RE: Oracle Gurus

2002-04-21 Thread Sicular, Alexander

are you out of your mind? pick up an oracle book. at the least you should
offer dinner to the nice coder who is willing to help you.

alex

-Original Message-
From: Joshua Tipton [mailto:[EMAIL PROTECTED]]
Sent: Sunday, April 21, 2002 6:59 PM
To: CF-Talk
Subject: Oracle Gurus


I would be at anyone's mercy if they could do this for me.

 

1.Create a sequence DeptCodeSeq to generate dept codes in the range 

 

1000, 1020, 1040, . .., 9080

 

Create table called Departments that has the following columns in it.

 


DeptCode

Name

DeptSize


NUMBER(4)

VARCHAR2(30)

NUMBER(5)

 

Create a PL/SQL anonymous block called  POPDEPTS.sql  (Populate Department )
using  FOR .. LOOP that uses the DeptCodeSeq to generate the department code
and the name

Where the name is constructed as DEPT-1020 DEPT-1040, and so on. That is the
name of the department is the concatenation of DEPT- and the department
code generated by the sequence. As each row is inserted print out the
department t code and department name delimited by ';' on a separate line. (
use the DBMS_OUTPUT.PUT_LINE ).

 

 

When testing your code you may need to constantly drop your sequence and
create it until your PL/SQL block works correctly.

 

DECLARE



...

BEGIN

 

Your code goes here

( you need  FOR .. LOOP statement )

END;

 

2.Create a PL/SQL block to delete from Departments the departments
that have their name ending in 40 and 80 digits.



   

 

 




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Re: Oracle Gurus

2002-04-21 Thread Jochem van Dieten

Joshua Tipton wrote:
 I would be at anyone's mercy if they could do this for me.

If I understand your questions correctly you are currently at the mercy 
of your teacher. What makes you believe that being at the mercy of just 
anybody would be any better?

Jochem

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RE: Oracle Gurus

2002-04-21 Thread Sicular, Alexander

ok... i'll help a little.

a search for 'oracle sequence' at google spits out
http://members.tripod.com/mdameryk/CreateSequence.htm as the first hit. now
your well on your way.

-Original Message-
From: Joshua Tipton [mailto:[EMAIL PROTECTED]]
Sent: Sunday, April 21, 2002 6:59 PM
To: CF-Talk
Subject: Oracle Gurus


I would be at anyone's mercy if they could do this for me.

 

1.Create a sequence DeptCodeSeq to generate dept codes in the range 

 

1000, 1020, 1040, . .., 9080

 

Create table called Departments that has the following columns in it.

 


DeptCode

Name

DeptSize


NUMBER(4)

VARCHAR2(30)

NUMBER(5)

 

Create a PL/SQL anonymous block called  POPDEPTS.sql  (Populate Department )
using  FOR .. LOOP that uses the DeptCodeSeq to generate the department code
and the name

Where the name is constructed as DEPT-1020 DEPT-1040, and so on. That is the
name of the department is the concatenation of DEPT- and the department
code generated by the sequence. As each row is inserted print out the
department t code and department name delimited by ';' on a separate line. (
use the DBMS_OUTPUT.PUT_LINE ).

 

 

When testing your code you may need to constantly drop your sequence and
create it until your PL/SQL block works correctly.

 

DECLARE



...

BEGIN

 

Your code goes here

( you need  FOR .. LOOP statement )

END;

 

2.Create a PL/SQL block to delete from Departments the departments
that have their name ending in 40 and 80 digits.



   

 

 




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RE: Oracle Gurus

2002-04-21 Thread Matt Liotta

I think you would do better to offer money than mercy.

-Matt

 -Original Message-
 From: Joshua Tipton [mailto:[EMAIL PROTECTED]]
 Sent: Sunday, April 21, 2002 3:59 PM
 To: CF-Talk
 Subject: Oracle Gurus
 
 I would be at anyone's mercy if they could do this for me.
 
 
 
 1.Create a sequence DeptCodeSeq to generate dept codes in the
 range
 
 
 
 1000, 1020, 1040, . .., 9080
 
 
 
 Create table called Departments that has the following columns in it.
 
 
 
 
 DeptCode
 
 Name
 
 DeptSize
 
 
 NUMBER(4)
 
 VARCHAR2(30)
 
 NUMBER(5)
 
 
 
 Create a PL/SQL anonymous block called  POPDEPTS.sql  (Populate
Department
 )
 using  FOR .. LOOP that uses the DeptCodeSeq to generate the
department
 code
 and the name
 
 Where the name is constructed as DEPT-1020 DEPT-1040, and so on. That
is
 the
 name of the department is the concatenation of DEPT- and the
department
 code generated by the sequence. As each row is inserted print out the
 department t code and department name delimited by ';' on a separate
line.
 (
 use the DBMS_OUTPUT.PUT_LINE ).
 
