Re: [ccp4bb] very informative - Trends in Data Fabrication

2012-04-01 Thread Philippe DUMAS

David Briggs drdavidcbri...@gmail.com a écrit :


Trollus, Trollum, Trolli, Trollo, Trolli, Trollos, Trollorum, Trollis.




Should we say Alea data est or Alea data sunt ?



Philippe DUMAS


Re: [ccp4bb] Using intrinsically bound Zn atoms for phasing

2012-03-06 Thread Philippe DUMAS

A reference for a real MAD phasing with Zinc (worked very well):
Ennifar et al. MAD phasing replacing magnesium with zinc. Acta Cryst.  
(2001). D57, 330


Philippe Dumas

Bosch, Juergen jubo...@jhsph.edu a écrit :

Since you've collected the data already use your favourite data   
processing program and treat the Friedel pairs separately. I'd   
suggest to try HKL2map in conjunction with SHELX C/D/E (sorry for   
the non CCP4 advertisement here) for solving the heavy atom sites.   
You can in parallel also try SnB or BnP to find a substructure   
solution. Depending how bad you resulting density looks like you   
might want to improve your phases via Sharp.


If you want to stay in the CCP4 protected sandbox, then give Crank a try.

Jürgen

On Mar 6, 2012, at 3:24 PM, Francis E Reyes wrote:

http://skuld.bmsc.washington.edu/scatter/AS_form.html

Maybe useful to you.

However, I would advise to do a fluorescence scan  over the range   
given in the graph and then use chooch to provide the precise   
energies for your peak and inflection.


If you have a large crystal don't expose all of it when you do the   
fluorescence scan but rather reserve a 'fresh' piece to do your   
actual data collection.


F


On Mar 6, 2012, at 1:09 PM, Deepthi wrote:

Hi

I am trying to solve the structure of an engineered protein.The   
protein is crystallized with Zn bound to it  .We collected a 1.5A0   
data. Molecular Replacement didn't yield a good match for the   
protein. I want to try MAD taking advantage of the Zn atoms in   
protein. I am not sure what wavelength should i use to collect the   
diffraction data for Zn. any suggestions?


Thank You
Deepthi

--
Deepthi

..
Jürgen Bosch
Johns Hopkins University
Bloomberg School of Public Health
Department of Biochemistry  Molecular Biology
Johns Hopkins Malaria Research Institute
615 North Wolfe Street, W8708
Baltimore, MD 21205
Office: +1-410-614-4742
Lab:  +1-410-614-4894
Fax:  +1-410-955-2926
http://web.mac.com/bosch_lab/





Re: [ccp4bb] New Faster-than-fast Fourier transform

2012-01-20 Thread Philippe DUMAS

George Sheldrick gshe...@shelx.uni-ac.gwdg.de a écrit :

For all those interested in the technical details about this new  
Fourier stuff, I saw that the whole paper is available from the web  
site, not only the simplified account (look at right of this awfully  
wrong 3-term Fourier synthesis illutration that I would never show to  
beginners!)

P. Dumas


From the rather non-technical inofrmation available so far, it seems to
me that it is like leaving out all but the strongest reflections (or
perhaps the strongest normalized structure factors). This is unlikely
to improve the quality of structure refinement, the importance of using
as much data as possible and not leaving out the weakest reflections
has often been emphasized. This is quite different to data compression
of music. However there is one case where we are already doing this,
namely small molecule direct methods or using the same programs to find
the heavy atoms in SAD and MAD experiments. These programs use only the
strongest 15-20% of the normalized structure factors (E-values). This
is possible because the data to parameter ratio is still sufficient,
and these reflections contain much of the useful information. However
the Fourier routines used by these programs (at least the ones I wrote)
are not taking full advantage of the 'sparseness' of the data, so if
the MIT people have found a clever way of doing this it might still be
useful for heavy atom location  (though FFTW and the Intel MKL FFT will
be difficult to beat).

George

On 01/20/2012 06:57 PM, Ethan Merritt wrote:

On Friday, 20 January 2012, Jim Fairman wrote:

New Fourier transform algorithm supposedly improves the speed of Fourier
transforms get up to a tenfold increase in speed depending upon
circumstances.  Hopefully this will get incorporated into our refinement
programs.

http://web.mit.edu/newsoffice/2012/faster-fourier-transforms-0118.html

This report is interesting, but it is not immediately obvious to me that
crystallographic transforms are in the class of problems for which
this algorithm is applicable.

From reading the very non-technical article linked above, I conclude that
a better summary would be New approach to Fourier approximation provides
a very cheap (fast) way of identifying and then discarding components that
contribute very little to the signal.  In other words, it seems to be a
way of increasing the compression ratio for lossy image/audio compression
without increasing the amount of time required for compression.

