Re: [ccp4bb] Dependency of theta on n/d in Bragg's law

2013-09-02 Thread Peter Keller
On Sun, 2013-09-01 at 22:28 +0200, James Holton wrote:

  ... but Bragg's genius was in simplifying all this to a little 
 rule which tells you how much to turn the crystal to see a given spot.  
 We sort of take this for granted now that we have automated 
 diffractometers that do all the math for us, but in 1914 realizing that 
 the rules or ordinary optics could be applied to x-rays and crystals was 
 a pretty important step forward.

The history of all this can be read in chapter 5 of Fifty Years of
X-Ray Diffraction, edited by Ewald, that can be found here:
http://www.iucr.org/publ/50yearsofxraydiffraction

As noted on page 58, recognising that the principles of optics could be
applied to X-rays and crystals meant that W.H. Bragg had to abandon his
cherished view of X-rays as having a purely particle-like nature. An
object lesson in open-mindedness, I think.

Regards,
Peter.

-- 
Peter Keller Tel.: +44 (0)1223 353033
Global Phasing Ltd., Fax.: +44 (0)1223 366889
Sheraton House,
Castle Park,
Cambridge CB3 0AX
United Kingdom


Re: [ccp4bb] Dependency of theta on n/d in Bragg's law

2013-09-01 Thread James Holton
Perhaps some of the confusion here arises because Bragg's Law is not a 
Fourier transform.


Remember, in the standard diagram of Bragg's Law, there are only two 
atoms that are d apart.  The full diffraction pattern from just two 
atoms actually looks like this:

http://bl831.als.lbl.gov/~jamesh/nearBragg/intimage_twoatom.img

This is an ADSC format image, so you can look at it in your favorite 
diffraction image viewer, such as ADXV, imosflm, HKL2000, XDSviewer, 
ipdisp, fit2d, whatever you like.  Or, you can substitute png for 
img in the filename and look at it in your web browser.  Notice how 
there are 9 bands for only 2 atoms?  If you look at the *.img file you 
can see that the d spacing of the middle of each line is indeed 10 A, 
5A, 3.33A, and 2.5A.  Just as Bragg's Law predicts for n=1,2,3,4 because 
the two atoms were 10 A apart (d = 10 A) and the wavelength was 1 A.  
But what about the corners?  The 2.5 A band reads a d-spacing of 1.65 
A at the corners of the detector!  Also, if you look at the central 
band, it passes through the direct beam (d=infinity), but at the edge 
of the detector it reads 2.14 A!   Does this mean that Bragg's Law is 
wrong!?


Of course not, it just means that Bragg's Law is one dimensional. 
Strictly speaking, it is about planes of atoms, not individual atoms 
themselves.  The Fourier transform of two dots is indeed a series of 
bands (an interference pattern), but the Fourier transform of two 
planes (edge-on to the beam) is this:

http://bl831.als.lbl.gov/~jamesh/nearBragg/BraggsLaw/20A_disks.img

What?  A caterpillar?  How does that happen?  Well, it helps to look at 
the diffraction pattern of a single plane:

http://bl831.als.lbl.gov/~jamesh/nearBragg/BraggsLaw/20A_disk.img

 I should point out here that I'm not modelling an infinite plane, but 
rather a disk 20A in radius.  This is why the edge of the caterpillar 
has a d-spacing of 40 A.  If it were an infinite plane, its Fourier 
transform would be an infinitely thin line, visible at only one point: 
the origin.  Which is not all that interesting. The halo around the 
main line is because the plane has a hard edge, and so its Fourier 
transform has fringes (its a sinc function).  The reason why it does 
not run from the top of the image to the bottom is because the Ewald 
sphere (a geometric representation of Bragg's law) is curved, but the 
Fourier transform of a disk is a straight line in reciprocal space.


  By giving the plane a finite size you can more easily see that the 
diffraction pattern of a stack of two planes is nothing more than the 
diffraction pattern of one plane, multiplied by that of two points.  
This is a fundamental property of Fourier transforms: convolution 
becomes a product in reciprocal space.  Where convolution is nothing 
more than copying an object to different places in space, and in this 
case these places are the two points in the Bragg diagram.


But, still, why the caterpillar?  It is because the Ewald sphere is 
curved, so the reciprocal-space line only brushes against it for a few 
orders.  We can, however, get more orders by tilting the planes by some 
angle theta, such as the 11.53 degrees that satisfies n*lambda = 
2*d*sin(theta) for n = 4.  That is this image:

http://bl831.als.lbl.gov/~jamesh/nearBragg/BraggsLaw/tilted_20A_disks.png

Yes, you can still see the caterpillar, but clearly the 4th spot up is 
brighter than all but the 0th-order one.  The only reason why it is not 
identical in intensity is because of the inverse square law: the pixels 
on the detector for the 4th-order reflection are a little further away 
from the sample than the zeroeth-order ones.


 As the planes get wider:
http://bl831.als.lbl.gov/~jamesh/nearBragg/BraggsLaw/tilted_20A_disks.png
http://bl831.als.lbl.gov/~jamesh/nearBragg/BraggsLaw/tilted_40A_disks.png
http://bl831.als.lbl.gov/~jamesh/nearBragg/BraggsLaw/tilted_80A_disks.png
http://bl831.als.lbl.gov/~jamesh/nearBragg/BraggsLaw/tilted_160A_disks.png
the caterpillar gets thinner you see less and less of the n=1,2,3 
orders.  For an infinite pair of planes, there will be only two 
intersection points: the origin and the n=4 spot.  This is not because 
the intermediate orders are not there, they are just not satisfying the 
Bragg condition, and neither are their fringes.


Of course, with only two planes, even the infinite-plane spot will be 
much fatter in the vertical.  Formally, about half as fat as the 
distance between the spots.  This is because the interference pattern 
for only two points is still there.  But if you have three, four or five 
planes, you get these:

http://bl831.als.lbl.gov/~jamesh/nearBragg/BraggsLaw/tilted_20A_disk.png
http://bl831.als.lbl.gov/~jamesh/nearBragg/BraggsLaw/tilted_20A_disks.png
http://bl831.als.lbl.gov/~jamesh/nearBragg/BraggsLaw/tilted_20A_3disks.png
http://bl831.als.lbl.gov/~jamesh/nearBragg/BraggsLaw/tilted_20A_4disks.png

Re: [ccp4bb] Dependency of theta on n/d in Bragg's law

2013-08-28 Thread Ian Tickle
On 22 August 2013 07:54, James Holton jmhol...@lbl.gov wrote:

 Well, yes, but that's something of an anachronism.   Technically, a
 Miller index of h,k,l can only be a triplet of prime numbers (Miller, W.
  (1839). A treatise on crystallography. For J.  JJ Deighton.).  This is
 because Miller was trying to explain crystal facets, and facets don't have
 harmonics.  This might be why Bragg decided to put an n in there.  But
 it seems that fairly rapidly after people starting diffracting x-rays off
 of crystals, the Miller Index became generalized to h,k,l as integers,
 and we never looked back.


Yes but I think it would be a pity if we lost IMO the important distinction
in meaning between Miller indices as defined above as co-prime integers
and (for want of a better term) reflection indices as found in an MTZ
file.  For example, Stout  Jensen makes a careful distinction between them
(as I recall they call reflection indices something like general
indices: sorry I don't have my copy of S  J to hand to check their exact
terminology).

The confusion that can arise by referring to reflection indices as
Miller indices is well illustrated if you try to explain Bragg's equation
to a novice, because the d in the equation (i.e. n lambda = 2d
sin[theta]) is the interplanar separation for planes as calculated from
their Miller indices, whereas the theta is of course the theta angle as
calculated from the corresponding reflection indices.  If you say that
Miller  reflection indices are the same thing you have a hard time
explaining the equation!  One obvious way out of the dilemma is to drop the
n term (so now lambda = 2d sin[theta]) and then redefine d as d/n so
the new d is calculated from the same reflection indices as theta, and the
Miller indices don't enter into it.  But then you have to explain to your
novice why you know better than a Nobel prizewinner!  As you say Bragg no
doubt had a good reason to include the n (i.e. to make the connection
between the macroscopic properties of a crystal and its diffraction
pattern).

Sorry for coming into this discussion somewhat late!

Cheers

-- Ian


Re: [ccp4bb] AW: [ccp4bb] Dependency of theta on n/d in Bragg's law

2013-08-23 Thread Petr Leiman
Dear Dom,

No attachment here in either of your messages...

Maybe you can put it up on Dropbox or Google drive and send us the URL?

Thanks,

Petr

On 08/23/2013 04:33 AM, Dom Bellini wrote:
 Hi

 Some people emailed me saying that the attachment did not get through.

 I hope this will work.

 Sorry.

 D

 
 From: CCP4 bulletin board [CCP4BB@JISCMAIL.AC.UK] on behalf of Edward A. 
 Berry [ber...@upstate.edu]
 Sent: 23 August 2013 00:01
 To: ccp4bb
 Subject: Re: [ccp4bb] AW: [ccp4bb] Dependency of theta on n/d in Bragg's law

 OK, I see my mistake. n has nothing to do with higher-order
 reflections or planes at closer spacing than unit cell dimensions.
 n 1 implies larger d, like the double layer mentioned by the original
 poster, and those turn out to give the same structure factor as the
 n=1 reflection so we only consider n=1 (for monochromatic).
 The higher order reflection from closer spaced miller planes
 of course do not satisfy bragg lawat the same lambda and theta.
 So I hope people will disregard my confused post (but I think the
 one before was somewhat in the right direction)

 The higher order diffractions come from finding planes through
 the latticethat intersect a large number of points? no- planes
 corresponding to 0,0,5 in an orthorhombic crystal do not  all
 intersect lattice points, and anyway protein crystals aren't
 made of lattice points, they havecontinuous density.