 
 
 
 
 When testing your code you may need to constantly drop your sequence
and
 create it until your PL/SQL block works correctly.
 
 
 
 DECLARE
 
 .
 
 
 
 BEGIN
 
 
 
 Your code goes here
 
 ( you need  FOR .. LOOP statement )
 
 END;
 
 
 
 2.Create a PL/SQL block to delete from Departments the
departments
 that have their name ending in 40 and 80 digits.
 
 
 
 
 
 
 
 
 
 
 
 
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Re: Oracle Gurus

2002-04-21 Thread Alex

Is this a homework assignment or a spec? Anyway, send me full details
off-list and I'll give you a timeline and my rate.  

On Sun, 21 Apr 2002, Joshua Tipton wrote:

 I would be at anyone's mercy if they could do this for me.
 
  
 
 1.Create a sequence DeptCodeSeq to generate dept codes in the range 
 
  
 
 1000, 1020, 1040, . .., 9080
 
  
 
 Create table called Departments that has the following columns in it.
 
  
 
 
 DeptCode
 
 Name
 
 DeptSize
 
 
 NUMBER(4)
 
 VARCHAR2(30)
 
 NUMBER(5)
 
  
 
 Create a PL/SQL anonymous block called  POPDEPTS.sql  (Populate Department )
 using  FOR .. LOOP that uses the DeptCodeSeq to generate the department code
 and the name
 
 Where the name is constructed as DEPT-1020 DEPT-1040, and so on. That is the
 name of the department is the concatenation of DEPT- and the department
 code generated by the sequence. As each row is inserted print out the
 department t code and department name delimited by ';' on a separate line. (
 use the DBMS_OUTPUT.PUT_LINE ).
 
  
 
  
 
 When testing your code you may need to constantly drop your sequence and
 create it until your PL/SQL block works correctly.
 
  
 
 DECLARE
 
 .
 
 
 
 BEGIN
 
  
 
 Your code goes here
 
 ( you need  FOR .. LOOP statement )
 
 END;
 
  
 
 2.Create a PL/SQL block to delete from Departments the departments
 that have their name ending in 40 and 80 digits.
 
 
 

 
  
 
  
 
 
 
 
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RE: Oracle Gurus

2002-04-21 Thread Joshua Tipton

I already have the create table and create sequence part complete I just
actually need help with the insert part.  I have never worked with a
sequence.

I have this much can anyone tell me if I am heading in the right
direction and if so feel free to throw in any thing to help put me in
the correct direction.

CREATE SEQUENCE DeptCodeSeq
INCREMENT BY 20
START WITH 1000
MAXVALUE 9080
NOCYCLE;

CREATE TABLE Departments
(DeptCode NUMBER(4),
 Name VARCHAR2(30),
 DeptSize NUMBER(5));


DECLARE


V_DeptCode DeptCodeSeq.nextval%type;
v_Name  varchar2(30);
v_DeptSize  number(5);


BEGIN







END

-Original Message-
From: Joshua Tipton [mailto:[EMAIL PROTECTED]] 
Sent: Sunday, April 21, 2002 6:59 PM
To: CF-Talk
Subject: Oracle Gurus

I would be at anyone's mercy if they could do this for me.

 

1.Create a sequence DeptCodeSeq to generate dept codes in the
range 

 

1000, 1020, 1040, . .., 9080

 

Create table called Departments that has the following columns in it.

 


DeptCode

Name

DeptSize


NUMBER(4)

VARCHAR2(30)

NUMBER(5)

 

Create a PL/SQL anonymous block called  POPDEPTS.sql  (Populate
Department )
using  FOR .. LOOP that uses the DeptCodeSeq to generate the department
code
and the name

Where the name is constructed as DEPT-1020 DEPT-1040, and so on. That is
the
name of the department is the concatenation of DEPT- and the
department
code generated by the sequence. As each row is inserted print out the
department t code and department name delimited by ';' on a separate
line. (
use the DBMS_OUTPUT.PUT_LINE ).

 

 

When testing your code you may need to constantly drop your sequence and
create it until your PL/SQL block works correctly.

 

DECLARE



...

BEGIN

 

Your code goes here

( you need  FOR .. LOOP statement )

END;

 

2.Create a PL/SQL block to delete from Departments the
departments
that have their name ending in 40 and 80 digits.



   

 

 




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