So if you're doing map fitting while listening to streamed mp3 music
files, perhaps your map inversion will get a slightly larger slice of
the CPU time relative to LastFM.

On the other hand, it is possible that somewhere in here lies a clever
approach to faster solvent flattening.

Ethan





Philippe DUMAS, responsable d'équipe
Directeur de Recherche au CNRS
Equipe de Biophysique  Biologie Structurale
Unité 'Architecture  Réactivité de l'ARN', UPR9002
Institut de Biologie Moléculaire et Cellulaire
15, rue René Descartes F67084 STRASBOURG
+33 (0)388 41 70 02
http://www-ibmc.u-strasbg.fr/arn/Dumas/index_dum_fr.html


Re: [ccp4bb] how to quantitate protein which dont have ne aromatic residue

2011-04-09 Thread Philippe Dumas

Michael Thompson mi...@chem.ucla.edu a écrit :

There is a very simple and very quick  method that yields an answer  
approx. 15% reliable: measuring the increment of index of refraction  
due to the protein. The measurement of an index of refraction can be  
very accurate.  You only need something like a 5µl drop at 1 mg/ml  
(the order of magnitude should be correct...). Unfortunately, a  
refractometer is not common in biology labs, but this is a very  
valuable method.
The link between the increment of index of refraction and the protein  
conc. can be found easily on the web.

Philippe Dumas

It is not surprising that your bradford and BCA assays don't agree   
if you have no aromatic amino acids in your protein. Bradford dye   
binds to hydrophobic residues, mainly aromatics, so I would guess   
your bradford is consistantly giving lower measurements than the BCA  
 assay. I also wouldn't be surprised if the results of your Bradford  
 vary significantly between replicates. The BCA assay reagent   
interacts with the backbone amides, not with any sidechains, so I   
would tend to believe that measurement more than anything else you   
have done.


I work with a protein that has very few hydrophobics (only one   
aromatic - a Phe) and I have found that Bradfords are unreliable,   
but the BCA assay tends to be consistent.


Mike




- Original Message -
From: Arpit Mishra ar...@igib.in
To: CCP4BB@JISCMAIL.AC.UK
Sent: Saturday, April 9, 2011 2:52:21 AM GMT -08:00 US/Canada Pacific
Subject: [ccp4bb] how to quantitate protein which dont have ne   
aromatic residue


hello everybody


i am working on the protien which dont have any aromatic residue i   
do fplc other purification using 220 absorption, but i want to   
quantitate protein precisely i have tried using BCA nd bradford but   
both methods quantification is not matching,,so any one is having   
sum idea how to quantitate it precisely



thanks in advance for your valuable suggestion..




Arpit Mishra

--
Michael C. Thompson

Graduate Student

Biochemistry  Molecular Biology Division

Department of Chemistry  Biochemistry

University of California, Los Angeles

mi...@chem.ucla.edu



Re: [ccp4bb] Fw: Re: [ccp4bb] Solidarity with Japan

2011-03-16 Thread Philippe DUMAS

Le 16/03/2011 17:59, REX PALMER a écrit :

Would it be possible to get information through the CCP4BB about 
colleagues who do not answer mails ?
I'd like to have news about TAKENAKA Akio, Faculty of Pharmacy, Iwaki 
Meisei University, Tokyo Institute of Technology.

Thank you if somebody can transmit the information.

Philippe Dumas



I was very relieved to learn that my friend and colleague Hideaki
Niwa who took his MSc and PhD with me at Birkbeck is safe and well
in Japan.
I believe that International the Red Cross is doing great work out
there and need all the help they can get. You can donate by going
to the link below:


http://clicks.aweber.com/y/ct/?l=7vf_Vm=1adA9w4Zgg1yh1b=_szL3OnaO1I3NyRX06YTVA

http://clicks.aweber.com/y/ct/?l=7vf_Vm=1adA9w4Zgg1yh1b=_szL3OnaO1I3NyRX06YTVA


Rex Palmer
Birkbeck College



attachment: p_dumas.vcf

Re: [ccp4bb] {Spam?} Re: {Spam?} Re: [ccp4bb] {Spam?} Re: {Spam?} Re: [ccp4bb] units of the B factor

2009-11-20 Thread Philippe DUMAS

What a funny  pleasant piece of discussion !

Given any physical quantity Something, having any kind of dimension 
(even as awful as inches^2*gallons*pounds^-3)
Would it exist any room for a discussion about the dimension of  
2*Something ? And what about  1*Something ?


