On Wednesday 30 April 2003 08:44 am, Jacques Kerner wrote:Thank you very much, it works great. I had missed the fact that create_thread makes a copy
Hi,
I get the following error :
error C2664: 'void boost::function0<R,Allocator>::assign_to(Functor)' : unable to convert parameter 1 from 'const CTaskManager' to 'CTaskManager'
when doing this :
class CTaskManager { public: CTaskManager(); ~CTaskManager(); void operator()() {}
private: boost::mutex m_mutex; }
and
CTaskManager taskManager; boost::thread_group mainThreadGroup; mainThreadGroup.create_thread(taskManager); mainThreadGroup.join_all();
The error dissapears when I remove the mutex from the definition of CTaskManager ... (?!!)
So what is the right way to use mutex and threads together? Do I have to
declare the mutex outside of the
functor? Why?
Mutexes are not copyable, and when you pass taskManager to create_thread it tries to make a local copy of the function object . If you would prefer to pass a reference to taskManager to create_thread, do this:
mainThreadGroup.create_thread(boost::ref(taskManager));
Doug
_______________________________________________ Unsubscribe & other changes: http://lists.boost.org/mailman/listinfo.cgi/boost
of the functor. Thanks again!
_______________________________________________ Unsubscribe & other changes: http://lists.boost.org/mailman/listinfo.cgi/boost