[asterisk-users] Understanding CHANNEL function values

2012-08-25 Thread Stefan at WPF
Hello all,

I need some help understand the values of the CHANNEL function, e.g.

 txploss // local packets loss
 rxploss // remote packets loss
 txjitter  // local jitter
 rxjitter  // remote jitter


My main problem in understand is that a CHANNEL has two nodes (sender and
receiver), while a typical setup includes at least 3 nodes:
SIP phone - Asterisk - SIP Provider ( - each is a node)

1) So e.g. txploss, is it
- what is lost between SIP phone and Asterisk
- what is lost between Asterisk and SIP Provider
- or probably both?

I guess the SIP Provider sends back a info about missed packets, then it
wouldn't be relevant where they got lost, but just that they were lost
somewhere between the SIP phone and the SIP Provider?


2) Also, how can I monitor only the connections SIP phone - Asterisk and
Asterisk - SIP Provider each on their own?


3) txploss are the lost packets in the direction from SIP phone to SIP
provider, right? I am aware of tx and rx and what it normally means, but in
this case it would also fit the other way round ;-)


4) I always have txjitter but never rxjitter, does this make sense?
Shouldn't txjitter be less of a problem? Also, how exactly is the txjitter
/ jitter in general defined in Asterisk?


Thanks very much and best regards
Stefan
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Re: [asterisk-users] Understanding CHANNEL function values

2012-08-25 Thread Patrick Lists

On 25-08-12 14:31, Stefan at WPF wrote:

Hello all,

I need some help understand the values of the CHANNEL function, e.g.

txploss // local packets loss
rxploss // remote packets loss
txjitter  // local jitter
rxjitter  // remote jitter


My main problem in understand is that a CHANNEL has two nodes (sender
and receiver), while a typical setup includes at least 3 nodes:
SIP phone - Asterisk - SIP Provider ( - each is a node)

1) So e.g. txploss, is it
- what is lost between SIP phone and Asterisk
- what is lost between Asterisk and SIP Provider
- or probably both?


I would assume that those statistics apply to a leg and not an 
end-to-end connection. So in your example I would assume that a txploss 
value is determined for the leg between the SIP phone and the Asterisk 
server and another txploss value is determined for the leg between the 
Asterisk server and the upstream SIP provider.


Interesting stuff. If you figure it all out, please update this thread 
(and possibly the wiki).


Regards,
Patrick


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Re: [asterisk-users] Understanding CHANNEL function values

2012-08-25 Thread Stefan at WPF
Hello Patrick,

there are the channel and dstchannel properties of the CHANNEL function,
indicating that the channel is some kind of virtual connection between the
sip phone and the sip provider, so it seems not to be for legs or at least
the output values are already a combination of both legs. (I also would
find it more intuitive to have 2 legs and values for those instead of one
single value for 2 legs, but lets wait to find out, how to interpret those
things).

2012/8/25 Patrick Lists asterisk-l...@puzzled.xs4all.nl

 On 25-08-12 14:31, Stefan at WPF wrote:

 Hello all,

 I need some help understand the values of the CHANNEL function, e.g.

 txploss // local packets loss
 rxploss // remote packets loss
 txjitter  // local jitter
 rxjitter  // remote jitter


 My main problem in understand is that a CHANNEL has two nodes (sender
 and receiver), while a typical setup includes at least 3 nodes:
 SIP phone - Asterisk - SIP Provider ( - each is a node)

 1) So e.g. txploss, is it
 - what is lost between SIP phone and Asterisk
 - what is lost between Asterisk and SIP Provider
 - or probably both?


 I would assume that those statistics apply to a leg and not an end-to-end
 connection. So in your example I would assume that a txploss value is
 determined for the leg between the SIP phone and the Asterisk server and
 another txploss value is determined for the leg between the Asterisk server
 and the upstream SIP provider.

 Interesting stuff. If you figure it all out, please update this thread
 (and possibly the wiki).

 Regards,
 Patrick


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