 Applying Braggs law to these closer-spaced miller planes
 will tell you that points in one plane will diffract in phase.
 But since the protein in the five layers between the planes
 will be different, in fact the layers will not diffract in
 phase  and diffraction condition will not be met.

 You could say OK, each of the 5 layesr will diffract
 with different amplitude and out of phase, but their
 vector-sum resultant will be the same as that of
 every other five layers, so diffraction from points
 through the whole crystal  will interfere constructively.

 Or you could say that this theta and lambda satisfy the
 bragg equation with d= c axis and n=5, so that points
 separated by cell dimensions, which are equal due to
 the periodicity of the crystal, will diffract in phase.
 That would be a use for n1 with monochromatic light.
 The points separated by the small d-spacing scatter in
 phase, but that is irrelevant since they are not
 crystallographically equivalent. But they also scatter in phase
 (actually out of phase by 5 wavelengths) with points separated
 by one unit cell, because they satisfy braggs law with
 d=c and n=5 (for 0,0,5 reflection still).
 So then the higher-order reflections do involve n,
 but it is the small d-spacing that corresponds to n=1
 and the unit cell spacing which corresponds to the higher n.
 The latter results in the diffraction condition being met.
 (or am I still confused?)
 (and I hope I've got my line-wrapping under control now so this won't be so 
 hard to read)






















 Ethan Merritt wrote:
 On Thursday, August 22, 2013 02:19:11 pm Edward A. Berry wrote:
 One thing I find confusing is the different ways in which d is used.
 In deriving Braggs law, d is often presented as a unit cell dimension,
 and n accounts for the higher order miller planes within the cell.
 It's already been pointed out above, and you sort of paraphrase it later,
 but let me give my spin on a non-confusing order of presentation.

 I think it is best to tightly associate n and lambda in your mind
 (and in the mind of a student). If you solve the Bragg's law equation for
 the wavelength, you don't get a unique answer because you are actually
 solving for n*lambda rather than lambda.

 There is no ambiguity about the d-spacing, only about the wavelength
 that d and theta jointly select for.

 That's why, as James Holton mentioned, when dealing with a white radiation
 source you need to do something to get rid of the harmonics of the wavelength
 you are interested in.

 But then when you ask a student to use Braggs law to calculate the 
 resolution
 of a spot at 150 mm from the beam center at given camera length and 
 wavelength,
 without mentioning any unit cell, they ask, do you mean the first order 
 reflection?
 I would answer that with Assume a true monochromatic beam, so n is 
 necessarily
 equal to 1.

 Yes, it would be the first order reflection from planes whose spacing is the
 answer i am looking for, but going back to Braggs law derived with the unit 
 cell
 it would be a high order reflection for any reasonable sized protein 
 crystal.
 For what it's worth, when I present Bragg's law I do it in three stages.
 1) Explain the periodicity of the lattice (use a 2D lattice for clarity).
 2) Show that a pair of indices hk defines some set of planes (lines)
  through the lattice.
 3) Take some arbitrary set of planes and use it to draw the Bragg 
 construction.

 This way the Bragg diagram refers to a particular set of planes,
 d refers to the 

[ccp4bb] AW: [ccp4bb] AW: [ccp4bb] Dependency of theta on n/d in Bragg's law

2013-08-23 Thread Herman . Schreuder
Dear Edward,

Now I am getting a little confused: If you look at a higher order 2n 
reflection, you will also get diffraction from the intermediate 1n layers, so 
the structure factor you are looking at is in fact the 1n structure factor. I 
think your original post was correct.

To summarize how I see it:
1) Braggs law has nothing to do with crystals or unit cells, it only describes 
diffraction from sets of planes.
2) However, to get constructive interference from all unit cells in the 
crystal, the periodicity of the set of planes must match the periodicity of the 
crystal, which means that only sets of planes with integer miller indices are 
allowed.

So the unit cell dictates which sets of planes are able to constructively 
diffract. However, there might not be anything physically present in the 
crystal with that periodicity. In this case the corresponding reflection will 
be weak or absent. This is the kind of information we use to calculate our 
wonderful electron density maps.

Best,
Herman



-Ursprüngliche Nachricht-
Von: CCP4 bulletin board [mailto:CCP4BB@JISCMAIL.AC.UK] Im Auftrag von Edward 
A. Berry
Gesendet: Freitag, 23. August 2013 01:01
An: CCP4BB@JISCMAIL.AC.UK
Betreff: Re: [ccp4bb] AW: [ccp4bb] Dependency of theta on n/d in Bragg's law

OK, I see my mistake. n has nothing to do with higher-order reflections or 
planes at closer spacing than unit cell dimensions.
n 1 implies larger d, like the double layer mentioned by the original poster, 
and those turn out to give the same structure factor as the
n=1 reflection so we only consider n=1 (for monochromatic).
The higher order reflection from closer spaced miller planes of course do not 
satisfy bragg lawat the same lambda and theta.
So I hope people will disregard my confused post (but I think the one before 
was somewhat in the right direction)

The higher order diffractions come from finding planes through the latticethat 
intersect a large number of points? no- planes corresponding to 0,0,5 in an 
orthorhombic crystal do not  all intersect lattice points, and anyway protein 
crystals aren't made of lattice points, they havecontinuous density.

Applying Braggs law to these closer-spaced miller planes will tell you that 
points in one plane will diffract in phase.
But since the protein in the five layers between the planes will be different, 
in fact the layers will not diffract in phase  and diffraction condition will 
not be met.

You could say OK, each of the 5 layesr will diffract with different amplitude 
and out of phase, but their vector-sum resultant will be the same as that of 
every other five layers, so diffraction from points through the whole crystal  
will interfere constructively.

Or you could say that this theta and lambda satisfy the bragg equation with d= 
c axis and n=5, so that points separated by cell dimensions, which are equal 
due to the periodicity of the crystal, will diffract in phase.
That would be a use for n1 with monochromatic light.
The points separated by the small d-spacing scatter in phase, but that is 
irrelevant since they are not crystallographically equivalent. But they also 
scatter in phase (actually out of phase by 5 wavelengths) with points separated 
by one unit cell, because they satisfy braggs law with d=c and n=5 (for 0,0,5 
reflection still).
So then the higher-order reflections do involve n, but it is the small 
d-spacing that corresponds to n=1 and the unit cell spacing which corresponds 
to the higher n.
The latter results in the diffraction condition being met.
(or am I still confused?)
(and I hope I've got my line-wrapping under control now so this won't be so 
hard to read)






















Ethan Merritt wrote:
 On Thursday, August 22, 2013 02:19:11 pm Edward A. Berry wrote:
 One thing I find confusing is the different ways in which d is used.
 In deriving Braggs law, d is often presented as a unit cell 
 dimension, and n accounts for the higher order miller planes within the 
 cell.

 It's already been pointed out above, and you sort of paraphrase it 
 later, but let me give my spin on a non-confusing order of presentation.

 I think it is best to tightly associate n and lambda in your mind (and 
 in the mind of a student). If you solve the Bragg's law equation for 
 the wavelength, you don't get a unique answer because you are actually 
 solving for n*lambda rather than lambda.

 There is no ambiguity about the d-spacing, only about the wavelength 
 that d and theta jointly select for.

 That's why, as James Holton mentioned, when dealing with a white 
 radiation source you need to do something to get rid of the harmonics 
 of the wavelength you are interested in.

 But then when you ask a student to use Braggs law to calculate the 
 resolution of a spot at 150 mm from the beam center at given camera 
 length and wavelength, without mentioning any unit cell, they ask, do you 
 mean the first order reflection?

 I would answer that with Assume a true monochromatic 

Re: [ccp4bb] AW: [ccp4bb] Dependency of theta on n/d in Bragg's law

2013-08-23 Thread Dom Bellini
Hi,

Despite the not so large size of the pdf (256 kbs), the file does not want to 
get through.

Since a reasonable amount of people seem to have liked a copy for their 
students, following some smart suggestions I have put the booklet on Dropbox.

Here's the link: https://www.dropbox.com/s/gljckhw7ui6df6c/Booklet.pdf?m

Best,

D

-Original Message-
From: CCP4 bulletin board [mailto:CCP4BB@JISCMAIL.AC.UK] On Behalf Of Dom 
Bellini
Sent: 22 August 2013 23:38
To: ccp4bb
Subject: Re: [ccp4bb] AW: [ccp4bb] Dependency of theta on n/d in Bragg's law

Dear Community,

I have attached a short booklet written some 6 years ago during rainy evenings 
to teach principle of crystal diffraction with biologist students in mind, 
never used it as I don't have students, but I now believe its mission was this 
thread ;-)

It uses lots of real space diffraction examples, easily to picture them in the 
head, so to stick with the students for good. It was written with the 
philadelphia philosophy of explain it to me as if I was a 5 yo.

I hope it can save some students the time of going to look for many different 
sources as it is probably a nice summary of the diffraction process.

A short answer, same as many of the other answers but in different words, to 
the original post would be: each hkl family of planes generates one and only 
one structure factor or diffraction spot without any contributions from other 
families (talking of monochromatic experiments). Perhaps doubts may arise due 
to the fact that, e.g., every other 002 plane superpose/aligns with one 001 
plane, but since their spacing d is half of the other and lambda is fixed, from 
2d sin(theta)=lambda it will result that 002, despite perfectly superposing 
with (same inclination of) 001, will reflect in a different direction with 
sin(theta) twice as that for 001. Despite 001 and 002 superpose/align with one 
another the diffraction angle changes because it is not a real reflection 
phenomenon (as if they were mirrors), keeping in mind that the planes are only 
imaginary and a way to help us to visualize the process.

Probably many people from the bb that could have given a better explanation 
than mine might have been put off by the length of the email that might have 
been required. Since I had already written it and ready to go I decided to 
attach it with the best of intentions.

