[cfaussie] Re: RegEx Backreferences...
Something like this should do it for you:
cfset regex = (\d+)\s+(\d{4}\s+\d{4})
cfset str = 07 1234 5678
cfset stResult = reFindNoCase(regex,str,1,true)
cfdump var=#stResult#
cfset areacode = mid(str,stResult.pos[2],stResult.len[2])
cfset number = mid(str,stResult.pos[3],stResult.len[3])
cfoutput(#areacode#) #number#/cfoutput
If you return sub-expressions, the resulting structure will contain
multiple entries. The first element in the pos and len arrays will be
the match for the whole regex. The subsequent entries will be the
matches for the sub-expressions.
There should be n+1 entries in those arrays. Where n is the number of
sub-expressions in your regex.
Spike
Taco Fleur wrote:
Morning!
How do I return back references? (maybe I need another coffee, but I
just don't see it)
The regex
(\d+)\s+(\d{4}\s+\d{4})
07 1234 5678
I know I can reference to the area code by
07 = \1
I know I can reference to the telephone number by
1234 5678 = \2
But how in godsname do I output it?
I could NOT just do
cfoutput
#\1# #\2#
/cfoutput
All I can think of is using reReplace() but surely there must be some
other way!?
*Taco Fleur
07 3535 5072*
Tell me and I will forget
Show me and I will remember
Teach me and I will learn
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[cfaussie] Re: RegEx Backreferences...
off course, cheers!
-Original Message-
From: Spike [mailto:[EMAIL PROTECTED]
Sent: Thursday, 20 November 2003 9:41 AM
To: CFAussie Mailing List
Subject: [cfaussie] Re: RegEx Backreferences...
Something like this should do it for you:
cfset regex = (\d+)\s+(\d{4}\s+\d{4})
cfset str = 07 1234 5678
cfset stResult = reFindNoCase(regex,str,1,true)
cfdump var=#stResult#
cfset areacode = mid(str,stResult.pos[2],stResult.len[2])
cfset number = mid(str,stResult.pos[3],stResult.len[3])
cfoutput(#areacode#) #number#/cfoutput
If you return sub-expressions, the resulting structure will contain
multiple entries. The first element in the pos and len arrays will be
the match for the whole regex. The subsequent entries will be the
matches for the sub-expressions.
There should be n+1 entries in those arrays. Where n is the number of
sub-expressions in your regex.
Spike
Taco Fleur wrote:
Morning!
How do I return back references? (maybe I need another coffee, but I
just don't see it)
The regex
(\d+)\s+(\d{4}\s+\d{4})
07 1234 5678
I know I can reference to the area code by
07 = \1
I know I can reference to the telephone number by
1234 5678 = \2
But how in godsname do I output it?
I could NOT just do
cfoutput
#\1# #\2#
/cfoutput
All I can think of is using reReplace() but surely there must be some
other way!?
*Taco Fleur
07 3535 5072*
Tell me and I will forget
Show me and I will remember
Teach me and I will learn
---
You are currently subscribed to cfaussie as: [EMAIL PROTECTED]
To unsubscribe send a blank email to
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MXDU2004 + Macromedia DevCon AsiaPac + Sydney, Australia
http://www.mxdu.com/ + 24-25 February, 2004
--
Stephen Milligan
Software Architect for http://www.bestrates.com.au
MSN: [EMAIL PROTECTED]
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[cfaussie] Re: RegEx Backreferences...
The example I showed was just an example, really the telephone number could be anything
+31 07 3433 3243
07 3433 2111
4345 3434
4455
-Original Message-
From: Matthew Walker [mailto:[EMAIL PROTECTED]
Sent: Thursday, 20 November 2003 10:25 AM
To: CFAussie Mailing List
Subject: [cfaussie] Re: RegEx Backreferences...
It's so that I know pos[3] will always return the area code.
But the area code is the first subexpression starting at pos[2] . . . ?
-Original Message-
From: [EMAIL PROTECTED] [mailto:bounce-cfaussie-
[EMAIL PROTECTED] On Behalf Of Taco Fleur
Sent: Thursday, 20 November 2003 11:56 a.m.
To: CFAussie Mailing List
Subject: [cfaussie] Re: RegEx Backreferences...
ok next one...
Can you do something like
(\+\d+|select nothing here, but populate structure)
Reason for doing this is so that
pos[2] len[2] will exists, if that makes any sense?
It's so that I know pos[3] will always return the area code.
-Original Message-
From: Spike [mailto:[EMAIL PROTECTED]
Sent: Thursday, 20 November 2003 9:41 AM
To: CFAussie Mailing List
Subject: [cfaussie] Re: RegEx Backreferences...
Something like this should do it for you:
cfset regex = (\d+)\s+(\d{4}\s+\d{4})
cfset str = 07 1234 5678
cfset stResult = reFindNoCase(regex,str,1,true)
cfdump var=#stResult#
cfset areacode = mid(str,stResult.pos[2],stResult.len[2])
cfset number = mid(str,stResult.pos[3],stResult.len[3])
cfoutput(#areacode#) #number#/cfoutput
If you return sub-expressions, the resulting structure will contain
multiple entries. The first element in the pos and len arrays will be
the match for the whole regex. The subsequent entries will be the
matches for the sub-expressions.
There should be n+1 entries in those arrays. Where n is the number of
sub-expressions in your regex.
Spike
Taco Fleur wrote:
Morning!
How do I return back references? (maybe I need another coffee, but I
just don't see it)
The regex
(\d+)\s+(\d{4}\s+\d{4})
07 1234 5678
I know I can reference to the area code by
07 = \1
I know I can reference to the telephone number by
1234 5678 = \2
But how in godsname do I output it?
I could NOT just do
cfoutput
#\1# #\2#
/cfoutput
All I can think of is using reReplace() but surely there must be some
other way!?
*Taco Fleur
07 3535 5072*
Tell me and I will forget
Show me and I will remember
Teach me and I will learn
---
You are currently subscribed to cfaussie as: [EMAIL PROTECTED]
To unsubscribe send a blank email to
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MXDU2004 + Macromedia DevCon AsiaPac + Sydney, Australia
http://www.mxdu.com/ + 24-25 February, 2004
--
Stephen Milligan
Software Architect for http://www.bestrates.com.au
MSN: [EMAIL PROTECTED]
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You are currently subscribed to cfaussie as: [EMAIL PROTECTED]
To unsubscribe send a blank email to leave-cfaussie-
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