Philippe Dumas


attachment: p_dumas.vcf

Re: [ccp4bb] images

2009-03-19 Thread Philippe DUMAS

Jacob,
Just for the fun, and for historical exactness...
I would rather invoke Laplace for such an argumentation, whereas 
Poincaré should better be invoked for a very strong warning against it.
Therefore, ignoring the warning and following Laplace, we could even 
readily extend your suggestion from  back-calculating the images to 
solving the corresponding structures (and thus also writing the 
corresponding  papers). And write The End  (as nauseam, of course ::))


Philippe Dumas


Jacob Keller a écrit :
Perhaps we could use Poincare's argument(?), that knowing one cross 
section of the universe in all of its detail would allow forward and 
back-calculation of all previous states. Then the universe would be 
its own lab notebook/ archive, and we would not need to bother with 
all of these technicalities in the first place. The images, then, 
could be back-calculated from the current (or any) configuration of 
all the universe's atoms, and then we could work better on improving 
our crystallography software (and ferreting out fraud) from those...


JPK

***
Jacob Pearson Keller
Northwestern University
Medical Scientist Training Program
Dallos Laboratory
F. Searle 1-240
2240 Campus Drive
Evanston IL 60208
lab: 847.491.2438
cel: 773.608.9185
email: j-kell...@northwestern.edu
***


begin:vcard
fn:Philippe Dumas
n:Dumas;Philippe
org:CNRS;Biophysique et Biologie Structurale
adr;quoted-printable:15 rue Ren=C3=A9 Descartes;;IBMC;Strasbourg;;67084;France
email;internet:p.du...@ibmc.u-strasbg.fr
title:Directeur de Recherche
tel;work:+33 (0)388 41 70 02
tel;fax:+33 (0)388 60 22 18
url:http://www-ibmc.u-strasbg.fr/arn/Dumas/index_dum_fr.html
version:2.1
end:vcard



Re: [ccp4bb] Weakest protein-protein complex crystallised

2008-07-01 Thread Philippe DUMAS
Continuation about this competition between crystal contacts and
biologically-relevant contacts
Your example is quite interesting because you were able to make the
comparison with different ligand affinities, which is exactly what we would
have like to test...

I just want to add a comment about a possible kinetic, rather than purely
thermodynamic, effect.
It may be possible that one cannot really compare the affinity of the ligand
with that of the molecule-molecule interaction in the lattice because once a
molecule-ligand complex has been incorporated into a growing crystal it may
be very rapidly protected against the loss of its ligand (and in our case
against the binding of a second ligand).

Philippe Dumas
IBMC-CNRS, UPR9002
15, rue René Descartes 67084 Strasbourg cedex
tel: +33 (0)3 88 41 70 02
[EMAIL PROTECTED]




[Philippe DUMAS]  -Message d'origine-
De : Filip Van Petegem [mailto:[EMAIL PROTECTED]
Envoyé : Monday, June 30, 2008 9:01 PM
À : Philippe DUMAS
Cc : CCP4BB@jiscmail.ac.uk
Objet : Re: [ccp4bb] Weakest protein-protein complex crystallised


  Hi,

  we've had a similar situation:  a protein-peptide complex with a Kd in the
nM range crystallized in the same condition as the protein alone, and
yielded a structure of a complex (voltage-gated calcium channel beta
subunit). The exact crystal contacts turned out to be a bit different, as
the peptide would clash with a neighbouring molecule in the lattice.

  However, a mutant protein that increased the  Kd to ca 160nM (as confirmed
by ITC), using the same peptide crystallized in the same conditions, but
this time not as a complex. This effect was reproducible: the WT
consistently crystallized as complex, whereas relatively mild mutants (Kd in
100nM range and worse) only yielded crystals of the apo-protein.

  Conclusion would be that crystal contacts can break relatively tight
protein-protein interactions in the ~100nM range, and that crystal contacts
are not always that weak. However, the crystallization conditions themselves
(PEGs, non-neutral pH) are likely to affect the binding as well.

  Cheers

  Filip Van Petegem


  On Mon, Jun 30, 2008 at 10:42 AM, Philippe DUMAS
[EMAIL PROTECTED] wrote:

Hello

We have had an interesting example where the crystal packing seems to
have won against the biological interaction. This is about a sliding
clamp made of a very symmetric homodimer having the shape of a ring
(encircling DNA during its replication).
This beta-ring had been crystallized alone by the Kuriyan group in P1
(thus there was NCS). In our case, we crystallized it with an additional
peptide mimicking the C-term of a polymerase binding to the beta-ring
[Burnouf et al, JMB 335(2004) 1187]. We expected a symmetric binding of two
peptides/ring (one peptide for each protein in the dimer). However, we
observed only one peptide/ring. It turns out that we had obtained exactly
the same packing in P1 and that one of the two possible binding sites was
engaged in crystal contacts. We estimated the Kd of peptide-ring interaction
as being in the µmolar range and that there was only a few percent of
beta-rings in crystallization drops being singly occupied. Yet the
crystallization process selected this minor species to build crystals with
(supposedly) a good crystal packing, rather than finding another crystal
packing accomodating the doubly-occupied species present in large excess.
Our conclusion was that a very modest gain of ca. 2 kcal/mol in the free
energy of interaction of singly-occupied beta-rings was sufficient to
account for their selection to build crystals against a great majority of
doubly-occupied contaminants. This is exactly the order of magnitude
mentioned by Ed Pozharski: a single additional H-bond is enough to account
for 2 kcal/mol ! And apparently this may be enough to win against
biological interactions. Let us not forget that there are many processes
comparable to crystallization in living cell...

I hope this story makes sense in the frame of this discussion.

Philippe Dumas
IBMC-CNRS, UPR9002
15, rue René Descartes 67084 Strasbourg cedex
tel: +33 (0)3 88 41 70 02
[EMAIL PROTECTED]

-Message d'origine-
De : CCP4 bulletin board [mailto:[EMAIL PROTECTED] la part de Ed
Pozharski
Envoyé : Monday, June 30, 2008 4:50 PM
À : CCP4BB@JISCMAIL.AC.UK
Objet : Re: [ccp4bb] Weakest protein-protein complex crystallised



The word weak is, of course, relative.  Free energy of crystallization
is roughly 1-2 kcal/mole of crystal contacts (I think I carried this
number from Sir Blundell's book, but quick look at papers by Peter
Vekilov's group seems to confirm it - am I wrong on this?).  I think
that crystal contacts are still much weaker than any interaction of
biological importance (perhaps I am wrong on this one too and there are
important biological protein-protein interaction with 10mM affinity, but
I doubt that they are many

Re: [ccp4bb] birefringent spacegroups

2008-06-13 Thread Philippe DUMAS
Thank you Ian for the comment !
Apparently, I was a bit too quick in my answer.
By the way, my mentioning of Fresnel's theory was of pure historical
interest and not at all to say that the whole story was written at that
time.

I went back to my Born  Wolf (some kind of a bible in the optics field)
and I am somewhat surprised of not seeing any comment on that topics. May be
the comments exist, but implicitly in the cited litterature...

Now, I am still wondering whether external stresses on biological crystals
could indeed induce such unexpected birefringence.

Philippe Dumas
IBMC-CNRS, UPR9002
15, rue René Descartes 67084 Strasbourg cedex
tel: +33 (0)3 88 41 70 02
[EMAIL PROTECTED]


-Message d'origine-
De : CCP4 bulletin board [mailto:[EMAIL PROTECTED] la part de Ian
Tickle
Envoyé : Thursday, June 12, 2008 9:20 PM
À : CCP4BB@JISCMAIL.AC.UK
Objet : Re: [ccp4bb] birefringent spacegroups


But it seems that Hendrik Lorentz was the first to realise that symmetry
breaking of the isotropy of the refractive index  other optical properties
could occur in cubic crystals at sufficiently short wavelength even in the
absence of a distorting force - the spatial-dispersion-induced
birefringence effect referred to in the paper.  Note that this is an
intrinsic effect, it has nothing to do with external stress, electric field
etc., and if you read the paper you'll see that such external effects were
specifically eliminated as the cause of the observed effect.

-- Ian

 -Original Message-
 From: [EMAIL PROTECTED]
 [mailto:[EMAIL PROTECTED] On Behalf Of Philippe DUMAS
 Sent: 12 June 2008 19:20
 To: Ian Tickle; CCP4BB@JISCMAIL.AC.UK
 Subject: RE: [ccp4bb] birefringent spacegroups

 Hello,

 A short comment of historical interest: the first theory about double
 refraction in crystals (with explicit calculation of the
 index ellipsoid)
 goes back to 3 memoirs by A. Fresnel in 1821 and 1822. So, we
 are even in
 older regions.

 This being said, in cubic crystals the index ellipsoid can
 only be a sphere.
 An so, no birefringence should exist (unless there is some
 external cause of
 anisotropy: mecanical stress, electric field,...). See Born  Wolff
 (principles of optics) p. 703. May be, our biological
 crystals might quite
 easily develop such stress birefringence...