Hopefully it may turn up to be useful for some one.

D




From: CCP4 bulletin board [CCP4BB@JISCMAIL.AC.UK] on behalf of Ethan Merritt 
[merr...@u.washington.edu]
Sent: 22 August 2013 22:57
To: ccp4bb
Subject: Re: [ccp4bb] AW: [ccp4bb] Dependency of theta on n/d in Bragg's law

On Thursday, August 22, 2013 02:19:11 pm Edward A. Berry wrote:
 One thing I find confusing is the different ways in which d is used.
 In deriving Braggs law, d is often presented as a unit cell dimension, 
 and n accounts for the higher order miller planes within the cell.

It's already been pointed out above, and you sort of paraphrase it later, but 
let me give my spin on a non-confusing order of presentation.

I think it is best to tightly associate n and lambda in your mind (and in the 
mind of a student). If you solve the Bragg's law equation for the wavelength, 
you don't get a unique answer because you are actually solving for n*lambda 
rather than lambda.

There is no ambiguity about the d-spacing, only about the wavelength that d and 
theta jointly select for.

That's why, as James Holton mentioned, when dealing with a white radiation 
source you need to do something to get rid of the harmonics of the wavelength 
you are interested in.

 But then when you ask a student to use Braggs law to calculate the 
 resolution of a spot at 150 mm from the beam center at given camera 
 length and wavelength, without mentioning any unit cell, they ask, do you 
 mean the first order reflection?

I would answer that with Assume a true monochromatic beam, so n is necessarily 
equal to 1.

 Yes, it would be the first order reflection from planes whose spacing 
 is the answer i am looking for, but going back to Braggs law derived 
 with the unit cell it would be a high order reflection for any reasonable 
 sized protein crystal.

For what it's worth, when I present Bragg's law I do it in three stages.
1) Explain the periodicity of the lattice (use a 2D lattice for clarity).
2) Show that a pair of indices hk defines some set of planes (lines)
   through the lattice.
3) Take some arbitrary set of planes and use it to draw the Bragg construction.

This way the Bragg diagram refers to a particular set of planes, d refers to 
the resolution of that set of planes, and n=1 for a monochromatic X-ray source. 
 The unit cell comes back into it only if you try to interpret the Bragg 
indices belonging to that set of planes.

Ethan


 Maybe the mistake is in bringing the unit cell into the derivation in 
 the first place, just define it in terms of planes. But it is 

Re: [ccp4bb] AW: [ccp4bb] AW: [ccp4bb] Dependency of theta on n/d in Bragg's law

2013-08-23 Thread Edward A. Berry

I think we are just discussing different ways of saying the same thing now.
But that can be interesting, too.  If not, read no farther.

herman.schreu...@sanofi.com wrote:

Dear Edward,

Now I am getting a little confused: If you look at a higher order 2n reflection, you will also 
get diffraction from the intermediate 1n layers, so the structure factor you are looking at is in 
fact the 1n structure factor. I think your original post was correct.


Yes- I think the original poster's question about diffraction from
the 2n planes, and whether that contributes to diffraction in the
1n reflection, has been answered- physically they are the same thing.

My question now is whether it is useful to consider Braggs-law n to
have values other than one, and whether it is useful to tie Braggs law
to the unit cell, or better to derive it for a set of equally spaced
planes (as I think it originally was derived) and later put conditions
on when those planes will diffract.

In addition to Bragg's law one also talks about the Bragg condition,
as somewhat related to the diffraction condition although maybe that
is closer to Laue condition.
But anyway, the motivation for presenting Braggs law is to decide where
(as a function of lambda and theta) diffraction will be observed.
And in a continuos crystal (admittedly not what Braggs law was derived
for, but what the students are interested in) you don't get diffraction
without periodicity, and the spacing of the planes has to be related to
the unit cell for braggs law to help (as you say, periodicity of the planes
must match periodicity of the crystal).

When Bragg's condition is met, points separated by d scatter in phase.
Diffraction occurs when d matches the periodicity of the material, so that
crystallographically-equivalent-by-translation points scatter in phase,
and the resultants from each unit layer (1-D unit cell) scatter in phase.

If we are just considering equal planes separated by d with nothing between,
then the periodicity is just d, and bragg condition gives diffraction
condition.
If we are considering a crystal with continuous density, if d is equal to
a unit cell dimension and the planes are perpendicular to that axis, then
then the periodicity is d and brags law gives the (1-dimensional) diffraction
condition.
If d is some arbitrary spacing not related to periodicity of the matter,
brag condition still tells you that points separated by d along S scatter
in phase but if d has no relation to the periodicity, diffraction conditions
are not met and the different slabs thickness d will not scatter in phase.
If d is an integral submultiple of the periodicity, we get diffraction.
What is the best way to explain this?
1. if points separated by d scatter in phase (actually out of phase by one 
wavelength),
then spots separated by an integral multiple n of d will scatter in phase
(out of phase by n wavelengths). Now if n*d is the unit cell spacing, spots
separated by nd will be crystallographically equivalent, and scatter in
phase (actually out of phase by n wavelengths).
  But this is more elegantly expressed by using braggs law with d' =  the unit
cell spacing, nd, and n'= n. The right hand side of braggs law is calculating
the phase difference, and the left hand is saying this must be = n lambda.
That's what n is there for!

2. the periodicity of the set of planes must match the periodicity of the 
crystal-
if d is a submultiple of the unit cell spacing, points separated by d will 
scatter in
phase, but there is no relation between what exists at those points, so they 
will
not interfere constructively. each slab of thickness d will have resultant phase
(and amplitude) different from the slab above or below it.
But if d is an integral submultiple of unit cell spacing, there will be
periodicity to these slabs- the sixth slab will have the same content as
the first (or the fifth will be the same as the zero'th may be more comfortable)
so each stack of five slabs will interfere constructively with the 5 slabs above
it and so on throughout the crystal.
And as in the answer to original poster's question, it is the same diffraction
whether you consider it to be the first order diffraction of planes with d=c/5
or the fifth-order diffraction from the unit cell spacing.

I think these are equivalent in terms of the underlying physics
so this is semantics, or choosing the most intuitive explanation.
I will consider introducing Bragg's law for arbitrary planes in space
and introducing diffraction condition later with Laue condition.
And of course I should look again at some of the excellent textbooks
that are available in coming up with a plan.

But when a colleague studying 2D crystals in cryo-EM gloats:
I got diffraction out to the fifth order, we don't want to pour
cold water by saying, sorry, those are first order diffraction from
from planes at 1/5 spacing! even though it means the same thing in
terms of resolution. (OK, order of diffraction doesn't have to be
equated 

Re: [ccp4bb] AW: [ccp4bb] AW: [ccp4bb] Dependency of theta on n/d in Bragg's law

2013-08-23 Thread Jrh
Dear Edward,
Re your em colleagues:-
We are indeed happy to understand their diffraction to 5th order, by which we 
mean the d/5 reflection (1st order) because the two are simply different 
viewpoints.

Just one loose end:-
The remarkable thing is that the diffraction from a crystal is largely empty. 
We focus on the spots, true, but the largely empty diffraction space from a 
crystal in a sense is a most useful aspect about the W L Bragg equation.

Finally, just to mention, when I saw the laser light diffraction from a 
periodic ruled grating for the first time i thought:- it is magnificent. I rank 
it alongside the spectral lines in an atom's emission spectrum, such as the 
sodium D lines ie as i saw in my physics teaching lab. The red shifted hydrogen 
spectra of Hubble himself, available to view in the museum of the astronomical 
observatory in Los Angeles, are of course in a yet different, higher, league of 
where we are in the (expanding) universe. 

Yours sincerely,
John

Prof John R Helliwell DSc FInstP CPhys FRSC CChem F Soc Biol.
Chair School of Chemistry, University of Manchester, Athena Swan Team.
http://www.chemistry.manchester.ac.uk/aboutus/athena/index.html
 
 

On 23 Aug 2013, at 16:34, Edward A. Berry ber...@upstate.edu wrote:

 I think we are just discussing different ways of saying the same thing now.
 But that can be interesting, too.  If not, read no farther.
 
 herman.schreu...@sanofi.com wrote:
 Dear Edward,
 
 Now I am getting a little confused: If you look at a higher order 2n 
 reflection, you will also get diffraction from the intermediate 1n layers, 
 so the structure factor you are looking at is in fact the 1n structure 
 factor. I think your original post was correct.
 
 Yes- I think the original poster's question about diffraction from
 the 2n planes, and whether that contributes to diffraction in the
 1n reflection, has been answered- physically they are the same thing.
 
 My question now is whether it is useful to consider Braggs-law n to
 have values other than one, and whether it is useful to tie Braggs law
 to the unit cell, or better to derive it for a set of equally spaced
 planes (as I think it originally was derived) and later put conditions
 on when those planes will diffract.
 
 In addition to Bragg's law one also talks about the Bragg condition,
 as somewhat related to the diffraction condition although maybe that
 is closer to Laue condition.
 But anyway, the motivation for presenting Braggs law is to decide where
 (as a function of lambda and theta) diffraction will be observed.
 And in a continuos crystal (admittedly not what Braggs law was derived
 for, but what the students are interested in) you don't get diffraction
 without periodicity, and the spacing of the planes has to be related to
 the unit cell for braggs law to help (as you say, periodicity of the planes
 must match periodicity of the crystal).
 
 When Bragg's condition is met, points separated by d scatter in phase.
 Diffraction occurs when d matches the periodicity of the material, so that
 crystallographically-equivalent-by-translation points scatter in phase,
 and the resultants from each unit layer (1-D unit cell) scatter in phase.
 
