Re: [ccp4bb] off topic: rmsf in simulation

2012-12-09 Thread Jeremy Tame
Different proteins do different things. Some adopt fewer conformations and a 
more rigid structure after binding
a ligand, and others do the opposite. Haemoglobin is a nice example of a 
protein that becomes a lot more flexible
after picking up ligands. For any reaction of the kind P + L - PL there is an 
entropy cost of making one molecule
from two. For the protein to activate low frequency modes in the complex is one 
way to compensate for this by
increasing the entropy of the bound form. The paper by Sturtevant (PNAS 74, 
2236, 1977) is worth a read, as is
Cooper and Dryden (Eur Biophys J, 11, 103, 1984), if you are interested in 
relating fluctuations to thermodynamics.
All too often people attempt direct comparisons of structural models and 
affinities without realising that the so-called
angstroms to calories problem often frames the question in a form that cannot 
be answered sensibly. For
example, imagine a protease which is produced as a zymogen. Both forms may have 
essentially identical crystal
structures even though the zymogen is more flexible. The protease can be 
activated by loss of vibrational modes
in the unbound state which are re-awakened in the complex with substrate; hence 
the zymogen will have lower
substrate binding and activity. You might be interested in a review by Homans 
(ChemBioChem 6, 1585, 2005) which
discusses the use of NMR to look at entropy changes in protein-ligand binding 
reactions. It is by no means unusual
for a residue's entropy to increase in the bound state, although in your case 
it seems to be the whole protein! 

On Dec 9, 2012, at 1:05 PM, anita p wrote:

 Hi All,
 I am trying to understand the mechanism of protein-peptide interaction in two 
 complexes (protein-pepA and protein-pepB).
 While trying to perform some simulation experiments, I find that the root 
 mean square fluctuation (RMSF) by residues of protein in the complex is 
 higher than that of the protein alone.
 Please refer the figure attached to this email. pepA binds with higher 
 affinity (in uM-range) than pepB according to invitro studies.
 
 Does this happen normally?? Please advice.
 Thanks in advance
 Anita
 RMSF.png


Re: [ccp4bb] off topic: rmsf in simulation

2012-12-09 Thread Chandra Verma
to complement the very nice description by jeremy, you may wish to try  
and decompose the vibrational modes to get this sense by focussing on  
the origins of  the red shift in the vibrational spectrum and this  
accounts largely for the increased vibrational entropies upon  
complexation. This paper may be used as a guide
(Dissecting the vibrational entropy change on protein/ligand binding:  
burial of a water molecule in bovine pancreatic trypsin inhibitor J  
Phys Chem B  2001 105 8050-8055)



There is some very nice work by Olano  Rick in

JACS 2004 126:7991 on Hydration free energies and entropies for water  
in protein interiors.


and by carol post on how the increased entropies upon complexation are  
the origin of the mechanism of some drugs. (for example Influence of  
an Antiviral Compound on the Temperature Dependence of Viral Protein  
Flexibility and Packing: a Molecular Dynamics Study J. Mol. Biol.  
(1998) 276: 331-337)




Quoting Jeremy Tame jt...@tsurumi.yokohama-cu.ac.jp:

Different proteins do different things. Some adopt fewer  
conformations and a more rigid structure after binding
a ligand, and others do the opposite. Haemoglobin is a nice example  
of a protein that becomes a lot more flexible
after picking up ligands. For any reaction of the kind P + L - PL  
there is an entropy cost of making one molecule
from two. For the protein to activate low frequency modes in the  
complex is one way to compensate for this by
increasing the entropy of the bound form. The paper by Sturtevant  
(PNAS 74, 2236, 1977) is worth a read, as is
Cooper and Dryden (Eur Biophys J, 11, 103, 1984), if you are  
interested in relating fluctuations to thermodynamics.
All too often people attempt direct comparisons of structural models  
and affinities without realising that the so-called
angstroms to calories problem often frames the question in a form  
that cannot be answered sensibly. For
example, imagine a protease which is produced as a zymogen. Both  
forms may have essentially identical crystal
structures even though the zymogen is more flexible. The protease  
can be activated by loss of vibrational modes
in the unbound state which are re-awakened in the complex with  
substrate; hence the zymogen will have lower
substrate binding and activity. You might be interested in a review  
by Homans (ChemBioChem 6, 1585, 2005) which
discusses the use of NMR to look at entropy changes in  
protein-ligand binding reactions. It is by no means unusual
for a residue's entropy to increase in the bound state, although in  
your case it seems to be the whole protein!


On Dec 9, 2012, at 1:05 PM, anita p wrote:


Hi All,
I am trying to understand the mechanism of protein-peptide  
interaction in two complexes (protein-pepA and protein-pepB).
While trying to perform some simulation experiments, I find that  
the root mean square fluctuation (RMSF) by residues of protein in  
the complex is higher than that of the protein alone.
Please refer the figure attached to this email. pepA binds with  
higher affinity (in uM-range) than pepB according to invitro studies.