 Philippe Dumas
 IBMC-CNRS, UPR9002
 15, rue René Descartes 67084 Strasbourg cedex
 tel: +33 (0)3 88 41 70 02
 [EMAIL PROTECTED]



 -Message d'origine-
 De : CCP4 bulletin board [mailto:[EMAIL PROTECTED] la
 part de Ian
 Tickle
 Envoyé : Thursday, June 12, 2008 7:19 PM
 À : CCP4BB@JISCMAIL.AC.UK
 Objet : Re: [ccp4bb] birefringent spacegroups


 PS in case you missed it, here's the bottom line from the paper:

 Interestingly, a cubic crystal has seven nonbirefringent
 axes, four in
 the 111
 directions and three in the 100 directions, with
 birefringence maxima
 in the twelve 110 directions.

 So it would appear that the optical properties of cubic crystals are
 *more* complicated than those of lower symmetry systems, not
 less! - and
 previous conclusions about isotropy of cubic crystals probably arose
 because the measurements were simply not precise enough (or
 not carried
 out at short enough wavelength) to detect the effect.  However the
 relevant theory goes back to Lorentz (1878) so it's not exactly new!

 Cheers

 -- Ian

  -Original Message-
  From: [EMAIL PROTECTED]
  [mailto:[EMAIL PROTECTED] On Behalf Of Ian Tickle
  Sent: 12 June 2008 17:50
  To: Ethan A Merritt; Jacob Keller
  Cc: CCP4BB@jiscmail.ac.uk
  Subject: RE: [ccp4bb] birefringent spacegroups
 
  Hi Ethan
 
  You could be right, see this paper:
 
 
 http://physics.nist.gov/Divisions/Div842/Gp2/DUVMatChar/PDF/In
 tBiref.pdf
 
  Cheers
 
  -- Ian
 
 
   -Original Message-
   From: [EMAIL PROTECTED]
   [mailto:[EMAIL PROTECTED] On Behalf Of Ethan A Merritt
   Sent: 12 June 2008 15:46
   To: Multiple recipients
   Cc: CCP4BB@jiscmail.ac.uk
   Subject: Re: [ccp4bb] birefringent spacegroups
  
   On Wednesday 11 June 2008 23:55, Robin Owen wrote:
Hi Jacob,
   
The birefringence of a crystal is determined by a three
  dimensional
shape (the indicatrix) describing how refractive index
  varies with
direction within the crystal. You can think of this as a 3d
   ellipse and
the birefringence is given by the difference in length of
   the two axes
of the ellipse 'seen' by light as it passes through the crystal.
   
The orientation and shape of the indicatrix are constrained
   by the point
group symmetry of the crystal. In the case of cubic
 crystals, the
indicatrix is characterised by four 3-fold axes. The
   indicatrix for all
cubic crystals is thus a sphere and cubic crystals are
   non-birefringent.
Hexagonal, trigonal and tetragonal crystals are uniaxial and the
indicatrix is an ellipsoid of revolution
- there is one direction in which the crystal appears
   non-birefringent.
Orthorhombic, monoclinic

Re: [ccp4bb] Help with Superpose results

2008-04-08 Thread Philippe DUMAS
Although this is not a very important issue..., I am a bit surprised by
Gerard's insistance for a 'stop calling rmsd rms deviation'. Isn'it a
general term in statistical studies, valid for distances separating
homologous atoms as well as for any other factor (B factors for example) ?

Philippe Dumas
IBMC-CNRS, UPR9002
15, rue Rene Descartes 67084 Strasbourg cedex
tel: +33 (0)3 88 41 70 02
[EMAIL PROTECTED]




-Message d'origine-
De : CCP4 bulletin board [mailto:[EMAIL PROTECTED] la part de
Gerard DVD Kleywegt
Envoye : Monday, April 07, 2008 7:20 PM
A : CCP4BB@JISCMAIL.AC.UK
Objet : Re: [ccp4bb] Help with Superpose results


Is the rms xyz displacement equivalent to an rmsd??

yes. it is in fact a better name than rms deviation, although i think
'root-mean-square distance' is even better, as it says exactly what you
calculate.

think of it like this, the formula for rmsd is:

RMSD = square-root [ SUM(atoms) { (x1-x2)^2 + (y1-y2)^2 + (z1-z2)^2 } /
Natoms
]

now, (x1-x2)^2 + (y1-y2)^2 + (z1-z2)^2 is the Square of the Distance
between
two equivalenced atoms in structure 1 and 2; adding them for all pairs of
equivalenced atoms and dividing by the number of atoms gives you the Mean
Squared Distance; finally, taking the square root yields the
Root-Mean-Square
Distance, or RMSD

so, people, can we all please stop calling rmsd rms deviation - it really
is
an rms distance (or rms displacement). you could argue that the formula
gives some kind of rms coordinate deviation, but in that case you ought to
divide by 3*Natoms instead.

(having said that, the term RMS B displacement sounds positively silly!)