 If we are just considering equal planes separated by d with nothing between,
 then the periodicity is just d, and bragg condition gives diffraction
 condition.
 If we are considering a crystal with continuous density, if d is equal to
 a unit cell dimension and the planes are perpendicular to that axis, then
 then the periodicity is d and brags law gives the (1-dimensional) diffraction
 condition.
 If d is some arbitrary spacing not related to periodicity of the matter,
 brag condition still tells you that points separated by d along S scatter
 in phase but if d has no relation to the periodicity, diffraction conditions
 are not met and the different slabs thickness d will not scatter in phase.
 If d is an integral submultiple of the periodicity, we get diffraction.
 What is the best way to explain this?
 1. if points separated by d scatter in phase (actually out of phase by one 
 wavelength),
 then spots separated by an integral multiple n of d will scatter in phase
 (out of phase by n wavelengths). Now if n*d is the unit cell spacing, spots
 separated by nd will be crystallographically equivalent, and scatter in
 phase (actually out of phase by n wavelengths).
  But this is more elegantly expressed by using braggs law with d' =  the unit
 cell spacing, nd, and n'= n. The right hand side of braggs law is calculating
 the phase difference, and the left hand is saying this must be = n lambda.
 That's what n is there for!
 
 2. the periodicity of the set of planes must match the periodicity of the 
 crystal-
 if d is a submultiple of the unit cell spacing, points separated by d will 
 scatter in
 phase, but there is no relation between what exists at those points, so they 
 will
 not interfere constructively. each slab of thickness d will have resultant 
 phase
 

[ccp4bb] AW: [ccp4bb] Dependency of theta on n/d in Bragg's law

2013-08-22 Thread Herman . Schreuder
Dear James,
thank you very much for this answer. I had also been wondering about it. To 
clearify it for myself, and maybe for a few other bulletin board readers, I 
reworked the Bragg formula to:

sin(theta) = n*Lamda / 2*d

which means that if we take n=2, for the same sin(theta) d becomes twice as big 
as well, which means that we describe interference with a wave from a second 
layer of the same stack of planes, which means that we are still looking at the 
same structure factor. 

Best,
Herman


-Ursprüngliche Nachricht-
Von: CCP4 bulletin board [mailto:CCP4BB@JISCMAIL.AC.UK] Im Auftrag von James 
Holton
Gesendet: Donnerstag, 22. August 2013 08:55
An: CCP4BB@JISCMAIL.AC.UK
Betreff: Re: [ccp4bb] Dependency of theta on n/d in Bragg's law

Well, yes, but that's something of an anachronism.   Technically, a 
Miller index of h,k,l can only be a triplet of prime numbers (Miller, W.  
(1839). A treatise on crystallography. For J.  JJ Deighton.).  This is because 
Miller was trying to explain crystal facets, and facets don't have harmonics. 
 This might be why Bragg decided to put an n in there.  But it seems that 
fairly rapidly after people starting diffracting x-rays off of crystals, the 
Miller Index became generalized to h,k,l as integers, and we never looked 
back.

It is a mistake, however, to think that there are contributions from different 
structure factors in a given spot.  That does not happen.  The harmonics you 
are thinking of are actually part of the Fourier transform.  Once you do the 
FFT, each h,k,l has a unique F and the intensity of a spot is proportional to 
just one F.

The only way you CAN get multiple Fs in the same spot is in Laue diffraction. 
Note that the n is next to lambda, not d.  And yes, in Laue you do get 
single spots with multiple hkl indices (and therefore multiple structure 
factors) coming off the crystal in exactly the same direction.  Despite being 
at different wavelengths they land in exactly the same place on the detector. 
This is one of the more annoying things you have to deal with in Laue.

A common example of this is the harmonic contamination problem in beamline 
x-ray beams.  Most beamlines use the h,k,l = 1,1,1 reflection from a large 
single crystal of silicon as a diffraction grating to select the wavelength for 
the experiment.  This crystal is exposed to white beam, so in every 
monochromator you are actually doing a Laue diffraction experiment on a small 
molecule crystal.  One good reason for using Si(111) is because Si(222) is a 
systematic absence, so you don't have to worry about the lambda/2 x-rays going 
down the pipe at the same angle as the lambda you selected.  However, Si(333) 
is not absent, and unfortunately also corresponds to the 3rd peak in the 
emission spectrum of an undulator set to have the fundamental coincide with the 
Si(111)-reflected wavelength.  This is probably why the third harmonic is 
often the term used to describe the reflection from Si(333), even for beamlines 
that don't have an undulator.  But, technically, Si(333) is not a harmonic of 
Si(111).  They are different reciprocal lattice points and each has its own 
structure factor.  It is only the undulator that has harmonics.

However, after the monochromator you generally don't worry too much about the 
n=2 situation for:
n*lambda = 2*d*sin(theta)
because there just aren't any photons at that wavelength.  Hope that makes 
sense.

-James Holton
MAD Scientist


On 8/20/2013 7:36 AM, Pietro Roversi wrote:
 Dear all,

 I am shocked by my own ignorance, and you feel free to do the same, 
 but do you agree with me that according to Bragg's Law a diffraction 
 maximum at an angle theta has contributions to its intensity from 
 planes at a spacing d for order 1, planes of spacing 2*d for order 
 n=2, etc. etc.?

 In other words as the diffraction angle is a function of n/d:

 theta=arcsin(lambda/2 * n/d)

 several indices are associated with diffraction at the same angle?

 (I guess one could also prove the same result by a number of Ewald 
 constructions using Ewald spheres of radius (1/n*lambda with n=1,2,3 
 ...)

 All textbooks I know on the argument neglect to mention this and in 
 fact only n=1 is ever considered.

 Does anybody know a book where this trivial issue is discussed?

 Thanks!

 Ciao

 Pietro



 Sent from my Desktop

 Dr. Pietro Roversi
 Oxford University Biochemistry Department - Glycobiology Division 
 South Parks Road Oxford OX1 3QU England - UK Tel. 0044 1865 275339


Re: [ccp4bb] Dependency of theta on n/d in Bragg's law

2013-08-22 Thread Bernhard Rupp
Adding to what James wrote: I see this as follows:

Bragg's law is only a necessary but not a sufficient criterion for
occurrence of a diffraction peak if viewed as a reflection. The problem imho
comes from not considering the structure factor as the actual quantifier of
(single photon) diffraction. Take for example the reflection condition rules
for I centered cells: Sum of  the three reflection indices all even. 111 333
missing but 222 is there...

The problem does not arise if you treat the diffraction pattern as a
probability distribution where the intensities are proportional to the
(Square of) the structure factors which includes the hkls and thus
automatically and necessarily the Bragg ns. Taking the simple 2-wave Bragg
reflection picture verbatim does not do justice to the diffraction process
(e.g. the non-coherence between incoming photons and necessity for a single
photon process have been discussed here before). James has already suggested
a few historic reasons.

Best, BR

-Original Message-
From: CCP4 bulletin board [mailto:CCP4BB@JISCMAIL.AC.UK] On Behalf Of Dom
Bellini
Sent: Dienstag, 20. August 2013 16:49
To: CCP4BB@JISCMAIL.AC.UK
Subject: Re: [ccp4bb] Dependency of theta on n/d in Bragg's law

Dear Pietro,

Ladd  Palmer book does explain it, just first example that springs to mind.

HTH

D

-Original Message-
From: CCP4 bulletin board [mailto:CCP4BB@JISCMAIL.AC.UK] On Behalf Of Pietro
Roversi
Sent: 20 August 2013 15:37
To: ccp4bb
Subject: [ccp4bb] Dependency of theta on n/d in Bragg's law

Dear all,

I am shocked by my own ignorance, and you feel free to do the same, but do
you agree with me that according to Bragg's Law a diffraction maximum at an
angle theta has contributions to its intensity from planes at a spacing d
for order 1, planes of spacing 2*d for order n=2, etc. etc.?

In other words as the diffraction angle is a function of n/d:

theta=arcsin(lambda/2 * n/d)

several indices are associated with diffraction at the same angle?

(I guess one could also prove the same result by a number of Ewald
constructions using Ewald spheres of radius (1/n*lambda with n=1,2,3 ...)

All textbooks I know on the argument neglect to mention this and in fact
only n=1 is ever considered.

Does anybody know a book where this trivial issue is discussed?

Thanks!

Ciao

Pietro



Sent from my Desktop

Dr. Pietro Roversi
Oxford University Biochemistry Department - Glycobiology Division South
Parks Road Oxford OX1 3QU England - UK Tel. 0044 1865 275339



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Re: [ccp4bb] AW: [ccp4bb] Dependency of theta on n/d in Bragg's law

2013-08-22 Thread Edward A. Berry

herman.schreu...@sanofi.com wrote:

Dear James,
thank you very much for this answer. I had also been wondering about it. To 
clearify it for myself, and maybe for a few other bulletin board readers, I 
reworked the Bragg formula to:

sin(theta) = n*Lamda / 2*d

which means that if we take n=2, for the same sin(theta) d becomes twice as big 
as well, which means that we describe interference with a wave from a second 
layer of the same stack of planes, which means that we are still looking at the 
same structure factor.

Best,
Herman




This is how I see it as well- if you do a Bragg-law construct with two periods of d and consider the second order 
diffraction from the double layer, and compare it to the single-layer case you will see it is the same wave traveling 
the same path with the same phase  at each point. When you integrate rho(r) dot S dr, the complex exponential will have 
a factor of 2 because it is second order, so the spatial frequency is the same. (I haven't actually shown this, being a 
math-challenged biologist, but put it on my list of things to do).
 So we could calculate the structure factor as either first order diffraction from the conventional d or second order 
diffraction from spacing of 2d and get the same result. by convention we use first order diffraction only.

(same would hold for 3'd order diffraction from 3 layers etc.)