Does this happen normally?? Please advice.
Thanks in advance
Anita
RMSF.png


Re: [ccp4bb] refining against weak data and Table I stats

2012-12-09 Thread DUMAS Philippe (UDS)

Le Vendredi 7 Décembre 2012 18:48 CET, Gerard Bricogne g...@globalphasing.com 
a écrit:

May I add something to Gerard's comment.
In the same vein, provided one does consider two sets of terms with zero mean 
(which corresponds to the proviso mentioned by Gerard), one can define an 
R-factor R as the sine of the same angle leading to a correlation coefficient C 
and one has R^2 + C^2 = 1.
Thus, in some way, on a practical ground, an R-factor is a sensitive criterion 
for higly correlated data, whereas a correlation coefficient is better suited 
for poorly correlated data.
Likely, I just rephrased here  ideas that have been written long time ago in 
well-known papers.
Did I ?
Philippe Dumas



 Dear Zbyszek,

  That is a useful point. Another way of making it is to notice that the
 correlation coefficient between two random variables is the cosine of the
 angle between two vectors of paired values for these, with the proviso that
 the sums of the component values for each vector add up to zero. The fact
 that an angle is involved means that the CC is independent of scale, while
 the fact that it is the cosine of that angle makes it rather insensitive to
 small-ish angles: a cosine remains close to 1.0 for quite a range of angles.

  This is presumably the nature of correlation coefficients you were
 referring to.


  With best wishes,

   Gerard.

 --
 On Fri, Dec 07, 2012 at 11:14:50AM -0600, Zbyszek Otwinowski wrote:
  The difference between one and the correlation coefficient is a square
  function of differences between the datapoints. So rather large 6%

  relative error with 8-fold data multiplicity (redundancy) can lead to
  CC1/2 values about 99.9%.
  It is just the nature of correlation coefficients.
 
  Zbyszek Otwinowski
 
 
 
   Related to this, I've always wondered what CC1/2 values mean for low
   resolution. Not being mathematically inclined, I'm sure this is a naive
   question, but i'll ask anyway - what does CC1/2=100 (or 99.9) mean?
   Does it mean the data is as good as it gets?
  
   Alan
  
  
  
   On 07/12/2012 17:15, Douglas Theobald wrote:
   Hi Boaz,
  
   I read the KK paper as primarily a justification for including

   extremely weak data in refinement (and of course introducing a new
   single statistic that can judge data *and* model quality comparably).
   Using CC1/2 to gauge resolution seems like a good option, but I never
   got from the paper exactly how to do that.  The resolution bin where
   CC1/2=0.5 seems natural, but in my (limited) experience that gives
   almost the same answer as I/sigI=2 (see also KK fig 3).
  
  
  
   On Dec 7, 2012, at 6:21 AM, Boaz Shaanan bshaa...@exchange.bgu.ac.il
   wrote:
  
   Hi,
  
   I'm sure Kay will have something to say  about this but I think the
   idea of the K  K paper was to introduce new (more objective) standards
   for deciding on the resolution, so I don't see why another table is
   needed.
  
   Cheers,
  
  
  
  
  Boaz
  
  
   Boaz Shaanan, Ph.D.
   Dept. of Life Sciences
   Ben-Gurion University of the Negev
   Beer-Sheva 84105
   Israel
  
   E-mail: bshaa...@bgu.ac.il
   Phone: 972-8-647-2220  Skype: boaz.shaanan
   Fax:   972-8-647-2992 or 972-8-646-1710
  
  
  
  
  
   
   From: CCP4 bulletin board [CCP4BB@JISCMAIL.AC.UK] on behalf of Douglas
   Theobald [dtheob...@brandeis.edu]
   Sent: Friday, December 07, 2012 1:05 AM
   To: CCP4BB@JISCMAIL.AC.UK
   Subject: [ccp4bb] refining against weak data and Table I stats

  
   Hello all,
  
   I've followed with interest the discussions here about how we should be
   refining against weak data, e.g. data with I/sigI  2 (perhaps using
   all bins that have a significant CC1/2 per Karplus and Diederichs
   2012).  This all makes statistical sense to me, but now I am wondering
   how I should report data and model stats in Table I.
  
   Here's what I've come up with: report two Table I's.  For comparability
   to legacy structure stats, report a classic Table I, where I call the
   resolution whatever bin I/sigI=2.  Use that as my high res bin, with
   high res bin stats reported in parentheses after global stats.   Then
   have another Table (maybe Table I* in supplementary material?) where I
   report stats for the whole dataset, including the weak data I used in
   refinement.  In both tables report CC1/2 and Rmeas.
  
   This way, I don't redefine the (mostly) conventional usage of
   resolution, my Table I can be compared to precedent, I report stats
   for all the data and for the model against all data, and I take
   advantage of the information in the weak data during refinement.
  
   Thoughts?
  
