[Aus-soaring] Maths and rope breaks

2008-09-10 Thread Texler, Michael
I was by no way suggesting that one does the maths whilst in flight.

It is used as the justification for performing such manoevures!

Ok, radius of turn is given by R=V*V/(g*tan(bank))

R is radius in metres
V is given in metres per second
g is acceleration due gravity = 9.81 m/s/s
Bank = angle of bank (AOB) in degrees (0=level)

To convert knots to metres per second use:
Airspeed in knots * 0.515 =metres/second.

Given an example sink rate (i.e Bergfalke IV) at zero angle of bank at 60 KIAS 
as -3m/s (almost 600fpm down), making an approximation that the sink rate for a 
particular angle of bank is = 1/cos(bank).

So at 30 degree AOB, the sink rate is -3.5m/s
At 45 degree AOB, the sink rate is -4.2m/s
At 60 degree AOB, the sink rate is -6

Hence pluging in values:
At an airspeed of 60 knots
AOB = 30, radius of turn is 552 feet = circling diameter of 336 metres
AOB 45, radius = 319 feet, = circling diameter of 194 metres
AOB 60, radius = 184 feet, = circling diameter of 112 metres

The distance to travel half way around these circels (180 degree turn) is pi * 
diameter, time required to go the distance is distance travelled / airspeed

AOB=30, distance=529m, time required=17secs, height loss (at sink of 3.5m/s) = 
194 feet, diameter 336m
AOB=45, distance=305m, time required=10secs, height loss (at sink of 4.2m/s) = 
137 feet, diameter 194m
AOB=60, distance=176m, time required=6secs, height loss (at sink of 6m/s) = 112 
feet, diameter 112m

Remember that the wider the diameter of the turn, you will have to turn through 
more than 180 degrees to get back to the strip, because the shallower turn will 
carry you further away from the airfield.

These figures are for still air, add at least another 60ft to the height loss 
to allow for the surprise factor (i.e. in the 5-6seconds after the rope break, 
allowing for reaction times, and time to stabilise speed before turning). That 
is your level sink rate is 600fpm (i.e. 10 feet per second down), hence over 6 
seconds, you would descend 60 feet).

I will let people go figure what course of action they would decide.

I sincerely hope that people have this all thought through when they do their 
pre-take-off checks, always(hint: it is under O for outside, obtacles and 
options).

I have my flame suit on, and I am prepared for feedback re the maths

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Re: [Aus-soaring] Maths and rope breaks

2008-09-10 Thread Colin Collyer

Hey Michael
 I was just being smart, suggesting that instinct should be  inbuilt... 
maths only for those that like figures. Having said that, your maths is 
interesting... Imagine this, at the end of the 180 turn, if (but its not 
) still at  60 deg bank, the wingtip is going to be about 300 ft  away 
from the ground.. That should get them out of the club house to watch
  And a 180 only gets you going the other way, still over the next 
door paddock.   If you were to use a procedure turn to get you lined up, 
you can add another 2 X 90 deg turns, and a roll of 120 deg. Youv'e 
really got their attention now !

 Pulling the bung at 400 ft.. not much safety space
 And no, I don't know how to teach it realistically
 Cheers
 Col

Texler, Michael wrote:

I was by no way suggesting that one does the maths whilst in flight.

It is used as the justification for performing such manoevures!

Ok, radius of turn is given by R=V*V/(g*tan(bank))

R is radius in metres
V is given in metres per second
g is acceleration due gravity = 9.81 m/s/s
Bank = angle of bank (AOB) in degrees (0=level)

To convert knots to metres per second use:
Airspeed in knots * 0.515 =metres/second.

Given an example sink rate (i.e Bergfalke IV) at zero angle of bank at 60 KIAS 
as -3m/s (almost 600fpm down), making an approximation that the sink rate for a 
particular angle of bank is = 1/cos(bank).