--dvd

**
 Gerard J.  Kleywegt
 [Research Fellow of the Royal  Swedish Academy of Sciences]
Dept. of Cell  Molecular Biology  University of Uppsala
 Biomedical Centre  Box 596
 SE-751 24 Uppsala  SWEDEN

 http://xray.bmc.uu.se/gerard/  mailto:[EMAIL PROTECTED]
**
The opinions in this message are fictional.  Any similarity
to actual opinions, living or dead, is purely coincidental.
**


Re: [ccp4bb] Help with Superpose results

2008-04-08 Thread Philippe DUMAS
Apparently I had missed some subtle considerations...

Yet, I confess am not fully convinced: is it so wrong to speak of how much
different structures DEVIATE from each other ? I do not see what prevents
you from defining the correct underlying probability distribution. That
interatomic distances can be used to quantify deviations does not hurt me so
much.

Thank you anyway...

Philippe Dumas
IBMC-CNRS, UPR9002
15, rue René Descartes 67084 Strasbourg cedex
tel: +33 (0)3 88 41 70 02
[EMAIL PROTECTED]





-Message d'origine-
De : Ed Pozharski [mailto:[EMAIL PROTECTED]
Envoyé : Tuesday, April 08, 2008 3:56 PM
À : Philippe DUMAS
Cc : CCP4BB@JISCMAIL.AC.UK
Objet : Re: [ccp4bb] Help with Superpose results


RMS deviation refers to the variance of a random variable - it is a
characteristic of the underlying probability distribution.  When you
superpose two different structures, you are looking at the DISTANCE
between atoms, not the DEVIATION in their position.  In fact, for
individual atoms you can't even say root-mean-square, it's just plain
distance.  The core argument is that you are looking at two structures
that represent different underlying probability distributions, and so
it's definitely not the rms deviation you are calculating, but rms
distance (rms over all the atoms in the structure).  HTH,

Ed.

On Tue, 2008-04-08 at 11:07 +0200, Philippe DUMAS wrote:
 Although this is not a very important issue..., I am a bit surprised by
 Gerard's insistance for a 'stop calling rmsd rms deviation'. Isn'it a
 general term in statistical studies, valid for distances separating
 homologous atoms as well as for any other factor (B factors for example) ?

 Philippe Dumas
 IBMC-CNRS, UPR9002
 15, rue Rene Descartes 67084 Strasbourg cedex
 tel: +33 (0)3 88 41 70 02
 [EMAIL PROTECTED]




 -Message d'origine-
 De : CCP4 bulletin board [mailto:[EMAIL PROTECTED] la part de
 Gerard DVD Kleywegt
 Envoye : Monday, April 07, 2008 7:20 PM
 A : CCP4BB@JISCMAIL.AC.UK
 Objet : Re: [ccp4bb] Help with Superpose results


 Is the rms xyz displacement equivalent to an rmsd??

 yes. it is in fact a better name than rms deviation, although i think
 'root-mean-square distance' is even better, as it says exactly what you
 calculate.

 think of it like this, the formula for rmsd is:

 RMSD = square-root [ SUM(atoms) { (x1-x2)^2 + (y1-y2)^2 + (z1-z2)^2 } /
 Natoms
 ]

 now, (x1-x2)^2 + (y1-y2)^2 + (z1-z2)^2 is the Square of the Distance
 between
 two equivalenced atoms in structure 1 and 2; adding them for all pairs of
 equivalenced atoms and dividing by the number of atoms gives you the Mean
 Squared Distance; finally, taking the square root yields the
 Root-Mean-Square
 Distance, or RMSD

 so, people, can we all please stop calling rmsd rms deviation - it
really
 is
 an rms distance (or rms displacement). you could argue that the
formula
 gives some kind of rms coordinate deviation, but in that case you ought to
 divide by 3*Natoms instead.

 (having said that, the term RMS B displacement sounds positively silly!)

 --dvd

 **
  Gerard J.  Kleywegt
  [Research Fellow of the Royal  Swedish Academy of Sciences]
 Dept. of Cell  Molecular Biology  University of Uppsala
  Biomedical Centre  Box 596
  SE-751 24 Uppsala  SWEDEN

  http://xray.bmc.uu.se/gerard/  mailto:[EMAIL PROTECTED]
 **
 The opinions in this message are fictional.  Any similarity
 to actual opinions, living or dead, is purely coincidental.
 **
--
Edwin Pozharski, PhD, Assistant Professor
University of Maryland, Baltimore
--
When the Way is forgotten duty and justice appear;
Then knowledge and wisdom are born along with hypocrisy.
When harmonious relationships dissolve then respect and devotion arise;
When a nation falls to chaos then loyalty and patriotism are born.
--   / Lao Tse /


Re: [ccp4bb] radiation damage question

2008-03-03 Thread Philippe DUMAS
Yes indeed ! H2 is one product of H2O radiolysis by recombination of two H
radicals.
Whether or not the cleavage of iodine (quite efficient under X-rays) is a
factor increasing H2 production, I don't know.