-Ursprüngliche Nachricht-
Von: CCP4 bulletin board [mailto:CCP4BB@JISCMAIL.AC.UK] Im Auftrag von James 
Holton
Gesendet: Donnerstag, 22. August 2013 08:55
An: CCP4BB@JISCMAIL.AC.UK
Betreff: Re: [ccp4bb] Dependency of theta on n/d in Bragg's law

Well, yes, but that's something of an anachronism.   Technically, a
Miller index of h,k,l can only be a triplet of prime numbers (Miller, W.  (1839). A treatise on 
crystallography. For J.  JJ Deighton.).  This is because Miller was trying to explain crystal facets, and facets don't 
have harmonics.  This might be why Bragg decided to put an n in there.  But it seems that fairly 
rapidly after people starting diffracting x-rays off of crystals, the Miller Index became generalized to h,k,l 
as integers, and we never looked back.

It is a mistake, however, to think that there are contributions from different structure factors in 
a given spot.  That does not happen.  The harmonics you are thinking of are actually 
part of the Fourier transform.  Once you do the FFT, each h,k,l has a unique F and the 
intensity of a spot is proportional to just one F.

The only way you CAN get multiple Fs in the same spot is in Laue diffraction. Note that the 
n is next to lambda, not d.  And yes, in Laue you do get single spots with 
multiple hkl indices (and therefore multiple structure factors) coming off the crystal in exactly 
the same direction.  Despite being at different wavelengths they land in exactly the same place on 
the detector. This is one of the more annoying things you have to deal with in Laue.

A common example of this is the harmonic contamination problem in beamline x-ray beams.  Most beamlines use the h,k,l 
= 1,1,1 reflection from a large single crystal of silicon as a diffraction grating to select the wavelength for the experiment.  
This crystal is exposed to white beam, so in every monochromator you are actually doing a Laue diffraction experiment 
on a small molecule crystal.  One good reason for using Si(111) is because Si(222) is a systematic absence, so you 
don't have to worry about the lambda/2 x-rays going down the pipe at the same angle as the lambda you selected.  
However, Si(333) is not absent, and unfortunately also corresponds to the 3rd peak in the emission spectrum of an undulator set 
to have the fundamental coincide with the Si(111)-reflected wavelength.  This is probably why the third harmonic is 
often the term used to describe the reflection from Si(333), even for beamlines that don't have an undulator.  But, technically, 
Si(333) is n

ot a har
monic of Si(111).  They are different reciprocal lattice points and each has its own 
structure factor.  It is only the undulator that has harmonics.


However, after the monochromator you generally don't worry too much about the 
n=2 situation for:
n*lambda = 2*d*sin(theta)
because there just aren't any photons at that wavelength.  Hope that makes 
sense.

-James Holton
MAD Scientist


On 8/20/2013 7:36 AM, Pietro Roversi wrote:

Dear all,

I am shocked by my own ignorance, and you feel free to do the same,
but do you agree with me that according to Bragg's Law a diffraction
maximum at an angle theta has contributions to its intensity from
planes at a spacing d for order 1, planes of spacing 2*d for order
n=2, etc. etc.?

In other words as the diffraction angle is a function of n/d:

theta=arcsin(lambda/2 * n/d)

several indices are associated with diffraction at the same angle?

(I guess one could also prove the same result by a number of Ewald
constructions using Ewald spheres of radius (1/n*lambda with n=1,2,3
...)

All textbooks 

Re: [ccp4bb] Dependency of theta on n/d in Bragg's law

2013-08-22 Thread Jrh
Dear Pietro,
The n in Bragg's Law is indeed most interesting for teachers and a most 
delicate matter for those enquiring about it. 

The diffraction grating equation, from which W L Bragg got the idea, a 'cheap 
accolade' he said to have it named after him in his Scientific American 
article, has each order at its own specific theta. n=1 at one angle, n=2 the 
next order of diffraction at higher angle, n=3 the next order at higher angle 
still and so on. This is how physicists usually first meet the effect and use 
monochromatic laser light and a periodically ruled, line, grating to see the 
laser diffraction pattern in the modern physics teaching labs. 

In crystal structure analysis the ruled line of the above is now the unit cell 
of the crystal and the contents are of chemical and biological interest, unlike 
the inside of a ruled line! Thus the switch to using lamba = 2d sin theta form 
of the equation and the n subsumed into the interplanar spacing. d=1 is the 
unit cell edge, d/2 half the unit cell and so on. Each has its own reflection 
intensity. The highest resolution molecular detail we get of the insides of the 
unit cell arising from the highest n diffraction reflection with a 'measurable' 
 intensity.

The use of polychromatic light, or white X-rays, we need not consider just now. 
Suffice to say at this point that, eg historically, the W H Bragg X-ray 
spectrometer provided monochromatic X-rays to illuminate a single crystal and 
so, as his son W L Bragg put it, immediately enabled a clear and more powerful 
analysis of crystal structure and thereby allowed the first detailed atomic  
X-ray crystal structure, sodium chloride, to be resolved. Several other Xray 
crystal structures immediately followed from the Braggs, using the Xray 
spectrometer, before 1914 ie when the Great War pretty much put all basic 
research and development 'on hold'. 

When one does come to the question of 'Laue diffraction' the so called 
multiplicity distribution of Bragg reflections in Laue pattern spots has been 
treated in detail by Cruickshank et al 1987 Acta Cryst A, as pointed out by 
Tim.  Prime numbers are pivotal to the analysis, as James pointed out. 

Best wishes,
John

Prof John R Helliwell DSc FInstP CPhys FRSC CChem F Soc Biol.
Chair School of Chemistry, University of Manchester, Athena Swan Team.
http://www.chemistry.manchester.ac.uk/aboutus/athena/index.html
 
 

On 20 Aug 2013, at 15:36, Pietro Roversi pietro.rove...@bioch.ox.ac.uk wrote:

 Dear all,
 
 I am shocked by my own ignorance, and you feel free to do the same, but
 do you agree with me that according to Bragg's Law
 a diffraction maximum at an angle theta has contributions
 to its intensity from planes at a spacing d for order 1, 
 planes of spacing 2*d for order n=2, etc. etc.?
 
 In other words as the diffraction angle is a function of n/d:
 
 theta=arcsin(lambda/2 * n/d)
 
 several indices are associated with diffraction at the same angle?
 
 (I guess one could also prove the same result by
 a number of Ewald constructions using Ewald spheres
 of radius (1/n*lambda with n=1,2,3 ...)
 
 All textbooks I know on the argument neglect to mention this
 and in fact only n=1 is ever considered.
 
 Does anybody know a book where this trivial issue is discussed?
 
 Thanks!
 
 Ciao
 
 Pietro
 
 
 
 Sent from my Desktop
 
 Dr. Pietro Roversi
 Oxford University Biochemistry Department - Glycobiology Division
 South Parks Road
 Oxford OX1 3QU England - UK
 Tel. 0044 1865 275339


Re: [ccp4bb] AW: [ccp4bb] Dependency of theta on n/d in Bragg's law

2013-08-22 Thread Gregg Crichlow
I thank everybody for the interesting thread. (I'm sort of a nerd; I find
this interesting.) I generally would always ignore that “n” in Bragg's Law
when performing calculations on data, but its presence was always looming in
the back of my head. But now that the issue arises, I find it interesting to
return to the derivation of Bragg's Law that mimics reflection geometry from
parallel planes. Please let me know whether this analysis is correct.

To obtain constructive 'interference', the extra distance travelled by the
photon from one plane relative to the other must be a multiple of the
wavelength.

 

\_/_

\|/_

 

The vertical line is the spacing d between planes, and theta is the angle
of incidence of the photons to the planes (slanted lines for incident and
diffracted photon - hard to draw in an email window). The extra distance
travelled by the photon is 2*d*sin(theta), so this must be some multiple of
the wavelength: 2dsin(theta)=n*lambda.

But from this derivation, “d” just represents the distance between any two
parallel planes that meet this Bragg condition – not only consecutive planes
in a set of Miller planes. However, when we mention d-spacing with regards
to a data set, we usually are referring to the spacing between consecutive
planes. [The (200) spot represents d=a/2 although there are also planes that
are spaced by a, 3a/2, 2a, etc]. So the minimum d-spacing for any spot would
be the n=1 case. The n=2,3,4 etc, correspond to planes farther apart, also
represented by d in the Bragg eq (based on this derivation) but really are
2d, 3d, 4d etc, by the way we define “d”. So we are really dealing with
2*n*d*sin(theta)=n*lambda, and so the “n’s” cancel out. (Of course, I’m
dealing with the monochromatic case.)

  I never really saw it this way until I was forced to think about it by
this new thread – does this makes sense?

 

 

Gregg

 

-Original Message-
From: CCP4 bulletin board [mailto:CCP4BB@JISCMAIL.AC.UK] On Behalf Of Edward
A. Berry
Sent: Thursday, August 22, 2013 2:16 PM
To: CCP4BB@JISCMAIL.AC.UK
Subject: Re: [ccp4bb] AW: [ccp4bb] Dependency of theta on n/d in Bragg's law

 

 mailto:herman.schreu...@sanofi.com herman.schreu...@sanofi.com wrote:

 Dear James,

 thank you very much for this answer. I had also been wondering about it.
To clearify it for myself, and maybe for a few other bulletin board readers,
I reworked the Bragg formula to:

 

 sin(theta) = n*Lamda / 2*d

 

 which means that if we take n=2, for the same sin(theta) d becomes twice
as big as well, which means that we describe interference with a wave from a
second layer of the same stack of planes, which means that we are still
looking at the same structure factor.

