Re: [bash 3.1.5] sh -c echo -n ok broken
So, it is possible to have both the following working in sh and bash echo -n ok echo ok\c No. In posix mode, they are fundamentally incompatible. The combination of posix mode and xpg-echo cause bash to be strictly posix compliant and disable any option processing. This is item `c' in the New Features section of NEWS. Chet -- ``The lyf so short, the craft so long to lerne.'' - Chaucer ( ``Discere est Dolere'' -- chet ) Live Strong. Chet Ramey, ITS, CWRU[EMAIL PROTECTED]http://tiswww.tis.case.edu/~chet/ ___ Bug-bash mailing list Bug-bash@gnu.org http://lists.gnu.org/mailman/listinfo/bug-bash
Re: [bash 3.1.5] sh -c echo -n ok broken
On Wednesday 18 January 2006 18:34, Jeff Chua wrote: GNU bash, version 3.1.5(1)-release sh -c echo -n ok returns -n ok. works correctly for me: [EMAIL PROTECTED] 0 ~ $ sh -c echo -n ok [EMAIL PROTECTED] 0 ~ $ -mike ___ Bug-bash mailing list Bug-bash@gnu.org http://lists.gnu.org/mailman/listinfo/bug-bash
Re: [bash 3.1.5] sh -c echo -n ok broken
Jeff Chua wrote: GNU bash, version 3.1.5(1)-release sh -c echo -n ok returns -n ok. This breaks a lot of scripts ... startup scripts in /etc/rc.d and many packages like glibc make check that use sh instead of bash with -n option. How can I make sh -c echo -n ok returns ok instead -n ok? I've tried compiling with --disable-strict-posix-default but that doesn't work. It doesn't behave that way by default: z3.local(1)$ ./sh --version GNU bash, version 3.1.5(2)-release (powerpc-apple-darwin8.3.0) Copyright (C) 2005 Free Software Foundation, Inc. z3.local(1)$ ./sh -c 'echo -n ok' okz3.local(1)$ Somehow you've enabled the xpg_echo option, either by configuring with --enable-xpg-echo-default or running `shopt -s xpg_echo' somewhere. I suspect the former. Chet -- ``The lyf so short, the craft so long to lerne.'' - Chaucer ( ``Discere est Dolere'' -- chet ) Live Strong. Chet Ramey, ITS, CWRU[EMAIL PROTECTED]http://cnswww.cns.cwru.edu/~chet/ ___ Bug-bash mailing list Bug-bash@gnu.org http://lists.gnu.org/mailman/listinfo/bug-bash
[bash 3.1.5] sh -c echo -n ok broken
GNU bash, version 3.1.5(1)-release sh -c echo -n ok returns -n ok. This breaks a lot of scripts ... startup scripts in /etc/rc.d and many packages like glibc make check that use sh instead of bash with -n option. How can I make sh -c echo -n ok returns ok instead -n ok? I've tried compiling with --disable-strict-posix-default but that doesn't work. Thanks, Jeff ___ Bug-bash mailing list Bug-bash@gnu.org http://lists.gnu.org/mailman/listinfo/bug-bash
Re: [bash 3.1.5] sh -c echo -n ok broken
On Wed, 18 Jan 2006, Chet Ramey wrote: Somehow you've enabled the xpg_echo option, either by configuring with --enable-xpg-echo-default or running `shopt -s xpg_echo' somewhere. I suspect the former. Yes, I did --enable-xpg-echo-default as I need echo ok\c to work. The older bash-3.00.15(3) works with --enable-xpg-echo-default. So, it is possible to have both the following working in sh and bash echo -n ok echo ok\c Thanks, Jeff. ___ Bug-bash mailing list Bug-bash@gnu.org http://lists.gnu.org/mailman/listinfo/bug-bash
Re: [bash 3.1.5] sh -c echo -n ok broken
On Thu, 19 Jan 2006, Jeff Chua wrote: On Wed, 18 Jan 2006, Chet Ramey wrote: Somehow you've enabled the xpg_echo option, either by configuring with --enable-xpg-echo-default or running `shopt -s xpg_echo' somewhere. I suspect the former. Yes, I did --enable-xpg-echo-default as I need echo ok\c to work. The older bash-3.00.15(3) works with --enable-xpg-echo-default. So, it is possible to have both the following working in sh and bash echo -n ok echo ok\c printf %s ok -- Chris F.A. Johnson http://cfaj.freeshell.org === Author: Shell Scripting Recipes: A Problem-Solution Approach (2005, Apress) ___ Bug-bash mailing list Bug-bash@gnu.org http://lists.gnu.org/mailman/listinfo/bug-bash