Philippe Dumas
IBMC-CNRS, UPR9002
15, rue Rene Descartes 67084 Strasbourg cedex
tel: +33 (0)3 88 41 70 02
[EMAIL PROTECTED]


  -Message d'origine-
  De : CCP4 bulletin board [mailto:[EMAIL PROTECTED] la part de
Patrick Loll
  Envoye : Monday, March 03, 2008 6:00 PM
  A : CCP4BB@JISCMAIL.AC.UK
  Objet : [ccp4bb] radiation damage question


  Hi all,


  I had an interesting experience, and wonder if others have seen similar
things.


  I was collecting data from a crystal that contains an iodinated
macromolecule. After 2 days on a copper rotating anode, with the crystal at
100 K, we experienced a detector problem, so I put the crystal back into the
dewar; it was diffracting nicely when I took it off. For various reasons, I
didn't get back to this crystal until about 3 weeks later. When I put it
back on the goniostat, the mother liquor was milky white in appearance.
There were no ice rings, but alas the crystal only gave a few anemic spots
around the beamstop. Annealing didn't help, and I noticed that when I
blocked the cold stream, the milky white appearance didn't go away when the
sample thawed. I finally took the crystal off and looked at it under a
microscope, at which point I discovered that the milky white appearance was
due to the presence of bubbles in the mother liquor.


  I seem to recall some talks on radiation damage in which people mention
the evolution of a gas (H2?).


  So: Does this seem like a radiation damage phenomenon? And have others
seen this kind of delay in the manifestation of damage during storage at
liquid N2 temperatures?


  Thanks,


  Pat


  --
-

  Patrick J. Loll, Ph. D. (215) 762-7706

  Professor FAX: (215) 762-4452

  Department of Biochemistry  Molecular Biology

  Director, Biochemistry Graduate Program

  Drexel University College of Medicine

  Room 10-102 New College Building

  245 N. 15th St., Mailstop 497

  Philadelphia, PA 19102-1192 USA




  [EMAIL PROTECTED]




Re: [ccp4bb] CCP4 rotation convention

2007-08-13 Thread Philippe DUMAS
Just my own amount of salt in the Rotation function soup...
I just want to try defending the poor little Euler angles.

First, Euler invented them... Yes !

Second, only Euler angles yield a very nice interpretation of Rot Funct
symmetry in terms of space group.
See the two venerable papers:
Tollin, Main  Rossmann, Acta Cryst 20 (1966) 404
and Narasinga, Jih  Hartsuck, Acta Cryst A36(1980) 878

Third, only Euler angles yield a very practical and intuitive thing, namely
it does not matter rotating by (alpha, beta,gamma) in the usual way,
or first, prerotating by gamma around Z (but without rotating any axes !)
and then making the alpha rotation around Z (rotating now the axes) followed
by the beta rotation around the new Y. This is most easily seen with a
cylinder that one rotates in the two ways.

Last, the inverse rotation matrix of the Euler matrix defined by (alpha,
beta, gamma) is just the Euler matrix defined by (-gamma, -beta, -alpha).

Ian, isn't worth the effort ?

Philippe Dumas
IBMC-CNRS, UPR9002
15, rue René Descartes 67084 Strasbourg cedex
tel: +33 (0)3 88 41 70 02
[EMAIL PROTECTED]






-Message d'origine-
De : CCP4 bulletin board [mailto:[EMAIL PROTECTED] la part de Ian
Tickle
Envoyé : Monday, August 13, 2007 8:11 PM
À : CCP4BB@JISCMAIL.AC.UK
Objet : Re: [ccp4bb] CCP4 rotation convention



Hi folks

I hate to say this but I think everyone here has got it wrong to some
degree (including myself - and I hereby retract my previous e-mail and
issue the correction below!).  If you don't believe me then read 
digest Jorge Navaza's article Rotation functions in Int. Tab. Vol. F
(sect 13.2, p. 269), particularly sections 13.2.2 and Appendix
A13.2.1.1.

Phil's article in Acta D57 1355-1359 (2001), i.e. the 2001 S/W
proceedings, states:

... the convention used in AMoRe (Navaza, 1994) and other CCP4 programs
(Collaborative Computational Project, Number 4, 1994) is to rotate by
gamma around z, then by beta around the new y, then by alpha around the
new z again, R = Rz'(a).Ry'(b).Rz(g)

Compare this with Jorge's equation 13.2.2.3 which he explicitly states
applies to rotations about fixed axes, not rotated axes (but using my
notation):

R = Rz(a).Ry(b).Rz(g)

i.e. first by gamma about z, then by beta about the *fixed* y axis, then
by alpha about the *fixed* z axis.

