Additional delay after pcalls?
Hello everyone, I am a beginner with clojure and I am playing around with pcalls (I am using clojure 1.2.1). I see different behavior if I run some code from inside the REPL or launching it form the command line. I have the following code in a file called test-pcalls.clj: (let [waste-time (fn [label] (dotimes [k 4] (let [msg (str label k \n)] (Thread/sleep 2000) (print msg] (dorun (pcalls #(waste-time A) #(waste-time b This just creates the function 'waste-time' which slowly (2 seconds at a time) counts 0..3 and prints a label and the count each time. Two copies of the function are then started in parallel with a different label (A and b) I start clojure and then from the REPL I do (load-file test- pcalls.clj). After 8 seconds (2 seconds x 4) I see the two sequences being printed out all in one go. First question I cannot find an aswer is: why do I see everything printed together instead of one step a time? Then I exit to the command line and then start clojure with the source file: clojure test-pcalls.clj Again after 8 seconds I see the sequences printed out as above. But now clojure hangs for a minute or so before returning to the command prompt. Can anyone explain this additional delay? thanks -- You received this message because you are subscribed to the Google Groups Clojure group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
Re: Additional delay after pcalls?
On Wed, Jul 27, 2011 at 11:44 AM, mc4924 claudio.potenza...@gmail.com wrote: Hello everyone, I am a beginner with clojure and I am playing around with pcalls (I am using clojure 1.2.1). I see different behavior if I run some code from inside the REPL or launching it form the command line. I have the following code in a file called test-pcalls.clj: (let [waste-time (fn [label] (dotimes [k 4] (let [msg (str label k \n)] (Thread/sleep 2000) (print msg] (dorun (pcalls #(waste-time A) #(waste-time b This just creates the function 'waste-time' which slowly (2 seconds at a time) counts 0..3 and prints a label and the count each time. Two copies of the function are then started in parallel with a different label (A and b) I start clojure and then from the REPL I do (load-file test- pcalls.clj). After 8 seconds (2 seconds x 4) I see the two sequences being printed out all in one go. First question I cannot find an aswer is: why do I see everything printed together instead of one step a time? Buffering of I/O. Try using println, or adding (.flush *out*) after each print. Then I exit to the command line and then start clojure with the source file: clojure test-pcalls.clj Again after 8 seconds I see the sequences printed out as above. But now clojure hangs for a minute or so before returning to the command prompt. Can anyone explain this additional delay? Waiting for the pcalls thread pool to shut down, I expect. -- Protege: What is this seething mass of parentheses?! Master: Your father's Lisp REPL. This is the language of a true hacker. Not as clumsy or random as C++; a language for a more civilized age. -- You received this message because you are subscribed to the Google Groups Clojure group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
Re: Additional delay after pcalls?
On 7/27/11 11:19 AM, Ken Wesson wrote: On Wed, Jul 27, 2011 at 11:44 AM, mc4924claudio.potenza...@gmail.com wrote: Hello everyone, I am a beginner with clojure and I am playing around with pcalls (I am using clojure 1.2.1). I see different behavior if I run some code from inside the REPL or launching it form the command line. I have the following code in a file called test-pcalls.clj: (let [waste-time (fn [label] (dotimes [k 4] (let [msg (str label k \n)] (Thread/sleep 2000) (print msg] (dorun (pcalls #(waste-time A) #(waste-time b This just creates the function 'waste-time' which slowly (2 seconds at a time) counts 0..3 and prints a label and the count each time. Two copies of the function are then started in parallel with a different label (A and b) I start clojure and then from the REPL I do (load-file test- pcalls.clj). After 8 seconds (2 seconds x 4) I see the two sequences being printed out all in one go. First question I cannot find an aswer is: why do I see everything printed together instead of one step a time? Buffering of I/O. Try using println, or adding (.flush *out*) after each print. Then I exit to the command line and then start clojure with the source file: clojure test-pcalls.clj Again after 8 seconds I see the sequences printed out as above. But now clojure hangs for a minute or so before returning to the command prompt. Can anyone explain this additional delay? Waiting for the pcalls thread pool to shut down, I expect. Yeah, you will want to call '(shutdown-agents)' to have Clojure shut down the thread pool it uses for agents, futures, etc.. -Ben -- You received this message because you are subscribed to the Google Groups Clojure group. To post to this group, send email to clojure@googlegroups.com Note that posts from new members are moderated - please be patient with your first post. To unsubscribe from this group, send email to clojure+unsubscr...@googlegroups.com For more options, visit this group at http://groups.google.com/group/clojure?hl=en