 

 Best,

 Herman

 

 

 

This is how I see it as well- if you do a Bragg-law construct with two
periods of d and consider the second order diffraction from the double
layer, and compare it to the single-layer case you will see it is the same
wave traveling the same path with the same phase  at each point. When you
integrate rho(r) dot S dr, the complex exponential will have a factor of 2
because it is second order, so the spatial frequency is the same. (I haven't
actually shown this, being a math-challenged biologist, but put it on my
list of things to do).

  So we could calculate the structure factor as either first order
diffraction from the conventional d or second order diffraction from spacing
of 2d and get the same result. by convention we use first order diffraction
only.

(same would hold for 3'd order diffraction from 3 layers etc.)

 

 

 

 -Ursprüngliche Nachricht-

 Von: CCP4 bulletin board [ mailto:CCP4BB@JISCMAIL.AC.UK
mailto:CCP4BB@JISCMAIL.AC.UK] Im Auftrag von 

 James Holton

 Gesendet: Donnerstag, 22. August 2013 08:55

 An:  mailto:CCP4BB@JISCMAIL.AC.UK CCP4BB@JISCMAIL.AC.UK

 Betreff: Re: [ccp4bb] Dependency of theta on n/d in Bragg's law

 

 Well, yes, but that's something of an anachronism.   Technically, a

 Miller index of h,k,l can only be a triplet of prime numbers (Miller, W.
(1839). A treatise on crystallography. For J.  JJ Deighton.).  This is
because Miller was trying to explain crystal facets, and facets don't have
harmonics.  This might be why Bragg decided to put an n in there.  But
it seems that fairly rapidly after people starting diffracting x-rays off of
crystals, the Miller Index became generalized to h,k,l as integers, and we
never looked back.

 

 It is a mistake, however, to think that there are contributions from
different structure factors in a given spot.  That does not happen.  The
harmonics you are thinking of are actually part of the Fourier transform.
Once you do the FFT, each h,k,l has a unique F and the intensity of a spot
is proportional to just one F.

 

 The only way you CAN get multiple Fs in the same spot is in Laue
diffraction. Note that the n is next to lambda, not d.  And yes, in Laue
you do get single spots with multiple hkl indices 

Re: [ccp4bb] AW: [ccp4bb] Dependency of theta on n/d in Bragg's law

2013-08-22 Thread Edward A. Berry
One thing I find confusing is the different ways in which d is used. In deriving Braggs law, d is often presented as a 
unit cell dimension, and n accounts for the higher order miller planes within the cell.


But then when you ask a student to use Braggs law to calculate the resolution of a spot at 150 mm from the beam center 
at given camera length and wavelength, without mentioning any unit cell, they ask, do you mean the first order 
reflection?
Yes, it would be the first order reflection from planes whose spacing is the answer i am looking for, but going back to 
Braggs law derived with the unit cell it would be a high order reflection for any reasonable sized protein crystal.


Maybe the mistake is in bringing the unit cell into the derivation in the first place, just define it in terms of 
planes. But it is the periodicity of the crystal that results in the diffraction condition, so we need the unit cell 
there. The protein is not periodic at the higher d-spacing we are talking about now (one of its fourier components is, 
and that is what this reflection is probing.)

eab

Gregg Crichlow wrote:

I thank everybody for the interesting thread. (I'm sort of a nerd; I find this 
interesting.) I generally would always
ignore that “n” in Bragg's Law when performing calculations on data, but its 
presence was always looming in the back of
my head. But now that the issue arises, I find it interesting to return to the 
derivation of Bragg's Law that mimics
reflection geometry from parallel planes. Please let me know whether this 
analysis is correct.

To obtain constructive 'interference', the extra distance travelled by the 
photon from one plane relative to the other
must be a multiple of the wavelength.

\_/_

\|/_

The vertical line is the spacing d between planes, and theta is the angle of 
incidence of the photons to the planes
(slanted lines for incident and diffracted photon - hard to draw in an email 
window). The extra distance travelled by
the photon is 2*d*sin(theta), so this must be some multiple of the wavelength: 
2dsin(theta)=n*lambda.

But from this derivation, “d” just represents the distance between /any/ two 
parallel planes that meet this Bragg
condition – not only consecutive planes in a set of Miller planes. However, 
when we mention d-spacing with regards to a
data set, we usually are referring to the spacing between /consecutive/ planes. 
[The (200) spot represents d=a/2
although there are also planes that are spaced by a, 3a/2, 2a, etc]. So the 
minimum d-spacing for any spot would be the
n=1 case. The n=2,3,4 etc, correspond to planes farther apart, also represented 
by d in the Bragg eq (based on this
derivation) but really are 2d, 3d, 4d etc, by the way we define “d”. So we are 
really dealing with
2*n*d*sin(theta)=n*lambda, and so the “n’s” cancel out. (Of course, I’m dealing 
with the monochromatic case.)

   I never really saw it this way until I was forced to think about it by 
this new thread – does this makes sense?

Gregg

-Original Message-
From: CCP4 bulletin board [mailto:CCP4BB@JISCMAIL.AC.UK] On Behalf Of Edward A. 
Berry
Sent: Thursday, August 22, 2013 2:16 PM
To: CCP4BB@JISCMAIL.AC.UK
Subject: Re: [ccp4bb] AW: [ccp4bb] Dependency of theta on n/d in Bragg's law

herman.schreu...@sanofi.com mailto:herman.schreu...@sanofi.com wrote:

  Dear James,

  thank you very much for this answer. I had also been wondering about it. To 
clearify it for myself, and maybe for a
few other bulletin board readers, I reworked the Bragg formula to:

 

  sin(theta) = n*Lamda / 2*d

 

  which means that if we take n=2, for the same sin(theta) d becomes twice as 
big as well, which means that we describe
interference with a wave from a second layer of the same stack of planes, which 
means that we are still looking at the
same structure factor.

 

  Best,

  Herman

 

 

This is how I see it as well- if you do a Bragg-law construct with two periods 
of d and consider the second order
diffraction from the double layer, and compare it to the single-layer case you 
will see it is the same wave traveling
the same path with the same phase  at each point. When you integrate rho(r) dot 
S dr, the complex exponential will have
a factor of 2 because it is second order, so the spatial frequency is the same. 
(I haven't actually shown this, being a
math-challenged biologist, but put it on my list of things to do).

   So we could calculate the structure factor as either first order diffraction 
from the conventional d or second order
diffraction from spacing of 2d and get the same result. by convention we use 
first order diffraction only.

(same would hold for 3'd order diffraction from 3 layers etc.)

  -Ursprüngliche Nachricht-

  Von: CCP4 bulletin board [mailto:CCP4BB@JISCMAIL.AC.UK] Im Auftrag von

  James Holton

  Gesendet: Donnerstag, 22. August 2013 08:55

  An: CCP4BB@JISCMAIL.AC.UK mailto:CCP4BB@JISCMAIL.AC.UK

  Betreff: Re: 

Re: [ccp4bb] AW: [ccp4bb] Dependency of theta on n/d in Bragg's law

2013-08-22 Thread Ethan Merritt
On Thursday, August 22, 2013 02:19:11 pm Edward A. Berry wrote:
 One thing I find confusing is the different ways in which d is used. 
 In deriving Braggs law, d is often presented as a unit cell dimension, 
 and n accounts for the higher order miller planes within the cell.

It's already been pointed out above, and you sort of paraphrase it later,
but let me give my spin on a non-confusing order of presentation.

I think it is best to tightly associate n and lambda in your mind
(and in the mind of a student). If you solve the Bragg's law equation for
the wavelength, you don't get a unique answer because you are actually
solving for n*lambda rather than lambda.

There is no ambiguity about the d-spacing, only about the wavelength
that d and theta jointly select for.

That's why, as James Holton mentioned, when dealing with a white radiation
source you need to do something to get rid of the harmonics of the wavelength
you are interested in.

 But then when you ask a student to use Braggs law to calculate the resolution
 of a spot at 150 mm from the beam center at given camera length and 
 wavelength,
 without mentioning any unit cell, they ask, do you mean the first order 
 reflection?

I would answer that with Assume a true monochromatic beam, so n is necessarily 
equal to 1.

 Yes, it would be the first order reflection from planes whose spacing is the 
 answer i am looking for, but going back to Braggs law derived with the unit 
 cell
 it would be a high order reflection for any reasonable sized protein crystal.

For what it's worth, when I present Bragg's law I do it in three stages.
1) Explain the periodicity of the lattice (use a 2D lattice for clarity).
2) Show that a pair of indices hk defines some set of planes (lines)
   through the lattice.
3) Take some arbitrary set of planes and use it to draw the Bragg construction.

This way the Bragg diagram refers to a particular set of planes,
d refers to the resolution of that set of planes, and n=1 for a 
monochromatic X-ray source.  The unit cell comes back into it only if you
try to interpret the Bragg indices belonging to that set of planes.

Ethan

 
 Maybe the mistake is in bringing the unit cell into the derivation in the 
 first place, just define it in terms of 
 planes. But it is the periodicity of the crystal that results in the 
 diffraction condition, so we need the unit cell 
 there. The protein is not periodic at the higher d-spacing we are talking 
 about now (one of its fourier components is, 
 and that is what this reflection is probing.)
 eab
 
 Gregg Crichlow wrote:
  I thank everybody for the interesting thread. (I'm sort of a nerd; I find 
  this interesting.) I generally would always
  ignore that �n� in Bragg's Law when performing calculations on data, but 
  its presence was always looming in the back of
  my head. But now that the issue arises, I find it interesting to return to 
  the derivation of Bragg's Law that mimics
  reflection geometry from parallel planes. Please let me know whether this 
  analysis is correct.
 
  To obtain constructive 'interference', the extra distance travelled by the 
  photon from one plane relative to the other
  must be a multiple of the wavelength.
 