So at 30 degree AOB, the sink rate is -3.5m/s
At 45 degree AOB, the sink rate is -4.2m/s
At 60 degree AOB, the sink rate is -6

Hence pluging in values:
At an airspeed of 60 knots
AOB = 30, radius of turn is 552 feet = circling diameter of 336 metres
AOB 45, radius = 319 feet, = circling diameter of 194 metres
AOB 60, radius = 184 feet, = circling diameter of 112 metres

The distance to travel half way around these circels (180 degree turn) is pi * 
diameter, time required to go the distance is distance travelled / airspeed

AOB=30, distance=529m, time required=17secs, height loss (at sink of 3.5m/s) = 
194 feet, diameter 336m
AOB=45, distance=305m, time required=10secs, height loss (at sink of 4.2m/s) = 
137 feet, diameter 194m
AOB=60, distance=176m, time required=6secs, height loss (at sink of 6m/s) = 112 
feet, diameter 112m

Remember that the wider the diameter of the turn, you will have to turn through 
more than 180 degrees to get back to the strip, because the shallower turn will 
carry you further away from the airfield.

These figures are for still air, add at least another 60ft to the height loss 
to allow for the surprise factor (i.e. in the 5-6seconds after the rope break, 
allowing for reaction times, and time to stabilise speed before turning). That 
is your level sink rate is 600fpm (i.e. 10 feet per second down), hence over 6 
seconds, you would descend 60 feet).

I will let people go figure what course of action they would decide.

I sincerely hope that people have this all thought through when they do their 
pre-take-off checks, always(hint: it is under O for outside, obtacles and 
options).

I have my flame suit on, and I am prepared for feedback re the maths

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Re: [Aus-soaring] Maths and rope breaks

2008-09-10 Thread Tom Wilksch

Could teach it in a Simulator :-)

*plug plug*


- Original Message - 
From: Colin Collyer [EMAIL PROTECTED]
To: Discussion of issues relating to Soaring in Australia. 
aus-soaring@lists.internode.on.net

Sent: Thursday, September 11, 2008 2:25 PM
Subject: Re: [Aus-soaring] Maths and rope breaks



Hey Michael
 I was just being smart, suggesting that instinct should be  inbuilt... 
maths only for those that like figures. Having said that, your maths is 
interesting... Imagine this, at the end of the 180 turn, if (but its not ) 
still at  60 deg bank, the wingtip is going to be about 300 ft  away from 
the ground.. That should get them out of the club house to watch
  And a 180 only gets you going the other way, still over the next 
door paddock.   If you were to use a procedure turn to get you lined up, 
you can add another 2 X 90 deg turns, and a roll of 120 deg. Youv'e really 
got their attention now !

 Pulling the bung at 400 ft.. not much safety space
 And no, I don't know how to teach it realistically
 Cheers
 Col

Texler, Michael wrote:

I was by no way suggesting that one does the maths whilst in flight.

It is used as the justification for performing such manoevures!

Ok, radius of turn is given by R=V*V/(g*tan(bank))

R is radius in metres
V is given in metres per second
g is acceleration due gravity = 9.81 m/s/s
Bank = angle of bank (AOB) in degrees (0=level)

To convert knots to metres per second use:
Airspeed in knots * 0.515 =metres/second.

Given an example sink rate (i.e Bergfalke IV) at zero angle of bank at 60 
KIAS as -3m/s (almost 600fpm down), making an approximation that the sink 
rate for a particular angle of bank is = 1/cos(bank).


