
is_numeric($blocka)  $npaa=200  $nxxa=200  $npaa!=900 
$npaa!=911) *
*
*
*  {*

  echo Number passed sanitization;

  }

What do you think? :-)

-Bruce
On Sat, Jul 10, 2010 at 2:17 PM, bruce bruce bruceb...@gmail.com wrote:

 Thanks again. Apparently all POST variables come through as strings. The
 function you pointed out is I think already built in php as

 is_numeric() http://www.php.net/manual/en/function.is-numeric.php.

 http://php.net/manual/en/function.is-int.php
 http://www.php.net/manual/en/function.is-numeric.php

 http://www.php.net/manual/en/function.is-numeric.phpIf that runs TRUE
 and if I keep my =200 and !=911 or !900 I should be safe from SQL
 injections. And along with dial-out routes rules, I think I can make this
 stronger.

 I have my html/php file set so that the input field only takes 3 digit 3
 digit 4 digit (NPA, NXX, Block) so your purposal of: *'201,0); drop
 database YOUR_DATABASE'; *would fail due to big length and also I tested
 with inputing letters and my IF function caught it and exited.

 Further more, everything else (other than phone input fields) is drop down
 boxes with specific numbers or letters inserted in them. I should be 100%
 safe with those right?

 By using form POST there should be no other loop holes left opened right?
 It's not like php $_GET so people can't try typing to the browser in this
 format:

 http://www.w3schools.com/welcome.php?fname=Peterage=37

 Thanks a lot,
 Bruce

 On Sat, Jul 10, 2010 at 1:41 PM, Gerald A geraldabli...@gmail.com wrote:

 Hi Bruce,

 On Sat, Jul 10, 2010 at 11:12 AM, bruce bruce bruceb...@gmail.comwrote:

 Further to my last post, I added this to santize. I also created a new
 mysql user with access to only findmefollow portion of the asterisk table
 for limited access and assigned only two simultaneous connections with only
 10 changes queries per hour (as I know that no more queries will be put
 through probably)

 if ($npaa=200  $nxxa=200  $npaa!=900  $npaa!=911)

 Should that suffice against SQL injections? The if condition changes the
 string to number so it removes the chance of people adding
 other characters and it also sticks to format NPAN or 2XX2.


 There are two things -- the first is, who call this script? If it's
 something you control 100%, you can mitigate the risk a bit. I don't really
 like this tact, because if the script gets repurposed, you end up with
 something that could be very dangerous.

 The second thing is simple -- most people think small here, but you have
 to think big and know a bit about how PHP works. PHP strings are pretty
 amazing things, and one of the pesky things is that you can put all kinds of
 things in it. Now, if that string variable is created as a result of a form
 input, then that string can be anything. For a moment, think about if it
 $npaa = '201,0); drop database YOUR_DATABASE'; Now, that is pretty nasty,
 and it would muck up further SQL injections, but now you get the idea. You
 should always check to make sure the data you are getting is what you are
 expecting, and exclude what you aren't.

 So, are your tests sufficient? I can't remember off the top of my head if
 the string - integer only considers the first number, or it considers the
 whole string. (PHP usually errs on the side of ease of use, so I think my
 snippet above would still pass your test). If your expecting only numbers,
 I'd write a function that ensures that only numbers are parts of the input.
 (And not just for the 3 above variables).
 Really, you should never see $_POST(var) (or any PHP CGI variable) that
 derives directly from user input.

 It takes a few minutes extra, but it'll save hours of sorting later if you
 get hit by a SQL injection.

 Hope this helps,
 Gerald



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Re: [asterisk-users] PHP can't insert - Can someone please help

2010-07-10 Thread Steve Edwards

On Sat, 10 Jul 2010, bruce bruce wrote:


Here is the steel strong sanitizer:
$npaa = $_POST[anpa];
$nxxa = $_POST[anxx];
$blocka = $_POST[ablock];

# Sanitize
$blocka_san = strspn($blocka, 0123456789);

if ($blocka_san==4  is_numeric($npaa)  is_numeric($nxxa)  
is_numeric($blocka)  $npaa=200  $nxxa=200  $npaa!=900  
$npaa!=911) 

              {
  echo Number passed sanitization;
              }

What do you think? :-)


Yuk.

On Sat, Jul 10, 2010 at 2:17 PM, bruce bruce bruceb...@gmail.com 
wrote:



Thanks again. Apparently all POST variables come through as strings.


You may want to read the relevant RFCs. Look for ENCTYPE.

The function you pointed out is I think already built in php 
as is_numeric(). 


http://www.php.net/manual/en/function.is-numeric.php


You may want to read the function definition again. It allows plus, 
exponential notation and hexadecimal notation as well.


I have my html/php file set so that the input field only takes 3 digit 3 
digit 4 digit (NPA, NXX, Block) so your purposal of: '201,0); drop 
database YOUR_DATABASE'; would fail due to big length and also I tested 
with inputing letters and my IF function caught it and exited.


Further more, everything else (other than phone input fields) is drop 
down boxes with specific numbers or letters inserted in them. I should 
be 100% safe with those right?


By using form POST there should be no other loop holes left opened 
right? It's not like php $_GET so people can't try typing to the browser 
in this format:


You may want to read the man pages for curl and wget -- both can submit 
POST requests.


--
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-
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[asterisk-users] PHP can't insert - Can someone please help

2010-07-09 Thread bruce bruce
Hi Guys,

I am making another module for Voicemail. I have three fields in a POST form
that have to be connected together to make it a single 10 digit number but
there is something wrong in my syntax probably.


$npaa = ('$_POST[anpa]');
$nxxa = ('$_POST[anxx]');
$blocka = ('$_POST[ablock]');

*$grplist = $npaa.$nxxa.$blocka;*

$sql=INSERT INTO findmefollow(grpnum, strategy, grptime, grppre, grplist,
annmsg_id, postdest, dring, needsconf, remotealert_id, toolate_id, ringing,
pre_ring)
VALUES 
('$_POST[grpnum]','ringall','$_POST[grptime]','$_POST[grppre]',$grplist,'0','$_POST[postdest]','','','0','0','Ring','$_POST[pre_ring]');


It seems that $grplist is the problem. Can someone please point what is
wrong?

Error:
Error: You have an error in your SQL syntax; check the manual that
corresponds to your MySQL server version for the right syntax to use near
'('333')(''),'0','ext-local,vmb2000,1','','','0','0','Ring','0')' at
line 3

Thanks,
Bruce
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