  \_/_
 
  \|/_
 
  The vertical line is the spacing d between planes, and theta is the angle 
  of incidence of the photons to the planes
  (slanted lines for incident and diffracted photon - hard to draw in an 
  email window). The extra distance travelled by
  the photon is 2*d*sin(theta), so this must be some multiple of the 
  wavelength: 2dsin(theta)=n*lambda.
 
  But from this derivation, �d� just represents the distance between /any/ 
  two parallel planes that meet this Bragg
  condition � not only consecutive planes in a set of Miller planes. However, 
  when we mention d-spacing with regards to a
  data set, we usually are referring to the spacing between /consecutive/ 
  planes. [The (200) spot represents d=a/2
  although there are also planes that are spaced by a, 3a/2, 2a, etc]. So the 
  minimum d-spacing for any spot would be the
  n=1 case. The n=2,3,4 etc, correspond to planes farther apart, also 
  represented by d in the Bragg eq (based on this
  derivation) but really are 2d, 3d, 4d etc, by the way we define �d�. So we 
  are really dealing with
  2*n*d*sin(theta)=n*lambda, and so the �n�s� cancel out. (Of course, I�m 
  dealing with the monochromatic case.)
 
 I never really saw it this way until I was forced to think about it 
  by this new thread � does this makes sense?
 
  Gregg
 
  -Original Message-
  From: CCP4 bulletin board [mailto:CCP4BB@JISCMAIL.AC.UK] On Behalf Of 
  Edward A. Berry
  Sent: Thursday, August 22, 2013 2:16 PM
  To: CCP4BB@JISCMAIL.AC.UK
  Subject: Re: [ccp4bb] AW: [ccp4bb] Dependency of theta on n/d in Bragg's law
 
  herman.schreu...@sanofi.com mailto:herman.schreu...@sanofi.com wrote:
 
Dear James,
 
thank you very much for this 

Re: [ccp4bb] AW: [ccp4bb] Dependency of theta on n/d in Bragg's law

2013-08-22 Thread Dom Bellini
Dear Community,

I have attached a short booklet written some 6 years ago during rainy evenings 
to teach principle of crystal diffraction with biologist students in mind, 
never used it as I don't have students, but I now believe its mission was this 
thread ;-)

It uses lots of real space diffraction examples, easily to picture them in the 
head, so to stick with the students for good. It was written with the 
philadelphia philosophy of explain it to me as if I was a 5 yo.

I hope it can save some students the time of going to look for many different 
sources as it is probably a nice summary of the diffraction process.

A short answer, same as many of the other answers but in different words, to 
the original post would be: each hkl family of planes generates one and only 
one structure factor or diffraction spot without any contributions from other 
families (talking of monochromatic experiments). Perhaps doubts may arise due 
to the fact that, e.g., every other 002 plane superpose/aligns with one 001 
plane, but since their spacing d is half of the other and lambda is fixed, from 
2d sin(theta)=lambda it will result that 002, despite perfectly superposing 
with (same inclination of) 001, will reflect in a different direction with 
sin(theta) twice as that for 001. Despite 001 and 002 superpose/align with one 
another the diffraction angle changes because it is not a real reflection 
phenomenon (as if they were mirrors), keeping in mind that the planes are only 
imaginary and a way to help us to visualize the process.

Probably many people from the bb that could have given a better explanation 
than mine might have been put off by the length of the email that might have 
been required. Since I had already written it and ready to go I decided to 
attach it with the best of intentions.

Hopefully it may turn up to be useful for some one.

D




From: CCP4 bulletin board [CCP4BB@JISCMAIL.AC.UK] on behalf of Ethan Merritt 
[merr...@u.washington.edu]
Sent: 22 August 2013 22:57
To: ccp4bb
Subject: Re: [ccp4bb] AW: [ccp4bb] Dependency of theta on n/d in Bragg's law

On Thursday, August 22, 2013 02:19:11 pm Edward A. Berry wrote:
 One thing I find confusing is the different ways in which d is used.
 In deriving Braggs law, d is often presented as a unit cell dimension,
 and n accounts for the higher order miller planes within the cell.

It's already been pointed out above, and you sort of paraphrase it later,
but let me give my spin on a non-confusing order of presentation.

I think it is best to tightly associate n and lambda in your mind
(and in the mind of a student). If you solve the Bragg's law equation for
the wavelength, you don't get a unique answer because you are actually
solving for n*lambda rather than lambda.

There is no ambiguity about the d-spacing, only about the wavelength
that d and theta jointly select for.

That's why, as James Holton mentioned, when dealing with a white radiation
source you need to do something to get rid of the harmonics of the wavelength
you are interested in.

 But then when you ask a student to use Braggs law to calculate the resolution
 of a spot at 150 mm from the beam center at given camera length and 
 wavelength,
 without mentioning any unit cell, they ask, do you mean the first order 
 reflection?

I would answer that with Assume a true monochromatic beam, so n is necessarily
equal to 1.

 Yes, it would be the first order reflection from planes whose spacing is the
 answer i am looking for, but going back to Braggs law derived with the unit 
 cell
 it would be a high order reflection for any reasonable sized protein crystal.

For what it's worth, when I present Bragg's law I do it in three stages.
1) Explain the periodicity of the lattice (use a 2D lattice for clarity).
2) Show that a pair of indices hk defines some set of planes (lines)
   through the lattice.
3) Take some arbitrary set of planes and use it to draw the Bragg construction.

This way the Bragg diagram refers to a particular set of planes,
d refers to the resolution of that set of planes, and n=1 for a
monochromatic X-ray source.  The unit cell comes back into it only if you
try to interpret the Bragg indices belonging to that set of planes.

Ethan


 Maybe the mistake is in bringing the unit cell into the derivation in the 
 first place, just define it in terms of
 planes. But it is the periodicity of the crystal that results in the 
 diffraction condition, so we need the unit cell
 there. The protein is not periodic at the higher d-spacing we are talking 
 about now (one of its fourier components is,
 and that is what this reflection is probing.)
 eab

 Gregg Crichlow wrote:
  I thank everybody for the interesting thread. (I'm sort of a nerd; I find 
  this interesting.) I generally would always
  ignore that �n� in Bragg's Law when performing calculations on data, but 
  its presence was always looming in the back of
  my head. But now that 

Re: [ccp4bb] AW: [ccp4bb] Dependency of theta on n/d in Bragg's law

2013-08-22 Thread Edward A. Berry

OK, I see my mistake. n has nothing to do with higher-order
reflections or planes at closer spacing than unit cell dimensions.
n 1 implies larger d, like the double layer mentioned by the original
poster, and those turn out to give the same structure factor as the
n=1 reflection so we only consider n=1 (for monochromatic).
The higher order reflection from closer spaced miller planes
of course do not satisfy bragg lawat the same lambda and theta.
So I hope people will disregard my confused post (but I think the
one before was somewhat in the right direction)

The higher order diffractions come from finding planes through
the latticethat intersect a large number of points? no- planes
corresponding to 0,0,5 in an orthorhombic crystal do not  all
intersect lattice points, and anyway protein crystals aren't
made of lattice points, they havecontinuous density.

Applying Braggs law to these closer-spaced miller planes  
will tell you that points in one plane will diffract in phase.
But since the protein in the five layers between the planes  
will be different, in fact the layers will not diffract in

phase  and diffraction condition will not be met.

You could say OK, each of the 5 layesr will diffract
with different amplitude and out of phase, but their
vector-sum resultant will be the same as that of
every other five layers, so diffraction from points
through the whole crystal  will interfere constructively.

Or you could say that this theta and lambda satisfy the
bragg equation with d= c axis and n=5, so that points
separated by cell dimensions, which are equal due to
the periodicity of the crystal, will diffract in phase.
That would be a use for n1 with monochromatic light.
The points separated by the small d-spacing scatter in
phase, but that is irrelevant since they are not
crystallographically equivalent. But they also scatter in phase
(actually out of phase by 5 wavelengths) with points separated
by one unit cell, because they satisfy braggs law with
d=c and n=5 (for 0,0,5 reflection still).
So then the higher-order reflections do involve n,
but it is the small d-spacing that corresponds to n=1
and the unit cell spacing which corresponds to the higher n.
The latter results in the diffraction condition being met.
(or am I still confused?)
(and I hope I've got my line-wrapping under control now so this won't be so 
hard to read)






















Ethan Merritt wrote:

On Thursday, August 22, 2013 02:19:11 pm Edward A. Berry wrote:

One thing I find confusing is the different ways in which d is used.
In deriving Braggs law, d is often presented as a unit cell dimension,
and n accounts for the higher order miller planes within the cell.


It's already been pointed out above, and you sort of paraphrase it later,
but let me give my spin on a non-confusing order of presentation.

I think it is best to tightly associate n and lambda in your mind
(and in the mind of a student). If you solve the Bragg's law equation for
the wavelength, you don't get a unique answer because you are actually
solving for n*lambda rather than lambda.

There is no ambiguity about the d-spacing, only about the wavelength
that d and theta jointly select for.

That's why, as James Holton mentioned, when dealing with a white radiation
source you need to do something to get rid of the harmonics of the wavelength
you are interested in.


But then when you ask a student to use Braggs law to calculate the resolution
of a spot at 150 mm from the beam center at given camera length and wavelength,
without mentioning any unit cell, they ask, do you mean the first order 
reflection?


I would answer that with Assume a true monochromatic beam, so n is necessarily
equal to 1.


Yes, it would be the first order reflection from planes whose spacing is the
answer i am looking for, but going back to Braggs law derived with the unit cell
it would be a high order reflection for any reasonable sized protein crystal.


For what it's worth, when I present Bragg's law I do it in three stages.
1) Explain the periodicity of the lattice (use a 2D lattice for clarity).
2) Show that a pair of indices hk defines some set of planes (lines)
through the lattice.
3) Take some arbitrary set of planes and use it to draw the Bragg construction.