   Douglas
  
  
   ^`^`^`^`^`^`^`^`^`^`^`^`^`^`^`^`^`^`^`^`
   Douglas L. Theobald
   Assistant Professor
   Department of Biochemistry
   Brandeis University
   Waltham, MA  02454-9110
  
   dtheob...@brandeis.edu
   http://theobald.brandeis.edu/
  
   ^\
 /`  /^.  / /\
   

Re: [ccp4bb] Binding constants/kinetics for crystallisation

2012-12-09 Thread Feld, Geoffrey Keith
Good points have been brought up; here's one more to consider from my
experience. If you are going to run SEC prior to crystallization, I would
highly recommend running a native gel of the peak you collect. Especially
if you don't know the stoichiometry or if the stoichiometry is complex. I
crystallized a multimeric complex where a large oligomer bound to four
smaller proteins with high affinity (sub nM), and even after making the
complex in stoichiometric excess, somehow one of the ligands would fall
off during SEC (probably the 3-bound and 4-bound mers were in equilibrium
on column) and only after I discovered this by running a native gel did I
start getting single crystals instead of multi-lattice xtals. Basically
the band for the full complex was fuzzy (I.e. A range of stoichiometries)
and after titrating in more ligand after SEC did the band look nice. Also,
you can run a native gel of your crystals (assuming you obtain some!) by
harvesting a number of them in a buffer in which they'll dissolve and then
use a sensitive staining method, like silver staining.

Good luck!
Geoff

On 12/7/12 4:00 PM, CCP4BB automatic digest system
lists...@jiscmail.ac.uk wrote:




Re: [ccp4bb] off topic: rmsf in simulation

2012-12-09 Thread anita p
Hi All
thanks for your detailed reply. A higher RMSF(as I showed in the png.) *doesnot
*mean that the RMSD for Calpha backbone showed be high. Am I correct ??
Because in my case the backbone RMSD for the receptor of the peptide bound
structure is lower than the receptor alone. Because I wanted to know if my
simulations have gone fine.
thanks again in advance.
Anita

On Sun, Dec 9, 2012 at 6:44 PM, Chandra Verma chan...@bii.a-star.edu.sgwrote:

 to complement the very nice description by jeremy, you may wish to try and
 decompose the vibrational modes to get this sense by focussing on the
 origins of  the red shift in the vibrational spectrum and this accounts
 largely for the increased vibrational entropies upon complexation. This
 paper may be used as a guide
 (Dissecting the vibrational entropy change on protein/ligand binding:
 burial of a water molecule in bovine pancreatic trypsin inhibitor J Phys
 Chem B  2001 105 8050-8055)
 

 There is some very nice work by Olano  Rick in

 JACS 2004 126:7991 on Hydration free energies and entropies for water in
 protein interiors.

 and by carol post on how the increased entropies upon complexation are the
 origin of the mechanism of some drugs. (for example Influence of an
 Antiviral Compound on the Temperature Dependence of Viral Protein
 Flexibility and Packing: a Molecular Dynamics Study J. Mol. Biol. (1998)
 276: 331-337)




 Quoting Jeremy Tame 
 jt...@tsurumi.yokohama-cu.ac.**JPjt...@tsurumi.yokohama-cu.ac.jp
 :

  Different proteins do different things. Some adopt fewer conformations
 and a more rigid structure after binding
 a ligand, and others do the opposite. Haemoglobin is a nice example of a
 protein that becomes a lot more flexible
 after picking up ligands. For any reaction of the kind P + L - PL there
 is an entropy cost of making one molecule
 from two. For the protein to activate low frequency modes in the complex
 is one way to compensate for this by
 increasing the entropy of the bound form. The paper by Sturtevant (PNAS
 74, 2236, 1977) is worth a read, as is
 Cooper and Dryden (Eur Biophys J, 11, 103, 1984), if you are interested
 in relating fluctuations to thermodynamics.
 All too often people attempt direct comparisons of structural models and
 affinities without realising that the so-called
 angstroms to calories problem often frames the question in a form that
 cannot be answered sensibly. For
 example, imagine a protease which is produced as a zymogen. Both forms
 may have essentially identical crystal
 structures even though the zymogen is more flexible. The protease can be
 activated by loss of vibrational modes
 in the unbound state which are re-awakened in the complex with substrate;
 hence the zymogen will have lower
 substrate binding and activity. You might be interested in a review by
 Homans (ChemBioChem 6, 1585, 2005) which
 discusses the use of NMR to look at entropy changes in protein-ligand
 binding reactions. It is by no means unusual
 for a residue's entropy to increase in the bound state, although in your
 case it seems to be the whole protein!

 On Dec 9, 2012, at 1:05 PM, anita p wrote:

  Hi All,
 I am trying to understand the mechanism of protein-peptide interaction
 in two complexes (protein-pepA and protein-pepB).
 While trying to perform some simulation experiments, I find that the
 root mean square fluctuation (RMSF) by residues of protein in the complex
 is higher than that of the protein alone.
 Please refer the figure attached to this email. pepA binds with higher
 affinity (in uM-range) than pepB according to invitro studies.

 Does this happen normally?? Please advice.
 Thanks in advance
 Anita
 RMSF.png