So at 30 degree AOB, the sink rate is -3.5m/s
At 45 degree AOB, the sink rate is -4.2m/s
At 60 degree AOB, the sink rate is -6

Hence pluging in values:
At an airspeed of 60 knots
AOB = 30, radius of turn is 552 feet = circling diameter of 336 metres
AOB 45, radius = 319 feet, = circling diameter of 194 metres
AOB 60, radius = 184 feet, = circling diameter of 112 metres

The distance to travel half way around these circels (180 degree turn) is 
pi * diameter, time required to go the distance is distance travelled / 
airspeed


AOB=30, distance=529m, time required=17secs, height loss (at sink of 
3.5m/s) = 194 feet, diameter 336m
AOB=45, distance=305m, time required=10secs, height loss (at sink of 
4.2m/s) = 137 feet, diameter 194m
AOB=60, distance=176m, time required=6secs, height loss (at sink of 6m/s) 
= 112 feet, diameter 112m


Remember that the wider the diameter of the turn, you will have to turn 
through more than 180 degrees to get back to the strip, because the 
shallower turn will carry you further away from the airfield.


These figures are for still air, add at least another 60ft to the height 
loss to allow for the surprise factor (i.e. in the 5-6seconds after the 
rope break, allowing for reaction times, and time to stabilise speed 
before turning). That is your level sink rate is 600fpm (i.e. 10 feet per 
second down), hence over 6 seconds, you would descend 60 feet).


I will let people go figure what course of action they would decide.

I sincerely hope that people have this all thought through when they do 
their pre-take-off checks, always(hint: it is under O for outside, 
obtacles and options).


I have my flame suit on, and I am prepared for feedback re the maths

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Re: [Aus-soaring] Maths and rope breaks

2008-09-10 Thread Scott Penrose

On a parallel note...

I always loved the bit of the C Certificate which requires you to show  
an entry into and recovery from a spin - that can be viewed from the  
glider or the ground.


Wo while watching, the instructor will probably not offer a C- 
Certificate from the student who can't recover from the spin.


Scott

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Re: [Aus-soaring] Maths and rope breaks

2008-09-10 Thread Mike Borgelt

Michael,

I'm sure Anthony thinks his Bergie  goes better than that.

You have also not shown that 60 degrees is a minimum height loss just 
lower than 30 and 45 degrees.


I take it you aren't a fan of a quick pull to vertical, stall turn 
and recover from dive going in the opposite direction with minimum offset?


Thre's the sound of crickets chirping here from the instructors who 
were vocal about doing low altitude practice rope breaks. Surely 
somebody will be brave enough to give us an answer?


Mike

Borgelt Instruments - manufacturers of quality soaring instruments
phone Int'l + 61 746 355784
fax   Int'l + 61 746 358796
cellphone Int'l + 61 428 355784
  Int'l + 61 429 355784
email:   [EMAIL PROTECTED]
website: www.borgeltinstruments.com

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Re: [Aus-soaring] Maths and rope breaks

2008-09-10 Thread Colin Collyer

Hey Mike
 A stall turn from level flight at 'normal' speed.. Ill come 
outside and watch that.

 In  aero modeling, we'd bring a plastic bag for the bits too !
 Cheers
 Col

Mike Borgelt wrote:

Michael,

I'm sure Anthony thinks his Bergie  goes better than that.

You have also not shown that 60 degrees is a minimum height loss just 
lower than 30 and 45 degrees.


I take it you aren't a fan of a quick pull to vertical, stall turn and 
recover from dive going in the opposite direction with minimum offset?


Thre's the sound of crickets chirping here from the instructors who were 
vocal about doing low altitude practice rope breaks. Surely somebody 
will be brave enough to give us an answer?


Mike

Borgelt Instruments - manufacturers of quality soaring instruments
phone Int'l + 61 746 355784
fax   Int'l + 61 746 358796
cellphone Int'l + 61 428 355784
  Int'l + 61 429 355784
email:   [EMAIL PROTECTED]
website: www.borgeltinstruments.com

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Re: [Aus-soaring] Maths and rope breaks

2008-09-10 Thread Kevin Roden
I take it you aren't a fan of a quick pull to vertical, stall turn and
recover from dive going in the opposite direction with minimum offset?

Of course, that is the best way to obtain the maximum benefit from dynamic
soaring.

Kevin

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