This way the Bragg diagram refers to a particular set of planes,
d refers to the resolution of that set of planes, and n=1 for a
monochromatic X-ray source.  The unit cell comes back into it only if you
try to interpret the Bragg indices belonging to that set of planes.

Ethan



Maybe the mistake is in bringing the unit cell into the derivation in the first 
place, just define it in terms of
planes. But it is the periodicity of the crystal that results in the 
diffraction condition, so we need the unit cell
there. The protein is not periodic at the higher d-spacing we are talking about 
now (one of its fourier components is,
and that is what this reflection is probing.)
eab

Gregg Crichlow wrote:

I thank 

Re: [ccp4bb] AW: [ccp4bb] Dependency of theta on n/d in Bragg's law

2013-08-22 Thread Dom Bellini
Hi

Some people emailed me saying that the attachment did not get through.

I hope this will work.

Sorry.

D 


From: CCP4 bulletin board [CCP4BB@JISCMAIL.AC.UK] on behalf of Edward A. Berry 
[ber...@upstate.edu]
Sent: 23 August 2013 00:01
To: ccp4bb
Subject: Re: [ccp4bb] AW: [ccp4bb] Dependency of theta on n/d in Bragg's law

OK, I see my mistake. n has nothing to do with higher-order
reflections or planes at closer spacing than unit cell dimensions.
n 1 implies larger d, like the double layer mentioned by the original
poster, and those turn out to give the same structure factor as the
n=1 reflection so we only consider n=1 (for monochromatic).
The higher order reflection from closer spaced miller planes
of course do not satisfy bragg lawat the same lambda and theta.
So I hope people will disregard my confused post (but I think the
one before was somewhat in the right direction)

The higher order diffractions come from finding planes through
the latticethat intersect a large number of points? no- planes
corresponding to 0,0,5 in an orthorhombic crystal do not  all
intersect lattice points, and anyway protein crystals aren't
made of lattice points, they havecontinuous density.

Applying Braggs law to these closer-spaced miller planes
will tell you that points in one plane will diffract in phase.
But since the protein in the five layers between the planes
will be different, in fact the layers will not diffract in
phase  and diffraction condition will not be met.

You could say OK, each of the 5 layesr will diffract
with different amplitude and out of phase, but their
vector-sum resultant will be the same as that of
every other five layers, so diffraction from points
through the whole crystal  will interfere constructively.

Or you could say that this theta and lambda satisfy the
bragg equation with d= c axis and n=5, so that points
separated by cell dimensions, which are equal due to
the periodicity of the crystal, will diffract in phase.
That would be a use for n1 with monochromatic light.
The points separated by the small d-spacing scatter in
phase, but that is irrelevant since they are not
crystallographically equivalent. But they also scatter in phase
(actually out of phase by 5 wavelengths) with points separated
by one unit cell, because they satisfy braggs law with
d=c and n=5 (for 0,0,5 reflection still).
So then the higher-order reflections do involve n,
but it is the small d-spacing that corresponds to n=1
and the unit cell spacing which corresponds to the higher n.
The latter results in the diffraction condition being met.
(or am I still confused?)
(and I hope I've got my line-wrapping under control now so this won't be so 
hard to read)






















Ethan Merritt wrote:
 On Thursday, August 22, 2013 02:19:11 pm Edward A. Berry wrote:
 One thing I find confusing is the different ways in which d is used.
 In deriving Braggs law, d is often presented as a unit cell dimension,
 and n accounts for the higher order miller planes within the cell.

 It's already been pointed out above, and you sort of paraphrase it later,
 but let me give my spin on a non-confusing order of presentation.

 I think it is best to tightly associate n and lambda in your mind
 (and in the mind of a student). If you solve the Bragg's law equation for
 the wavelength, you don't get a unique answer because you are actually
 solving for n*lambda rather than lambda.

 There is no ambiguity about the d-spacing, only about the wavelength
 that d and theta jointly select for.

 That's why, as James Holton mentioned, when dealing with a white radiation
 source you need to do something to get rid of the harmonics of the wavelength
 you are interested in.

 But then when you ask a student to use Braggs law to calculate the resolution
 of a spot at 150 mm from the beam center at given camera length and 
 wavelength,
 without mentioning any unit cell, they ask, do you mean the first order 
 reflection?

 I would answer that with Assume a true monochromatic beam, so n is 
 necessarily
 equal to 1.

 Yes, it would be the first order reflection from planes whose spacing is the
 answer i am looking for, but going back to Braggs law derived with the unit 
 cell
 it would be a high order reflection for any reasonable sized protein crystal.

 For what it's worth, when I present Bragg's law I do it in three stages.
 1) Explain the periodicity of the lattice (use a 2D lattice for clarity).
 2) Show that a pair of indices hk defines some set of planes (lines)
 through the lattice.
 3) Take some arbitrary set of planes and use it to draw the Bragg 
 construction.

 This way the Bragg diagram refers to a particular set of planes,
 d refers to the resolution of that set of planes, and n=1 for a
 monochromatic X-ray source.  The unit cell comes back into it only if you
 try to interpret the Bragg indices belonging to that set of planes.

   Ethan


 Maybe the mistake is in bringing the unit 

[ccp4bb] Dependency of theta on n/d in Bragg's law

2013-08-20 Thread Pietro Roversi
Dear all,

I am shocked by my own ignorance, and you feel free to do the same, but
do you agree with me that according to Bragg's Law
a diffraction maximum at an angle theta has contributions
to its intensity from planes at a spacing d for order 1, 
planes of spacing 2*d for order n=2, etc. etc.?

In other words as the diffraction angle is a function of n/d:

theta=arcsin(lambda/2 * n/d)

several indices are associated with diffraction at the same angle?

(I guess one could also prove the same result by
a number of Ewald constructions using Ewald spheres
of radius (1/n*lambda with n=1,2,3 ...)

All textbooks I know on the argument neglect to mention this
and in fact only n=1 is ever considered.

Does anybody know a book where this trivial issue is discussed?

Thanks!

Ciao

Pietro



Sent from my Desktop

Dr. Pietro Roversi
Oxford University Biochemistry Department - Glycobiology Division
South Parks Road
Oxford OX1 3QU England - UK
Tel. 0044 1865 275339

Re: [ccp4bb] Dependency of theta on n/d in Bragg's law

2013-08-20 Thread Tim Gruene
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1

Dear Pietro,

You may take a textbook into account which deals with Laue
diffraction. If you search for the keyword Laue and the author
Helliwell at the IUCR journals, you will get a large number of hits,
indicating that this is by no means a 'trivial' issue (e.g.
http://dx.doi.org/10.1107/S0909049599006366 for an overview or
http://dx.doi.org/10.1107/S0108767387098763 for the treatment of
harmonics).

As far as I understand, certain scaling programs take the lambda/2
contribution of monochromators into account.

Regards,
Tim Gruene

On 08/20/2013 04:36 PM, Pietro Roversi wrote:
 Dear all,
 
 I am shocked by my own ignorance, and you feel free to do the same,
 but do you agree with me that according to Bragg's Law a
 diffraction maximum at an angle theta has contributions to its
 intensity from planes at a spacing d for order 1, planes of spacing
 2*d for order n=2, etc. etc.?
 
 In other words as the diffraction angle is a function of n/d:
 
 theta=arcsin(lambda/2 * n/d)
 
 several indices are associated with diffraction at the same angle?
 
 (I guess one could also prove the same result by a number of Ewald
 constructions using Ewald spheres of radius (1/n*lambda with
 n=1,2,3 ...)
 
 All textbooks I know on the argument neglect to mention this and in
 fact only n=1 is ever considered.
 
 Does anybody know a book where this trivial issue is discussed?
 
 Thanks!
 
 Ciao
 
 Pietro
 
 
 
 Sent from my Desktop
 
 Dr. Pietro Roversi Oxford University Biochemistry Department -
 Glycobiology Division South Parks Road Oxford OX1 3QU England - UK 
 Tel. 0044 1865 275339

- -- 
- --
Dr Tim Gruene
Institut fuer anorganische Chemie
Tammannstr. 4
D-37077 Goettingen

GPG Key ID = A46BEE1A

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Version: GnuPG v1.4.14 (GNU/Linux)
Comment: Using GnuPG with Mozilla - http://enigmail.mozdev.org/

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UuckhqtUEG0uB9hheG1uxz0=
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Re: [ccp4bb] Dependency of theta on n/d in Bragg's law

2013-08-20 Thread Dom Bellini
Dear Pietro,

Ladd  Palmer book does explain it, just first example that springs to mind.

HTH

D

-Original Message-
From: CCP4 bulletin board [mailto:CCP4BB@JISCMAIL.AC.UK] On Behalf Of Pietro 
Roversi
Sent: 20 August 2013 15:37
To: ccp4bb
Subject: [ccp4bb] Dependency of theta on n/d in Bragg's law

Dear all,

I am shocked by my own ignorance, and you feel free to do the same, but do you 
agree with me that according to Bragg's Law a diffraction maximum at an angle 
theta has contributions to its intensity from planes at a spacing d for order 
1, planes of spacing 2*d for order n=2, etc. etc.?

In other words as the diffraction angle is a function of n/d:

theta=arcsin(lambda/2 * n/d)

several indices are associated with diffraction at the same angle?

(I guess one could also prove the same result by a number of Ewald 
constructions using Ewald spheres of radius (1/n*lambda with n=1,2,3 ...)

All textbooks I know on the argument neglect to mention this and in fact only 
n=1 is ever considered.

Does anybody know a book where this trivial issue is discussed?

Thanks!

Ciao

Pietro



Sent from my Desktop

Dr. Pietro Roversi
Oxford University Biochemistry Department - Glycobiology Division South Parks 
Road Oxford OX1 3QU England - UK Tel. 0044 1865 275339



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