The same formula cannot apply to both rotations about fixed and rotated
axes at the same time!

Looking at Jorge's equation 13.2.2.1 it's plain that the correct version
involving rotated axes is (again substituting my own notation which
should be obvious):

R = Rz'(g).Ry'(b).Rz(a)

i.e. the correct statement is that the rotation is generated by rotating
first by alpha about z, then by beta about the rotated y axis (y'), then
by gamma about the rotated z axis (z').

Of course it may well be that Phil's equation is based on an older
version of Jorge's analysis perhaps using a different convention in his
Acta Cryst. (1994), A50, 157-163 paper, but unfortunately I don't have
online access to AC(A) to check it out, maybe someone who has access
could do so.

In fact it's quite obvious looking at the individual matrices Rz(a) 
Ry(b) at the bottom of page 1358 in Phil's paper that they must apply to
fixed not rotating axes, because if say the Ry(b) matrix were for
rotation about the rotated y axis, it would have to be a function of
gamma: applying the Rz(g) matrix as given in the paper first to the
y-axis vector (0,1,0) gives the rotated y-axis vector
(-sin(g),cos(g),0).  Similarly if the Rz(a) matrix represented rotation
about the rotated z axis it would have to be a function of both beta 
gamma and plainly it's not.

This all goes to show that a) even the experts sometimes get it wrong
particularly where matrix algebra is concerned, and b) you should avoid
the concept of rotating about rotated axes like the plague!

-- Ian


 -Original Message-
 From: [EMAIL PROTECTED]
 [mailto:[EMAIL PROTECTED] On Behalf Of Bernhard Rupp
 Sent: 12 August 2007 20:37
 To: CCP4BB@JISCMAIL.AC.UK
 Subject: CCP4 rotation convention

 Dear programmers -

 Phil Evans writes in acta D57 1355 (2001) on p 1358 section 5.2:

 the convention used in AMoRe (Navaza, 1994)
 and other CCP4 programs (Collaborative Computational
 Project, Number 4, 1994) is to rotate by gamma around z, then by 
beta
 around the new y, then by alpha around the new z again,
 R = Rz(al)Ry(be)Rz(ga)

 This seems correct, as the first rotation is applied first to
 vector x, then the second to the new one, etc, thus
 x' = (Rz(al)(Ry(be)(Rz(ga)x)))

 In J.Appl.Cryst. 30 402-410 (1977) in the convrot description,
 Sascha Uzhumtsev lists in table one for (Navaza 1994):

 alpha about Z, beta about Y and gamma about new Z
 and gives the *same* resulting rotation
 Rz(al)Ry(be)Rz(ga)

 This seems to be a contradiction I cannot resolve?

 Thx, br
 -
 Bernhard Rupp
 001 (925) 209-7429
 +43 (676) 571-0536
 [EMAIL

[ccp4bb] Post-doc position

2007-06-18 Thread Philippe DUMAS
Postdoc position in Protein-RNA crystallography

A postdoc position is available in the group of crystallography headed by P.
Dumas in the laboratory RNA Architecture and Reactivity at IBMC,
Strasbourg (France). The position is for an HIV-related project that will
focus on the structure of a ternary complex between (1) a tRNA(Lys,3)
(diverted from the infected cell), (2) a fragment of the viral RNA and (3)
the viral retrotranscriptase (RT). The formation of this ternary complex is
a key step in the viral replication cycle since it occurs early and involves
a cellular partner (the tRNA(Lys,3)) that is independent of any viral
mutations. For that reason, it might be an excellent target for a new
antiviral drug.

The structural work will benefit strongly of a large body of previous
solution studies. In particular, a selenomethionine viral RT, the
tRNA(Lys,3), as well as viral RNA fragments of various lenght are routinely
produced in our lab. We are equipped with a crystallization robot and with
an X-ray facility for crystal testing. Our laboratory is located into a
thriving environment for all aspects of RNA research.

Qualification: The candidate should have a PhD with a background in RNA
biology. An experience in X-ray crystallography will be strongly
appreciated.

How to apply: send a CV with a list of publications to Eric Ennifar:
[EMAIL PROTECTED]



Philippe Dumas
IBMC-CNRS, UPR9002
15, rue René Descartes 67084 Strasbourg cedex
tel: +33 (0)3 88 41 70 02
[EMAIL PROTECTED]